Answer:
2880 N/c
Explanation:
Given that:
Charge per unit length ; λ = 4 * 10^-9
radius, r = 10
Radius, R = 0.5m
Using the relation :
2λr / 4πE0R²
Columb's constant, k = 1/4πE0 =. 9* 10^9Nm²/C²
Hence, we have :
2λrk/ R²
(2 * 4 * 10^-9 * 10 * 9 * 10^9) / 0.5^2
(720 ÷ 0.25)
= 2880 N/c
Which of the following variables can be measured in joules?
A. momentum
B. Energy
C. Power
D. Work
Answer:
The variables that can be measured in joules are
B. Energy
D. Work
Hope it will help :)
Fusion probability is greatly enhanced when appropriate nuclei are brought close together, but mutual Coulomb repulsion must be overcome. This can be done using the kinetic energy of high-temperature gas ions or by accelerating the nuclei toward one another. Calculate the potential energy of two singly charged nuclei separated by 1.00 x 10-12 m by finding the voltage of one at that distance and multiplying by the charge of the other.
Answer:
the Potential Energy is 2.304 × 10⁻¹⁶ J
Explanation:
Given the data in the data in the question;
The expression for the electric potential energy between the charges can be expressed as follows;
PE = qV ------equ 1
where q is the charge and V is the electric potential
Also the formula for electric potential due to point a point in a field is;
V = kq / r -------equ 2
where k is the electrostatic constant and r is the distance form the charged particle
input equation 2 into 1
PE = q × kq / r
PE = kq²/r ------- equ 3
so we substitute into equation 3; 1.00×10⁻¹² for r, 9.00×10⁹ for k( constant ) and 1.60×10⁻¹⁹ for q( charge )
PE = ((9.00×10⁹) (1.60×10⁻¹⁹)²) / 1.00×10⁻¹²
PE = 2.304 × 10⁻²⁸ / 1.00×10⁻¹²
PE = 2.304 × 10⁻¹⁶ J
Therefore, the Potential Energy is 2.304 × 10⁻¹⁶ J
Steam at 6 MPa, 400C is flowing in a pipe. Connected to this pipe through a valve is a tank of volume 0.4 m 3 . This tank initially contains saturated water vapor at 0.1MPa. The valve is opened and the tank fills with steam until the pressure is 6MPa, and then the valve is closed. The process takes place adiabatically. Determine the temperature in the tank right as the valve is closed.
Answer:
2400°C
Explanation:
Volume of tank = 0.4 m^3
steam pressure = 6 Mpa
Steam temperature = 40°C
Initial pressure of tank = 0.1 MPa
Final pressure of Tank = 6 Mpa
Calculate the temperature in the tank when the Pressure in Tank = 6Mpa
since the volume of the Tank is constant = 0.4 m^3
we will apply Gay-Lussac's Law
= [tex]\frac{T1}{P1} = \frac{T2}{P2}[/tex] ------ ( 1 )
T1 = 40°c
P1 = 0.1 MPa
P2 = 6 Mpa
T2 = ?
From equation 1 above
T2 = ( T1 * P2 ) / P1
= ( 40 * 6 ) / 0.1
= 2400°C
how can you rewrite the force formula (f=ma) to solve the acceleration?
The force formula can be rewritten to solve the acceleration as:
acceleration = force/mass.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
From Newton's 2nd law of motion, we can write that:
Force = mass × acceleration
⇒ acceleration = force/mass.
Hence, the force formula can be rewritten to solve the acceleration as:
acceleration = force/mass.
Learn more about acceleration here:
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Two ice skaters approach each other at right angles. Skater A has a mass of 68.2 kg and travels in the x direction at 2.48 m/s. Skater B has a mass of 34.4 kg and is moving in the y direction at 1.18 m/s. They collide and cling together. Find the final speed of the couple. Answer in units of m/s.
Answer:
1.70 m/s
Explanation:
The computation of the final speed of the couple is shown below:
initial momentum of A is
= mv
= 68.2 × 2.48
= 169.136 kg
And, the initial momentum of B is
= mv
= 34.4 × 1.18
= 40.592 kg
Now magnitude is
= sqrt( A^2 + B^2)
= sqrt( 28,606.99 + 1,647.71)
= 173.94
Now the final speed is
= 173.94 ÷ (68.2 + 34.4)
= 1.70 m/s
Problem 2: Estimate the electric power requirement, in kW, of a 1,400 ft2floor area (three bedroomshome) with three occupants. Using your home power estimate, predict the power requirementsfor a city of 300,000 people. Use these results to estimate the area (inkm2)of silicon solar cells requiredto satisfy the community power requirements. Assume, thepower requirements for an average single family home of 3 are 108.4 x 106BTU per year and solar panels insolation
Answer:
a) 3170 kw
b) 377 km^2
Explanation:
Estimate of electric power
a) Given :
Average power consumption for a family of 3 = 108.4 * 106 BTU per year = 0.0317 kw = 31.7 watts
The power requirement for a city of 300000 people
= 31.7 watts * 100000 = 3170000 watts = 3170 kw
b) Given :
Average solar panel insulation = 8.4 W /m^2
Estimate the area of silicon solar cells required to satisfy community power requirement
= (1 * 3170) * (1000/8.4 )
= 377.380 * 10^3 m2 = 377 km^2
A hiker walks 11 km due north from camp and then turns and walks due east. The
total distance walked is 22 km. How far due east did the hiker walk?
Answer:
Thats probably 11
Explanation:
. Why is it harder to stop an elephant accelerating at 1m/s2 than a rabbit accelerating at 1m/s2
(10 Points)
the elephant has more mass
the rabbit is faster
the rabbit has more mass
the elephant is faster
Answer:
this is about momentum p=mv
A, the elephant has more mass
A 4-stroke heat engine in an automobile is
used to
A convert mechanical energy into heat
energy.
B convert heat energy into mechanical
energy.
с convert steam into solar energy.
D convert chemical energy into electrical
energy.
Answer:
b
Explanation:
convert heat energy into mechanical
Climbing a tree would
A. decrease your potential energy
B. increase your kinetic energy
C. increase your potential energy
Answer:
C Increase your potential energy
Explanation:
Because if you start falling your potential energy would convert to kinetic energy. So you would get potential energy climbing up a tree
Answer:
I think it's potential energy
Tasks
Task 2 - Compare and contrast the use of D'Alembert's principle with
the principle of conservation of energy to solve an
engineering problem
A motor vehicle having a mass of 800 kg is at rest on an incline of 1 in 8 when the
brakes are released. The vehicle travels 30 m down the incline against a constant
frictional resistance to motion of 100 N where it reaches the bottom of the slope.
a) Using the principle of conservation of energy, calculate the velocity of the
vehicle at the bottom of the incline.
b) Using an alternative method that does not involve a consideration of energy,
cacluate the velocity of the vehicle at the bottom of the incline.
c) Discuss the merits of the two methods you have used for parts a) and b) of
this question. Justify the use of an energy method for these types of
problems.
Answer:
NE DIYON INGILIZ MISIN SEN
4. John drives his car 5 miles north to visit his friend, and then drives 7 miles east to go to the store,
What is John's displacement? * 1
Answer:
John's displacement is 8.6 miles.
Explanation:
We need to fin the magnitude of the sum of the partial displacement. So we will have:
[tex]d=\sqrt{5^{2}+7^{2}}[/tex]
[tex]d=8.6\: miles[/tex]
I hope it helps you!
Substance X is in a chamber (Chamber 1) containing 10L of fluid. The concentration of substance X in this chamber is 100mmol/L. A solid division separates this chamber from another chamber (Chamber 2) containing 5L of fluid. You remove this division leaving only a membrane separating the two chambers. This membrane is permeable to Substance X and nothing else. Which of the following statements are true?There are several answers to this question, but only one is giving me issues. One of the correct answers is: "The concentration of Substance X in Chamber 2 will never exceed 66mmol/L." I do not understand how they got this as I did a ratio and came up with 50 mmol/L instead. Could someone please point out how it is 66?
Answer:
Explanation:
concentration of substance X in chamber 1 = 100 mmol/L
total volume of chamber 1 = 10 L
total mass of substance X in chamber 1 = 100 x 10 mmol = 1000 mmol .
When the two chamber is joined , total volume of both the chamber
= 10 L + 5 L = 15 L .
In the volume of 15 litre , substance x is uniformly distributed because it is permeable .
concentration of substance X = mass of X / total volume = 1000 mmol / 15
= 66.67 mmol / L
Hence ,
"The concentration of Substance X in Chamber 2 will never exceed 66mmol/L."
In order for the eye to see an object _____ from the object myst be reflected to your eye.
Light or particle ?
Answer: light from the object
Explanation:
When light is reflected off an object like a lamp or a door is travels in a straight line but in a new direction so if the light enters our eyes we will see the object because our eyes can detect light
Please help! This is due in 10 minutes
Answer:
Atom - the basic particle of matter
Density - calculated from measurements of mass and volume
Motion - calculated from measurements of distance and time
Energy - can change form and move matter
Matter - the scientific word for stuff
Hope this helps! Please mark brainliest if correct :D
A 70 kg Throckmorton was riding his skateboard when a small, but juicy 0.001 kg beetle hits the front of his helmet, splattering, obstructing his view. Who experienced the greatest change in momentum?
Answer:
The beetle
Explanation:
The beetle is correct because of the the force of the Throckmortan was a lot heavier and thus making the beetle feel the force.
Momentum before = momentum after
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(70.0 kg) (3.0 m/s) + (2.0 kg) (3.0 m/s) = (70.0 kg) (3.1 m/s) + (2.0 kg) v
210 kg m/s + 6 kg m/s = 217 kg m/s + (2.0 kg) v
-1 kg m/s = (2.0 kg) v
v = -0.5 m/s
The skateboard's velocity is 0.5 m/s west. Hope I helped and have a good day!
________________________________________________________
前の勢い=後の勢い
m₁u₁+m₂u₂=m₁v₁+m₂v₂
（70.0 kg）（3.0 m / s）+（2.0 kg）（3.0 m / s）=（70.0 kg）（3.1 m / s）+（2.0 kg）v
210 kg m / s + 6 kg m / s = 217 kg m / s +（2.0 kg）v
-1 kg m / s =（2.0 kg）v
v = -0.5 m / s
スケートボードの速度は西に0.5m / sです。私が助けて、良い一日を過ごせることを願っています！
A student claims an object in motion must experience a force to stay in motion. Do you agree or disagree?
Answer:
agree because there is always a force that causes motion..
Consider a stone in free fall on a planet with gravitational acceleration 3.4 m/s^2. Suppose you would like the stone to experience the same magnitude of acceleration down an inclined plane on Earth. Neglecting friction and air resistance, which angle should the inclined plane have with respect to the horizontal ? (in deg)
Answer:
Angle of incline is 20.2978°
Explanation:
Given that;
Gravitational acceleration on a planet a = 3.4 m/s²
Gravitational acceleration on Earth g = 9.8 m/s²
Angle of incline = ∅
Mass of the stone = m
Force on the stone along the incline will be;
F = mgSin∅
F = ma
The stone has the same acceleration as that of the gravitational acceleration on the planet.
so
ma = mgSin∅
a = gSin∅
Sin∅ = a / g
we substitute
Sin∅ = (3.4 m/s²) / (9.8 m/s²)
Sin∅ = 0.3469
∅ = Sin⁻¹( 0.3469 )
∅ = 20.2978°
Therefore, Angle of incline is 20.2978°
If a rock and a feather are dropped in a 98-meter-long tube in which there is a vacuum, which one will hit the bottom first?
The feather will hit the bottom first.
А
B
The rock will hit the bottom first
С
Both will hit at the same time
D
More information is needed
Answer:
C. Both will hit at the same time.
Explanation:
Gravity accelerates them both the same since the vacume has no other particles. Gravity pulls down at about 9.81 m/s/s on earth and since there are no air particles in a vacume, there is no air-resistance. Your final velocity can be found with the equation [tex]Vf=Vi+g*t[/tex]
Vf is final velocity and Vi is initial velocity. Them both accelerating at the same time with the same gravity means that the initial velocity will be the same for both and therfore so will the final velocity. All of that leads to them landing at the same time. This is all an assumption that they are being dropped from the same height.
Please correct me if I was wrong about anything said above.
Thanks!
If rock and a feather are dropped in a 98-meter-long tube in which there is a vacuum, Both will hit at the same time.
Why do objects fall at the same rate in a vacuum?If your heavy and light objects are in a vacuum, then they fall at the same speed. This is because they only have one force acting on them: gravity.
Which would fall with greater acceleration in a vacuum a leaf or a stone?Q. Which would fall with greater acceleration in a vacuum—a leaf or a stone. They would accelerate at the same rate.
Learn more about vacuum at
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PLS HELP In which situation is work being done? (Check all that apply.) Your answer:
A boy coasting down the sidewalk on a skateboard.
Lifting your binder out of your backpack into your top row locker.
Pushing a shopping cart down the aisle at Publix.
Pushing on a broken down car but it doesn’t move.
The legs on your science table holding up the table top.
Carrying a heavy backpack down the hall.
Answer:
Lifting your binder out of your backpack into your top row locker.
Pushing a shopping cart down the aisle at Publix
Explanation:
These are the only two in which an object is moving because of an applied force
If an ocean wave has a wavelength of 2 m and a frequency of 1 wave/s, then its speed is m/s Enter the answer Check it CRATCHPAD Improve this questic 트
Answer:
2m/s
Explanation:
v=f×wavelength
v=2×1
=2m/s
Help please ! Ill give brainliest !! ☁️✨
After watching this video, Blake, a student in an introductory physics class, makes the following claim: The acceleration and velocity of the glider are both momentarily zero when the glider changes direction. The velocity of the glider must be zero for an instant when the glider changes direction. Because the velocity is zero, the acceleration must also be zero. 1. Respond to Blake's claim. Which parts, if any do you agree with, and which parts do you not agree with
Answer:
Please see below as the answer is self- explanatory.
Explanation:
Any time that an object changes direction (from leftward to rightwward, or from upward to downward) the velocity must be zero just for one instant, when is on the verge of changing the direction.This is needed because velocity changes as a continuous function of time, so it needs to cross the t-axis when passing from positive to negative or vice versa.However, the claim that in the moment that velocity is zero, the acceleration is also zero, is false.Due to acceleration is the rate of change of velocity, and velocity is a vector, this means at any time there is a change of direction, there is an acceleration that is non-zero.For example, when an object that has been thrown upward, reaches to its maximum height, just one instant before starting to fall, the velocity becomes zero, but the acceleration (which causes the object to fall) is non-zero, due to it's the acceleration due to gravity.how can you decrease the numbers
of calories you consume
Answer: by eating less of the recommendEd servings
Explanation:
A car starts from rest and accelerates uniformly at a rate of 2.0 meter per second squared for 4.0 seconds. During this time interval, the car traveled ________ meters.
Answer:
16
Explanation:
[tex] \frac{1}{2} \times 2 \times {4}^{2} = 16[/tex]
If someone walkes 1000m
in 20min, what is their speed?
Answer:
Distance - 1000m
Time - 20min
Speed - ?
Use the formula of distance ÷ time = speed.
s = d/t
s = 1000m/20min
s = 50 m/min
Hope this helps, thank you !!
A box of bananas weighing 51.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.46 and the coefficient of kinetic friction is 0.23. Part A If no horizontal force is applied to the box and the box is at rest, how large is the frictional force exerted on the box by the surface
static friction force = The coefficient of static friction * normal force
static friction force = 0.46 * 51 = 23.46 N
kinetic friction force = The coefficient of kinetic friction * normal force
kinetic friction force = 0.23 * 51 = 11.73 N
the applied force acting on the object must be more than 23.5 N if the object was stationary to move it and must be more than 11.7 N during the movement to keep the object moving
which newton's laws applies to a slinky?
PLEASE HELP !!
When a Slinky sits atop a staircase, gravity acts on the toy, keeping it still. Knock over the Slinky, and Newton's second law comes into play. As middle school physics class may have taught you, this law states that providing force to an object increases its acceleration.
hopes this helps uh ❣
Answer:
We know from Newton's First Law of motion that an object at rest stays at rest unless acted upon by an external force. So in the case of the slinky, that is exactly why the bottom of the slinky does not move.
Explanation:
) A 73-mH solenoid inductor is wound on a form that is 0.80 m long and 0.10 m in diameter. A coil having a resistance of is tightly wound around the solenoid at its center. The mutual inductance of the coil and solenoid is At a given instant, the current in the solenoid is and is decreasing at the rate of At the given instant, what is the induced current in the coil
Complete question is;. A 73mH solenoid inductor is wound on a form that is 0.80m long and 0.10m in diameter a coil having a resistance of 7.7 ohms is tightly wound around the solenoid at its center the mutual inductance of the coil and solenoid is 19μH at a given instant the current in the solenoid is 820mA and is decreasing at the rate of 2.5A/s at the given instant what is the induced current in the coil
Answer:
6.169 μA
Explanation:
Formula for induced EMF is given by the equation;
EMF = M(di/dt). We are given;
di/dt = 2.5 A/s
M = 19μH = 19 × 10^(-6) H
Thus;
EMF = 19 × 10^(-6) × 2.5.
EMF = 47.5 × 10^(-6) V
Formula for current is;
i = EMF/R. R is resistance given as 7.7 ohms.
Thus; i = 47.5 × 10^(-6)/7.7
i = 6.169 μA
What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 640 N/C
Answer:
[tex]q=-2.26\times 10^{-5}\ C[/tex]
Explanation:
Given that,
The mass of a particle, m = 1.48 g = 0.00148 kg
The electric field, E = 640 N/C
We need to find the charge of the particle when placed in a downward-directed electric field.
The force of gravity is balanced by the electric force such that,
mg = qE
Where
q is the charge of the particle
[tex]q=\dfrac{mg}{E}\\\\q=\dfrac{0.00148\times 9.8}{640}\\\\q=2.26\times 10^{-5}\ C[/tex]
q must be negative, the force must be upward (opposite direction of the electric field).
