The reaction A→B is to be carried out isothermally in a continuous-flow reactor. Calculate the PFR volume to consume 99% of A (CA = 0.01CA0) when the entering molar flow rate is 5 mol/h (assume pure A), the volumetric flow rate is constant at 10 dm3 /h and the rate is: -rA=3CA 2 [ dm3 /mol•h]

Answers

Answer 1

Answer:

Explanation:

From the information above:

The equation for the reactor volume of CSTR is given by the formula:

[tex]V = \dfrac{C_{Ao}V_o - C_A V_o }{-rA}[/tex]

[tex]V = \dfrac{C_{Ao}V_o (1 - 0.01)}{KC_A^2}[/tex]

The reaction rate of A is:

[tex]-r_A = kC_A^2[/tex] and k = 3 dm³/mol.h

replacing the values in the above equation to solve for v;

[tex]V = \dfrac{(0.5 \ mol/dm^3) (10 \ dm^3/h) (1 - 0.01)}{ ( 3 \ dm^3/mol.h) (0.01 \times 0.5 \ mol/dm^3)^2}[/tex]

V = 66,000 dm³

Thus, the reactor volume of CSTR is 66000 dm³

Taking the differential mole balance equation for PFR is as follows:

[tex]\dfrac{d(C_AV_o)}{dV} = -r_A[/tex]

[tex]\dfrac{d(C_AV_o)}{dV} = Kc^2A[/tex]

Taking the integral between initial and final concentrations;

[tex]\dfrac{v_o}{k} \int ^{C_A}_{C_{Ao}} \dfrac{dC_A}{C^2A}= - \int ^V_o \ dV[/tex]

[tex]V = \dfrac{V_o}{K} \Big [\dfrac{1}{C_A}- \dfrac{1}{C_{Ao}} \Big ][/tex]

replace the values in the above equation;

[tex]V= \dfrac{(10 \ dm^3/h) }{(3 \ dm^3/mol.h)}\Big [ \dfrac{1}{0.01(0.5 \ mol/dm^3)} - \dfrac{1}{0.5 \ mol/dm^3} \Big ][/tex]

[tex]\mathbf{V = 66 0 \ dm^3}[/tex]

Thus, the reactor volume of PFR is 660 dm³


Related Questions

If you were to burn a candle inside of a closed jar and the mass of the
closed jar and candle was 50 grams to begin with, what would the mass of
the jar and smoke be after the candle is done burning?

Answers

Answer:

50g

Explanation:

At the end of the burning process, the mass of the jar and smoke should be 50g after the candle burning is done.

In most systems, the law of conservation of matter finds expression. According to this law "matter is neither created nor destroyed but atoms are rearranged".

In this kind of system, no matter is allowed to escaped and the starting mass of the reactants compared to that of the product will be the same.

Convert 8.876 × 10^12 m^2 to units of km^2.

Answers

Answer:

[tex]8.876\times 10^{18}\ km^2[/tex]

Explanation:

In this problem, we need to convert [tex]8.876 \times 10^{12}\ m^2[/tex] to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

[tex]8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2[/tex]

So, [tex]8.876 \times 10^{12}\ m^2[/tex] is equal to [tex]8.876\times 10^{18}\ km^2[/tex].

How many elements are present in the compound RbMnO4?

Answers

3 elements

Rubidium
Manganese
Oxygen

Hope this helped☺️

Sound waves are longitudinal, mechanical, compression waves.
A. True
B. False

Answers

Answer:

True

Explanation:

Sound waves traveling through air are indeed longitudinal waves with compressions and rarefactions. As sound passes through air (or any fluid medium), the particles of air do not vibrate in a transverse manner.

Answer:

true

Explanation:

ape x

How to get the density of this unknown liquid?

Answers

Answer:

Measure the volume of water poured into a graduated cylinder, then place the object in the water and remeasure the volume. The difference between the two volume measurements is the volume of the object. Now simply divide the mass by the volume to calculate the density of the object.

Helppppp pleaseeee xxxxxx

Answers

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

Disaccharides are held together by a glycosidic bond. Hydrolysis of the disaccharide requires_____

Answers

Answer:

monosaccharides and glycosidic, I think

Explanation:

Answer:

pasagottt po plss

Explanation:

edi wow

What is the concentration of lithium ions in 0.400 M Li₂HPO₄?

Answers

Answer: 0.800 M

Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.

I'm bad at explaining it, but got it right on chem101 sooo

The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.

The concentration of a substance is simply the amount of the substance in 1 L of water.

To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:

Li₂HPO₄ (aq) <=> 2Li⁺(aq) + HPO₄²¯(aq)

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.

Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 mole of Li⁺.

Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺

Thus, 0.8 M lithium ion, Li⁺ is present in the solution.

Learn more: https://brainly.com/question/19536817

Convert 3.93 x 10-22 grams of X4Z3 into molecules/formula units of the same compound. (Assume that the molar mass of X is 59.45 grams per mole and the molar mass of Z is 13.84 grams per mole.)

Assume that Avogadro's number is 6.022 x 1023. Report your answer to three decimal places.

Answers

Answer:

0.847 molecule.

Explanation:

From the question given above, the following data were obtained:

Mass of X₄Z₃ = 3.93×10¯²² g

Number of molecules of X₄Z₃ =?

Avogadro's number = 6.022×10²³ molecules

Next, we shall determine the molar mass of X₄Z₃. This can be obtained as follow:

Molar mass of X₄Z₃ = (4×59.45) + (3×13.84)

= 237.8 + 41.52

= 279.32 g/mol

Finally, we shall determine the number of molecules in 3.93×10¯²² g of X₄Z₃. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of X₄Z₃ = 6.022×10²³ molecules

But 1 mole of X₄Z₃ = 279.32 g

Thus we can say that:

279.32 g = 6.022×10²³ molecules

Therefore,

3.93×10¯²² g = 3.93×10¯²² × 6.022×10²³ / 279.32

3.93×10¯²² g = 0.847 molecule.

Thus, 3.93×10¯²² g of X₄Z₃ contains 0.847 molecule.

Which bond would require more energy to break apart? (Short bond or Long bond). Explain
a) longer bond. because the charges are further apart
b) shorter bond. because the charges are closer together
c) shorter bond. because the charges are both positive
d) longer bond. because the charges are closer together

Answers

Answer:

shorter bond, because charges are close apart

Explanation:

shorter the bond length more is the energy required to break the bond for example if you take three pencils of different sizes one longer One medium sized One Shot sized if you try to break them the longer pencil will break much faster than the other two because the greater the length the lesser the strength the lesser energy you need to apply to break them apart ...

hope you understand

PLZZZ help asaap plzzz I give brainliest are the following reactions a SYNTHESIS, DECOMPOSITION, COMBUSTION, SINGLE REPLACEMENT or DOUBLE REPLACEMENT reactions?
N2 (g) + 3 H2 (g)→ 2NH3 (l) ______________

2 H2(g) + O2(g--> 2 H2O(g)

Answers

Answer:

Synthesis

Explanation:

Two reactants are becoming one product, so it is a synthesis reaction.

Decomposition is the opposite, so when one molecule becomes simpler atoms.

Example: 2NaCl -> Cl2 + Na

Combustion is reaction with a product of water and carbon dioxide.

Example: CH4 + 2O2 -> CO2 + 2H2O

Single displacement is when one atom takes the place of the other.

Example: K + NaCl -> KCl +Na (where K took the place of Na)

Double displacement is like single displacement but it happens twice. Think of it like the atoms exchanging partners.  

Example: HCl +NaH -> NaCl + HOH

Answer:

(i) N2(g)+3H2(g) -->2NH3(g) - When the equilibrium changes, the concentrations of all substances involved in the equilibrium must also change. For our equilibrium reaction: N2(g) + 3H2(g) ⇔ 2NH3(g) + Heat

(ii) 2 H2(g) + O2(g) --> 2 H2O(g) - Synthesis Reaction

HENCE BOTH THE REACTIONS COULD BE CLASSIFIED AS SYNTHEYIC REACTION

PLEASE DO MARK MY ANSWER AS THE BRAINLIEST..

<HOPE IT HELPS>

The Chinese first began recording astronomical observations about 2,000 years ago.


True
False

Answers

The answer is false

3. Match each of the following descriptions with one of the beakers in Model 1. In each case, assume the change in volume as the solid(s) are added is minimal. a. A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of water in beaker . b. A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.500 M sodium hydroxide solution in beaker . c. A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M sodium hydroxide solution in beaker . d. A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M calcium nitrate solution in beaker . 4. Based on the solubility product constant, Ksp, for calcium hydroxide given in Model 1, do you expect most of the 1.00 mole sample of solid to dissolve in any of the four beakers

Answers

Answer:

Explanation:

When calcium hydroxide is dissolved in water , it ionizes as follows .

Ca( OH)₂ = Ca⁺² + 2 OH ⁻

When it is dissolved in water which contains minimal OH⁻ , so there is almost no common ion effect . Hence calcium hydroxide is fully dissolved in pure water solvent .

When 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.500 M sodium hydroxide solution in beaker , it is not fully dissolved due to common ion of hydroxide ion ( OH⁻ )

NaOH = Na⁺ + OH⁻

OH⁻ ion from NaOH , suppresses the dissolution of calcium hydroxide .

Similarly

When A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M sodium hydroxide solution in beaker , it is not fully dissolved due to common ion of hydroxide ion ( OH⁻ )  

NaOH = Na⁺ + OH⁻

OH⁻ ion from NaOH , suppresses the dissolution of calcium hydroxide

When 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M calcium nitrate solution , it is not fully dissolved due to common ion of calcium  ion ( Ca⁺² )

Ca( NO₃)₂ = Ca⁺² + 2NO₃⁻

Ca⁺²  ion from Ca( NO₃)₂ , suppresses the dissolution of calcium hydroxide .

How are the cells made by meiosis different from the original parent cell that
produced them?

Answers

Mitosis creates two identical daughter cells that each contain the same number of chromosomes as their parent cell. In contrast, meiosis gives rise to four unique daughter cells, each of which has half the number of chromosomes as the parent cell.

A given compound has the following solubility properties. At room temperature, it is soluble in diethyl ether but insoluble in both ethanol and water. At higher temperatures, it is soluble in both diethyl ether and ethanol, but insoluble in water. Propose a procedure for purifying this compound by recrystallization.

Answers

Answer:

See explanation

Explanation:

If we desire to recrystallize the given compound then we must do the following;

1) Add the compound to ethanol and heat the system

2) As the solute dissolves, the solution is allowed to cool

3) The solution may be seeded or the vessel scratched to aid crystallization.

4) The pure crystals are now filtered out, washed and dried.

Remember that recrystallization has to do with dissolving a solute in a solvent in which it is only soluble at high temperature but insoluble at low temperature.

The solvent dissolves the impure solute while pure crystals emerges as the temperature decreases.

I need help with the bottom two pls The first answer I will mark brainliest

Answers

Answer:

I dunno,  what is the answer

Explanation:

52
p3
N?
Br1
CaBr2
Cas
Ca3P2
Cal2
Ca3N2
Cat2
K1
Mg2
Zn2
Fe3

Answers

I’m not sure what you are asking sorry.

What is made when a salt is dissolved in water?

Answers

Answer:

water

Explanation:

the salt dissapears and turns

into vapor

Answer:

A solution is made when a solid (which we call a solute) dissolves into a liquid (that we call the solvent) one example of a solution is salt dissolved in water. The salt and water can be separated again by evaporation (the water will evaporate if left in a got place leaving the salt behind. I don't know if that was the answer that you were looking for

Which of the following is an example of a physical change, but not a chemical change?

Answers

Answer:

Boiling Water

Explanation:

Boiling water is an example of physical change and not and not a chemical change because the water vapor still has the same molecular structure as liquid water.If the bubbles were caused by the decomposition of a molecule into gas then boiling would be a chemical change.

Answer:

A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity. Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding

Explanation:

Deforestation happens when people try to provide more:
a) water
b) waste
c) timber
d) oxygen.​

Answers

C! Timber, deforestation happens when trees are being removed! :)

1. Imagine that you need to take a medicine that the doctor has prescribed for
you. Explain why scientists who developed that medicine would need to know
whether or not the compound in that medicine is polar. How might a polar
medicine behave differently as it dissolved in the body than a nonpolar medicine
would? Answer in 1 to 2 paragraphs. (10 points) Think about how polar and
nonpolar compounds might behave differently in the watery environment of your
stomach or bloodstream

Answers

Answer: Only non-polar medicines can diffuse across the membrane. non-polar drugs are lipid soluble, while polar drugs are water soluble, so polar drugs cant absorb through biological membranes.


Determine the the nuclei indicated in blanks in the
right side when Radium (Ra-226) undergoes an
alpha decay
Ne
226/ 88
Ra -->
+

Answers

The daughter isotope  : Radon-222 (Rn-222).

Further explanation

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

alpha α particles ₂He⁴ beta β ₋₁e⁰ particles gamma particles ₀γ⁰ positron particles ₁e⁰ neutron ₀n¹

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

A reversible reaction is said to have reached equilibrium when which of the following conditions is established?

Answers

The given question is incomplete. The complete question is:

A reversible reaction is said to have reached equilibrium when which of the following conditions is established?

a. concentration of reactants and products are equal

b. opposing reactions cease

c. speeds of opposite reactions become equal

d. temperature of opposite reactions become equal

Answer: c. speeds of opposite reactions become equal

Explanation:

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.The state of equilibrium refers to the dynamic state as both forward and backwad reactions continue.

For a chemical equilibrium reaction, equilibrium state is achieved when the rate of forward reaction becomes equals to rate of the backward reaction.

Thus at chemical equilibrium, the amount of product and reactant remains constant because the rates of the forward and reverse reactions are equal.

2. What is the final temperature when a 32.0 g piece of diamond at 33.5°C is heated with 360 J of energy?
(Cp = 0.509

Answers

Answer:

55.6 °C

Explanation:

From the question given above, the following data were obtained:

Mass (M) of diamond = 32.0 g

Initial temperature (T₁) = 33.5°C

Heat (Q) required = 360 J

Specific heat capacity (C) of diamond = 0.509 J/gºC

Final temperature (T₂) =?

Next, we shall determine the change in temperature. This can be obtained as follow:

The final temperature can be obtained as follow:

Mass (M) of diamond = 32.0 g

Heat (Q) required = 360 J

Specific heat capacity (C) of diamond = 0.509 J/gºC

Change in temperature (ΔT ) =?

Q = MCΔT

360 = 32 × 0.509 × ΔT

360 = 16.288 × ΔT

Divide both side by 16.288

ΔT = 360 / 16.288

ΔT = 22.1 °C

Finally, we shall determine the final temperature. This can be obtained as follow:

Initial temperature (T₁) = 33.5°C

Change in temperature (ΔT ) = 22.1 °C

Final temperature (T₂) =?

ΔT = T₂ – T₁

22.1 = T₂ – 33.5

Collect like terms

22.1 + 33.5 = T₂

T₂ = 55.6 °C

Therefore, the final temperature is 55.6 °C.

47.4 grams of calcium carbonate (CaCO3) is dissolved in 450 mL of water. What is the molarity of this aqueous solution?

Answers

Answer:

[tex]M=1.05M[/tex]

Explanation:

Hello!

In this case, since the formula for the calculation of molarity is defined in terms of moles and volume in liters as shown below:

[tex]M=\frac{n}{V}[/tex]

Whereas the moles are computed by considering the molar mass of CaCO3 (100.09 g/mol):

[tex]n=47.4g*\frac{1mol}{100.09g}=0.4736mol[/tex]

Thus, we obtain:

[tex]M=\frac{0.4736mol}{0.450L}\\\\M=1.05M[/tex]

Best regards!

Consider a reaction that connects the ends of a chain of carbons to form a ring. The closure of the ring results in the formation of a new chemical bond, with the bonding electrons going into a bonding sigma molecular orbital at a lower energy. Which of the following statements correctly describes the resulting enthalpy, entropy, and heat changes? Mark all that are correct.
A. The entropy of the surroundings decreases (AS surr < 0) because the closure of the ring results in fewer conformations for the system.
B. The system releases energy to the environment, because its internal energy decreases.
C. The entropy of the surroundings increases (AS surr > 0) because the surroundings absorb heat released by the reaction, and become more disordered.
D. The entropy of the system decreases (AS sys < 0) because the closure of the ring reduces the number of conformations the ring can adopt.
E. The enthalpy or internal energy of the system decreases (AH sys < 0) because the electrons that form the bond enter an orbital that is at a lower energy.

Answers

Answer:

The system releases energy to the environment, because its internal energy decreases.

The entropy of the surroundings increases (AS surr > 0) because the surroundings absorb heat released by the reaction, and become more disordered.

The entropy of the system decreases (AS sys < 0) because the closure of the ring reduces the number of conformations the ring can adopt.

The enthalpy or internal energy of the system decreases (AH sys < 0) because the electrons that form the bond enter an orbital that is at a lower energy.

Explanation:

Now we know that when a reaction is exothermic heat is given off. In this case, we have a reaction that connects the ends of a chain of carbons to form a ring.  The bonding electrons now move into a lower energy bonding sigma molecular orbital.

This leads to a decrease in the entropy and enthalpy of the system because energy is given off, the closure of the ring reduces the number of conformations the ring can adopt and  the electrons that form the bond enter an orbital that is at a lower energy.

The entropy of the surroundings is increased as energy is given out. The surroundings absorb heat released by the reaction, and become more disordered.

1. Which list of nuclear emissions is arranged in order from the least penetrating power to
the greatest penetrating power?
A) alpha particle, beta particle, gamma ray
B) alpha particle, gamma ray, beta particle
C) gamma ray, beta particle, alpha particle
D) beta particle, alpha particle, gamma ray

Answers

Answer:

A) alpha particle, beta particle, gamma ray

Explanation:

Alpha beta and gamma radiations are the examples of ionizing radiations. When an atom is an excited state and having high energy, the atom is in unstable state. The excess of energy is released by the atom to get the stability. The released energy is in the form of radiations which may include alpha, beta, gamma, X-ray etc.

Properties of alpha radiation:  

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

Beta radiations:  

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminum is used to block the beta radiation

⁴₆C → ¹⁴₇N + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.  

Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

Sound waves travel better through solid than through a gas. Example why this is true​

Answers

Answer:

This is because molecules in a solid are packed against each other. When a vibration begins, the molecules of a solid immediately collide and the compression wave travels rapidly.

Explanation:

3. Determine the [OH-] and pH of a solution that is [H3O+] = 3.7x10-2 M.

Answers

[OH⁻]= 2.7 x 10⁻¹³

pH = 1.431

Further explanation

Given

[H3O+] = 3.7x10⁻² M.

Required

the [OH-] and pH

Solution

pH = - log [H⁺]

pH = 2 - log 3.7

pH = 1.431

pOH = 14 - 1.431

pOH = 12.569

pOH = - log [OH⁻]

[OH⁻]= 2.7 x 10⁻¹³

or

[OH-][H3O+]=10⁻¹⁴

[OH-]=10⁻¹⁴ : 3.7 x 10⁻²

[OH-] = 2.7 x 10⁻¹³

2. Methyl dichloroacetate (Cl2CHCO2CH3) decays into methanol (CH3OH) and dichloroacetic acid (Cl2CHCO2H) on reaction with water. Given a rate constant of 2.7 x 10-4/sec and an initial concentration of 1-ppm methyl dichloroacetate in the water, how much methanol will be present in the water after 30 min

Answers

Answer:

2.69 * 10^-6 Mol/L

Explanation:

The equation of the reaction is;

Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH

To convert from ppm concentration to Mol/L, we have

M = ppm/MM * 1000

Where;

M = mol/l

MM= Molar mass

M = 1/142.97 g/mol * 1000 =

M= 6.99 * 10^-6 Mol/L

For first order reaction;

ln[A] = ln[A]o -kt

Given that

[A]o = 6.99 * 10^-6 Mol/L

[A]=??

k= 2.7 x 10-4/sec

t= 30 mins * 60 = 1800 s

ln[A] = ln[6.99 * 10^-6] -   (2.7 x 10-4 * 1800)

ln[A] = -11.87 - 0.486

ln[A] = -12.356

[A] = e^(-12.356)

[A] = 4.3 * 10^-6 Mol/L

Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L

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