the length of a rectangle is 4 meters longer than the width. if the area is 22 square meters , find the rectangle dimension

Answer:

There is no sufficient evidence to support the claim.

Step-by-step explanation:

Given the data:

7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42

Sample size, n = 10

The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407

The sample standard deviation, s = 0.41158 ( from calculator)

The hypothesis :

H0 : μ = 7

H0 : μ ≠ 7

The test statistic :

(xbar - μ) ÷ (s/√(n))

(7.047 - 7) ÷ (0.41158/√(10))

0.047 / 0.1301530

Test statistic = 0.361

Testing the hypothesis at α = 0.05

The Pvalue ;

df = n - 1 ; 10 - 1 = 9

Two tailed test

Pvalue(0.361, 9) = 0.7263

Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.

Answer:

1

Step-by-step explanation:

1 increased by 3=1+3=4

Twice of 1=1+1=2

4 is two more than 2.

Therefore, the number=1

Answer:

its the same above

Step-by-step explanation:

Answer:

240000

Step-by-step explanation:

Represent the exponential equation.

[tex]10000 (5 {t}^{ \frac{2}{3} } + 4) = [/tex]

Replace 8 with t

[tex]10000(5(8) {}^{ \frac{2}{3} } + 4)[/tex]

[tex]10000(5 \times 4 + 4) [/tex]

[tex]10000(24) = 240000[/tex]

The population of the town after 8 month will be 2,40,000.

Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.

Let P be the population of the town after 8 months

According to the given question

The current population of the town = 10,000.

Also, the population of the town is changing at the rate of [tex]4+5t^{\frac{2}{3} }[/tex].

Therefore, the population of the town after 8 month is given by the exponential function

[tex]P = 10000(4+5t^{\frac{2}{3} } )[/tex]

Substitute t =8 in the above equation

⇒[tex]P = 10000(4 + 5(8)^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4 + 5(2^{3}) ^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4+5(4))[/tex]

⇒[tex]P = 10000(24)[/tex]

⇒[tex]P = 240000[/tex]

Hence, the population of the town after 8 month will be 2,40,000.

Find out more information about exponential growth here:

https://brainly.com/question/11487261

#SPJ2

Answer:

168 km

Step-by-step explanation:

24*7 is equal to 168 km

Answer:

Upto 40 g or 160 mmols

Step-by-step explanation:

Can you plz mark me as brainliest?

Answer:

140 mL

Step-by-step explanation:

10% of 140 is 14

Answer:

Step-by-step explanation:

3x - 5 = 0

3x = 5

x = 5/3

2x - 10 = 0

2x = 10

x = 10/2 = 5

Answer:

x- 1

y-5

z-3

Step-by-step explanation:

all u have to do is calculate the distance, so for example y is 5 because - -4 -3 -2 -1 0 1 and that is a 5 number distance

Answer:

one solution

Step-by-step explanation:

3 -2x=5-x+3+4x

Combine like terms

3-2x = 8+3x

Add 2x to each side

3-2x+2x = 8+3x+2x

3 = 8+5x

Subtract 8 from each side

3-8 =8+5x-8

-5 =5x

Divide by 5

-5/5 = 5x/5

-1 =x

There is one solution

Answer:

A

Step-by-step explanation:

The answer is choice A.

The two angles are alternate exterior angles of lines LG and KH cut by transversal JF.

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

(a) The graph is scaled by a factor of 2, and shifted up 1 unit. The scaling moves each point away from the x-axis by a factor of 2. The points on the x-axis stay there. The translation moves that scaled figure up 1 unit.

__

(b) The graph is reflected across the x-axis and shifted right 4 units. The point on the x-axis stays on the x-axis.

12321-3x3x37x37

(3)^2×(37)^2

square root = 3×37=111

Hope it helps you..!!

Answer:

z=0

50%

Step-by-step explanation:

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

Answer:

6w+(2×4w)-(2×7)

(6w+8w)-14=14w-14

Answer:

7 7/80 or 7.0875

Step-by-step explanation:

product is the result of multiplication

7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875

Answer:

their distance is increasing at the rate of 41.6 miles/hr

Step-by-step explanation:

Given the data in the question;

first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;

⇒ ( 30/60 ) × 10 = 5 miles

so as illustrated in the diagram below;

y² = x² + ( x + 5 )²

2y[tex]\frac{dy}{dt}[/tex] = 2x[tex]\frac{dx}{dt}[/tex] + 2(x+5)[tex]\frac{dx}{dt}[/tex]

y[tex]\frac{dy}{dt}[/tex] = ( 2x + 5 ) ][tex]\frac{dx}{dt}[/tex]

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]   ------ let this be equation 1

Now, given that, [tex]\frac{dx}{dt}[/tex]  = 30 miles/hr, when x = 10

so

y = √( 10² + 15² ) = √325

so from equation 1

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]

we substitute

[tex]\frac{dy}{dt}[/tex] = [( 2(10) + 5 ) / √325 ]30

[tex]\frac{dy}{dt}[/tex] = [ 25 / √325 ] × 30

[tex]\frac{dy}{dt}[/tex] = 41.6 miles/hr

Therefore, their distance is increasing at the rate of 41.6 miles/hr

Answer:

length = 20 inches

width = 13 inches

Step-by-step explanation:

l = length

w = width

area = l×w

perimeter = (2×l) + (2×w)

l = w + 7

l×w = 4×(2×l + 2×w) - 4

(w+7)×w = 4×(2×(w+7) + 2×w) - 4

w² + 7w = 4×(2w + 14 + 2w) - 4

w² + 7w = 8w + 56 + 8w - 4 = 16w + 52

w² - 9w - 52 = 0

the solution for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

here we use now w instead of x.

and a=1

b=-9

c=-52

w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =

= (9 ± sqrt(289))/2 = (9 ± 17)/2

w1 = (9+17)/2 = 26/2 = 13

w2 = (9-17)/2 = -8/2 = -4

and a negative length does not make any sense for a geometric shape.

so, only w1 = 13 applies.

l = w + 7 = 13 + 7 = 20

Answer:

15÷39

Step-by-step explanation:

I hope it will help you

cos x = adjacent÷ hypotenuse

cos x =15÷39

cos x = 5÷13

Answer:

Step-by-step explanation:

CE and are the sides making up the sine of an angle.

CE is the side opposite the angle

DE is the side hypotenuse.

<D = 61 degrees

Sin(D) = opposite / hypotenuse

hypotenuse = 8

Sin(61) = 0.8746

CE = ?

sin(61) = CE / 8                multiply both sides  by 8

8 sin(61) = CE

CE = 8 * 0.8746

CE = 6.9969

CE = 7.0

That 0 should be included in the answer, but I think it is safe to say that if you enter 7, you will get it right.

Answer:

7.0

Step-by-step explanation:

Answer:

Inverses

Step-by-step explanation:

One things I could tell about the earth from this graph is that the northern and southern hemispheres are inverses because when the temp of one goes up over the months, the other goes down.

Step-by-step explanation:

her it Go i think it is helpful for u

Answer:

18

Step-by-step explanation:

The diameter is equal to twice the length of the radius

So if the radius is 9 then the diameter is 9 * 2 = 18

Answer:

n=4

Step-by-step explanation:

f(x+n)=3(x+n)^2-7=3x^2+24x+41

3x^2+3n^2+6xn-7=3x^2+24x+41

Comparing and we will get, n=4

Answer:

ayyyy i go to RSM too? Which location r u at? ANyways the answer is

Answer:

Rs. 80

Step-by-step explanation:

Given that :

Purchase price = 70

Profit = 6

Discount = 5%

Let selling price = x

Selling price * (1 - discount) = (purchase price + profit)

x * (1 - 5%) = (70 + 6)

x * (1 - 0.05) = 76

x * 0.95 = 76

0.95x = 76

x = 76 / 0.95

x = 80

Hence, selling price = Rs. 80

Answers:

The areas from left to right are:  13 m^2, 49 m^2, 24 m^2, 14 m^2

The largest area occurs when the rectangle is a square

===========================================================

Explanation:

The area rectangle formula is base*height, or length*width, whichever you prefer.

From left to right, we have these areas:

We get the largest area (49 m^2) when the figure is a square. This happens with any problem in which we have a fixed amount of fencing and we want to max out the area. So it's not particular to this specific problem only.

Why a square? Well an informal way to think of it would be to consider that as one dimension goes up, the other goes down, and vice versa. Think of it like a see-saw. As the examples show, if one dimension is particularly large, then its area wont be as big compared to when the dimensions are closer together. It's only when all dimensions are equal is when we max the area out entirely.

I am sry but he has don wrong calculation the answer is last one 9*5=45m and its the answer.

and the noticiable thing is the larger the shape is the area increases.

Answer:i think it is b not really sure      

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

the maximum of f(X)=sin(X) is 1

Answer:

See Below.

Step-by-step explanation:

We are given the function:

[tex]\displaystyle y=\sqrt{\sin x}[/tex]

And we want to show that:

[tex]\displaystyle 4y^3\frac{d^2y}{dx^2}+y^4+1=0[/tex]

Find the first derivative of y using the chain rule:

[tex]\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{\sin x}}\cdot \cos x = \frac{\cos x}{2\sqrt{\sin x}}[/tex]

And find the second derivative using the quotient and chain rules:

[tex]\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{1}{2}\left(\frac{(\cos x)'(\sqrt{\sin x})-(\cos x)(\sqrt{\sin x})'}{(\sqrt{\sin x})^2}\right) \\ \\ &=\frac{1}{2}\left(\frac{-\sin x\sqrt{\sin x} - \left(\cos x\right) \left (\dfrac{\cos x}{2\sqrt{\sin x}}\right)}{\sin x}\right) \\ \\ & = \frac{1}{2}\left(\frac{ -\sin x(2\sin x) -\cos x(\cos x) }{\sin x \left(2\sqrt{\sin x}\right) }\right) \\ \\ &= -\frac{1}{2} \left(\frac{2\sin^2 x + \cos^2 x}{2\sin^{{}^{3}\!/\! {}_{2}}x}\right)\end{aligned}[/tex]

Find y³:

[tex]\displaystyle y^3 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right) ^3= \sin^{{}^{3}\! / \! {}_{2} }x[/tex]

And find y⁴:

[tex]\displaystyle y^4 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right)^4 = \sin^2 x[/tex]

Substitute:

[tex]\displaystyle 4\left( \sin^{{}^{3}\! / \! {}_{2} }x\right)\left(-\frac{1}{2}\left(\frac{2\sin ^2x + \cos ^2 x}{2\sin^{{}^{3}\!/ \! {}_{2}}x}\right)\right)+\left(\sin ^2 x\right) + 1= 0[/tex]

Simplify:

[tex]-\left(2\sin^2 x + \cos^2 x\right) + \sin ^2 x + 1=0[/tex]

Distribute:

[tex]-2\sin ^2 x - \cos^2 x + \sin ^2 x + 1=0[/tex]

Simplify:

[tex]-\sin ^2 x - \cos^2 x + 1= 0[/tex]

Factor:

[tex]-(\sin ^2 x + \cos^2 x ) + 1=0[/tex]

Pythagorean Identity:

[tex]-(1)+1=0\stackrel{\checkmark}{=}0[/tex]

Q.E.D.