There are 20 questions on a test. Three points are awarded for a correct answer and – 1 for an incorrect answer. If Brian answered 14 questions correctly and 6 incorrectly, what is his score?

Answer:

y = 30

Step-by-step explanation:

Substitute x = 5 into the equation and solve for y

4(5) - y = - 10

20 - y = - 10 ( subtract 20 from both sides )

- y = - 30 ( multiply both sides by - 1 )

y = 30

Then (5, 30 ) is a solution of the equation

Answer:

q = -4   q=2

Step-by-step explanation:

q²+2q-8=0​

Factor

What 2 numbers multiply to -8 and add to 2

4*-2 = -8

4-2 = 2

(q+4)(q-2) =0

Using the zero product property

q+4 = 0  q-2 =0

q = -4   q=2

Answer:

19 is the answer i think.

Answer:

192

Step-by-step explanation:

According to Euclidian theorem

x^2 = 144*(400-144)

x^2 = 144*256

x^2 = 36864 find the root of both

x = 192

Answer:

2688 cm³

Step-by-step explanation:

2058×704/539 = 2688 cm³

Answer:

4 TOPPING WITH 5 CENTS LEFT

Step-by-step explanation:

A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so

3.5-0.75=2.75 (1 topping

2.75-0.75=2 (2 topping

2-0.75=1.25 (3 topping

1.25-0.75=0.5 (4 topping

there for you can get 4 toppings with 5 cents left over

Answer:

.

.

.❥︎ᴀᴀɴᴋʜ ᴜᴛʜɪ ᴍᴏʜᴀʙʙᴀᴛ ɴᴇ ᴀɴɢᴅᴀɪ ʟɪ ,

.ᴅɪʟ ᴋᴀ sᴀᴜᴅᴀ ʜᴜᴀ ᴄʜᴀɴᴅɴɪ ʀᴀᴀᴛ ᴍᴇ ❣︎

.

.

Answer:

you would receive 12.5% of the discount

Step-by-step explanation:

20% off of 62.50 is 50; so you would pay $50

Tan=24/10 ≈ 2.4

using Pythagoras theorem

x²=(24)²+(10)²

x²=576+100

x²=57600

x=√57600 => 240

Therefore

sina=24/240 => 0.1

cota=1/tana => 1/(24/10) => 10/24

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]

Answer/Step-by-step explanation:

✔️Volume of right cylinder = πr²h

Where,

π = 3.14

radius (r) = 4 cm

height (h) = 3 cm

Plug in the values into the formula

Volume of cylinder = 3.14*4²*3

= 150.72 cu cm

✔️Volume of cone = ⅓πr²h

Where,

π = 3.14

radius (r) = 5 cm

height (h) = 12 cm

Plug in the values into the formula

Volume of cylinder = ⅓*3.14*5²*12

= 314 cu cm

✔️Volume of pyramid = ⅓*Bh

Where,

Base area (B) = 16 cm²

height (h) = 30 cm

Substitute

Volume of pyramid = ⅓*16*30

= 160 cu cm

✔️Volume of square pyramid = ⅓*s²*h

Where,

Length of square base (s) = 3 cm

Height (h) = 16 cm

Substitute

Volume of square pyramid = ⅓*3²*16

= 48 cu cm

Answer:

X=

Step-by-step explanation:

x-1= 4x+3x+x-8

x-1 = 8x-8

shift places

8-1= 8x-x

7x = 7

X=7/7

X=1

I think so

please mark this answer as brainlist

Answer: x = 52

Step-by-step explanation:

You'd first deal with the 4 outside the parentheses, multiplying 10x-20 by 4. This would result in 40x - 80 = 200.

You'd then further isolate x, adding 80 on both sides, resulting in 40x = 2080. Divide by 40 on both sides and You'd get your answer of x = 52.

The sides of the image and pre-image are congruent

Each point has moved the same number of units

Answer:

-9.705

Step-by-step explanation:

f-g+(-2)

Let  f = -3.005 and g = 4.7

-3.005 -4.7 -2

-9.705

Answer:

12 lemons

Step-by-step explanation:

CP of 15 lemon = ₹ 1

Profit = 25 %

SP of 15 lemons = [tex]\frac{100+profit}{100}*CP[/tex]

    [tex]= \frac{125}{100}*1\\\\= \frac{5}{4}[/tex]

SP of 15 lemons =  ₹  [tex]\frac{5}{4}[/tex]

Number of lemon for  ₹  [tex]\frac{5}{4}[/tex]  = 15

Number of lemons for  ₹  1 = 15 ÷ [tex]\frac{5}{4}[/tex]

                                            [tex]= 15 *\frac{4}{5}\\\\= 3*4\\\\= 12[/tex]

Answer:

37degrees

Step-by-step explanation:

In order to get the required angle, we will use the SOH, CAH, TOA identity.

Let;

Adjacent = 60m

Opposite = 45m

According to TOA:

tan theta = opp/adj

tan theta = 45/60

tan theta = 0.75

theta = arctan 0.75

theta =  36.86

Hence the  angle, to the  nearest degree, between her path and the longest side of the playground is 37degrees

Answer:

answer to that is A 1.75 per pint

Answer:

b the answer

Step-by-step explanation:

Answer:

50.24

Step-by-step explanation:

A = Area

Radius = 4 (The radius is half of the diameter

Diameter = 8

Pie = 3.14

A = (pie)r^2

A = (3.14)4^2

A = (3.14)16

A = 50.24

Answer:

a) 3.5 cm / month

b y = 3.5(x-1) + 4, x >= 1

Step-by-step explanation:

the plant grew 32-4 = 28 cm in 9-1 = 8 months.

so, the growth rate is 28 cm / 8 months = 7 cm / 2 months, or (to norm it to a typical 1 unit denominator) 3.5 cm per month.

x = months of growth

y = height of plant

so, considering the "start" of 4 cm after one month, the equation is

y = 3.5(x-1) + 4, x >= 1

since we don't know anything about anything that happened before the first month was over, we cannot validate this equation for anything x<1.

Answer:

m = 36

Step-by-step explanation:

A^2 + B^2 =  C^2

81 +  144 = 225

square root of 225 =  15

n = 15

m = ?

39 = 39

225  + m ^2 = 1521

m^2 = 1296

m = 36.

CHECK :

225 + 1296 =  1521

CORRECT!

Answer:

[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]

By expanding the expression, we get;

[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]

Collecting like terms gives;

[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

(b) The given expression is presented as follows;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]

Therefore, we get;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]

Collecting like terms gives;

[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]

[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Answer:

C

Step-by-step explanation:

We are given that:

[tex]\displaystyle \sin y^\circ = \frac{s}{8}\text{ and } \tan y^\circ = \frac{s}{t}[/tex]

And we want to find the value of:

[tex]\displaystyle \sec y^\circ[/tex]

Recall that tan(θ) = sin(θ) / cos(θ). Since sec(θ) = 1 / cos(θ), tan(θ) = sin(θ)sec(θ). Substitute:

[tex]\displaystyle \sin y^\circ \sec y^\circ = \frac{s}{t}[/tex]

Substitute:

[tex]\displaystyle \frac{s}{8}\sec y^\circ =\frac{s}{t}[/tex]

Solve for secant:

[tex]\displaystyle \sec y^\circ = \frac{8}{t}[/tex]

Hence, our answer is C.

Answer:

c. sec y° = 8/t

Step-by-step explanation:

I took the test

Step-by-step explanation:

Against the wind, the wind works against the speed. With the wind, the wind aids the speed.

4(p - w) = 2416

4(p + w) = 2896

p - w = 604

p + w = 724

2p = 1328

p = 664 mph

664 + w = 724

w = 60 mph

Answer:

0.92 to nearest 100th.

Step-by-step explanation:

cos T  = adjacent side / hypotenuse

= 12/13

= 0.9231