I think the given series is
[tex]\displaystyle\sum_{n=2}^\infty \frac{n^2}{n^3+1}[/tex]
You can use the integral test because the summand is clearly positive and decreasing. Then
[tex]\displaystyle\sum_{n=2}^\infty\frac{n^2}{n^3+1} > \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx[/tex]
Substitute u = x ³ + 1 and du = 3x ² dx, so the integral becomes
[tex]\displaystyle \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx = \frac13\int_9^\infty\frac{\mathrm du}u = \frac13\ln(u)\bigg|_{u=9}^{u\to\infty}[/tex]
As u approaches infinity, we have ln(u) also approaching infinity (whereas 1/3 ln(9) is finite), so the integral and hence the sum diverges.
Determine whether the integral is divergent or convergent. If it is convergent, evaluate it.
[infinity]
â« e^-1.3x dx
1
Which is the graph of the equation y- 1 =} (x 3)?
10
06
6 4
(9,5)
3.1)
1
-10-A-22
2 4 6 8 10 x
4
od
wo
10
6
A motel has a policy of booking as many as 150 guests in a building that holds 140. Past studies indicate that only 85% of booked guests show up for their room. Find the probability that if the motel books 150 guests, not enough seats will be available.
Answer:
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
150 guests booked:
This means that [tex]n = 150[/tex]
85% of booked guests show up for their room.
This means that [tex]p = 0.85[/tex]
Is the normal approximation suitable:
[tex]np = 150(0.85) = 127.5[/tex]
[tex]n(1-p) = 150(0.15) = 22.5[/tex]
Both greater than 10, so yes.
Mean and standard deviation:
[tex]\mu = E(X) = np = 150*0.85 = 127.5[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150*0.85*0.15} = 4.3732[/tex]
Find the probability that if the motel books 150 guests, not enough seats will be available.
More than 140 show up, which, using continuity correction, is [tex]P(X > 140 + 0.5) = P(X > 140.5)[/tex], which is 1 subtracted by the p-value of Z when X = 140.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140.5 - 127.5}{4.3732}[/tex]
[tex]Z = 2.97[/tex]
[tex]Z = 2.97[/tex] has a p-value of 0.9985.
1 - 0.9985 = 0.0015.
0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.
Which best represents data that is not likely to be clustered?
A. a low MAD and IQR
B. low MAD and a great IQR
C. a low IQR and a great MAD
D. a great MAD and IQR
Answer: guess it your self
Step-by-step explanation:
You $12 for a day, and plan to spend your time feeding the Lorakeets. $2 per feed (f), and drinking ICEE's (I), $4 each. What is the equation for the total number f times you can feed the lorakeets and icees you can drink with your total amount of money you brought?
Answer: 85 i think
Step-by-step explanation:
3/8 x 1 1/2 x1 1/2 What is the answer please and step by step
Answer:
=3/8×1 1/2×1 1/2
=3/8 ×3/2×3/2 ∴ 1 1/2 =2×1+1/2=3/2
=27/32 ∴3×3×3=27 ∴8×2×2=32
The gcf of two numbers is 3 and their lcm is 180, if one of the numbers is 45 then found the second number
Answer:
answer is 12
Step-by-step explanation:
gcf = 3
lcm = 180
let 45 be y
let unknown be X
to get x
X=( lcm * gcf) / y
X=(180*3)/45
X=(540)/45
X=12
the other number is 12
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 401 drivers and find that 294 claim to always buckle up. Construct a 90% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5].
Answer:
[0.6969, 0.7695]
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
They randomly survey 401 drivers and find that 294 claim to always buckle up.
This means that [tex]n = 401, \pi = \frac{294}{401} = 0.7332.
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7332 - 1.645\sqrt{\frac{0.7332*0.2668}{401}} = 0.6969[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7332 + 1.645\sqrt{\frac{0.7332*0.2668}{401}} = 0.7695[/tex]
The 90% confidence interval for the population proportion that claim to always buckle up is [0.6969, 0.7695]
Solve for the value of x
x= 55°
according to the picture .........
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
f(x)= sqrt of x [0,9]
c =
Answer:
9/4
Step-by-step explanation:
f(x) is continuous and differentiable on (0,9).
We want to find c using the following equation.
f'(c)=(f(9)-f(0))/(9-0)
This will require us to find f'(x) first.
f(x)=sqrt(x) is the same as f(x)=(x)^(1/2)
Using power rule to differentiate this gives f'(x)=(1/2)(x)^(1/2-1) or simplified f'(x)=(1/2)x^(-1/2) or f'(x)=1/(2x^(1/2)).
So we want to solve:
(1/2)c^(-1/2)=(f(9)-f(0))/(9-0)
Simplify denominator on right:
(1/2)c^(-1/2)=(f(9)-f(0))/9
This will require us to find f(9) and f(0).
If f(x)=sqrt(x), then f(9)=sqrt(9)=3 and f(0)=sqrt(0)=0.
So we have the following equation so far:
(1/2)c^(-1/2)=(3-0)/9
Simplify numerator on right:
(1/2)c^(-1/2)=3/9
Multiply both sides by 2:
c^(-1/2)=6/9
Raise both sides to the -2 power:
c^(1)=(6/9)^(-2)
Note c^1=c:
c=(6/9)^(-2):
Note negative exponent means to find reciprocal of base to change exponent to opposite
c=(9/6)^2
Apply the second power:
c=81/36
Reduce by dividing top and bottom by 9:
c=9/4
This means the slope of the tangent to the curve f at x=9/4 is the same value as the slope of the secant line going through points (0,0) and (9,3).
Also 9/4 is between 0 and 9... According to the theorem we were suppose to get a value c between x=0 and x=9.
Confirmation:
Slope of the secant line is (3-0)/(9-0)=3/9=1/3.
Slope of the tangent line to curve f at x=9/4.
f'(x)=(1/2)x^(-1/2)
f'(9/4)=(1/2)(9/4)^(-1/2)
f'(9/4)=(1/2)(3/2)^(-1)
f'(9/4)=(1/2)(2/3)
f'(9/4)=1/3
They are indeed equal values (talking about the 1/3 from the secant and the tangent.)
Matematykakdbebox
Jaggbn
Answer:
theres no question....
Step-by-step explanation:
???
Given the following coordinates complete the glide reflection transformation.
Answer:
[tex]A" = (7,-2)[/tex]
[tex]B" = (10,0)[/tex]
[tex]C"= (12,-3)[/tex]
Step-by-step explanation:
Given
[tex]A = (4,2)[/tex]
[tex]B = (7,0)[/tex]
[tex]C =(9,3)[/tex]
a: Reflect over x-axis
The rule of this is:
[tex](x,y) \to (x,-y)[/tex]
So, we have:
[tex]A' = (4,-2)[/tex]
[tex]B' = (7,0)[/tex]
[tex]C' = (9,-3)[/tex]
b: Shift 3 units left
The rule of this is:
[tex](x,y) \to (x+3,y)[/tex]
So, we have:
[tex]A" = (4+3,-2)[/tex]
[tex]A" = (7,-2)[/tex]
[tex]B" = (7+3,0)[/tex]
[tex]B" = (10,0)[/tex]
[tex]C"= (9+3,-3)[/tex]
[tex]C"= (12,-3)[/tex]
In a survey one-forth like cake only and 20 didn't like cake at all. Also 50% children like ice cream but 12 like none of them.How many like both?
Answer:
2
Step-by-step explanation:
Let x represent the total number of people. Let C represent those that like cake and let I represent those that like ice cream. Given:
C = (1/4)x = 0.25x, I = 0.5x, (C ∪ I)' = 12, C' = 20
Therefore:
C ∩ I' = C' - (C ∪ I)' = 20 - 12 = 8
C ∩ I = C - C ∩ I' = 0.25x - 8
C' ∩ I = I - C ∩ I = 0.5x - (0.25x - 8) = 0.25x + 8
The total students = (C ∩ I) + (C' ∩ I) + (C ∩ I') + (C ∪ I)'
x = 0.25x - 8 + 0.25x + 8 + 8 + 12
x = 0.5x + 8 + 12
x = 0.5x + 20
0.5x = 20
x = 40
Students that liked both = C ∩ I = 0.25(40) - 8 = 2
Determine the dimension of the vector space. M4,2
STEP 1: Determine the number of linearly independent vectors needed to span M4,2. The basis for M4,2 has linearly independent vectors.
STEP 2: Using the result from Step 1, determine the dimension of M4,2.
Answer:
STEP 1
M_{4,2} is set of 4x2 matrices hence each matrix has 4*2=8 entries. Each entry can be filled independently.
Hence its basis has 8 linearly independent vectors.
STEP 2
Dimension= cardinality of basis = 8.
Q3) He decorated the path in his garden with LED bulbs in three rows so that the bulbs in the first row blink at every 4 min, the bulbs in the second row blink at every 6 min and the bulbs in the third row blink at every 8 min. When will they blink together for the first time if he switches the lights on together at 6pm?
6.24 pm
6.30 pm
6.40 pm
They will not blink together at any time
Q4) If so, which is the next time they blink together?
6.28 pm
6.48 pm
6.50 pm
None of these.
Answer:
They will blink together at 24minutes
Step-by-step explanation:
Using product of primes
4 = 2²
6 = 2 × 3
8 = 2³
Prime numbers with highest power
2³ × 3
8 x 3
24 minutes.
billy joe purchased a 60 gallon pool. at 1 pm he stared filling the pool at the rate of 3 gallons per hour. after 10 hours the horses started drinking the water at the rate of 1 gallon per hour. five hours after that he notices the animal and place a second hose in the pool which filled at the rate of 2 gallons per hour. at what time was the pool finally filled
Answer:
3*10=30 gallons after 10 hours
minus 1 gal/hr for 5 hours=25 gallons.
If the animals are still drinking, the pool is effectively filling at 1 gal/hr, 2-1, and it will take 35 more hours to fill.
If the animals aren't drinking, the pool will fill at 2 gal/hour and it will be full in 35/2 hours or 17.5 hours.
Step-by-step explanation:
Question 27 of 58
Select the equation that represents the problem. Let x represent the unknown
number.
Mr. Jefferson bought 336 markers for his class. The
markers came in packs of 12. How many packs did he
buy?
A. 336 - x= 12
B. 12x= 336
O C. 336x= 12
O D. x + 12 = 336
SUBMIT
Answer:
B.
Step-by-step explanation:
The answer is B.
A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 millimeters and standard deviation 0.08 millimeter. (a) [5pts] What proportions of the diameters are greater than 25.4
Answer:
The proportions of the diameters that are greater than 25.4 millimeters is 5%.
Step-by-step explanation:
Given;
mean of the normal distribution, m = 25.1 millimeters
standard deviation, d = 0.08 millimeter
1 standard deviation above the mean = m + d = 25.1 + 0.08 = 25.18
2 standard deviation above mean = m + 2d = 25.1 + 2(0.08) = 25.26
3 standard deviation above the mean = m + 3d = 25.1 + 3(0.08) = 25.34
4 standard deviation above the mean = m + 4d = 25.1 + 4(0.08) = 25.42
To obtain a diameter greater than 25.4, we select data after 4 standard deviation above the mean.
Data within 4 standard deviation above the mean is 95%
Data outside 4 standard deviation above the mean is 5%
Therefore, the proportions of the diameters that are greater than 25.4 millimeters is 5%.
find the intercept and graph the following linear equations: 2x+y=1
plz include x and y intercepts
Answer:
2(1)+y =1 for × intercept
2x+(1)=1 for y intercept
Solve the triangle. round your answer to the nearest tenth
Answer:
∡A =41°
~~~~~~~~~~~~
BC=21
~~~~~~~~~~~~~~
sin(24)/AC=sin(41)/21
AC=13
~~~~~~~~~~~~~~
sin(115)/AB=sin(41)/21
AB=29
Step-by-step explanation:
What is the value of the 2 in 4.502?
Answer:
0.002
Step-by-step explanation:
2 in 4.502 is in the thousandths place
Value is 0.002
Use the order of operations to simplify the following expression.
-2 3 + |7| - 4 · 2
-38
-23
-9
-10
Answer:
-9
Step-by-step explanation:
-2 3 + |7| - 4 · 2
I assume -2 3 means -2^3.
-2^3 + |7| - 4 · 2 =
= -8 + 7 - 8
= -1 - 8
= -9
Answer:
-9
Step-by-step explanation:
-2^ 3 + |7| - 4 · 2
Parentheses first and an absolute value is considered parentheses
-2 ^3 + 7 - 4 · 2
Then exponenets
Since the sign is outside of the exponent it is considered multiplication
-1 * (2^3)+ 7 - 4 · 2
-1 *8 + 7 - 4 · 2
Then multiply
-8 +7 -8
Then add and subtract from left to right
-1-8
-9
Six sophomores and 14 freshmen compete
Answer:
(6C1)(5C1)/20C2
Step-by-step explanation:
Was right on egde
what is 9/10 + 7/15
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}[/tex]
[tex]\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}[/tex]
[tex]\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}[/tex]
[tex]\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}[/tex]
[tex]\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}[/tex]
[tex]\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}[/tex]
[tex]\mathsf{= \dfrac{27+14}{30}}[/tex]
[tex]\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}[/tex]
[tex]\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}[/tex]
[tex]\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Please help me with the question?
Answer:
<a=55° ,< b=55° and <c=70°
I really need help!!!
Answer:
the third option (a=1, h=0, k=6)
Step-by-step explanation:
if I understand correctly what your teacher wants from you, then you need find a (the factor of x² in the equation) and the vertex (turnaround point) of the parabola represented by such a quadratic equation.
the vertex point coordinates are called (h, k).
the general form of such an equation equation is
y = ax² + bx + c
so, we have a right away : a=1
now we can make this quickly by using common sense, or a bit more complex by going through mathematical formulas.
the fast, practical way is to know that y=x² is the very basic parabola with its vertex at (0, 0).
y = x² + 6 is simply the same parabola just lifted up (y direction) by 6 units, that makes the vertex (0, 6).
in pure theory, though, we need to find the transformation from the general y = ax² + bx + c form to
y = a(x - h)² + k
we see right away that k = f(h) = h² + 6
y = a(x² - 2xh + h²) + k
a=1
y = x² - 2xh + h² + k = x² - 2xh + h² + h² + 6 =
= x² - 2xh + 2h² + 6
comparing with y = x² + 6
we know that
-2×h = 0
as we have no term with just x.
=> h = 0
2h² + 6 = k
2×0² + 6 = 6 = k
Armando planted a 9-inch tall magical beanstalk. The height of the beanstalk increases by 13% each day. Write a function f that determines the height of the beanstalk in inches in terms of the number of days t since Armando planted the beanstalk.
Answer:
F(t) = 9(1 + 0.13)^t
Step-by-step explanation:
Given :
Height of beanstalk = initial height = 9 inches
Percentage increase in height per day = 13%
This plant exhibits an exponential increase in growth per day, hence, the function will be modeled using an exponential function.
Using an exponential function :
F(t) = initial height(1 + percentage increase)^t
Where, t = number of days since tree was planted.
The function is :
F(t) = 9(1 + 0.13)^t
What number should be added to -3/2 to get -5/8
Answer: 7 / 8 should be added
Step-by-step explanation:
Let x be the number that should be added
Write the equation
-3/2 + x = -5/8
Add -3/2 on both sides
-3/2 + x + 3/2 = -5/8 + 3/2
x = -5/8 + 3/2
Change the denominator of 3/2 to 8 in order to do addition
x = -5/8 + 12 / 8
x = 7 / 8
Hope this helps!! :)
Please let me know if you have any questions
Suppose that it takes 12 units of carbohydrates and 8 units of protein to satisfy Jacob's minimum weekly requirements. A particular type of meat contains 2 units of carbohydrates and 2 units of protein per pound. A particular cheese contains 3 units of carbohydrates and 1 unit of protein per pound. The meat costs $3.70 per pound and the cheese costs $2.60 per pound. How many pounds of each are needed in order to minimize the cost and still meet the minimum requirements? What is the minimum cost?
Answer:
a. The number of pounds of the meat required is 3 pounds and the number of pounds of cheese required is 2 pounds.
b. $ 16.7
Step-by-step explanation:
a. How many pounds of each are needed in order to minimize the cost and still meet the minimum requirements?
Let c represent the carbohydrate units and p the protein units.
For the meat portion M, we have 2 units of carbohydrates and 2 units of protein per pound. So, M = 2c + 2p
For the cheese portion K, we have 3 units of carbohydrates and 1 units of protein per pound. So, K = 3c + p.
Let x be the number of pounds of meat required and y be the number of cheese pounds required. The total number of pounds required is T
So, we have xM + yK = x(2c + 2p) + y(3c + p)
= 2xc + 2xp + 3yc + yp
= 2xc + 3yc + 2xp + yp
= (2x + 3y)c + (2x + y)p
Since the required number of units, R is 12 units of carbohydrates and 8 units of protein, we have R = 12c + 8p
Since T = R, we have
(2x + 3y)c + (2x + y)p = 12c + 8p
Equating coefficients, we have
2x + 3y = 12 (1) and 2x + y = 8 (2)
Subtracting (2) from (1), we have
2x + 3y = 12 (1)
-
2x + y = 8 (2)
2y = 4
y = 4/2
y = 2
Substituting y = 2 into (2), we have
2x + y = 8
2x + 2 = 8
2x = 8 - 2
2x = 6
x = 6/2
x = 3
Since x = 3 and y = 2
The number of pounds of the meat required is 3 pounds and the number of pounds of cheese required is 2 pounds.
What is the minimum cost?
Since meat costs $3.70 per pound and the cheese costs $2.60 per pound and we have 3 pounds of meat and 2 pounds of cheese, the total cost of meat is C = $3.70/pound × 3 pounds = $ 11.1.
The total cost of cheese is C' = $2.60/pound × 2 pounds = $ 5.2.
So, the minimum cost C" = C + C' = $ 11.1 + $ 5.2 = $ 16.7
Answer:
Step-by-step explanation:
If 8 bags of chips cost 10.32;how much will you pay for 20 bags?
Answer:
$25.80
Step-by-step explanation:
First, let's find the cost of one bag of chip:
10.32/8 = 1.29
If one bag costs $1.29, simply multiply the number of bags (20) by 1.29
1.29 x 20 = 25.80
= $25.80
Answer:
25.80
Step-by-step explanation:
We can use a ratio to solve
8 bags 20 bags
------------- = ----------------
10.32 x dollars
Using cross products
8x = 10.32 * 20
8x =206.40
Divide each side by 8
8x/7 = 206.40/8
x =25.80
