Answer:
gtjgyjtjyjjjjk
Explanation:
Carbon monoxide and carbon dioxide have
Answer:
different chemical properties and the same physical properties
Explanation:
Both carbon monoxide and carbon dioxide are gases.
So physically, the two compounds have no fixed shape and volume and their molecules are far apart.
Therefore, they have similar physical properties.
Based on chemical properties, the compounds or molecules given are different.
They will combine chemically in diverse ways.
3. different chemical properties and the same physical properties
Physical properties:
Both carbon monoxide and carbon dioxide are gases. So physically, the two compounds have no fixed shape and volume and their molecules are far apart. Therefore, they have similar physical properties.Chemical properties:
The compounds or molecules given are different. They will combine chemically in diverse ways.Carbon Dioxide (CO₂) is a chemical compound consisting of one carbon atom and two oxygen atoms while Carbon Monoxide (CO) is a chemical compound which contains one carbon atom and one oxygen atom.CO is also a colorless and odorless gas while CO₂ is entirely human-made and is not naturally present in the atmosphere.Thus, both gases are chemically different.Therefore, option 3 is correct.
Learn more:
brainly.com/question/15821287
How many moles are in 3.69 x 1022 atoms of Ag?
Answer:
I'm assuming that 1022 is supposed to be 10^22, or 10 to the 22nd power. If that is the case, then the answer is 0.0612956811 mol. Round it to the number that you are supposed to round it to.
Carbon dioxide non examples? Please and catalyst non examples?
Answer:
I guess you mean by non element example. Non element examples have more than one elements. Carbon dioxide is a non element example since caebon dioxide has 2 oxygen atoms + 1 carbon atom = carbon dioxide.
I think catalyst is also a non element example because catalyst is inorganic which means that it is not a living thing. Since catalyst is in brass and brass is a non element example, I think catalyst is also a non element example.
Hope that helps, thank you !!
Answer and I’ll give you brainliest!
What type of reaction is this *
N2 + H2 → NH3
O synthesis
O combustion
O decomp
O single
O double
Helppp plssss pls help it’s Science I will give Brainlyist no cap I will just plssss help
Answer:
I cant see it that well but id be happy to help if u post a clearer picture!
Explanation:
50 points Two waves combine with constructive interference. What must be true of the
combined wave that forms?
A. It has a lower frequency than that of the original waves.
B. It has a higher amplitude than that of the original waves.
C. It has a higher frequency than that of the original waves.
D. It has a lower amplitude than that of the original waves.
Answer:B
Explanation:
Maybe
Answer:B is correct
Explanation:
A student determines the chromium(III) content of a solution by first precipitating it as chromium(III) hydroxide, and then decomposing the hydroxide to chromium(III) oxide by heating. How many grams of chromium(III) oxide should the student obtain if her solution contains 56.0 mL of 0.600 M chromium(III) nitrate?
Answer:
Explanation:
Chromium nitrate Cr( NO₃ )₂
Chromium hydroxide Cr( OH)₃
Chromium oxide ( Cr₂O₃ )
1 mole of chromium nitrate will form 1 mole of chromium hydroxide
1 mole of chromium hydroxide will form one mole of chromium oxide .
Moles of chromium nitrate in 56 mL of .6 M solution
= .056 x .6 = .336 moles
.336 moles of chromium nitrate will produce .336 moles of chromium hydroxide and .336 moles of chromium hydroxide will produce .336 moles of chromium oxide .
So chromium oxide produced = .336 moles
Molecular weight of chromium oxide = 152
.336 moles of chromium oxide is equal to
.336 x 152 grams of chromium oxide
= 51.07 grams .
The value of the rate constant for a gas phase reaction can be changed by increasing the A. temperature of the reaction vessel. B. volume of the reaction vessel. C. pressure of the reactant. D. amount of product.
Answer:
temperature of the reaction vessel
Explanation:
temperature of the reaction vessel
The value of the rate constant for a gas phase chemical reaction can be changed by increasing the: A. temperature of the reaction vessel.
What is the rate constant?In Chemistry, rate constant is typically used with rate law to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.
The rate law equation.Mathematically, the rate law is given by this formula:
[tex]R = k[A]^x[B]^y[/tex]
Where:
k is the rate constant.A is the concentration of reactant A.B is the concentration of reactant B.Generally, the value of the rate constant for a gas phase chemical reaction can be changed by increasing the temperature of the vessel (container) that is used in conducting the chemical reaction.
Read more on rate constant here: brainly.com/question/24749252
metric conversion ( convert )
Answer:
13. 2g
14. 5000mL
15. 104,000m
16. 160mm
17. 5600000mg
18. 10hs
19. 0.250km
20. 1daL
Explanation:
13. 1000milligram (mg) = 1gram (g)
Hence, 2000mg = 2000/1000
= 2g
14. 1 litre (L) = 1000millilitre (mL)
Hence, 5L = 5 × 1000
= 5000mL.
15. 1kilometre (km) = 1000metre (m)
Hence, 104km = 104 × 1000
= 104,000m
16. 1 centimetre (cm) = 10millimeters (mm)
Hence, 16cm = 16 × 10
= 160mm
17. 1kilogram (kg) = 1000000 milligram (mg)
Hence, 5.6kg = 5.6 × 1000000
= 5600000mg
18. 1 second (s) = 0.01 hectosecond (hs)
Hence, 1000s = 1000 × 0.01
= 10hs
19. 1000metre (m) = 1kilometre (km)
Hence, 250m = 250/1000
= 0.250km
20. 1 centiliter (cl) = 0.001 Decaliter (daL)
Hence, 1000cl = 1000 × 0.001
= 1daL
What is the mass of 5 liters of fluorine (F2) gas at STP?
Answer:
The molar density of any ideal gas at STP is:
1 mol / 22.4 L = 0.04464 mol / L
The molar mass of F2 is: 2(19) = 38 g/mol
0.04464 mol / L * (38 g / mol) = 1.70 g/L
Explanation:
How many moles of
salt (NaCl) is 28.7
grams?
Answer:
0.491 mol NaCl
Explanation:
Convert from grams to moles using the molar mass of NaCl:
28.7 g NaCl x 1 mol NaCl/58.44 g NaCl = 0.491 mol NaCl
The molar mass (58.44 g) can be found from adding the molar masses of the individual elements (Na and Cl); the g NaCl will cancel out (dimensional analysis), leaving you with mol NaCl.
What is a personal factor of resilience?
A. Feeling of belonging
B. Family and friends
C. Genetics
D. Coping Mechanisms
Answer:
B
Explanation:
B is a personal factor of resilience
How many atoms are in 0.580 moles of CO2?
Answer:
[tex]1.05x10^{24}atoms[/tex]
Explanation:
Hello!
In this case, according to the definition of the Avogadro's number, it is possible to realize that one molecule of CO2 contains 3 moles of atoms, one of carbon and two of oxygen, thus, we have:
[tex]0.580molCO_2*\frac{3mol\ atoms}{1molCO_2} =1.74mol\ atoms[/tex]
Then, we use the Avogadro's number to obtain:
[tex]1.74mol\ atoms*\frac{6.022x10^{23}atoms}{1mol\ atoms} \\\\1.05x10^{24}atoms[/tex]
Best regards!
Hurry I need Now!!!In which biome would the climax species be reached most quickly following a fire?
A Taiga
B desert
C Grassland
D. deciduous forest
E tropical rain forest
Answer:
D. Deciduous Forest.
Explanation:
Why is HCI a strong acid and HCIO a weak acid?
Strong Acid: dissolves and dissociates 100% to produce protons (H+) 1. seven strong acids: HCl, HBr, HI, HNO3, H2SO4, HClO4, & HClO3 2. ... Weak Acid: dissolves but less than 100% dissociates to produce protons (H+) 1.
PLEASE HELP it’s due in 30 minutes
Answer:
1-6
3 1 3 3 2 2
Explanation:
what the the noble gas configuration for Boron
Answer:
[He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]
Explanation:
The electron configuration for Boron is 1[tex]s^{2}[/tex]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex], but you can also write it as the noble gas configuration, which is [He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]
Note that helium has the configuration of 1[tex]s^{2}[/tex], so we instead of writing it, we write [He]. This can be useful when writing the configurations of elements from the later periods as it saves space.
Which of the following notations represents an alpha particle?
A. 2 He
C.B+
В. В
D. Y
Answer:
A. 2 He
Explanation:
The notation of an alpha particle is depicted as:
₂He
An alpha particles is a nucleus of 2 protons and 2 neutrons. So it is actually a Helium cation.
Alpha particles are monoenergetic and they mostly have discrete energy.
So, the mass number of the particle is 4 and atomic number is 2
For the reaction of reducing benzil (MW 210.23 g/mol) with sodium borohydride (MW 37.83 g/mol), if 2.56 g of benzil and 0.38 g of sodium borohydride were used to make hydrobenzoin (MW 214.26 g/mol), and 2.22 g of hydrobenzoin was obtained, which chemical is limiting reagent
Answer:
NaBH₄
Explanation:
First, we need to write the chemical formula of all the compounds:
Benzil: C₁₄H₁₀O₂
Sodium Borhydride: C₁₄H₁₀O₂
Hydrobenzoin: C₁₄H₁₄O₂
Now, let's write the reaction that is taking place and write all the products:
C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH
We can see that the reaction is already balanced, so we don't need to do anything else.
The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)
According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:
moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles
moles NaBH₄ = 0.38 / 37.83 = 0.01 moles
moles C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles
We have the moles of every species, now, let's see the mole ratio
If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄
Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄
Solving for X:
X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.
However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄
Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.
So, in conclusion, Limiting reagent NaBH₄Hope this helps
What type of equation is this?
AlCl3 + NaOH → Al(OH)3 + NaCL
double
single
synthesis
decomp
combustion
what is 78%
of 100? help
Answer:
78
Explanation:
You have 100%, you take 22% and get 78%
Help pls!!!!!!!!!!!!!!!!!!!!!!!
Answer:
D a compound
Explanation:
235U92 + 1N0 + 135Cs55 + 99Rb37 + x1n0
Please help
15 points
Given
Atomic symbol
RequiredAtomic composition
Solution
Atomic number = number of protons = number of electrons
Mass Number (A) is the sum of protons and neutrons
Number of protons and Number of Neutrons in nucleus
Number of electrons in the shell
From the picture:
protons = 3
neutrons = 4
electrons = 3
atomic number = protons = electrons = 3
mass number = protons + neutrons = 3+4 = 7
Identify the chromatography term that corresponds to each definition.
A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent Choose...
A method used to separate components of a mixture Choose...
The substance to which the sample is bound at the start of an experiment Choose...
The substance that carries the components of a mixture Choose...
Answer:
A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent- Retention factor
The substance to which the sample is bound at the start of an experiment- stationary phase
The substance that carries the components of a mixture- mobile phase
Explanation:
The retention is defined as a value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent. It shows us how effective a solvent is at separating a mixture.
The stationary phase is the the substance to which the sample is bound at the start of an experiment. The solvent pick up the substance to be analyzed from this stationary phase. The different components of the mixture are found to move up the stationary phase at different speeds, causing them to eventually separate from each other.
The mobile phase is the substance that carries the components of a mixture during chromatography.
A sample of compound A (a clear, colorless gas) is analyzed and found to contain 4.27g carbon and 5.69g oxygen. A sample of compound B (also a clear, colorless gas) is analyzed and found to contain 5.19g carbon and 13.84g oxygen. Are these data an example of the law of definite proportions, the law of multiple proportions, or neither? What do these data tell you about substances A and B?
Answer:
law of multiple proportions
Explanation:
The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in simple multiple ratio.
We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.
The substances A and B must be CO and CO2 respectively.
Energy can generally be considered to be either kinetic energy or potential energy. Some specific forms of energy, such as
electrical, magnetic, and gravitational energy, can operate in the space around objects and affect other objects that come near. In
these examples
A. energy is continuously created.
B. energy is continuously destroyed.
C. energy exists in a field.
D. all of these
Answer:
d hope it's right hope this helps
Answer:
Energy exists in a field.
Explanation:
Electrical field, magnetic field, and gravitational field.
A and B are wrong otherwise the law of conservation of energy would be violated
Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene
Answer:The correct names for the structure are:
--> 1. 1-bromo-3-chlorobenzene.
--> 3. meta-bromochlorobenzene.
--> 6. m-bromochlorobenzene.
Explanation:
Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.
Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.
The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:
--> the functional group is benzene
--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)
--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.
The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.
--> ortho or O : this is used when the substituents are close to each other in the benzene ring.
--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.
--> para or (p): This is used when the substituents are across each other in the benzene ring
From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.
In a laboratory experiment, students synthesized a new compound and found that when grams of the compound were dissolved to make mL of a diethyl ether solution, the osmotic pressure generated was atm at K. The compound was also found to be nonvolatile and a non-electrolyte. What is the molar mass they determined for this compound
The question is incomplete, the complete question is;
In a laboratory experiment, students synthesized a new compound and found that when 12.23 grams of the compound were dissolved to make 228.1 mL of a benzene solution, the osmotic pressure generated was 4.55 atm at 298 K. The compound was also found to be non-volatile and a non-electrolyte. What is the molecular weight they determined for this compound?
Answer:
287.76 g/mol
Explanation:
From;
π = M R T
M = molarity
R= gas constant
T = temperature
number of moles = π * volume/RT
number of moles = 4.55 * 228.1/1000/0.082 * 298
number of moles = 1.037855/24.436
number of moles = 0.0425 moles
Molar mass = mass/number of moles
Molar mass = 12.23 grams/0.0425 moles
Molar mass = 287.76 g/mol
What is the mass in grams of 2.5 mol of O2?
Answer:
80grams
Explanation:
RAM of O=16
molar mass of O2= 16×2=32g/mol
mass= mole × molar mass
= 2.5×32= 80g
