(x^2+1)(x-1)=0 help me pls

Answer:

x = 5.9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 26 = x /12

12 tan 26 =x

x=5.85279

Rounding to the nearest tenth

x = 5.9

1. the question is asking you to multiply the two function expressions together

2. so all we do is (3x - 1)(x² + 4) which gives you 3x³ + 12x - x² - 4

Answer:

0, 8, 5i, -51

Step-by-step explanation:

Just calculate algebraically. Let me know if you need a more elaborate explanation.

Answer:

Create a function representing number of published articles per month:

[tex]a=12m+60[/tex]

Where:

Now substitute in the values of m to get the a-value:

Answer:

The p-value of the test is 0.166 > 0.05, which means that there is not sufficient evidence at the 0.05 significance level to conclude that the bags contain more than 23.6 ounces.

Step-by-step explanation:

A company distributes candies in bags labeled 23.6 ounces. Test if the mean is more than this:

At the null hypothesis, we test if the mean is of 23.6, that is:

[tex]H_0: \mu = 23.6[/tex]

At the alternative hypothesis, we test if the mean is of more than 23.6, that is:

[tex]H_1: \mu > 23.6[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

23.6 is tested at the null hypothesis:

This means that [tex]\mu = 23.6[/tex]

The local bureau of weights and Measures randomly selects 60 bags of candies and obtain a sample mean of 24 ounces. Assuming that the standard deviation is 3.2.

This means that [tex]n = 60, X = 24, \sigma = 3.2[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{24 - 23.6}{\frac{3.2}{\sqrt{60}}}[/tex]

[tex]z = 0.97[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 24, which is 1 subtracted by the p-value of z = 0.97.

Looking at the z-table, z = 0.97 has a p-value of 0.834.

1 - 0.834 = 0.166

The p-value of the test is 0.166 > 0.05, which means that there is not sufficient evidence at the 0.05 significance level to conclude that the bags contain more than 23.6 ounces.

Hi there!  

»»————-　★　————-««

I believe your answer is:  

False.

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

⸻⸻⸻⸻

[tex]10.00 - 7.50 = 2.50[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

a.) 19.2cm

b.) 0.15375cm

Step-by-step explanation:

Cylinders are similar, so:

h1 / r1 = h2 / r2

8cm / 5cm = h2 / 12cm

h2 = (8cm × 12cm) / 5cm

h2 = 19.2cm

Same for b

32000cm2 / 246cm = 20cm2 / length

length = ((20 × 246) / 32000) cm

length = 0.15375cm

Answer:

the mode is 4 because it appears the most times in the detail set

Answer:

The mode is 3

Step-by-step explanation:

The mode of a set of numbers is whatever number appears the most. So here, you have four 4's, which is the most common number

Answer:

hey the answer is cylinder= 211.5л!

Answer:

yes the x increases by 6 and the y decreases by 3.

y = -1/2x - 7/2

Step-by-step explanation:

find the slope :

(1,-4), (7, -7)

y2- y1 / x2 - x1

substitute those numbers and you get -1/2.

point slope form :

y - y1 = m(x- x1)

y - (-4) = -1/2 ( x - (1))

y+4 = -1/2(x-1)

slope intercept form :

y = -1/2x - 7/2

does this help ?

Option C

Corresponding angles along parrellel lines are conguerent

Answered by Gauthmath pls mark brainliest and comment thanks and click thanks

Answer:

(-1,-6)

Step-by-step explanation:

(13 + x)/2 = 6

13+x= 12

x = -1

~~~~~~~~~~~~~~~

(-2 + y ) / 2 = -4

-2 + y = -8

y = -6

The coordinates of the other endpoint will be (-1,-6). The correct option is C.

Divide the measurement of the distance between the two end locations by 2. The middle of that line is located at this separation from either end.

A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

Given that the midpoint of a segment is (6,−4) and one endpoint is (13,−2).

The x- coordinate will be calculated as:-

(13 + x)/2 = 6

13+x= 12

x = -1

The y-coordinate will be calculated as:-

(-2 + y ) / 2 = -4

-2 + y = -8

y = -6

Therefore, the coordinates of the other endpoint will be (-1,-6). The correct option is C.

To know more about midpoints of the line follow

https://brainly.com/question/24431553

#SPJ2

Answer:

c 6m hope to help

tjabssb

Answer:

3 m

Step-by-step explanation:

because all sides are equal

Answer:

c

Step-by-step explanation:

Answer:

Shannon

Step-by-step explanation:

Cuando se habla de lo que uno tiene, podemos usar números positivos.

Por ejemplo:

Pedro tiene 10 manzanas.

Para el caso de deudas, utilizamos números negativos, por ejemplo:

Pedro tiene -10 manzanas

Lo cual significa que Pedro debe 10 manzanas a alguien.

Entonces si le diéramos a Pedro 12 manzanas, el ahora tendría:

-10 + 12 = 2

Pedro tiene 2 manzanas, porque tuvo que entregar 10 de las 12 que le dimos para pagar su deuda.

Ahora vamos a resolver el problema:

La cuenta de Sally tiene un saldo de:

S = -$200.90

El signo negativo quiere decir que Sally tiene una deuda de $200.90

La cuenta de su amiga Shannon tiene un saldo de:

S' = -$240.55

De vuelta, el signo negativo quiere decir que Shannon tiene una deuda de $240.55

Con esto ya podemos concluir que la deuda de Shannon es mayor, por lo tanto Shannon es la que tiene más deuda.

Answer:

108 squared centimeters

Step-by-step explanation:

Let's exchange π for 3:

area = πr^2

        = 3r^2

Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:

area = 3r^2

        = 3 · 6^2

Simplify 6^2:

area = 3 · 6^2

        = 3 · 36

Multiply 3 by 36:

area = 3 · 36

area = 108

108 squared centimeters

Answer: D

Step-by-step explanation:

To get rid of denominator in x, multiply everything by 3

3y=2x+21

Move the variables to the left

-2x+3y=21

Answer:

-10k×2+7

= -20k+7

Step-by-step explanation:

is the answer

Answer:

20 books

Step-by-step explanation:

35/1.75

20

Answer:

[tex]10^{-3}[/tex]

Step-by-step explanation:

Answer:

https://tex.z-dn.net/?f=10%5E%7B-3%7D

Step-by-step explanation:

Answer:

8.16 or 6.06

Step-by-step explanation:

final is 3.96

they reduced their time twice by 2.1min

3.96+2.1+2. 1=8.16

Answer:

Step-by-step explanation:

The series is missing from the question. I will answer this question with a general explanation by using the following similar series:

[tex]\sum\limits^6_{n=0} 7^n[/tex]

Required

The series

To do this, we simply replace n with the values

[tex]\sum\limits^6_{n=0}[/tex] means n starts from 0 and ends at 6

[tex]\sum[/tex] means the series is a summation series

So, we have:

[tex]\sum\limits^6_{n=0} 7^n = 7^0 + 7^1 + 7^2 + ...... + 7^6[/tex]

[tex]\sum\limits^6_{n=0} 7^n = 1 + 7 + 7^2 + ...... + 7^6[/tex]

Answer:

2,-2

you just have to look at the "menu" of choices and determine which one of the choices

fits the question... the f(-4) says you have to see which one of the three

choices has -4 in it ...

the middle one does -4≤x≤1 -4 is for sure in the range

this question #1 answer is "2" because the result is always a 2 for that choice...

the next question put in 3 ... three is greater than 1 (that is the third choice)

so the result is -(3) + 1 = -2

your answers are 2, and -2

Step-by-step explanation:

Answer:

The Constant is 9/2

Answer:

See Below (Boxed Solutions).

Step-by-step explanation:

We are given the two complex numbers:

[tex]\displaystyle z = \sqrt{3} - i\text{ and } w = 6\left(\cos \frac{5\pi}{12} + i\sin \frac{5\pi}{12}\right)[/tex]

First, convert z to polar form. Recall that polar form of a complex number is:

[tex]z=r\left(\cos \theta + i\sin\theta\right)[/tex]

We will first find its modulus r, which is given by:

[tex]\displaystyle r = |z| = \sqrt{a^2+b^2}[/tex]

In this case, a = √3 and b = -1. Thus, the modulus is:

[tex]r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2[/tex]

Next, find the argument θ in [0, 2π). Recall that:

[tex]\displaystyle \tan \theta = \frac{b}{a}[/tex]

Therefore:

[tex]\displaystyle \theta = \arctan\frac{(-1)}{\sqrt{3}}[/tex]

Evaluate:

[tex]\displaystyle \theta = -\frac{\pi}{6}[/tex]

Since z must be in QIV, using reference angles, the argument will be:

[tex]\displaystyle \theta = \frac{11\pi}{6}[/tex]

Therefore, z in polar form is:

[tex]\displaystyle z=2\left(\cos \frac{11\pi}{6} + i \sin \frac{11\pi}{6}\right)[/tex]

Part A)

Recall that when multiplying two complex numbers z and w:

[tex]zw=r_1\cdot r_2 \left(\cos (\theta _1 + \theta _2) + i\sin(\theta_1 + \theta_2)\right)[/tex]

Therefore:

[tex]\displaystyle zw = (2)(6)\left(\cos\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right) + i\sin\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right)\right)[/tex]

Simplify. Hence, our polar form is:

[tex]\displaystyle\boxed{zw = 12\left(\cos\frac{9\pi}{4} + i\sin \frac{9\pi}{4}\right)}[/tex]

To find the complex form, evaluate:

[tex]\displaystyle zw = 12\cos \frac{9\pi}{4} + i\left(12\sin \frac{9\pi}{4}\right) =\boxed{ 6\sqrt{2} + 6i\sqrt{2}}[/tex]

Part B)

Recall that when raising a complex number to an exponent n:

[tex]\displaystyle z^n = r^n\left(\cos (n\cdot \theta) + i\sin (n\cdot \theta)\right)[/tex]

Therefore:

[tex]\displaystyle z^{10} = r^{10} \left(\cos (10\theta) + i\sin (10\theta)\right)[/tex]

Substitute:

[tex]\displaystyle z^{10} = (2)^{10} \left(\cos \left(10\left(\frac{11\pi}{6}\right)\right) + i\sin \left(10\left(\frac{11\pi}{6}\right)\right)\right)[/tex]

Simplify:

Simplify using coterminal angles. Thus, the polar form is:

[tex]\displaystyle \boxed{z^{10} = 1024\left(\cos \frac{\pi}{3} + i\sin \frac{\pi}{3}\right)}[/tex]

And the complex form is:

[tex]\displaystyle z^{10} = 1024\cos \frac{\pi}{3} + i\left(1024\sin \frac{\pi}{3}\right) = \boxed{512+512i\sqrt{3}}[/tex]

Part C)

Recall that:

[tex]\displaystyle \frac{z}{w} = \frac{r_1}{r_2} \left(\cos (\theta_1-\theta_2)+i\sin(\theta_1-\theta_2)\right)[/tex]

Therefore:

[tex]\displaystyle \frac{z}{w} = \frac{(2)}{(6)}\left(\cos \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right) + i \sin \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right)\right)[/tex]

Simplify. Hence, our polar form is:

[tex]\displaystyle\boxed{ \frac{z}{w} = \frac{1}{3} \left(\cos \frac{17\pi}{12} + i \sin \frac{17\pi}{12}\right)}[/tex]

And the complex form is:

[tex]\displaystyle \begin{aligned} \frac{z}{w} &= \frac{1}{3} \cos\frac{5\pi}{12} + i \left(\frac{1}{3} \sin \frac{5\pi}{12}\right)\right)\\ \\ &=\frac{1}{3}\left(\frac{\sqrt{2}-\sqrt{6}}{4}\right) + i\left(\frac{1}{3}\left(- \frac{\sqrt{6} + \sqrt{2}}{4}\right)\right) \\ \\ &= \boxed{\frac{\sqrt{2} - \sqrt{6}}{12} -\frac{\sqrt{6}+\sqrt{2}}{12}i}\end{aligned}[/tex]

Part D)

Let a be a cube root of z. Then by definition:

[tex]\displaystyle a^3 = z = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]

From the property in Part B, we know that:

[tex]\displaystyle a^3 = r^3\left(\cos (3\theta) + i\sin(3\theta)\right)[/tex]

Therefore:

[tex]\displaystyle r^3\left(\cos (3\theta) + i\sin (3\theta)\right) = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]

If two complex numbers are equal, their modulus and arguments must be equivalent. Thus:

[tex]\displaystyle r^3 = 2\text{ and } 3\theta = \frac{11\pi}{6}[/tex]

The first equation can be easily solved:

[tex]r=\sqrt[3]{2}[/tex]

For the second equation, 3θ must equal 11π/6 and any other rotation. In other words:

[tex]\displaystyle 3\theta = \frac{11\pi}{6} + 2\pi n\text{ where } n\in \mathbb{Z}[/tex]

Solve for the argument:

[tex]\displaystyle \theta = \frac{11\pi}{18} + \frac{2n\pi}{3} \text{ where } n \in \mathbb{Z}[/tex]

There are three distinct solutions within [0, 2π):

[tex]\displaystyle \theta = \frac{11\pi}{18} , \frac{23\pi}{18}\text{ and } \frac{35\pi}{18}[/tex]

Hence, the three roots are:

[tex]\displaystyle a_1 = \sqrt[3]{2} \left(\cos\frac{11\pi}{18}+ \sin \frac{11\pi}{18}\right) \\ \\ \\ a_2 = \sqrt[3]{2} \left(\cos \frac{23\pi}{18} + i\sin\frac{23\pi}{18}\right) \\ \\ \\ a_3 = \sqrt[3]{2} \left(\cos \frac{35\pi}{18} + i\sin \frac{35\pi}{18}\right)[/tex]

Or, approximately:

[tex]\displaystyle\boxed{ a _ 1\approx -0.4309 + 1.1839i,} \\ \\ \boxed{a_2 \approx -0.8099-0.9652i,} \\ \\ \boxed{a_3\approx 1.2408-0.2188i}[/tex]

Answer:

Step-by-step explanation: