From the given question we are asked to find the least common multiple of two given numbers. Here for this question, we will use the prime factorisation method and find the factors for the two given numbers and then we find the least common multiple for the numbers given. So, we proceed with our solution as follows.
Required Answer :-2 | 5, 8
_______
2 | 5, 4
_______
2 | 5, 2
_______
5 | 5, 1
_________
1, 1
2×2×2×5 = 40
Additional information :-We should remember the concept of least common multiple, which means the smallest number that two numbers both can get to or which is the common multiple between two numbers. We should know that we have different method to find the least common multiple like listing the multiples, prime factorization and division
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 3 large boxes and 5 small boxes has a total weight of 88 kilograms. A delivery of 12 large boxes and 2 small boxes has a total weight of 235 kilograms. How much does each type of box weigh?
Answer:
Step-by-step explanation:
We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so
3L + 5s = 88
12L + 2s = 235 according to the other information given.
Solve the first equation for either L or s. I'll solve for L, just because:
3L = 88 - 5s and
L = [tex]\frac{88}{3}-\frac{5}{3}s[/tex] and sub that into the second equation for L:
[tex]12(\frac{88}{3}-\frac{5}{3}s)+2s=235[/tex] and if you distribute the 12 into the parenthesis you'll simplify it down a bit to
352 - 20s + 2s = 235 and combine like terms:
-18s= -117 so
s = 6.5 kg and plug that in to solve for L:
L = [tex]\frac{88}{3}-\frac{5}{3}(6.5)[/tex] and
L = 18.5 kg
16)dry air is trapped in a narrow uniform glass tube by a mercury pellet of length 25cm .when the tube is placed vertical with the open end um long.what is the external pressure if the column of air becomes 40 cm in length when inverted ? . ( required answer = 74cm hg )
Step-by-step explanation:
Ru Tu yulyryosuyyyhlsgjpcbmb kvjvlcykxnlvdlbvhck
chgkbhlxyovk m.
chchhlzixhvkh
Determine whether each relation is a function. Give the domain and range for each relation.
{(3, 4), (3, 5), (4, 4), (4, 5)}
Answer:
Not a function
Domain: {3,4}
Range: {4,5}
Step-by-step explanation:
A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function
For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function
Now let's find the domain and range.
Domain is the set of x values in a relation.
The x values of the given relation are 3 and 4 so the domain is {3,4}
The range is the set of y values in a relation
The y value of the given relation include 4 and 5
So the range would be {4,5}
Notes:
The values of x and y should be written from least to greatest when writing them out as domain and range.
They should be written inside of brackets
Do not repeat numbers when writing the domain and range
Question 10 of 25
If a regular polygon has exterior angles that measure 60° each, how many
sides does the polygon have?
A. 4
th
B. 6
O оо
C. 8
D. 3
SUBMIT
I need help ASAP
Answer:
I think the answer is 3
hope it will help you
Categorize the trigonometric functions as positive or negative.
Answer:
So, remember that:
cos(x) > 0 for -pi/2 < x < pi/2
cos(x) < 0 for pi/2 < x < (3/2)*pi
and
sin(x) > 0 for 0 < x < pi
sin(x) < 0 for -pi < x <0 or pi < x < 2pi
Also, we have the periodicty of the sine and cocine equations, such that:
sin(x) = sin(x + 2pi)
cos(x) = cos(x + 2pi)
Now let's solve the problem:
[tex]sin(\frac{13*\pi}{36} )[/tex]
here we have:
x = (13/36)π
This is larger than zero and smaller than π:
0 < (13/36)π < π
then:
[tex]sin(\frac{13*\pi}{36} )[/tex]
Is positive.
The next one is:
[tex]cos(\frac{7*\pi}{12} )[/tex]
Here we have x = (7/12)*pi
notice that:
7/12 > 1/2
Then:
(7/12)*π > (1/2)*π
Then:
[tex]cos(\frac{7*\pi}{12} )[/tex]
is negative.
next one:
[tex]sin(\frac{47*\pi}{36} )[/tex]
here:
x = (47/36)*π
here we have (47/36) > 1
then:
(47/36)*π > π
then:
[tex]sin(\frac{47*\pi}{36} )[/tex]
is negative.
the next one is:
[tex]cos(\frac{17*\pi}{10} )[/tex]
Here we have x = (17/10)*π
if we subtract 2*π (because of the periodicity) we get:
(17/10)*π - 2*π
(17/10)*π - (20/10)*π
(-3/10)*π
this is in the range where the cosine function is positive, thus:
[tex]cos(\frac{17*\pi}{10} )[/tex]
is positive.
the next one is:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
here we have:
x = (41/36)*π
Notice that both functions, sine and cosine are negatives for that value, then we have the quotient of two negative values, so:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
is positive.
The final one is:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Here:
x = (5/9)*π
The sin function is positive with this x value, while the cosine function is negative, thus:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Is negative.
Please solve the equation 4X-25=71
the quotient of (x^4 - 3x^2 + 4x - 3) and a polynomial is (x^2 + x - 3) what is the polynormial
Answer:
Hello,
polynomial is x²-x+1
Step-by-step explanation:
if a=b*c+r then a=c*b+r
Using a long division, see the picture.
I Will Mark Brainliest
The figure shows a rectangue with its length and breadth as indicated,
Give that the perimeter of a rectangle is 120cm, find the area of rectangle .
Answer:
Length = 2x+y cm and since it's a rectangle,
2x+y=3x-y ---------------- (i)
width = 2x-3 cm
It's perimeter,
2(2x+y+2x-3)=120 ---------------- (ii)
Solving both equations,
x = 14 cm
y = 7 cm
so length is, 2×14+7 = 35 cm
and width is, 2×14-3 = 25 cm
so area will be, 35×25 = 875 cm²
Answered by GAUTHMATH
Answer:
len = 35
width = 25
Step-by-step explanation:
3x-y = 2x+y
1) x-2y = 0
9x -6= 120
x = 14
y = 7
A basic cellular package costs $30/month for 60 minutes of calling with an additional charge of $0.40/minute beyond that time. The cost function C (2) for using x minutes would be • If you used 60 minutes or less, i.e. if if x < 60, then C (x) = 30 (the base charge). If you used more than 60 minutes, i.e. (x – 60 minutes more than the plan came with, you would pay an additional $0.40 for each of those (x – 60 minutes. Your total bill would be C (x) = 30 + 0.40 (x – 60). If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use? minutes. The maximum calling minutes you can use is ? Number
Answer:
The maximum number of minutes to keep the cost at $50 or less is 110 minutes
Step-by-step explanation:
Given
[tex]C(x) = 30[/tex] ---- [tex]x < 60[/tex]
[tex]C(x) = 30 + 0.40(x - 60)[/tex] --- [tex]x \ge 60[/tex]
Required
[tex]C(x) = 50[/tex] ---- find x
We have:
[tex]C(x) = 30 + 0.40(x - 60)[/tex]
Substitute 50 for C(x)
[tex]50 = 30 + 0.40(x - 60)[/tex]
Subtract 30 from both sides
[tex]20 = 0.40(x - 60)[/tex]
Divide both sides by 0.40
[tex]50 = x - 60[/tex]
Add 60 to both sides
[tex]110 = x[/tex]
[tex]x =110[/tex]
interest on 600 2 years at rate of paise per rupee per month
write your answer in simplest radical form
Answer:
a = 3√6 in
Step-by-step explanation:
From the question given above, the following data were obtained:
Angle θ = 60°
Adjacent = 3√2 in
Opposite = a =?
The value of 'a' can be obtained by using the tan ratio as illustrated below:
Tan θ = Opposite / Adjacent
Tan 60 = a / 3√2
√3 = a / 3√2
Cross multiply
a = √3 × 3√2
Recall:
c√d × n√m = (c×n) √(d×m)
Thus,
√3 × 3√2 = (1×3)√(3×2)
√3 × 3√2 = 3√6
a = 3√6 in
If f(x) = x2 + 7x and g(x) = 3x - 1, what is f(g(x))?
Answer:
f(g(x)) = 9x^2 + 15x - 6
Step-by-step explanation:
We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.
Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side. We obtain:
f(g(x)) = (3x - 1)^2 + 7(3x - 1).
If we multiply this out, we get:
f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or
f(g(x)) = 9x^2 + 15x - 6
Find the missing length in the image below
Answer:
1 length ityoughkdds hshlkb
Let it be x
[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{3}{6}[/tex]
Use cross multiplication[tex]\\ \sf\longmapsto 6x=10(3)[/tex]
[tex]\\ \sf\longmapsto 6x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{6}[/tex]
[tex]\\ \sf\longmapsto x=5[/tex]
There is a pile of 55 coins consisting of nickels and dimes worth $3.90. Find the number of each if you say that the nickels are x.
Answer:
There are 32 nickels and 23 dimes.
Step-by-step explanation:
Lets say x is nickels and y is dimes
The first equation would be 55 = x + y
The second equation would be .05x + .10y = 3.90
The Solving Part:
Move y to the other side: x = 55 - y
Substitute x in the second equation: .05(55-y) + .10y = 3.90
Distribute, rearrange, and combine like terms: .05y = 1.15
Solve for y: Y = 23
Plug in 23 for y and solve: 55 - y = x ; 55 - 23 = x ; 55 - 23 = 32
x = 32
y = 23
32 nickels and 23 dimes
Answer:
There are 32 nickels and 23 dimes.
Step-by-step explanation:
Yay :) we solved the problem together :)))))
Can someone help me solve this problem ?
Answer:
B
Step-by-step explanation:
Since x= 3/4
To take the fraction on left hand side, inverse 4/3
Take π as denominator
Then cube root the entire equation on the left hand side.
Answer:
Step-by-step explanation:
How do you Find the acute Angle A when sinA=0.616?
Answer:
arcsin0.616
Step-by-step explanation:
arcsino.616
Find f′ in terms of g′
f(x)=x2g(x)
Select one:
f′(x)=2xf′(x)+2xg′(x)
f′(x)=2xg′(x)
f′(x)=2x+g′(x)
f′(x)=x2g(x)+2x2g′(x)
f′(x)=2xg(x)+x2g′(x)
9514 1404 393
Answer:
(e) f′(x)=2xg(x)+x²g′(x)
Step-by-step explanation:
The product rule applies.
(uv)' = u'v +uv'
__
Here, we have u=x² and v=g(x). Then u'=2x and v'=g'(x).
f(x) = x²·g(x)
f'(x) = 2x·g(x) +x²·g'(x)
PLZ ANSWER ASAP
(look at images below, from khan)
Answer:
D Replace on equation with sum /difference of both equations
The systems are still the same
Step-by-step explanation:
5x + y = 3
4x - 7y = 8
Subtract the second equation from the first
5x + y = 3
-(4x - 7y = 8)
-----------------
x +8y = -5
The second equation in system B is the first equation in system a minus the second equation in system A
We added the same thing to each side of the equation so the the system is still the same
PLEASE HELP, IGNORE ALL ANWSERS FILLED IN CURRENTLY I WILL GOVE BRAINLIST
Answer:
32.64°
Step-by-step explanation:
From triangle Given :
The sides of the missing angle given are the Adjacent and hypotenus.
Since the triangle is right angled, we can apply trigonometry :
cosθ = adjacent / hypotenus
Cosθ = 16 / 19
θ = Cos^-1(16/19)
θ = 32.6368
θ = 32.64°
Please help and no links.While shopping, you find a shirt that you want. The shirt originally costs p dollars but it is on
sale for 20% off. Which of the following expressions could you use to find the price of the shirt
after the discount where p is the original price of the shirt? Select all that apply.
a) 0.2p
b) 0.8p
c) P-0.27
d) p-0.8p
expresión algebraica el cuadrado del cubo de la suma de dos números
Answer:
El cuadrado de la suma de dos números es igual a (a + b) ² = a² + 2ab + b²Un producto notable: es una expresión matemática que conocemos ya el resultado, a pesar de la operación ser sencilla tenemos
In the figure, m is parallel to n and m <4 = 125 degrees. Find the measures of the other angles.
Answer:
m<1 = 55°
m<2 = 125°
m<3 = 55°
m<5 = 55°
m<6 = 125°
m<7 = 55°
m<8 = 125°
Step-by-step explanation:
m<4 = 125° (given)
✔️m<8 = m<4 (alternate exterior angles are congruent)
m<8 = 125° (substitution)
✔️m<1 = 180° - m<8 (supplementary angles/linear pair)
m<1 = 180° - 125° (substitution)
m<1 = 55°
✔️m<2 = m<8 (vertical angles are congruent)
m<2 = 125° (substitution)
✔️m<7 = m<1 (vertical angles are congruent)
m<7 = 55° (Substitution)
✔️m<3 = m<7 (alternate interior angles are congruent)
m<3 = 55° (substitution)
✔️m<5 = m<3 (vertical angles are congruent)
m<5 = 55°
✔️m<6 = m<4 (vertical angles)
m<6 = 125°
2.5 cm in the ratio of 1:500000
Answer:
1250000cm
Step-by-step explanation:
1:500000
1x2.5 : 500000x2.5
2.5:1250000
Mr. Thomas invested an amount of ₱13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₱3508, what was the amount invested in Scheme B?
9514 1404 393
Answer:
₱6400
Step-by-step explanation:
Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...
14%(13900-b)(2) +11%(b)(2) = 3508
1946 -0.03b = 1754 . . . . . . divide by 2, simplify
-0.03b = -192 . . . . . . . . . subtract 1946
b = 6400 . . . . . . . . . . . divide by -0.03
The amount invested in scheme B was ₱6400.
Please help out explanation need it
Answer:
shifting to the right is just an east/west movement
not a north/south
an east west movement is on the "X" ais, a north/south is on the "Y"
axis...
so just ADD 10 units to all the "X" values
a" = (9,-3)
b"= (6,-1)
c"= (4,-4)
Step-by-step explanation:
If a parachutist lands at a random point on a line between markers A and B, find the probability that she is closer to A than to B. Find the probability that her distance to A is more than seven times her distance to B.
Answer and Step-by-step explanation:
The random point on the line is between A and B, and to find the probability of the A, let's find the probability that is distance A and more than times the distance B. Let's have the probability that A and distance to A are more than the distance to B. The distance C is the interval of A to B. If she is closer and landed in the interval, the equation can be (A, A+B/2). This is the interval length, and the probability is 0.5. If the distance to A is more than the distance B, then the interval is as follows in the given equation (A + 3B/2, B ). The probability of the given interval is 0.25.
Help me with this math problem !!!
Answer:
multiply the numerator together and denominator together
a cookie recipe calls 3 1/4 cups of flour. the recipe makes 3 dozen cookies. how much flour us needed to make 144 cookies
1 dozen = 12
144 / 12 = 12 dozen
12 dozen/ 3 = 4
They need 4 times the amount of flour:
3 1/4 x 4 = 13
They need 13 cups of flour
A normal distribution has a mean of 15 and a standard deviation of 2. Find the value that corresponds to the 75th
percentile. Round your answer to two decimal places.
N
0.00
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.09
0.5
0.6915
0.6950
0.6985
0.7019
0.7054
0.7088
0.7123
0.7157
0.7190
0.7224
0.6 0.7257
0.7291
0.7324
0.7357
0.7389 0.7422
0.7454
0.7486
0.7517
0.7549
0.7 0.7580
0.7611
0.76420.7673
0.7704
0.7734
0.7764
0.7794
0.7823
0.7852
0.8
0.7881
0.7910
0.7939
0.7967
0.7995
0.8023
0.8051
0.8078
0.8106
0.8133
w^2+2w-42=0
what is the width and the length
Answer:
answers in the explanation cz I'm too lazy to type :(
not entirely sure tho
Step-by-step explanation:
w²+2w-42=0
*quadratic formula*
w= -1+ square root 43 m
or w= -1- square root 43 m
then since the length is 2m more than w
add 2 to both answers
l= 1+ square root 43 m
l=1- square root 43 m
9514 1404 393
Answer:
width: 5.557 mlength: 7.557 mStep-by-step explanation:
Given:
a rectangular patio of width w meters, length w+2 meters, and area 42 m²
Find:
width and length
Solution:
The area is ...
A = LW
42 = w(w +2)
43 = w² +2w +1 . . . . . . add 1 to complete the square
√43 = w+1
w = √43 -1 ≈ 5.557 . . . meters
l = w+2 = √43 +1 ≈ 7.557 . . . meters
The width and length of the patio are 5.557 m and 7.557 m, respectively.
