i'm doing this as a system, ok?
x + y = 12
- x = - y - 10
x + y = 12
-x + y = -10
2y = 2
y = 1
x + 1 = 12
x = 11
so, the ordered pair is (11, 1) -> remember that the x always comes first
hope it helps :)
Answer:yes yes culo Rotox (b
Step-by-step explanation: pro gard1bas x12x14x20¿142
Helpo pleasssse
On my hw I have a parabola that opens down with its vertex at (-3,-6)......
For the range would I say that {yER | y > -6} OR {yER | y < -6} ????
I'm just confused from the negative numbers
Answer: The range is [tex]\{y \in \mathbb{R}\ | \ y \le -6\}[/tex]
Explanation:
The parabola opens down, forming a "frowny face" in a way (just without the eyes). Or you can think of it as a hill or mountain. This means that the vertex (-3,-6) is at the top of that mountain. It's the highest point of that parabola.
The range is the set of all possible y values. We see that y = -6 is the largest it can get. So y = -6 or y is smaller than this. We would then write [tex]y \le -6[/tex] to describe all the possible y values.
Therefore, the range is [tex]\{y \in \mathbb{R}\ | \ y \le -6\}[/tex]
This translates to "y is a real number such that y is -6 or smaller".
So the second answer you wrote is close, but you forgot the "or equal to" portion of the inequality sign.
See below for a visual example of what's going on.
please help don’t understand question!
Answer:
[tex]{ \sf{ - 2 {a}^{5} + 4 {a}^{4} + 5 {a}^{3} + \frac{2}{3}a }}[/tex]
Answer:
D
Step-by-step explanation:
A polynomial is in standard equation when the degree of the polynomial are in descending order.
x = 3
x = 5
x = 0
x = 2
Answer:
x=2 is incorrect
Step-by-step explanation:
Y(2)=(3/4)*x^2=(3/4)*4=3
I need help to find w =
Answer:
The answer is 12.
Step-by-step explanation:
Since one of the sides on the smaller polygon is two and on the other one is six that must mean the scale is multiply by 3 because 2x3=6. So 4 times 3 is 12.
So, w = 12
HELP PLS!! ILL GIVE POINTS !! :(( m
Find the product of the complex numbers. Express your answer in
trigonometric form.
Z1 =5(cos15° + i sin 15°)
Z2=3(cos70° + i sin 70°)
A. 8(cos85° + isin85°)
B. 2 (cos(-55°) + i sin(-55°))
C. 2 (cos305° + i sin 305°)
D. 15(cos85° + i sin85°)
Answer: Choice D
15(cos85° + i sin85°)
===========================================================
Explanation:
Let's say we had these two general complex numbers, which are in polar form.
[tex]z_1 = r_1*\left(\cos(\theta_1)+i*\sin(\theta_1)\right)\\\\z_2 = r_2*\left(\cos(\theta_2)+i*\sin(\theta_2)\right)\\\\[/tex]
We can abbreviate them into the shorthand form
[tex]z_1 = r_1*\text{cis}(\theta_1)\\\\z_2 = r_2*\text{cis}(\theta_2)\\\\[/tex]
The notation "cis" stands for "cosine i sine".
Now that we have those complex numbers set up, multiplying them is as simple as saying this:
[tex]z_1*z_2 = (r_1*r_2)*\text{cis}(\theta_1+\theta_2)[/tex]
We do two basic things:
Multiply the r values out frontAdd the theta values inside the the cis function---------------------------------------
With all that in mind, let's tackle the problem your teacher gave you.
The given complex numbers
[tex]z_1 = 5*\left(\cos(15^{\circ})+i*\sin(15^{\circ})\right)\\\\z_2 = 3*\left(\cos(70^{\circ})+i*\sin(70^{\circ})\right)\\\\[/tex]
abbreviate into
[tex]z_1 = 5*\text{cis}(15^{\circ})\\\\z_2 = 3*\text{cis}(70^{\circ})\\\\[/tex]
then those multiply to
[tex]z_1*z_2 = (r_1*r_2)*\text{cis}(\theta_1+\theta_2)\\\\z_1*z_2 = (5*3)*\text{cis}(15+70)\\\\z_1*z_2 = 15\text{cis}(85^{\circ})\\\\z_1*z_2 = 15\left(\cos(85^{\circ})+i\sin(85^{\circ})\right)\\\\[/tex]
which is why choice D is the final answer.
Will Mark Brainlest helpppp
Answer:
R = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]
Step-by-step explanation:
P - Q + R = I ( I is the identity matrix )
[tex]\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( subtract corresponding elements )
[tex]\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]
R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]
Need help here please and thank u
Answer:
I think C sorry if wrong
Step-by-step explanation:
Please hurry I will mark you brainliest
What is the equation of the line parallel to y = 2x - 4 and with the same x - intercept as 3x – 4y = 12?
Answer:
y=2x-8
Step-by-step explanation:
Hi there!
We want to find an equation of the line parallel to y=2x-4 but has the same x intercept as 3x-4y=12
Parallel lines have the same slope, but different y intercepts
In y=2x-4, which is written in y=mx+b form, m is the slope and b is the y intercept
2 is in the place of where the slope would be, so the slope of that line is 2
That means the slope of the line parallel to it would also have a slope of 2
Here is the equation of the parallel line so far:
y=2x+b
We need to find b, the y intercept
Typically, we'll substitute a point into the equation to solve for b, but we don't have a point, yet
We're given that the new line has the same x intercept as 3x-4y=12
The x intercept is the point where the line passes through the x axis, and so the value of y at that point is 0
Let's substitute 0 for y in 3x-4y=12 and solve for x to find the x intercept
3x-4(0)=12
Multiply
3x=12
Divide both sides by 3
x=4
So the value of the x intercept is 4. As a point, it's (4,0)
So now substitute the values of the point (4,0) into y=2x+b to find b
0=2(4)+b
Multiply
0=8+b
Subtract 8 from both sides
-8=b
Substitute -8 as b into the equation
y=2x-8
Hope this helps!
Will mark brainlest helppppppp
Answer:
6
Step-by-step explanation:
again ?
7 = (3x - 4)/2
14 = 3x - 4
18 = 3x
x = 6
f(x) = x2 – 12x – 29
f(3) = (x+ ?)+ ?
Answer:
-6 and - 65
Step-by-step explanation:
X-12x-29, by completing the square we get (x-6)^2-65
how to convert base two to base three
Consider this example: say we want to convert x = 11 0101 1001₂ to base 3.
The binary expansion of x is
x = 1×2⁹ + 1×2⁸ + 1×2⁶ + 1×2⁴ + 1×2³ + 1×2⁰
which in base 10 reduces to
x = 512 + 256 + 64 + 16 + 8 + 1 = 857
Recall the first several powers of 3:
3⁰ = 1; 3¹ = 3; 3² = 9; 3³ = 27; 3⁴ = 81; 3⁵ = 243; 3⁶ = 729
Now it's a matter of computing quotients and remainders. Pick the largest power of 3 that fits into the target number, then check the remainder and repeat.
• How many times does the 729 go into 857? 1 time, and it leaves a remainder of 128, or
857 = 1×729 + 128 = 1×3⁶ + 128
• How many times does 81 go into 128? Also 1 time, so
128 = 1×81 + 47 = 1×3⁴ + 47
• How many times does 27 go into 47? Also 1 time,
47 = 1×27 + 20 = 1×3³ + 20
• How many times does 9 go into 20? 2 times,
20 = 18 + 2 = 2×9 + 2 = 2×3² + 2
• How many times does 1 go into 2? Also 2 times,
2 = 2 + 1 = 2×1 + 0 = 2×3⁰
So we found
857 = 1×3⁶ + 1×3⁴ + 1×3³ + 2×3² + 2×3⁰
which is the ternary expansion of x,
x = 1 011 202₃
f The difference of 8 and 3 is multiplied by one-quarter of the sum of 7 and 5 37 vedanta Excel in Mathematics
Answer:
15
Step-by-step explanation:
first find f which is (8-3) × ( 1/4 × 7 + 5)
simplify
5 × (1/4 ×12)
5 × 3
15 is thw answer
which one of the following is not true about a rectangle? A. all its angels are right angels B. its opposite angels are equal C.opposite sides are parallel D. all its sides are equal
Answer:
I am not sure but it may be option c .
Step-by-step explanation:
I chose option c because in parallelogram the opposite sides are parallel .
Based on the markings of the two triangles, what statement could be made about ΔABC and ΔA′B′C′? Question 1 options: A) The corresponding pairs of sides and angles of ΔABC and ΔA′B′C′ aren't congruent. B) ΔABC and ΔA′B′C′ are congruent. C) ΔABC and ΔA′B′C′ are irregular polygons. D) ΔABC and ΔA′B′C′ aBased on the markings of the two triangles, what statement could be made about ΔABC and ΔA′B′C′? Question 1 options: A) The corresponding pairs of sides and angles of ΔABC and ΔA′B′C′ aren't congruent. B) ΔABC and ΔA′B′C′ are congruent. C) ΔABC and ΔA′B′C′ are irregular polygons. D) ΔABC and ΔA′B′C′ are similar but not congruent.re similar but not congruent.
Answer:
B) ΔABC and ΔA′B′C′ are congruent.
Step-by-step explanation:
Given
See attachment for [tex]\triangle ABC[/tex] and [tex]\triangle A'B'C'[/tex]
Required
Determine the relationship between both triangles
The single line on all sides of both triangles implies that the sides of the triangles are equal
i.e.
[tex]\triangle ABC \cong \triangle A'B'C'[/tex] --- sides
Similarly, the same mark on the three angles of both triangles means that the angles of the both triangles are equal
i.e.
[tex]\triangle ABC \cong \triangle A'B'C'[/tex] --- angles
Hence, both triangles are congruent
Answer:
B) ΔABC and ΔA′B′C′ are congruent.
Step-by-step explanation:
please help with math!! geometry explain if you can :)
Answer:
Step-by-step explanation:
Applying the midpoint formula to the points (a, 0) and (0, a) looks like this:
[tex]M=(\frac{a+0}{2},\frac{0+a}{2})[/tex] which simplifies to
[tex]M=(\frac{a}{2},\frac{a}{2})[/tex]
La señora Angélica fue al mercado y compró 2 visores protectores y 1 mascarilla, pagó $55.00, en total. En el mismo puesto, la señora Silvia compró 1 visor protector y 2 mascarillas y pagó $50.00. ¿Cuál es el precio de una mascarilla? ¿Cuáles el precio de un visor protector?
Answer:
Cost of 1 goggles = $20
Cost of 1 mask = 15
Step-by-step explanation:
Given:
Cost of 2 goggles and 1 mask = $55
Cost of 1 goggles and 2 mask = $50
Find:
Cost of each goggles and mask
Computation:
Assume;
Cost of 1 goggles = a
Cost of 1 mask = b
So,
2a + b = 55.....EQ1
a + 2b = 50.......EQ2
EQ1 x 2
4a + 2b = 110 ......EQ3
EQ3 - EQ2
3a = 60
a = 20
Cost of 1 goggles = $20
a + 2a = 50
20 + 2b = 50
2b = 30
b = 15
Cost of 1 mask = 15
.
HELP THANKS SO MUCH BRAIN FOR CORRECT
Answer:
i think the answet is 0.625
a party of 7 comes into your restaurant and says they want to split the bill evenly 7 ways their total is $247.79 what does each customer owe ?
Answer:
each costumer owe $35.40
Step-by-step explanation:
so, u get 247.79÷7 (cuz it is 7 people)
u get 35.40.
to check just get 35.40×7 and u will revice their total.
HELP PLS HELP MEEEEE IM FAILING PYTHAGOREAN THEOREM
7^2 + 6^2 = h^2
49 + 36 = h^2
85 = h^2
√85 = h
h = 9.21m
Answered by Gauthmath must click thanks and mark brainliest
x= 3/4 , y= - 2/5 then x+ y =
Step-by-step explanation:
Given
x = 3/4
y = -2/5
Now
X + y = 3/4 - 2/5
[tex] \frac{3 \times 5 - 2 \times 4}{20} [/tex]
[tex] = \frac{15 - 8}{20} [/tex]
[tex] = \frac{7}{20} [/tex]
Answer:
7/20
Step-by-step explanation:
x=3/4
y= -2/5
x+y=?
to get the sum, plug in x=3/4 into the x and y= -2/5 into the y
1. x + y = ?
2. 3/4 + (- 2/5) = ?
3. 3/4 - 2/5 =?
4. find the lcm of 4 and 5 to get the common denominator (in this case, the lcm of 4 and 5 is 20)
5. multiply 3/4 by 5 (numerator and denominator) and 2/5 by 4 (numerator and denominator)
6. 15/20 - 8/20 = 7/20
the answer is 7/20
The graph of g(x) = (x + 2)2 is a translation of the graph of f(x) ____ by ____ units.
Step-by-step explanation:
VERY EASY FOR ME
The real part (red) and imaginary part (blue) of the Riemann zeta function along the critical line Re(s) = 1/2. The first non-trivial zeros can be seen at Im(s) = ±14.135, ±21.022 and ±25.011. The Riemann h
ypothesis, a famous conjecture, says that all non-trivial zeros of the zeta function lie along the critical line.
SO 6+/7× and 78/+×
ANSWER
A garden is rectangular with a width of 8 feet and a length of 10 feet. If it is surrounded by a walkway 2 feet wide, how many square feet of area does the walkway cover?
Answer:
The rea of walk way is 32 ft^2.
Step-by-step explanation:
width, w = 8 feet
length, L = 10 feet
width of walkway, d = 2 feet
length of outer, L' = 10 + 2 + 2 = 14 feet
Area of outer, A' = L' x w = 14 x 8 = 112 ft^2
Area of inner, A = L x w = 10 x 8 = 80 ft^2
The area of walkway = A' - A = 112 - 80 = 32 ft^2
The rea of walk way is 32 ft^2.
If Sin x = -¼, where π < x < 3π∕2 , find the value of Cos 2x
Answer: 7/8
Cos2x has 3 formulas, Sinx is given in the question, we should use the formula with sinus. I guess that's the solution.
can you find the answer for m
Answer:
m∠LMK = 50°
Step-by-step explanation:
This is an isosceles triangle. Isosceles triangles have two sides of equal length and two equal angles. This means ∠K and ∠M will have the same degrees.
The sum of the angles of a triangle is 180°. The following equation can be arranged and solved for the missing angles:
[tex]x+x+80=180\\2x+80=180\\2x=100\\x=50[/tex]
Therefore, m∠LMK = 50°.
Please help me with this is so confusing
Answer:
The expression for the height of the solid is:
[tex]\displaystyle h = x^2+x-9[/tex]
Step-by-step explanation:
Recall that the volume of a rectangular solid is given by:
[tex]\displaystyle V = \ell wh[/tex]
Where l is the length, w is the width, and h is the height.
We know that the volume is given by the polynomial:
[tex]\displaystyle V = 3x^4-3x^3-33x^2+54x[/tex]
And that the length and width are given by, respectively:
[tex]\displaystyle \ell = 3x \text{ and } w =x-2[/tex]
Substitute:
[tex]\displaystyle 3x^4-3x^3-33x^2+54x=(3x)(x-2)h[/tex]
We can solve for h. First, divide both sides by 3x:
[tex]\displaystyle \frac{3x^4-3x^3-33x^2+54x}{3x}=(x-2)h[/tex]
Divide each term:
[tex]\displaystyle x^3-x^2-11x+18=(x-2)h[/tex]
To solve for h, divide both sides by (x - 2):
[tex]\displaystyle h = \frac{x^3-x^2-11x+18}{x-2}[/tex]
Since this is a polynomial divided by a binomial in the form of (x - a), we can use synthetic division, where a = 2. This is shown below. Therefore, the expression for the height of the solid is:
[tex]\displaystyle h = x^2+x-9[/tex]
4² − 7 + 55 − 74 + 3 (Ascending with respect to n):
Answer:
If its supposed to be simplify it will be -7 . If your finding the derivative it is 0.
Step-by-step explanation:
An airplane flies a distance of 800km from A to B. If its average speed is 600km/h, how long does it take to cover that distance?
Answer:
1 hour 33 minutes
Step-by-step explanation:
distance/speed= time
d =800/600
d=1.33
The aeroplane takes 1.33 hours to traverse a distance of 800 km.
What is the speed of an object?Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time
Given here: An airplane flies a distance of 800 km with an average speed of 600 km/h
Thus the time taken by the aeroplane to cover that distance is
t=800/600
t=4/3
t=1.33 hours
Hence, The aeroplane takes 1.33 hours to traverse a distance of 800 km.
Learn more about the speed of an object here:
https://brainly.com/question/28224010
#SPJ2
A rectangular drawing is enlarged by 30%. The original dimensions of this drawing are 16cm x 24cm.
Determine the scale factor, as a fraction that represents this enlargement. What are the new, enlarged
dimensions?
Answer:
Step-by-step explanation: Scale [tex]\frac{130}{100} = \frac{13}{10}[/tex]
New dimensions [tex]16 * 1.3 --- 24*1.3 =20.8 cm * 31.2 cm[/tex]
Does anyone know the answer for this?
Answer:
I'm pretty sure it's the 3rd option
Answer:
first option is correct
Step-by-step explanation:
because there are less no. on negative side than on positive one
use the ratio of a 45-45-99 triangle to solve for the variables.
hopefully this answer can help you to answer the next question.