Answer:
1/3^4
1/81
Step-by-step explanation:
(3^2)^-2
We know that a^b^c = a^(b*c)
3 ^(2*-2)
3^-4
We know that a^-b = 1/a^b
1/3^4
1/81
find the missing side lengths
Answer:
b = 2√3
a = 4
Step-by-step explanation:
Here taking 60 as reference angle
so
tan60 = p/b
[tex]\sqrt{3}[/tex] = p/2
so p = 2√3
so
b = 2√3
so
[tex]h^2 = p^2 + b^2\\h^2 = (2\sqrt{3})^2 + 2^2\\h^2 = 12 + 4\\h^2 = 16\\h = \sqrt{16} \\h = 4[/tex]
a = 4
Find the gcf for…………….
write an equation of the function in the form y=a(b)^x -c that has a y intercept of -6, asymptote of y= -2 and goes through (2,-18)
Step-by-step explanation:
Asymptote: y = 2 y-intercept: (0,8)
Step-by-step explanation:
The given function is
f(x) = 6(0.5)^{x} + 2f(x)=6(0.5)
x
+2
This function is of the form:
f(x) = a {b}^{x} + cf(x)=ab
x
+c
where y=c is the horizontal asymptote.
By comparing , we have c=2 hence the horizontal asymptote is
y = 2y=2
To find the y-intercept, we put x=0 into the function to get:
f(0) = 6(0.5)^{0} + 2 = 6 + 2 = 8f(0)=6(0.5)
0
+2=6+2=8
Therefore the y-intercept is (0,8).
John needs to rewrite the expression (4x3y5z)2. Identify which of the following is the simplified form of the expression.
A
4x5y7z3
B
4x6y10z
C
8x5y7z3
D
16x6y10z2
D [tex]\bold{16x^{6}y^{10}z²}[/tex]
Answer:
John needs to rewrite the expression [tex](4x^{3}y^{5}z)²[/tex]. Identify which of the following is the simplified form of the expression.
[tex](4x^{3}y^{5}z)²[/tex]
remenber that square is for all
and power is multiplied
[tex]4²x^{3*2}y^{5*2}*z²[/tex]
[tex]16x^{6}y^{10}z²[/tex]
Step-by-step explanation:
[tex]\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd\displaystyle\ \Large \boldsymbol{Rule: (a^n)^m=a^{n\cdot m }} \\\\\\ (4x^3\cdot y^5\cdot z)^2=4^2\cdot x^{3\cdot 2}\cdot y^{5\cdot 2}\cdot z^2=16 \ x^6 \cdot y^{10} \cdot z^2 \\\\\\ Answer : \boxed{ D)16 \ x^6 \cdot y^{10} \cdot z^2 }[/tex]
Solve the inequality 8 + n > 4.
Answer:
n>-4
Step-by-step explanation:
8+n>4
n>4-8
n>-4
Answer:
-4
Step-by-step explanation
Subtract 8 from 4 to get -4.
N = -4
God Bless.
NEED QUICK!!!
Describe the differences between a WiFi connection and a Cable connection when sending data on the internet. Respond in full sentences.
Answer:
they both connect to a tower of some sort but cable applies to channels of network and wifi applies the a wide web network.
Answer:
A WiFi connection transmits data via wireless signals, while an Ethernet connection transmits data over cable. ... An Ethernet connection is generally faster than a WiFi connection and provides greater reliability and security.
Mike and Ken shared some stamps. \frac{1}{5} 5 1 of Ken's stamps were \frac{1}{3} 3 1 of Mike's stamps. If Mike gave Ken 24 stamps, Ken would have thrice as many stamps as Mike. Find the number of stamps each of them had in the beginning.
Answer:
Mike had 72 stamps
Ken had 120 stamps
Step-by-step explanation:
Given
[tex]M \to Mike[/tex]
[tex]K \to Ken[/tex]
[tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]
[tex]K + 24 = 3 * ( M - 24)[/tex]
Required
Find K and M
Make K the subject in: [tex]K + 24 = 3 * ( M - 24)[/tex]
[tex]K = 3 * ( M - 24) - 24[/tex]
Substitute [tex]K = 3 * ( M - 24) - 24[/tex] in [tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]
[tex]\frac{1}{5} * [3 * ( M - 24) - 24] = \frac{1}{3} * M[/tex]
Open brackets
[tex]\frac{1}{5} * [3M - 72 - 24] = \frac{1}{3} * M[/tex]
[tex]\frac{1}{5} * [3M -96] = \frac{1}{3} * M[/tex]
Multiply both sides by 15
[tex]3* [3M -96] = 5 * M[/tex]
[tex]9M -288 = 5M[/tex]
Collect like terms
[tex]9M -5M= 288[/tex]
[tex]4M= 288[/tex]
Divide both sides by 4
[tex]M= 72[/tex]
Substitute [tex]M= 72[/tex] in [tex]K = 3 * ( M - 24) - 24[/tex]
[tex]K = 3 * (72 - 24) - 24[/tex]
[tex]K = 3 * 48 - 24[/tex]
[tex]K = 120[/tex]
The diameter of the circle above is 18 cm. What is the circumference of the circle? (Use = 3.14.)
Answer:
56.57
Step-by-step explanation:
See attached photo for steps
EDIT: I forgot to add 3.14, I am so sorry
Answer:
56.52
Step-by-step explanation:
Last month, Nate spent 12 % of his paycheck on
car repairs and 25 % of the remainder on food.
He gave $ 1,320 of the remaining money to his
parents and then bought a computer on sale. If
the usual price of the computer was $ 825 and
the discount was 20 %, how much money did
Nate have in the beginning?
Nate had $3000 at the beginning.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
Let the original amount of money is P
Nate spent 12 % of his paycheck on car repairs
⇒ 12% of P = 12P/100
And he spent 25 % of the remainder on food.
⇒ 0.25(88/100)P
He gave $ 1,320 of the remaining money to his parents
⇒ 1320
If the usual price of the computer was $ 825 and the discount was 20 %
⇒ 825 - 0.20(825) = 660
P = 12P/100 + 0.25(88/100)P + 1320 + 660
P - 34P/100 = 1980
100P - 66P = 198000
P = 3000
Hence, Nate had $3000 at the beginning.
Learn more about the percentages here:
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#SPJ2
On Sunday Paul earns 20 cents for every newspaper he delivers if Paul receives $6.40 then how many newspapers did he deliver on Sunday
Answer:
32 newspapers
Step-by-step explanation:
6.4 / 0.2 = 32
Answer:
32 papers
Step-by-step explanation:
Take the total amount and divide by .20
6.40 / .20
Multiply the top and bottom by 10
64/2
32
HURRYYYYYYYYYYYYYY PLZZZZ
Answer:
G
Step-by-step explanation:
you know its G just by the way it is
Which angles are adjacent to each other?
Angle CHG and Angle HDL
Angle AEB and Angle DEA
Angle CHG and Angle HCE
Angle JCH and Angle CHG
Please make sure it's correct because one person once tried it and got it wrong..lol.
Answer:
B
Step-by-step explanation:
Adjacent angles must have the same vertex, so if the middle letter of the three letters used to name each of the angles in a pair are not the same, the angles cannot be adjacent.
That eliminates choices A, C, and D.
Answer: B
Look in the picture first below. Each pair of angles with the same vertex marked in blue is a pair of adjacent angles. For two angles to be adjacent angles, they must be next to each other, have the same vertex, and one cannot be inside the other.
Now look in the second picture below. Each pair of angles marked in red is not a pair of adjacent angles. Some of them are not next to each other. Others have one angle inside the other.
WILL MARK BRAINLIEST IF CORRECT!!!!!!!!!!!!!!!!!!!!
How many times will the digit '3' appear if we write all whole numbers from 1 to 9999?
100 point!!!!!!!!!!!!!!!!!
(Will report if answer is not mathematical)
Answer:
4000 timesStep-by-step explanation:
The numbers from 1 to 9999 can be shown in the form of:
3xyz, x3yz, xy3z. xyz3Each of x, y, z represent the digits from 0 to 9, so 10 ways each.
For each of the forms we have:
10*10*10 = 1000 ways andTotal of:
1000*4 = 4000 waysBy the way this is applicable to any digit.
Max number of digits=4
Their can be 4ways to represent
Each form can repeat 3
(9999+1)/101000Total repeating
1000(4)4000times58×62 without actual multiplication
Answer:
3596
Step-by-step explanation:
Use long multiplication to evaluate.
Answer:
3596
Step-by-step explanation:
(58*10) = 580
580*6 = 3480
58 * 2 = 116
3480 + 116 = 3596
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.
Answer:
380
Step-by-step explanation:
This is a bit nasty. It depends on how you read the 20 miles more and what you do with it. The best and most careful way to do it is do it a long way setting up the two equations carefully.
Second day
Let the time travelled = t
Let the speed travelled = 60 mph
d2 = 60*t
First Day
40*(t + 2) = d1
but d1 = d2 + 20 because he travelled 20 miles further on d1
40 * (t + 2) = d2 + 20
d2 however = 60*t
40*(t+2 ) = 60*t + 20 Remove the brackets
40t + 80 = 60t + 20 Subtract 20 from both sides
40t + 60 = 60t Subtract 40t from both sides
60 = 20*t Divide by 20
t = 60/20
t = 3 hours.
Day 2 = 60 + t = 180
Day 1 = 40*5 = 200
Total distance = 380
Where did that 20 miles go? It was just an observation about the difference in distance travelled between the 2 days.
The total distance the driver traveled in the two days is 260 miles
From the question, on the first day, the driver was going as a speed of 40 mph.
Let s be speed
∴ [tex]s_{1}= 40mph[/tex]
On the second day, he increased the speed to 60 mph
∴ [tex]s_{2}= 60mph[/tex]
From the statement- If he drove 2 more hours on the first day
Let time be t
Then
[tex]t_{1}= t_{2} + 2[/tex] hrs
and traveled 20 more miles
Let d be distance
Then,
[tex]d_{1}= d_{2} + 20[/tex] miles
From the formula
Distance = Speed × Time
Then,
[tex]d = s \times t[/tex]
∴ [tex]d_{1} = s_{1} \times t_{1}[/tex]
From above,
[tex]d_{1}= d_{2}+20[/tex] miles
[tex]s_{1}= 40mph[/tex]
[tex]t_{1}= t_{2} + 2[/tex] hrs
Putting these into
[tex]d_{1} = s_{1} \times t_{1}[/tex]
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex] ...... (1)
But,
[tex]Time = \frac{Distance}{Speed}[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{s_{2} }[/tex]
From above, [tex]s_{2}= 60mph[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{60}[/tex]
Put this into equation (1)
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex]
[tex]d_{2} + 20 = 40\times (\frac{d_{2}}{60} +2)[/tex]
[tex]d_{2} + 20 = \frac{2}{3}d_{2} +80\\d_{2} = \frac{2}{3}d_{2} +80-20\\d_{2} = \frac{2}{3}d_{2} +60[/tex]
Multiply through by 3
[tex]3\times d_{2} = 3\times \frac{2}{3}d_{2} +3 \times 60\\3d_{2} = 2d_{2} + 120\\3d_{2} -2d_{2} = 120[/tex]
∴ [tex]d_{2} = 120[/tex] miles
∴The distance traveled on the second day is 120 miles
For the distance traveled on the first day,
Substitute [tex]d_{2}[/tex] into the equation
[tex]d_{1}= d_{2}+20[/tex] miles
∴ [tex]d_{1}= 120+20[/tex]
[tex]d_{1}= 140[/tex] miles
∴ The distance traveled on the first day is 140 miles
The total distance traveled in the two days = [tex]d_{1} + d_{2}[/tex]
The total distance traveled in the two days = 120 miles + 140 miles
The total distance traveled in the two days = 260 miles
Hence, the total distance the driver traveled in the two days is 260 miles
Learn more here: https://brainly.com/question/23531710
Need help on #7 , #8 Asap
using trig to solve for missing angle
plzz any help please
Answer:
9
Step-by-step explanation:
If the sine of an angle is equal to the cosine of an angle, that means that the sides adjacent and opposite to that angle are equal. One triangle that has two equal sides is an isosceles triangle. We can set this triangle to be a 45-45-90 degree triangle, which means that the angle would be 45.
Now, we have to find the value of
[tex]4\tan^2(45)[/tex]
and
[tex]5\tan(45)[/tex]
The tangent of 45 is 1, so 1 squared times 4 is 4.
We have [tex]4\tan^2(45) = 4[/tex].
Again, the tangent of 45 is 1, and 1 times 5 is 5.
We have [tex]5\tan(45) = 5[/tex]
5 + 4 = 9
A to B is 420 mile away, A travels 40 mph and B travels 80 mph. they toward to each other. how many hour will they meet ?
Answer:
Step-by-step explanation:
I hope these are people in vehicles travelling toward each other.
80 mh * t + 40 mph * t = 420 miles
The two vehicles are going to travel a total of 420 miles. B will cover a lot more ground than A, but together they will make 420 miles
80t + 40t = 420
120t = 420
t = 420/120
t = 3.5
So after driving 3.5 hours, the two cars will meet.
A student states that the translation of triangle ABC is A’B’C’. What measurements or properties of lines AA', BB', and CC' do you need to confirm that it is a translation? :D
If you can show that the following two items are true
AA' = BB' = CC'AA' || BB' || CC'then you have shown that triangle A'B'C' is a translated or shifted copy of triangle ABC. In other words, they are the same triangle.
A hot air balloon is released into the air. During its straight ascent, the angle of elevation was 15° and, 3 minutes later, the angle of elevation increased 20°. How fast is the balloon traveling, in km/h, if the angle measurements were taken 300m away from the launch site?
Answer:
The speed of the balloon is 0.16 m/s.
Step-by-step explanation:
CD = 300 m
Let AD = x
AB = y
time, t = 3 min
Triangle, ADC
[tex]tan 15 = \frac{AD}{BC}\\\\0.27 \times 300 = x \\\\x = 80.4 m[/tex]
Triangle, BCD
[tex]tan 20 = \frac{BD}{BC}\\\\0.36 \times 300 = x + y \\\\x + y = 109.2 m[/tex]
So, y = 109.2 - 80.4 = 28.8 m
Speed = 28.8/180 = 0.16 m/s
10^12 X (5.0 x 10^8) X (3.33 x 10^0) =
Answer:
1.665e+21
Step-by-step explanation:
hope it help
make it as brininst
Answer:
[tex]10^{12}\left(5\cdot \:10^8\right)\left(3.33\cdot \:10^0\right)[/tex]
Exponent rule: [tex]a^b\cdot \:a^c=a^{b+c}[/tex]
[tex]10^{12}\cdot \:10^8\cdot \:10^0=\:10^{12+8+0}[/tex]
[tex]5\cdot \:3.33\cdot \:10^{12+8+0}[/tex]
Now, add 12 + 8 + 0 =20
[tex]=5\cdot \:3.33\cdot \:10^{20}[/tex]
Multiply 5 × 3.33=16.65
[tex]=10^{20}\cdot \:16.65[/tex]
Convert to decimal form
[tex]10^{20}=1.0E20[/tex]
Multiply
[tex]16.65\cdot \:1.0E20=1.665E21[/tex]
OAmalOHopeO
The corresponding edges of two similar containers are 56cm and 84cm.Find the ratio of the capacities
Answer:
8 : 27
Step-by-step explanation:
Given the ratio of sides of 2 similar objects = a : b , then
ratio of volumes = a³ : b³
Here ratio of sides = 56 : 84 = 2 : 3 , then
ratio of volumes = 2³ : 3³ = 8 : 27
The height of a basketball thrown by a 6 foot tall man follows a path defined by the function h(x)= -0.5^(2)+3x+6, where x is the horizontal distance from where it is thrown. How far away from the basket should the player stand in order for the ball to go in the basket (10 feet high) on its way down? Show all work.
Given:
The height of a basketball is given by the function:
[tex]h(x)=-0.5x^2+3x+6[/tex]
where x is the horizontal distance from where it is thrown.
To find:
How far away from the basket should the player stand in order for the ball to go in the basket (10 feet high) on its way down.
Solution:
We have,
[tex]h(x)=-0.5x^2+3x+6[/tex]
Putting [tex]h(x)=10[/tex], we get
[tex]10=-0.5x^2+3x+6[/tex]
[tex]10+\dfrac{1}{2}x^2-3x-6=0[/tex]
[tex]\dfrac{1}{2}x^2-3x+4=0[/tex]
Multiply both sides by 2.
[tex]x^2-6x+8=0[/tex]
Splitting the middle term, we get
[tex]x^2-4x-2x+8=0[/tex]
[tex]x(x-4)-2(x-4)=0[/tex]
[tex](x-2)(x-4)=0[/tex]
[tex]x=2,4[/tex]
In the given function the leading coefficient is negative, so the given function represents a downward parabola. It means, first the function is increasing after that the function is decreasing.
So, the value of the function is 10 at [tex]x=2[/tex] (its way up) and at [tex]x=4[/tex] (its way down.
Therefore, the player should stand 4 units away from the basket in order for the ball to go in the basket (10 feet high) on its way down.
Graph the line that passes through (5, 5), and is perpendicular to a line whose slope is –2.
Answer:
y = 1/2x + 5/2
Step-by-step explanation:
y = 1/2x + b
5 = 1/2(5) + b
5 = 5/2 + b
5/2 = b
What is the domain of g(x)
X is a real number
Answer:
The doing would be x
Step-by-step explanation:
since you are calculating domain for a specific value it would be the corresponding g(x) value which is the domain
Indicate in standard form the equation of the line through the given points, writing the answer in the equation box below.
K(6, 4), L(-6, 4)
9514 1404 393
Answer:
y = 4
Step-by-step explanation:
The given points are on the horizontal line ...
y = 4
This is the standard-form equation of that line.
4x+3=x+9
What is the number?
X=?
Answer:x=3
Step-by-step explanation:
4x+3=x+9
4x-x=(-3)+9
3x=6
x=6:3
x=2
with work please and thanks
Answer:
Step-by-step explanation:
He bought a total of 5 tickets, some child, some adult. This is the NUMBER equation.
# of adult tickets + # of child tickets = 5 tickets
Now for the COST equation. Each child ticket costs $2, so the expression for that is 2c; each adult ticket costs $8, so the expression for that is 8a. He spend a total of $22:
$2c + $8a = $22
Money and the number of tickets are NOT THE SAME so they cannot be put into the same equation. They won't add or subtract because they're not like.
Your system is choice A
What are the solutions to the equation 3(x – 4)(x + 5) = 0
Answer:
x=4
x=-5
Step-by-step explanation:
in order for this to be equal to 0, 1 or both of the factors has to be 0, because anything multiplied by 0 is 0.
123 * 29382 * 8139* 0 = 0
x-4 = 0
x = 4
x+5 = 0
x=-5
