The price of a litre of milk increased from $1.25 in 2004 to $1.35 in 2006. What is the average price increase per year?

Answer:

16p - 2

Step-by-step explanation:

Answer:

20p - 2

Step-by-step explanation:

To find a perimeter, you take the values of each side and add them together.

[tex](p-8)+(9p-7)+(p-8)+(9p-7)[/tex]

[tex]p+9p+9p+p-8+7-8+7[/tex]

[tex]20p-8+7-8+7[/tex]

[tex]20p-2[/tex]

Answer:

2 miles per hour

Step-by-step explanation:

To find her walking pace in 'miles per hour' we need to divide the distance (in miles) by the time (in hours).

Speed = Distance/ Time

The time is given in minutes , but 50 minutes = 50/60 hours

=5/6 hours

1 2/3 ÷ 5/6

=5/3 × 6/5 miles per hour

Now cut it

= 2 miles per hour

Answer:

sqrt(3) + sqrt(7)

Step-by-step explanation:

3*sqrt(7) / sqrt(21) = 3/sqrt(3)

If you rationalize the denominator, you get 3*sqrt(3)/3. The threes cancel

You are left with sqrt(3)

7sqrt(3)/sqrt(21) = 7 / sqrt(7)

If you rationalize the denominator, you get

7  sqrt(7)/ 7 = sqrt(7)

The 7s have been canceled out

The answer is

sqrt(3) + sqrt(7)

Answer:

x = 17

Step-by-step explanation:

x ^2 = 8^2+ 15^2

√x^2 =√64+225

x=17

Answer:

17cm.

Step-by-step explaination:

The given triangle is a right angled triangle.

Using Pythagorean Theorem,

a² + b² = c²

Putting the given values in the equation;

(15)² + (8)² = c²

225 + 64 = c²

289 = c²

17² = c² (square root of 289 = 17)

17 = c

c = 17

Therefore, the missing side of the triangle is equal to 17 cm.

Answer:

[tex]x = - 8[/tex]

Step-by-step explanation:

First,Step write the given equation.

[tex] \frac{x}{2} + 7 = 3[/tex]

In Algebra, we learn how to solve for a missing term called a variable. We must use inverse operations to undo terms to isolate our variable. Inverse operations means that we do the opposite of the given.

For example, say we have a equation

[tex]x + 2 = 3[/tex]

We would subtract 2 from both sides. E.g( remember the golden rule of algebra). What we do to one side, we do the other. This applies when we solving for a variable.

This means that

[tex]x = 1[/tex]

And if we substitute 1 in for x, it is indeed true.

[tex]1 + 2 = 3 = 3[/tex]

Now, back to the question.

[tex] \frac{x}{2} + 7 = 3[/tex]

First, we subtract 7 from both sides to get rid of the 7 on the left side. Also remeber to undo terms that aren't included in the variable when solving these problems.

So now we got

[tex] \frac{x}{2} = - 4[/tex]

Then we multiply 2 by both sides since that the opposite of division.

[tex] \frac{x}{2} \times 2 = x = -4 \times 2 = - 8[/tex]

So this means that

[tex]x = - 8[/tex]

If we plug this in, this is true.

[tex] \frac{ - 8}{2} + 7 = 3[/tex]

These angles are corresponding angles, and we know that corresponding angles are equal when a transversal intersects two parallel lines.

So,

8x - 12 = 6x + 8

=> 8x - 6x = 8 + 12

=> 2x = 20

=> x = 20/2

=> x = 10

So, the value of x is 10.

please mark this answer as brainlist

Answer

15x^4+2x^3+8x^2-15

Answer:

15^4+2^3−8^2−22−15

Step-by-step explanation:

(3^2−2−3)(5^2+4+5)

Distribute:

3(5^2+4+5) ⋅ ^2−2(5^2+4+5) − 3(5^2+4+5)

15^4+12^3+15^2 − 2(52+4+5) − 3(52+4+5)

15^4+12^3+15^2 − 10^3−8^2−10 − 3(52+4+5)

15^4+12^3+15^2 − 10^3−8^2−10 − 15^2−12−15

Combine like terms:

15^4+12^3−10^3+15^2−8^2−15^2−10−12−15

15^4+2^3+15^2−8^2−15^2−10−12−15

15^4+2^3−8^2−10−12−15

15^4+2^3−8^2−22−15

15^4+2^3−8^2−22−15

hope it helps :)

please mark brainliest!

Answer:

A

Step-by-step explanation:

the brigde means anything in between

Step-by-step explanation:

the number in which 4 has the highest value is

6748.9251

Answer:

6834.2590

Step-by-step explanation:

..................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

Answer:

-86

Step-by-step explanation:

-102-

98 so the answer is -86

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Answer:

Step-by-step explanation:

I discounted the 2-m ramp. If we are supposed to be looking for the length of time the ride is above 38 m from the ground, that translates to 36 m from the very bottom of the circle that is the Ferris wheel (where the wheel would meet the "ground"). I first found the circumference of the circle:

C = 48(3.1415) so

C = 150.792 m

I enclosed this circle (the Ferris wheel is a circle) in a square and then split the square in 4 parts. Each square has a quarter of the circle in it. If you divide the circumference by 4, that means that the arc length of each quarter circle is a length of 37.698 m. But that doesn't put us 36 m above the ground, that only puts us 24 m above the ground (remember the diameter of the circle is 48, so half of that is 24, the side length of each of the 4 squares). What that means to us (so far, and we are not at the answer yet) is that when the height off the ground is 24 m, a car that starts at the bottom of the ride has traveled 37.698 m around the circle. Traveling in an arc around the outside of the circle is NOT the same thing as a height off the ground. Going around a circle takes longer because of the curve. In other words, if the car has traveled 37.698 m around the outside of the circle, it is NOT 37.698 m above the ground...it's only 24 m above the ground. Hence, the reason I enclosed the circle in a square so we have both the circle's curve {arc length} and height above the ground {side of the square}). As the car travels farther along the outside of the circle it gets higher off the ground. If one quarter of the circle is 24 m above the ground, we need to figure out how much farther around the circle we need to go so we are 36 m above the ground. The height difference is 36 - 24 = 12m. we need now to find how long the arc length of the circle is that translates to another 12 m (the difference between the 24 we found and the 36 total). Using right triangle trig I found that arc length to be 12.566. The total arc length on the circle that translates to 36 m above the ground is 50.26437 m.

Going back to the beginning of the problem, the circumference of the circle is 150.792, and it makes one complete revolution in 5 minutes. That means that a car will travel 30.1584 m in 1 minute. Since this is the case, we can use proportions to solve for how long it takes to get 36 m above the ground:

[tex]\frac{m}{min}:\frac{30.1584m}{1min}=\frac{50.26437m}{xmin}[/tex] and cross multiply:

30.1584x = 50.26437 so

x = 1.6667 minutes, the time it takes to reach a height of 36 m. BUT this is not what the question is asking. The question is asking how long it's HIGHER than that 36 m. Let's think.

The car starts at the bottom of the ride, gets to a height of 36 m, keeps going around the circle to its max height of 48 m, then eventually comes back down and keeps going til it's back on the ground. That means that there is a portion at the top of the wheel that is above 36 m. If it goes 50.2647 m around the circle til it's at 36 m, then when it passes the max height and drops back to 36 m, it's 50.2647 m around the other side of the circle. We just found that to travel that 50.2647 m, it took the car 1.6667 minutes. We travel this distance twice (once meeting the height going up and then again coming down) so that takes up 3.3334 minutes.

5 minutes - 3.3334 minutes leaves us off 36 m above the ground for 1.6664213 minutes.

Answer:

B. 24 sqrt 10

Step-by-step explanation:

Hope this helped.

Answer:

11√5

Step-by-step explanation:

just putting the question with the symbols here so its easier to find for others

Which choice is equivalent to the expression below? 3√5+8√5

A. 24√5
B. 24√10
C. 11√10
D. 11√5

Answer:

With new regime is 183,750Rs

Step-by-step explanation:

I. 75,000 * 13 [12 months + 1 month bonus] = 975,000

II. Ms.Gurung tax rate will be ₹37500 + 15%

III. Perform ratio x/975,000 = 15/100 [15% is 15/100] = 146,250

IIII. ₹37500 + 146,250 = 183,750Rs

It depends on how tax rate will costs, could be more or less.

f(x)=3x²+x-3x-1

=x(3x+1)-(3x+1)

=(x-1)(3x+1)

Answer:

Step-by-step explanation:

Hello !

(4,4*2,4) + (3,14 * 2,2² )/2 =

10,56 + 7,60 = 18,2 m²

9514 1404 393

Answer:

  138.77

Step-by-step explanation:

Your scientific or graphing calculator will have exponential functions for bases 10 and e. On the calculator shown in the first attachment, they are shifted (2nd) functions on the log and ln keys. Consult your calculator manual for the use of these functions.

The value can be found using Desmos, the Go.ogle calculator, or any spreadsheet by typing 10^2.1423 as input. (In a spreadsheet, that will need to be =10^2.1423.) The result using the Go.ogle calculator is shown in the second attachment.

You can also use the y^x key or the ^ key (shown to the left of the log key in the first attachment). Again, you would calculate 10^2.1423.

__

We have assumed your log is to the base 10. If it is base e (a natural logarithm), then you use the e^x key instead. Desmos, and most spreadsheets, will make use of the EXP( ) function for the purpose of computing e^( ). You can type e^2.1423 into the Go.ogle calculator.

_____

Additional comment

There are also printed logarithm tables available that you can use to look up the number whose log is 0.1423. You may have to do some interpolation of table values. You should get a value of 1.3877 as the antilog. The characteristic of 2 tells you this value is multiplied by 10^2 = 100 to get the final antilog value.

The logarithm 2.1423 has a "characteristic" (integer part) of 2, and a "mantissa" (fractional part) of 0.1423.

Answer:

Option D, HF is the answer........

Answer:

9514 1404 393

Answer:

  20 +2√10 ≈ 26.3 units

Step-by-step explanation:

Length AB is given as 10 units. Length AC is given as 2√10 ≈ 6.325 units. The length BC is the difference of the x-coordinates of its end points, since they are on a horizontal line: 5 -(-5) = 10 units.

The perimeter is the sum of the lengths of the sides of the triangle.

  P  = AB +AC +BC = 10 +2√10 +10 = 20 +2√10 ≈ 26.3 . . . units

Answer:

1045.01 rounded to the nearest hundredth

Step-by-step explanation:

First, we can draw this out. The angle of depression is the angle formed by the object at the top and the line formed by the object at the top and the object at the bottom.

If the truck on the left is truck A and the truck on the right is truck B, with the helicopter being the circle on top, there is one 60 degree angle of depression and one 20 degree one. If we make a point at the point in the road the helicopter is straight above, and we connect the points, we can form two right triangles, as shown. If we can calculate the lengths of sides x and y, we can add them up to find the length between the two trucks.

Starting with side x, we know one angle and the side length adjacent to that angle. We want to find the length opposite that angle. One formula that encompasses this is tan(θ) = opposite/adjacent. Therefore, tan(60) = x/500

tan(60) = x/500

multiply both sides by 500 to isolate the x

tan(60) * 500 = x

x = 866.0254

Similarly, with side y, we can say that tan(20) = y/500 and

tan(20) * 500 = y

y= 181.9851

The distance between the two trucks can be shown as x+y, so x+y= 1045.01 rounded to the nearest hundredth

Answer:

Step-by-step explanation:

Use Pythagorean's Theorem:

[tex]c^2=15^2+8^2[/tex] and

[tex]c^2=225+64[/tex] and

[tex]c^2=289[/tex] so

c = 17

Answer:

Simplifying

Simplifying

21 + x = 70

Solving

21 + x = 70

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21' to each side of the equation.

21 + -21 + x = 70 + -21

Combine like terms: 21 + -21 = 0

0 + x = 70 + -21

x = 70 + -21

Combine like terms: 70 + -21 = 49

x = 49

Simplifying

x = 49

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{21 + x = 70}[/tex]

[tex]\large\textsf{x + 21 = 70}[/tex]

[tex]\large\text{SUBTRACT 21 to BOTH SIDES}[/tex]

[tex]\large\textsf{x + 21 - 21 = 70 - 21}[/tex]

[tex]\large\text{CANCEL out: 21 - 21 because that gives you 0}[/tex]

[tex]\large\text{KEEP: 70 - 21 because that helps solve for the x-value}[/tex]

[tex]\large\textsf{x = 70 - 21}[/tex]

[tex]\large\textsf{\bf x = 49}[/tex]

[tex]\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 49}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

a)139°

Step-by-step explanation:

two co interior angles make one opposite exterior angle

49+90=139°

Answer: 32

No of workers = 8

No of days = 32

Now no of days = 8

Let the number of workers be x

ATQ

256/x = 8

x = 256/8

x = 32

Must click thanks and mark brainliest

Answer:

sinΘ = opposite/ hypotenuse

sin (37)= CV/55

55 sin (37) = CV

CV=33.1

OAmalOHopeO

Answer:

a)   [tex]s=482moh[/tex]

b)  [tex]s'=9mph[/tex]

Step-by-step explanation:

From the question we are told that:

Distance [tex]d=3930mi[/tex]

Time of flight [tex]T=8hr[/tex]

Flight back [tex]T_b=8.3hr[/tex]

Generally the equation for Time for flight with jet steam is mathematically given by

[tex]T=\frac{d}{s+s_1}[/tex]

[tex]8=\frac{3930}{s+s'}[/tex]

[tex]s+s'=491.3 ....equ1[/tex]

Generally the equation for Time for flight against jet steam is mathematically given by

[tex]T=\frac{d}{s-s_1}[/tex]

[tex]8.3=\frac{3930}{s-s_1}[/tex]

[tex]s+s'=473.5......equ 2[/tex]

Solving equ 1 and equ 2 simultaneously

[tex]s+s'=491.3[/tex]

[tex]s+s'=473.5[/tex]

Therefore

[tex]s=482moh[/tex]

[tex]s'=9mph[/tex]

Answer:

525 in³

Step-by-step explanation:

Use the direct variation equation, y = kx.

Substitute y with v (volume) and substitute x with l (length) to represent this situation:

y = kx

v = kl

Plug in 35 as l and 15 as k, then solve for v (the volume):

v = kl

v = 15(35)

v = 525

So, the volume of the box is 525 in³