I need help with pre calculus.

I Need Help With Pre Calculus.
I Need Help With Pre Calculus.
I Need Help With Pre Calculus.

Answers

Answer 1

Problem 1

Answer: Choice A.  (0,9)

---------------------

Explanation:

The first task is to determine the function for f(x). Because it's linear, it's in the form y = mx+b. Let's find the slope m.

Select any two columns to pick out (x,y) points from the f(x) function. I'll pick the first two columns to select the points (-6,15) and (-4,11). Apply the slope formula to these two points to get...

m = (y2-y1)/(x2-x1)

m = (11-15)/(-4-(-6))

m = (11-15)/(-4+6)

m = -4/2

m = -2

Then use this m value along with any of the points of the table to determine the y intercept b. I'll use the point (-6,15)

y = mx+b

b = y-mx

b = 15-(-2)*(-6)

b = 15-12

b = 3

The y = mx+b equation becomes y = -2x+3 and that leads directly to the function f(x) = -2x+3.

Repeat all of those steps but do so for g(x) this time. I'll skip those steps over but you should get the function g(x) = 5x-6.

The y intercepts of f(x) and g(x) found were 3 and -6 respectively. Subtract those values to find the y intercept of h(x) = (f-g)(x) = f(x)-g(x).

So we get 3-(-6) = 3+6 = 9 which leads to the location (0, 9).

=========================================================

Problem 2

Answer: Choice Ax is any real number but x cannot equal -2, -1 or 1.

---------------------

Explanation:

Through trial and error, the factor by grouping method, or using your graphing calculator, factor the denominator to get

g(x) = x^3+2x^2-x-2 = (x+2)(x+1)(x-1)

The factors (x+2), (x+1) and (x-1) lead to the roots of x = -2, x = -1, and x = 1 in that order. Those three roots of g(x) will make g(x) = 0 and cause a division by zero error in the denominator. So we must kick out those three values from the domain. Every other real number is allowed in the domain. So that's how we get the notation for choice A. It starts off saying x is a real number. Then it goes onto say that -2, -1 and 1 aren't allowed.

So overall the domain is described as: "x can be almost any real number except x cannot be -2, cannot be -1, and it cannot be 1".

Side note: We don't involve the numerator function at all.

=========================================================

Problem 3

Answer: Choice B. 2x+1 and x-3

---------------------

Explanation:

The height is x, which we can factor out like this

2x^3-5x^2-3x

2x^2*x - 5x*x - 3*x

x(2x^2-5x-3)

Effectively you would use the distribution rule in reverse.

Now let's factor the remaining expression in the parenthesis.

I'll use the factor by grouping method.

2x^2-5x-3

2x^2-6x+1x-3

(2x^2-6x) + (1x-3)

2x(x-3) + 1(x-3)

(2x+1)(x-3)

Therefore, the full factorization is

x(2x+1)(x-3)

which shows we have the dimensions of x, (2x+1) and (x-3). The order doesn't matter so we could easily have (2x+1) the length and (x-3) the width, or we could have it the other way around.

You can verify that (2x+1)(x-3) expands out to 2x^2-5x-3 using either the FOIL method or the box method.


Related Questions

AM and CM
BM and BM
AB and CB

Answers

These are variables on your graph

THIS IS NOT A TEST OR ASSESSMENT!! NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! PLEASE EXPLAIN!! Chapter 13


1. What is a conic ? How would you be able to model different conic sections at home(how would you slice a 3D shape to create the conic sections)?



2. How does the equation for the ellipse compare to the equation for a hyperbola? How can you determine the difference?


3. What is the difference between a vertex, a focus, and a directrix?

Answers

9514 1404 393

Explanation:

1.

A cone is a 3-dimensional object created by revolving a line about an axis that intersects that line. This figure is a "double-napped" cone. The point where the revolved line and the axis meet is the a.pex, or vertex, of the cone. Typically, we're concerned with a finite portion of the cone, from the vertex to a base that is a circle in a plane perpendicular to the axis.

A "conic" is a 2-dimensional figure that results from the intersection of a plane and a cone. There are four general categories, named according to the angle the plane makes with the axis and/or the side of the cone. These are illustrated in the attachment.

a circle - the plane of intersection is perpendicular to the axisan ellipse - the plane of intersection is at an angle between 90° and the angle of the side relative to the axis. Both an ellipse and a circle are closed figures.a parabola - the plane of intersection is at the same angle as the side of the cone. A parabola is a one-sided open figure.a hyperbola - The plane of intersection is at an angle between that of the side of the cone and the axis of the cone. The plane will intersect both parts of a double-napped cone producing a double-sided open figure.

Producing these at home can be an interesting project. A circle can be made using a compass.

An ellipse can be drawn using a pair of pins and a loop of string. The pins would be placed at the foci of the ellipse, and the string would constrain the drawing instrument (pen or pencil) to have a constant total distance to the two foci.

A parabola can be drawn on graph paper using coordinates derived from an equation for it. It can also be drawn using a compass and a set square by plotting points that are equidistant from the focus and a line that is called the directrix. If you have a physical cone-shaped object, you can cut it at an angle that will produce a parabola.

A hyperbola can be drawn on graph paper from an equation. It can also be drawn using a compass by plotting points that have a constant difference in their distance to the two foci, or by plotting points whose ratio of distance to focus and directrix is a constant. A physical cone-shaped object can be cut to produce a hyperbola.

__

2.

The general form equation for a conic is ...

  Ax² +Bxy +Cy² +Dx +Ey +F = 0

Usually, we're concerned with conics that have axes parallel to the coordinate axes, so B=0. The equation of an ellipse has A and C with the same sign. The equation of a hyperbola has A and C with opposite signs,

In standard form, the equations for figures centered at the origin are ...

ellipse: x²/a +y²/b = 1hyperbola: x²/a -y²/b = 1 (opens horizontally)hyperbola: y²/a -x²/b = 1 (opens vertically)

__

3.

The vertex of a conic is an extreme point on the (major) axis of the conic. The focus is a point used in the definition of the conic. The focus is "inside" the curve, on the axis of symmetry. The directrix is a line used in the definition of the conic. The directrix is "outside" the curve, perpendicular to the axis. The second attachment shows these for a parabola.

Help me plz help me plz plz

Answers

Im sorry I don't know the answer to the question

AABC is reflected across the x-axis and then translated 4 units up to create AA'BC. What are the coordinates of the vertices of AABC?

Answers

When Triangle ABC is reflected on the x-axis the new coordinates are A (-3,-1) B(-1,-3) C(-2,-1)

However the Triangle is then translated 4 units up, so the New and Final coordinates for Triangle ABC is A(-3,3) B(-1,0) and C(-2,4)

Hope this helps

Muka saved 476.60. He gave Kelvin 429.10 and bought T-Shirt for 432.05, how much money he has left over​

Answers

Definitely a typo in there he’d be in debt

A concave polygon can never be classified as a regular polygon true or false??? Need answer ASAP please

Answers

Answer:

Regular Polygons are never concave by definition.

Step-by-step explanation:

let a function F:A➡️B be defined by f(x)=x+1÷2x-1 with A={-1,0,1,2,3,4} and B= {-1,0,4/5,5/7,1,2,3,}.Find the range of f. plzzzz help​

Answers

Answer:

Range: {-1, 0, 5/7, 4/5, 1, 2}

Step-by-step explanation:

We know that:

f(x) = (x + 1)/(2x - 1)

And:

f: A ⇒ B

where:

A={-1,0,1,2,3,4}

B= {-1,0,4/5,5/7,1,2,3,}

We want to find the range of f(x).

The range of f(x) will be the set of the outputs of f(x) (and because f goes from A to B, we will only take the outputs that belong to B).

Then we only need to evaluate all the values of A in f(x), and see if the output belongs to B.

we have:

f(x) = (x + 1)/(2x - 1)

f(-1) = (-1 + 1)/(2*-1 - 1) = 0   (this does belong to B)

f(0) = (0 + 1)/(2*0 - 1) = -1  (this does belong to B)

f(1) = (1 + 1)/(2*1 - 1) = 2  (this does belong to B)

f(2) = (2 + 1)/(2*2 - 1) = 1 (this does belong to B)

f(3) = (3 + 1)/(2*3 - 1) = 4/5  (this does belong to B)

f(4) = (4 + 1)/(2*4 - 1) = 5/7  (this does belong to B)

So the range of f(x) is the set with all these outputs, which is:

Range: {-1, 0, 5/7, 4/5, 1, 2}

The correlation coefficient, r, between the ages of employees, x, and the number of sick days taken per year, y, equals 0.81.

Complete the statement based on the information provided.

The value of r is
✔ positive
and is relatively close to
✔ 1
, so the variables are
✔ closely
associated. It appears that, as the age of an employee increases, the number of sick days taken
✔ increases
.

Answers

Answer:

✔ positive

✔ 1

✔ closely

✔ increases

ED2021

what is the union of these two sets? E={-1,0,4,5,6,7} G={-2,-1,1,2,3,8}

Answers

Answer:

U={-2,-1,0,1,2,3,4,5,6,7,8}

What error, if any, did Noah make?

Answers

Answer:

breathing, jk buddy

Step-by-step explanation:

Verify that the indicated function y = ϕ(x) is an explicit solution of the given first-order differential equation. (y − x)y' = y − x + 18; y = x + 6 √(x + 4)

When y = x + 6√(x + 4) y'=_________
Thus in terms of x, (y-x)y'=________
y-x+18=________

Answers

If y = x + 6√(x + 4), then

y' = 1 + 3/√(x + 4)

Substituting y and y' into the DE gives

(y - x) y' = (x + 6√(x + 4) - x) (1 + 3/√(x + 4))

… = 6√(x + 4) (1 + 3/√(x + 4))

… = 6√(x + 4) + 18

on the left side, while on the right you get

y - x + 18 = x + 6√(x + 4) - x + 18

… = 6√(x + 4) + 18

so both sides match and the given function is indeed a solution to the DE.

If k(x) = 5x - 6, which expression is equivalent to (k+ k)(4)?

Answers

Answer:

3h33j333jj3

Step-by-step explanation:b3n3n3nn3n33

How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?

Answers

Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

an = 100

Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

n = 50

d = 2

l = ?

Find l

l = a1 + (n - 1)*2

l = 1 + 49*2

l = 99

Sum

Sum = (1 + 99)*50/2

Sum = 2500

The difference and answer is 2550 - 2500  = 50

You play a game where you roll a single die. You pay $1 to play, and the payouts are $0.50 if you roll an
even number, $2 if you roll a 1, and $1 if you roll a 3 or 5.
2. What are the odds for winning money if you play this game? Show your work and Explain.
dan
3. What is the expected value of this game? Show your work and Explain what the results mean.

Answers

All you do is first you ha

proving lines parallel!!! please help

Answers

Answer:

B.

Step-by-step explanation:

Since C and A are parallel

and B is perpendicular to C

then B is also perpendicular to A

meaning they have the same angle so 90 Degrees.

twice the difference of a number and 8 is 6. use the variable x for the unknown number.​

Answers

Answer:

11

Step-by-step explanation:

Unknown number = x

If twice the difference of x and 8 is 6:

2(x-8) = 6

2x-16 = 6

2x = 6 + 16

2x = 22

x = 22/2

x = 11

Answer from Gauthmath

What is the solution to the system of equations? 5x-2y=-16 4x-5y=-23

Answers

Answer:

The solution set is {-2, 3}.

Step-by-step explanation:

We can do this by elimination after manipulating the 2 equations so that the coefficients of  y  will disappear after addition:

5x - 2y = -16        Multiply this by -5:

-25x + 10y = 80 ...........(A)

4x - 5y = -23       Multiply this by 2:

8x - 10y = -46..............(B)

Now add A and B:

-17x = 34

x = 34/-17

x = -2.

Now substitute x = -2 into the first original equation:

5(-2) - 2y = -16

-2y = -16 +10 = -6

y = -6/-2

y = 3.

Confirm these results by substitution in the second original equation:

4(-2) - 5(3)

= - 8  - 15 = -23.

Checks OK.

ixl area of sectors. I am struggling on this question

Answers

Answer:

español :/

Step-by-step explanation:

Answer:

256/5 pi

Step-by-step explanation:

= angle/360 × pi×r^2

= 72/360 × pi × 16^2

= 51.2 pi

= 256/5 pi

What is an explicit formula for the geometric sequence -64,16,-4,1,... where the first term should be f(1).

Answers

Answer:

[tex]a_{n} = -64(-\frac{1}{4})^{n-1}[/tex]

it seems like the first term is -64, so lets write the formula accordingly:

a_n = a1(r)^(n-1)

where 'n' is the number of terms

a1 is the first term of the sequence

'r' is the ratio

the ratio is [tex]-\frac{1}{4}[/tex] because -64 * [tex]-\frac{1}{4}[/tex] = 16 and so on...

the explicit formula is :

[tex]a_{n}[/tex] = [tex]-64(-\frac{1}{4} )^{n-1}[/tex]

Hi! I'd appreciate it if you could help me on this question. The question I need help with is question 42. Thank you If you could help me!!

Answers

9514 1404 393

Answer:

  19 hours

Step-by-step explanation:

Add up the numbers:

  3×3.5 +2×2.0 +4.5 = 19

Jacob trains 19 hours per week.

A dinner mint costs 85¢ and a toffee costs 73¢. What is the cost of both sweets rounded to the nearest dollar?​

Answers

Answer:

85 rounded to the nearest dollar would be $1. 73 rounded to the nearest dollar would also be $1

Step-by-step explanation:

A one lane highway runs through a tunnel in the shape of one half a sine curve cycle

Answers

The sine curve equation, y = 10·sin(x·π/24), that models the entrance of the

tunnel with a cross section that is the shape of half of a sine curve and the

height of the tunnel at the edge of the road, (approximately 7.07 ft.) are

found by applying the following steps

(a) The equation for the sine curve is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is approximately 7.07 feet

The reason for the above answers are presented as follows;

(a) From a similar question posted online, the missing part of the question

is, what is the height of the tunnel at the edge of the road

The known parameters;

The shape of the tunnel = One-half sine curve cycle

The height of the road at its highest point = 10 ft.

The opening of the tunnel at road level = 24 ft.

The unknown parameter;

The equation of the sine curve that fits the opening

Method;

Model the sine curve equation of the tunnel using the general equation of a sine curve;

The general equation of a sine curve is y = A·sin(B·(x - C) + D

Where;

y = The height at point x

A = The amplitude = The distance from the centerline of the sine wave to the top of a crest

Therefore;

The amplitude, A = The height of half the sine wave = The height of the tunnel = 10 ft.

D = 0, C = 0 (The origin, (0, 0) is on the left end, which is the central line)

The period is the distance between successive points where the curve passes through the center line while rising to a crest

Therefore

The period, T = 2·π/B = 2 × Opening at the road level = 2 × 24 ft. = 48 ft.

T = 48 ft.

We get;

48 = 2·π/B

B = 2·π/48 = π/24

By plugging in the values for A, B, C, and D, we get;

y = 10·sin((π/24)·(x - 0) + 0 = 10·sin(x·π/24)

The equation of the sine curve that fits the opening is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is given by substituting

the value of x at the edge of the road into the equation for the sine curve

as  follows;

The width of the shoulders = 6 feet

∴ At the edge of the road, x = 0 + 6ft = 6 ft., and 6 ft. + 12 ft. = 18 ft.

Therefore, we get;

y = 10 × sin(6·π/24) = 10 × sin(π/4) = 5×√2

y = 10 × sin(18·π/24) = 10 × sin(3·π/4) = 5×√2

The height of the, y, tunnel at the edge of the road where, x = 6, and 18 is y = 5·√2 feet ≈ 7.07 ft.

Learn more about the sine curve here;

https://brainly.com/question/3827606

Factor the following expressions completely. Show and check all work on your own paper.
x^2+169

Answers

Is not factorable over real numbers, but if you want to use imaginary numbers then it would be (x+13i) (x-13i)

Answer with rational numbers: Not Factorable


Answer with imaginary numbers: (x-13i)(x+13i)

The number of dollars in x quarters

Answers

Answer:

There are four quarters in one dollar, so 4x quarters in x dollars
A dollar makes 4 quarters so 4x

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic equation with its solution set.​

Answers

Answer:

2x^2 - 9x -1 = 0

Solution: x = 9 ±√89/4

2x^2 -9x +6 = 0

Solution: 9 ± √33/4

Step-by-step explanation:

Given the equation;2x^2 - 9x -1 = 0

From the quadratic formula;

-b ±√ b^2 -4ac/2a

We have;

x= -(-9) ± √(-9)^2 - -4(2)(-1)/2(2)

x = 9 ±√89/4

Also;

Given the equation: 2x^2 -9x +6 = 0

From the quadratic formula: -b ±√ b^2 -4ac/2a

We have;

x= -(-9) ± √(-9)^2 - 4(2)(6)/2(2)

x= 9 ± √33/4

1.) 2x^2-9x+6 2.)  2x^2-8x+5 3.) 2x^2-9x-1   4.) 2x^2-8x-3

Step-by-step explanation:

Find the length of X

Answers

Answer:

[tex] x = 8\sqrt{2} [/tex]

Step-by-step explanation:

Leg = x

Hypotenuse = 16

[tex] x\sqrt{2} = 16 [/tex]

[tex] x = \dfrac{16}{\sqrt{2}} [/tex]

[tex] x = \dfrac{16}{\sqrt{2}} \times \dfrac{\sqrt{2}}{\sqrt{2}} [/tex]

[tex] x = \dfrac{16\sqrt{2}}{2} [/tex]

[tex] x = 8\sqrt{2} [/tex]

During a 1966 Tabiona High School track meet, Levere ran the 100 yard dash in
10.63 seconds. Ross took second with a time of 10.98 seconds.
a. Levere’s time was _______% shorter than Ross’.
b. Ross’ time was _______% longer than Levere’s.
c. Levere’s time was _______% of Ross’.

Answers

Answer:

a) 3.19

b) 3.29

c) 96.81

Step-by-step explanation:

Question a:

Levere's: 10.63s

Ross: 10.98s

10.98 - 10.63 = 0.35s shorter than 10.98s, so:

0.35*100%/10.98 = 3.19% shorter.

Question b:

35s longer than 10.63s, so:

0.35*100%/10.63 = 3.29% longer.

Question c:

3.19% shorter, so 100 - 3.19 = 96.81% of Ross.

Suppose a deck of cards contains 13 cards:
5 green cards numbered 1-5, 4 red cards numbered 1-4, and 4 blue cards numbered 1-4.
For 3.1-3.3, 5 draws are made without replacement. X is the number of green cards drawn and Y is the number of red cards drawn. Z is the sum of the numbers on the tickets.
G1 = first card is green
G2 = second card is green
Enter the probability as a fraction.
P(at least one green) = ______.

Answers

Answer:

[tex]P(G_1) = \frac{5}{13}[/tex]

[tex]P(G_2) = \frac{1}{3}[/tex]

[tex]P(X \ge 1) = \frac{25}{39}[/tex]

Step-by-step explanation:

Given

[tex]G = 5[/tex]

[tex]R = 4[/tex]

[tex]B = 4[/tex]

[tex]n = 13[/tex]

Solving (a): [tex]P(G_1)[/tex]

This is calculated as:

[tex]P(G_1) = \frac{G}{n}[/tex]

[tex]P(G_1) = \frac{5}{13}[/tex]

Solving (b): [tex]P(G_2)[/tex]

This is calculated as:

[tex]P(G_2) = \frac{G - 1}{n - 1}[/tex] -- this is so because the selection is without replacement

[tex]P(G_2) = \frac{5 - 1}{13 - 1}[/tex]

[tex]P(G_2) = \frac{4}{12}[/tex]

[tex]P(G_2) = \frac{1}{3}[/tex]

Solving (c): [tex]P(X \ge 1)[/tex]

Using the complement rule, we have:

[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

To calculate [tex]P(X = 0)[/tex], we have:

[tex]G = 5[/tex] --- Green

[tex]G' = 8[/tex] ---- Not green

The probability that both selections are not green is:

[tex]P(X = 0) = P(G'_1) * P(G'_2)[/tex]

So, we have:

[tex]P(X = 0) = \frac{G'}{n} * \frac{G'-1}{n-1}[/tex]

[tex]P(X = 0) = \frac{8}{13} * \frac{8-1}{13-1}[/tex]

[tex]P(X = 0) = \frac{8}{13} * \frac{7}{12}[/tex]

Simplify

[tex]P(X = 0) = \frac{2}{13} * \frac{7}{3}[/tex]

[tex]P(X = 0) = \frac{14}{39}[/tex]

Recall that:

[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

[tex]P(X \ge 1) = 1 - \frac{14}{39}[/tex]

Take LCM

[tex]P(X \ge 1) = \frac{39 -14}{39}[/tex]

[tex]P(X \ge 1) = \frac{25}{39}[/tex]

Help me plz help me plz

Answers

Answer: 4 13/30 cups

Step-by-step explanation:

Since Lila used 1 2/5 times as much lemonade as Naomi did (3 1/6 cups), we have to multiply 1 2/5 by 3 1/6:

1 2/5 ⋅ 3 1/6 = ?

19/6 ⋅ 7/5 = 133/30

133/30 = 4 13/30

4 13/30 cups

Hi someone already answered thx

g Two different factories named A and B both produce an automobile part. If a part came from A, the probability that the part is defective is .04. If the part came from B, the probability that it is defective is .05. In a sample of 180 parts, 100 came from A and 80 came from B. (a) What is the probability that a part chosen at random (from the sample) was defective

Answers

Answer:

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Step-by-step explanation:

Probability of a defective part:

0.04 of [tex]\frac{100}{180}[/tex], that is, coming from A.

0.05 of [tex]\frac{80}{180}[/tex], that is, coming from B. So

[tex]p = 0.04\frac{100}{180} + 0.05\frac{80}{180} = \frac{0.04*100 + 0.05*80}{180} = 0.0444[/tex]

0.0444 = 4.44% probability that a part chosen at random (from the sample) was defective.

Other Questions
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