4) The path of a satellite orbiting the earth causes it to pass directly over two
tracking stations A and B, which are 60 km apart. When the satellite is on one side of
the two stations, the angles of elevation at A and B are measured to be 86.4 ° and
85 °, respectively.
Find how far the satellite is from station A and how high the satellite is above the
ground. Round your answers to 2 decimal places.

Answers

Answer 1

Answers:

Satellite is approximately 2446.43 km from station A.Satellite is approximately 2441.61 km above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

AB = 60 kmAD = xCD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

4) The Path Of A Satellite Orbiting The Earth Causes It To Pass Directly Over Twotracking Stations A

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Answers

Answer:

D 2.10+0.80m=11.70, 12 miles

Step-by-step explanation:

11.70-2.10=9.6

9.6/0.80=12

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

D and can you please check my last two recent question

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Answers

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

Answer:

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Answers

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Answers

Answer:

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48-7)x(56+19

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Answers

A, B, and C. Fuisfisjudjsja extra letters

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Answers

Answer:

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Answers

The answer to this question is 26/45

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[tex]0.57 = 0.57[/tex]

D)

[tex]\dfrac{52}{99} = 0.52[/tex]

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Step-by-step explanation:

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Answers

Answer: See explanation

Step-by-step explanation:

I think your question isn't well written and that 234 was meant to be 2.34 and 112 was meant to be 1.12

Let the amount spent on tomatoes be x.

The information given in the question can then be used to form an equation as thus:

Apples + Peaches + Tomatoes = $9.63

(2.34 × $1.32) + (1.12 × $1.20) + x = $9.63

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x = $9.63 - ($3.0888 + $1.344)

x = $9.63 - $4.4328

x = $5.1972

The amount spent on tomatoes will be $5.1972

Answer:

The answer is 4.2 I did this question already

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