The operation manager is responsible to identify whether there are errors in quality of the tires manufactured.
There are three different shifts and each shift has different team of workers who manufacture tires. For this we test hypothesis as;
H0 ; Quality of tire manufactured is independent on shifts
Ha ; Quality of tires manufactured is dependent on shifts.
The p value of chi squared test is greater than the significance level therefore we reject the null hypothesis.
This hypothesis reach to conclusion that quality of tires is dependent on shifts, which means there are differences in quality among the three shifts.
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PLEASE HELPPPPPPPPPPPPP
Step-by-step explanation:
The following configurations are evaluated, as given or stated within the interrogate:
P(Q) = 0.6
P(R) = 0.9
When the variable constant of Q and R transition into independent events within the function notation, the product of the individual values, as equated to those particular independent variables, is required.
For example:
If P(Q) = 0.6 and P(R) = 0.9, and Q and R fuse, then find the product of 0.9 and 0.6 is obligated:
0.9 * 0.6 = 0.54
Thus, given the independent events, P(Q and R) is equivalent to 0.54.
ASK YOUR SIR BRO I DONT KNOW
Please help out explanation need it
Answer:
[tex] \sin(θ) = \frac{19}{41} \\ θ = 27.6 \\ θ = 28[/tex]
prove that.
lim Vx (Vx+ 1 - Vx) = 1/2 X>00
Answer:
The idea is to transform the expression by multiplying [tex](\sqrt{x + 1} - \sqrt{x})[/tex] with its conjugate, [tex](\sqrt{x + 1} + \sqrt{x})[/tex].
Step-by-step explanation:
For any real number [tex]a[/tex] and [tex]b[/tex], [tex](a + b)\, (a - b) = a^{2} - b^{2}[/tex].
The factor [tex](\sqrt{x + 1} - \sqrt{x})[/tex] is irrational. However, when multiplied with its square root conjugate [tex](\sqrt{x + 1} + \sqrt{x})[/tex], the product would become rational:
[tex]\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}[/tex].
The idea is to multiply [tex]\sqrt{x}\, (\sqrt{x + 1} - \sqrt{x})[/tex] by [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}[/tex] so as to make it easier to take the limit.
Since [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} = 1[/tex], multiplying the expression by this fraction would not change the value of the original expression.
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \lim\limits_{x \to \infty} \left[\sqrt{x} \, (\sqrt{x + 1} - \sqrt{x})\cdot \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}\right] \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}\, ((x + 1) - x)}{\sqrt{x + 1} + \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}}\end{aligned}[/tex].
The order of [tex]x[/tex] in both the numerator and the denominator are now both [tex](1/2)[/tex]. Hence, dividing both the numerator and the denominator by [tex]x^{(1/2)}[/tex] (same as [tex]\sqrt{x}[/tex]) would ensure that all but the constant terms would approach [tex]0[/tex] under this limit:
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}[/tex].
By continuity:
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}[/tex].
Answer:
Hello,
Step-by-step explanation:
[tex]\displaystyle \lim_{x \to \infty} \sqrt{x}*(\sqrt{x+1}-\sqrt{x} ) \\\\\\= \lim_{x \to \infty}\dfrac{ \sqrt{x}*(\sqrt{x+1}-\sqrt{x} )*(\sqrt{x+1}+\sqrt{x} )}{\sqrt{x+1} +\sqrt{x} } \\\\= \lim_{x \to \infty} \dfrac{\sqrt{x} *1}{\sqrt{x+1} +\sqrt{x} } \\\\\\= \lim_{x \to \infty} \dfrac{1} {\sqrt {\dfrac {x+1} {x} }+\sqrt{\dfrac{x}{x} } } \\\\\\=\dfrac{1} {\sqrt {1}+\sqrt{1} } \\\\\\=\dfrac{1} {2} \\[/tex]
Find the measure of the missing angles.
Answer:
Step-by-step explanation:
Find the missing side lengths leave your answer as a racials simplest form
Answer:
x = 20
y = 10
Answered by Gauthmat
write 6x10x10x10x10 with an expont
Answer:
6x10^4
Step-by-step explanation:
CAN SOMEBODY ANSWER MY QUESTIONS !!!!
9514 1404 393
Answer:
A''(-1, 2)B''(3, 5)C''(4, 3)Step-by-step explanation:
Reflection over the line x=a is the transformation ...
(x, y) ⇒ (2a -x, y)
Then the double reflection over x=a and x=b is the transformation ...
(x, y) ⇒ (2b -(2a -x), y) = (2(b-a) +x, y)
That is, the result is translation by twice the distance between the lines. For a=1 and b=3, the transformation is ...
(x, y) ⇒ (x +4, y) . . . . . . . translation to the right by 4 units.
A(-5, 2) ⇒ A''(-1, 2)
B(-1, 5) ⇒ B''(3, 5)
C(0, 3) ⇒ C''(4, 3)
HELP ASAP PIC IS BELOW!!!
Answer:
55°
Step-by-step explanation:
Vertical angles are similar
Answered by GAUTHMATH
Suppose a jar contains 7 red marbles and 28 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.
Answer:
3/85
Step-by-step explanation:
that's the answer above
Find x. Round your answer to the nearest tenth of a degree.
Answer: x=52.6°
Step-by-step explanation:
To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.
[tex]tan(x)=\frac{17}{13}[/tex]
To find x, we want to use inverse tangent.
[tex]x=tan^{-1}(\frac{17}{13} )[/tex] [plug into calculator]
[tex]x=52.6[/tex]
Now, we know that x=52.6°.
A survey asked 50 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 30 students are not in band.
Which table shows these data correctly entered in a two-way frequency?
C, just look at the "Total" for each single information.
the values in the inner grid combine multiple informations.
The table shows these data correctly entered in a two-way frequency is table C.
What is Two way Frequency?Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.
We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.
So, the two way table is:
Band Not in Band Total
Play instrument 20 5 25
Do not play instrument 0 25 25
Total 20 30 50
So, Table C is Correct.
Learn more about two-way frequency here:
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Move the numbers to the lines to order them from least to greatest.
least
greatest
67.98
68.6
68.11
Please answer ASAP
Answer:
67.98,68.11, 68.6
Which of the following represents the factorization of the trinomial below?
- 4x3 - 4x2 +24 x
O A. -4(x2-2)(x+3)
B. -4(x2 + 2)(x+3)
O C. -4x(x + 2)(x+3)
D. -4x(x - 2)(x+3)
Answer:
D. -4x(x - 2)(x+3)
Step-by-step explanation:
We are given the following trinomial:
[tex]-4x^3 - 4x^2 + 24x[/tex]
-4x is the common term, so:
[tex]-4x(\frac{-4x^3}{-4x} - \frac{4x^2}{-4x^3} + \frac{24x}{-4x}) = -4x(x^2+x-6)[/tex]
The second degree polynomial can also be factored, finding it's roots.
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
x² + x - 6
Quadratic equation with [tex]a = 1, b = 1, c = -6[/tex]
So
[tex]\Delta = 1^{2} - 4(1)(-6) = 25[/tex]
[tex]x_{1} = \frac{-1 + \sqrt{25}}{2} = 2[/tex]
[tex]x_{2} = \frac{-1 - \sqrt{25}}{2} = -3[/tex]
So
[tex]x^2 + x - 6 = (x - 2)(x - (-3)) = (x - 2)(x + 3)[/tex]
The complete factorization is:
[tex]-4x(x^2+x-6) = -4x(x - 2)(x + 3)[/tex]
Thus the correct answer is given by option d.
using the unit circle what is the exact value of tanpi/6
Answer:
[tex] \frac{ \sqrt{3} }{3} [/tex]
Step-by-step explanation:
[tex]\frac{1}{3} \div \sqrt{3} [/tex]
Which graph shows the quadratic function y = 3x2 + 12x + 10? (5 points)
The following graph is labeled A: A four quadrant graph with a parabola opening up, passing through the points negative 3, 1, negative 2, negative 2, and negative 1, 1 with the vertex at 2, negative 2. The following graph is labeled B: A four quadrant graph with a parabola opening up, passing through the points 1, 4, 2, 1, and 3, 4 with the vertex at 2, 1. The following graph is labeled C: A four quadrant graph with a parabola opening up, passing through the points negative 3, 5, negative 2, 2, and negative 1, 5 with the vertex at negative 2, 2. The following graph is labeled D: A four quadrant graph with a parabola opening up, passing through the points 1, 1, 2, negative 2, and 3, 1 with the vertex at 2, negative 2.
Answer:
The correct graph is A.
Answer:
A i got it right
Step-by-step explanation:
A math professor is wondering if students today are better or worse than in the past. He has given the same final to this year's class that he gave ten years ago. Compute mean, median, and mode for both classes and write a paragraph summarizing the differences.
This Year
35 45 65 75 87
80 69 71 53 90
99 95 70 82 73
93 67 61 57 74
72 77 71 81 83
Ten Years Ago
56 77 75 76 59
74 51 89 55 79
67 77 69 91 68
90 65 79 69 79
87 86 98 91 95
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following data:
This year :
35, 45, 53, 57, 61, 65, 67, 69, 70, 71, 71, 72, 73, 74, 75, 77, 80, 81, 82, 83, 87, 90, 93, 95, 99
Mean = ΣX / n = 1825 / 25 = 73
The mode = 71 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 73
10 years ago :
51, 55, 56, 59, 65, 67, 68, 69, 69, 74, 75, 76, 77, 77, 79, 79, 79, 86, 87, 89, 90, 91, 91, 95, 98
Mean = ΣX / n = 1902 / 25 = 76.08
The mode = 79 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 77
According to the computed statistics, we can conclude that, today is worse than the past as the average score which is almost similar to the median value is higher 10 years ago and the modal score is better 10 years ago as well.
Anyone know how to do this
Answer:
30 cm
Step-by-step explanation:
Since the length of tangents drawn from a point are equal, the perimeter is 3+3+9+9+3+3=30
Answer:
30 centimeter
Which of the following are exterior angles? Check all that apply.
Answer:
<5
Step-by-step explanation:
exterior angles + the corresponding interior angle of the triangle = 180º or a straight angle
the only exterior angle shown in the diagram is <5, which corresponds to the interior <2
hope this helps!
Answer:
<5
Step-by-step explanation:
everything else is matched up perfectly so it has to be <5
A ball is thrown upward with an initial velocity (v) of 13 meters per second. Suppose that the initial height (h) above the ground is 7 meters. At what time t will the ball hit the ground? The ball is on the ground when S=0. Use the equation S=−5t2+vt+h.
Answer:
the correct answer is, 4
I need help completing this problem ASAP
Answer:
8 sqrt(5)
Step-by-step explanation:
sqrt(45) + sqrt(125)
Rewriting
sqrt(9*5) + sqrt( 25 *5)
we know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(9) sqrt(5) + sqrt(25) sqrt(5)
3 sqrt(5)+5 sqrt(5)
Add like terms
8 sqrt(5)
Answer:
A. [tex] 8\sqrt{5} [/tex]
Step-by-step explanation:
[tex] \sqrt{45} + \sqrt{125} = [/tex]
[tex] = \sqrt{9 \times 5} + \sqrt{25 \times 5} [/tex]
[tex] = 3\sqrt{5} + 5\sqrt{5} [/tex]
[tex] = 8\sqrt{5} [/tex]
given that the following two are geometric series are convergent: 1+x+x^2+x^3+...and 1-x+x^2-x^3+... determine the value(s) of x for which the sum of the two series is equal to 8
Let S and T denote the two finite sums,
S = 1 + x + x ² + x ³ + … + x ᴺ
T = 1 - x + x ² - x ³ + … + (-x) ᴺ
• If both S = 8 and T = 8 as N goes to infinity:
Then
xS = x + x ² + x ³ + x ⁴ + … + x ᴺ⁺¹
-xT = -x + x ² - x ³ + x ⁴ + … + (-x) ᴺ⁺¹
so that
S - xS = 1 - x ᴺ⁺¹ ==> S = (1 - x ᴺ⁺¹)/(1 - x)
and similarly,
T = (1 - (-x) ᴺ⁺¹)/(1 + x)
For both sums, so long as |x| < 1, we have
lim [N → ∞] S = 1/(1 - x)
lim [N → ∞] T = 1/(1 + x)
Then if both sums converge to 8, this happens for
S : 1/(1 - x) = 8 ==> x = 7/8
T : 1/(1 + x) = 8 ==> x = -7/8
• If the sum S + T = 8 as N goes to infinity:
From the previous results, we have
1/(1 - x) + 1/(1 + x) = 8 ==> x = ±√3/2
Which statement is correct?
Answer:
c is the answer why cause I did it
Can someone please help with 25 , please put the way you got it. Please no links it’s serious
Answer:
X * 0.8 = $64
x = $80
Step-by-step explanation:
Solve for x.
5x - 3 = 12
A) X = 3
B) X = -3
C) X = -9/5
D) X = 9/5
Answer:
A. x = 3
Step-by-step explanation:
5x - 3 = 12
5x = 12 + 3
5x = 15
x = 15/5
= 3
Please Help with this
Answer:
csc = 6/5= 1.2
cot = √(11)/5= 0.6633
sin = 5÷6= 0.83333
Which function is graphed?
(Help please)
Answer:
the function that is graphed is y=½CSC(x)
Find the slope of the line
Slope=m=_______
Answer:
[tex]\displaystyle m = \frac{3}{4}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Reading a coordinate planeCoordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]Step-by-step explanation:
Step 1: Define
Identify points from graph.
Point (4, 0)
Point (0, -3)
Step 2: Find slope m
Simply plug in the 2 coordinates into the slope formula to find slope m
Substitute in points [Slope Formula]: [tex]\displaystyle m = \frac{-3 - 0}{0 - 4}[/tex]Simplify: [tex]\displaystyle m = \frac{3}{4}[/tex]
If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (9*h)(-3)?
9514 1404 393
Answer:
(g·h)(-3) = 2.8
Step-by-step explanation:
Given:
g(x) = (x +1)/(x -2)
h(x) = 4 -x
Find:
(g·h)(x) = g(x) × h(x) for x = -3
Solution:
g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5
h(-3) = 4 -(-3) = 4 +3 = 7
Then the product is ...
g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8
(g·h)(-3) = 2.8
14. In a garden 746496 apple trees are arranged in such a way that, there are as inany rows as there are in a row. How many rows are there in the garden
Answer:
864
Step-by-step explanation:
do the square root of the total number
Historically, the industries with the most complaints to the Better Business Bureau have been banks, cable and satellite television companies, collection agencies, cellular phone providers, and new car dealerships. The results for a sample of complaints are contained in the file BBB. Click on the datafile logo to reference the data. a. Construct a frequency distribution for the number of complaints by industry. Category Observed Frequency Bank Cable Car Cell Collection Total b. Using , conduct a hypothesis test to determine whether the probability of a complaint is the same for the five industries. The test-statistic is (to 3 decimals). -value (to 4 decimals) What is your conclusion
Answer:
χ² = 19
Pvalue = 0.0008 ( 4 decimal places)
WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries
Step-by-step explanation:
H0 : probability of complaint is the same for the 5 industries.
H1: probability of complaint is not the same for the 5 industries.
Category ____ observed frequency
Bank _______ 26
Cable _______44
Car _________42
Cell _________60
Collection ____ 28
Total ________200
The test statistic ;
χ² = (O - E)² / E
O = Observed Frequency ; E = Expected Frequency
Expected Frequency, E = (1 / n) * total
n = number of industries = 5
Expected frequency, E = (1/5)*200 = 40
Expected frequency is the same for all, thus E for all 5 industries = 40
χ² = Σ(O - E)² / E;
χ² = (26-40)² / 40 + (44-40)² / 40 + (42-40)² / 40 + (60-40)² / 40 + (28-40)² / 40
χ² = 19
At α = 0.05 ; df = n-1 = 4 ; χ²critical = 0.000786
Since Pvalue < α ; WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries.
