What is the approximate value of k when 30 = e^5k?

Answers

Answer 1

Answer:

Explanation:

30 = e^5k

ln30 = lne^5k

ln30 = 5k

k = ln30/5

k = 0.68023947...

round to your heart's content.


Related Questions

What is the difference between speed and velocity?

Answers

Speed is the rate of change of distance with time while velocity is the rate of change of displacement with time.Speed is a scalar quantity while velocity is a vector quantity.Speed cannot be negative but velocity can be negative.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Calculate the net force acting on a body of mass 20 kg moving with a
uniform velocity of 4 ms-1.

Answers

Answer:

0 N

Explanation:

Uniform velocity means no acceleration and therefore no net force.

Qué velocidad –en m/s– tiene un móvil, que recorre 15 km en 20 minutos
(es para hoy por faaaa)

Answers

Answer:

Explanation:

15 km(1000 m / km) / (20 min(60 s/min)) = 12.5 m/s

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula
KE = one half.mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of
0.8 m will be 4 m/s, and use this speed for each calculation.

Record your calculations in Table A of your Student Guide.

When the mass of the bottle is 0.125 kg, the KE is
✔ 1
kg m2/s2.

When the mass of the bottle is 0.250 kg, the KE is
✔ 2
kg m2/s2.

When the mass of the bottle is 0.375 kg, the KE is
✔ 3
kg m2/s2.

When the mass of the bottle is 0.500 kg, the KE is

✔ 4
kg m2/s2.

Answer included in Question

Answers

Answer:

kinetic energy is given as KE = (0.5) m v²given that : v = speed of the bottle in each case =  4 m/s when m = 0.125 kg KE = (0.5) m v² =  (0.5) (0.125) (4)²

Explanation:

Answer:

1. 0.5    2.  2    3. 3.75    4.  5

Explanation:

What are the two fundamental ways energy and momentum are moved from one place to another?​

Answers

The two fundamental ways energy and momentum are moved from one

place to another are through the mass and velocity.

The formula for momentum is mass multiplied with velocity.

Momentum= mass × velocity

The two factors in which momentum and energy is moved from one place to

another is however through how much and how fast the object is moving

which validates the answer.

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Suppose a cannon is sitting on top of a 50.0 m high hill and a 5.00 kg cannon ball is fired with a velocity of 30.0 m/s at some unknown angle. What is the velocity of the cannon ball when it strikes the earth?

Answers

The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

The given parameters:

Height of the hill, h = 50 mMass of the cannon, m = 5 kgVelocity of the ball, v = 30 m/s

The final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;

[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]

Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

Learn  more about conservation of energy here: https://brainly.com/question/166559

A container holds 192 g of oxygen gas at a pressure of 8.00 atm.
How much heat Q is required to increase the temperature by
145 °C at constant volume?

Answers

The quantity of heat (Q) that is required to increase the temperature at constant volume is 18,082.95 Joules.

Given the following data:

Mass of oxygen gas = 192 gPressure = 8.00 atmTemperature = 145°C

Scientific data:

Ideal gas constant, R = 8.314 J/molKMolar mass of oxygen gas = 32 g/mol.

To determine the quantity of heat (Q) that is required to increase the temperature at constant volume:

First of all, we would find the number of moles of oxygen gas.

[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{192}{32}[/tex]

Number of moles = 6 moles.

At constant volume, the heat capacity for a diatomic gas is given by:

[tex]C_v = \frac{5}{2} R\\\\C_v =\frac{5}{2} \times 8.314[/tex]

Heat capacity = 20.785 J/molK.

At constant volume, the quantity of heat (Q) is given by this formula:

[tex]Q = nC_v \Delta T\\\\Q=6 \times 20.785 \times 145[/tex]

Quantity of heat (Q) = 18,082.95 Joules

Note: [tex]\Delta T[/tex] = 145°C = 145 K (since the difference is the same).

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BECAUSE OF THEIR A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY

a. Acceleration
b. inertia
c. velocity
d. weight

Answers

Answer:

b. inertia

Explanation:

BECAUSE OF THEIR inertia A PAIR OF SUNGLEASSES ON THE DASHBOARD WILL CONTINUE MOVING FORWARD WHEN THE CAR TURNS SHARPLY.

Use the circuit diagram to decide if the lightbulb will
light. Justify your answer.

Answers

Answer:

The light bulb will NOT light because the lower switch being closed makes a short circuit. The light will have a high resistance and the electricity will choose to flow the easiest way possible through the low resistance wires.

Explanation:

Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by magnetic forces. Michelle is a(n)

Answers

Answer:

Explanation:

designer

illusionist

engineer

entrepreneur

salesperson

human

inventor

Which statement about diffraction is correct?
A. Sound waves bend around the corners of various obstacles.
B. Sound waves can only travel in straight lines.
C. The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
D. The amplitudes of two waves combine to appear as one big wave.

Answers

Answer:

I think A

Explanation:

Which statement about diffraction is correct?

A. Sound waves bend around the corners of various obstacles.

B. Sound waves can only travel in straight lines.

C. The amplitudes of two waves combine to appear as a wave smaller than the individual waves.

D. The amplitudes of two waves combine to appear as one big wave.

What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21

Answers

Answer:

OPTRIMUM PRIDE URGH URGH URGH

Explanation:

AHHAAHAHAHAHA

Who won the noble prize for physics. He led a coalition of scientists who argued to control nucleus weapons

Answers

Answer:

Linus Pauling

Explanation:

Prize motivation: "for his fight against the nuclear arms race between East and West." Linus Pauling received his Nobel Prize one year later, in 1963.

all pressure topics in physics​

Answers

Absolute, Atmospheric, Differential, and Gauge Pressure

The part of the circuit that converts electrical energy into other forms

Answers

Answer:

Load

Explanation:

The load in an electric circuit is any device that converts electrical energy into another form of energy.

K
Mission CG9: Weightlessness
Consider the several locations along a roller coaster
track. In which location(s) would the riders feel less
than their normal weight? Select all that apply.
Location A
Location B
Location C
a
=-10 m/s/s, dn
--2 m/s/s, up
a--6 m/s/s, dn
Location D
Location E
x=-12 m/s/s, dn
---6 m/s/s, up

Answers

The locations where the riders feel less than their normal weight are Location A, Location C and Location D.

The given parameters;

Location A, a = 10 m/s² downLocation B, a = 2 m/s² upLocation C, a = 6 m/s² downLocation D, a = 12 m/s² downLocation E, a = 6 m/s² up

The normal weight of the riders is calculated by applying Newton's second law of motion as follows;

W = mg

W = 9.8m

The apparent weight of the riders for the upward acceleration is calculated  as follows;

[tex]R = m(g + a)[/tex]

The apparent weight of the riders for the downward acceleration is calculated  as follows;

[tex]R = m(g - a)[/tex]

The apparent weight of the riders at location A is calculated as follows;

[tex]R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m[/tex]

The apparent weight of the riders at location B is calculated as follows;

[tex]R_B = m(9.8 + 2)\\\\R_B = 11.8 m[/tex]

The apparent weight of the riders at location C is calculated as follows;

[tex]R_C = m(9.8 - 6)\\\\R_C = 3.8 m[/tex]

The apparent weight of the riders at location D is calculated as follows;

[tex]R_D = m(9.8 - 12)\\\\R_D = -2.2 m[/tex]

The apparent weight of the riders at location E is calculated as follows;

[tex]R_E = m(9.8 + 6)\\\\R_E = 15.8 m[/tex]

Thus, the locations where the riders feel less than their normal weight are;

Location ALocation CLocation D.

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An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?

Answers

Answer:

Explanation:

acceleration=  change in velocity/time taken

acceleration=  93/49

=2.02

How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N

Answers

Answer:

14,400

Explanation:

You need to do 240x60 and you would get the answer as 14,000

As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.

O True O False​

Answers

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

Just like our bodies, Earth's cycles tend to maintain a balance or equilibrium .

Answers

The Correct answer is Equilibrium

the earth's cycle cycle tend to maintain the balance or equilibrium of the earth by maintaining the proper amount of water , nitrogen , carbon , phosphorous on earth . Each of the comonent of earth's cycle is equally important because they support life on earth. They are basis of life as carbon is found in abundant amount in all the life forms. Phosphorous, nitrogen and Water is equally important in the human beings as well as in plants and animals Hence , they maintain the equilibrium of earth

An elephant has a mass of 55,000 kg. What is the elephant’s weight on Saturn (g= 10.4)?

Answers

Answer:

Explanation:

F = ma

F = 55000 kg(10.4)

F = 572000 N

That is an amazingly large elephant, more like 11 elephants

A more typical mass for a single elephant would be 5000 kg with a weight on Saturn of 52000 N

Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.

What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?

Answers

Answer:

Explanation:

Conservation of momentum

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ

The kinetic energy of the system after the collision would be 128.5  KJ.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem Car 1 of mass m1 is waiting at a traffic light.

Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.

By using the conservation of the momentum,

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

The final velocity of the system comes out to be  8.57 m/s.

The kinetic energy of the system after the collision,

KE =1/2×(2500 + 1000)×8.57² = 128,571.4

    = 128.5  KJ

Thus, the kinetic energy of the system after the collision would be 128.5  KJ.

To learn more about momentum from here, refer to the link;

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#SPJ2

A 21 newton force keeps a 3 kg object in uniform circular motion. The speed of the object is 9 m/s. The magnitude of the centripetal acceleration is


3 m/s^2
7 m/s^2
27 m/s^2
30 m/s^2

Answers

Answer:

Explanation:

F = ma

a = F/m = 21/3 = 7 m/s²

A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical height of 19 m. If the sphere has a radius of 0.60 m, what is the angular speed of the sphere at the bottom of the incline plane

Answers

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

Which kind of chemical reaction is best
represented by the following equation?
BaCl2 + Na2S04 --> 2NaCl + BaSO4
A. Synthesis
B. Single displacement
C. Decomposition
D. Double displacement

Answers

Answer:

Synthesis

Explanation:

[tex] \color{lime}{ \sf better \: luck \: on \: your \: exam \: lol}[/tex]

have a difinite shape and do not easily take the shape of their containers

Answers


Ok well that’s something to think about

Which car is experiencing negative acceleration?
A. a car sitting at a red light
B. a car slowing down as it approaches a red light
C. a car driving in a circle at a constant speed
D. a car changing its speed from 0 km/hr to 10 km/hr

Answers

Answer:B

Explanation:

Answer: b

Explanation: b as it slows down and decelerates

3. A ball is dropped from the roof of a building 55 meters tall. What is the approximate time of fall?
(Neglect air resistance and round to 2 decimal places).

Answers

Answer:

3.35 seconds

Explanation:

Use one of the equations of accelerated motion:

Δd = v1Δt+1/2aΔt^2

and rearrange for Δt which is time

Δt = √(2Δd)/a

now we can substitute in the values

a= 9.8 (acceleration due to gravity) and Δd= 55 as that is the height of the building

Δt = √(2*55)/9.8

Δt = 3.3503s

what is the relationship between work and mechanical advantage

Answers

Answer:
Mechanical efficiency: the comparison of the machine's work output with it's work input
Mechanical advantage: the number of times that the machine multiplies the force


Explained:

Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.60 cm from the axis to equal 300000 g (where g is the acceleration due to gravity).
Express your answer numerically in revolutions per minute.

Answers

Answer:

Explanation:

300000(9.8) = ω²(0.0160)

ω = 13555 rad/s

13555 rad/s (60 s/min/ 2π rad/rev) = 129,445 rev/min

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