The height of a house is 21 feet tall. A tree beside the house is 7 feet more than twice as tall as the house. What is the height of the tree?

Answer:

99th term is 51

Step-by-step explanation:

Arithmetic sequence equation

a1= first term = 2

d= common difference = 0.5 or 1/2

2, 5/2 = 5/2 - 2 = 0.5 or 1/2

3 - 5/2 = 1/2

7/2 - 3 = 1/2

an = a1 + (n - 1)d

a99 = 2 + (99-1) 1/2

a99= 2 + 98 (1/2)

a99 = 2 + 49

a99 = 51

Answer:

Step-by-step explanation:

x-2y=-2     x=2y-2

7x-3y=19

substitute x  with 2y-2

7(2y-2)-3y=19     14y-14-3y=19       11y=33   y=3

substitue 3 for y

x-2(3)=-2     x-6=-2      x=4

x=4, y=3

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really useful

Answer:

Irrational

Step-by-step explanation:

The number is irrational because when you convert it to decimal form, you get 276.4601... a repeating decimal that goes on and on.

Answer:

Step-by-step explanation:

π is irrational and 88 is rational number.

The product of the two is irrational.

Answer:

I think 14 if not 10

Step-by-step explanation:

<%) pizza

Answer:

∠ C = 118°

Step-by-step explanation:

DE = DF , then Δ DEF is isosceles with base angles congruent , then

∠ DEF = ∠ DFE = [tex]\frac{180-56}{2}[/tex] = [tex]\frac{124}{2}[/tex] = 62°

∠ DFE and ∠ DFB are adjacent angles on a straight line and sum to 180° , so

∠ DFB = 180° - 62° = 118°

BCDF is a parallelogram ( opposite sides are parallel )

The opposite angles of a parallelogram are congruent , then

∠ C = ∠ DFB = 118°

Step-by-step explanation:

[tex]\overline{DA} \text{ bisects } \overline{EB}[/tex]     is given

[tex]\overline{BC} \cong \overline{EC}[/tex]  definition of bisect

[tex]\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}[/tex]  are both given

[tex]\angle B, \, \angle E \text{ are right angles}[/tex]  definition of perpendicular

[tex]\angle B \cong \angle E[/tex]   because all right angles are congruent

[tex]\angle{ACB} \cong \angle{DCE}[/tex]  vertical angles are congruent

[tex]\triangle{ACB} \cong \triangle{DCE}[/tex]   ASA (angle-side-angle)

[tex]\overline{ED} \cong \overline{BA}[/tex]  CPCTC (corresponding parts of congruent triangles are congruent)

He would have 4 pieces of rope

Answer:

1):Reaction

2):Action

3):Thought

4): Dialogue

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hoped this helped.

Answer:

8

Step-by-step explanation:

8

Answer:

Step-by-step explanation

Area of a triangle

      A = ½bh

dA/dt = ½(b(dh/dt) + h(db/dt)

dA/dt = ½(4(9) + 12(-5))

dA/dt = ½(36 - 60)

dA/dt = ½(-24)

dA/dt = -12 cm²/s

The rate of change of the area of the triangle is [tex]-12 cm^2/s[/tex].

The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to an area of an open surface or even the boundary of a three-dimensional object, whereas the area of a plane region as well as plane area refers to a area of a shape or planar lamina. Area can be interpreted as the quantity of material with a specific thickness required to create a model of the shape or as the quantity of paint required to completely cover a surface in a single coat. It is the two-dimensional equivalent of a curve's length.

A shape's area can be calculated by contrasting it with squares of a known size.

[tex]\frac{\mathrm{d} b(t)}{\mathrm{d} t}=-5cm/s[/tex]

[tex]\frac{\mathrm{d} h(t)}{\mathrm{d} t}=9 cm/s[/tex]

[tex]\frac{\mathrm{d}A }{\mathrm{d} t}=\frac{1}{2}\left (b\frac{\mathrm{d} h}{\mathrm{d} t} +h\frac{\mathrm{d} b}{\mathrm{d} t}\right )[/tex]

[tex]\frac{\mathrm{d} A}{\mathrm{d} t}=-12 cm^{2}/s[/tex]

Hence, The rate of change of the area of the triangle is [tex]-12 cm^2/s[/tex].

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Answer:

aprometly 19 I think

Step-by-step explanation:

cause don't you have yo divide 196 ÷ 10.25

Answer:

805.98

Step-by-step explanation:

671.65x.20=134.33

134.33+671.65=805.98

Answer:

hehehehe hey lois im in brainly

Step-by-step explanation:

this is so fricking epic

Answer:

Step-by-step explanation:

Let x be gallons of 7%

Let y be gallons of 3%

364 = x + y

y = 364 - x

364(0.06) = x(0.07) + y(0.03)

364(6) = x(7) + y(3)

364(6) = 7x + 3y

364(6) = 7x + 3(364 - x)

364(6 - 3) = 7x - 3x

364(3) = 4x

x = 273

y = 364 - 273 = 91

273 gallons of 7%

91    gallons of 3%

Answer:

850 divided by 7.5

Step-by-step explanation:

Answer: The answer is 1.62.

Explanation: It is in the image.

Answer:

b

Step-by-step explanation:

Answer: if you can choose multiple its c and d, otherwise i would just use c

Step-by-step explanation:

Answer:

I think the answer is c now I'm using words to meet the 20 character minimum

Answer:

No

Step-by-step explanation:

substitute -2 for 'x' and 5 for 'y'

2(-2) + 5(5) = 0?

-4 + 25 = 21, not 0

Answer:

D. 144km

Step-by-step explanation:

If the vehicle travels 72km every hour, in two hours, it will drive 144km. (72x2=144)

Answer:

LCD = 12

Equivalent Fractions with the LCD

5/6 = 10/12

5/4 = 15/12

Step-by-step explanation:

Rewriting input as fractions if necessary:

5/6, 5/4

For the denominators (6, 4) the least common multiple (LCM) is 12.

LCM(6, 4)

Therefore, the least common denominator (LCD) is 12.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

5/6 = 5/6 × 2/2 = 10/12

5/4 = 5/4 × 3/3 = 15/12

I used a least common denominator calculator so I hope this helped!!

Answer: 60

Step-by-step explanation:

Answer:

Answer:

+1/-1

Step-by-step explanation:

assuming the original phrase is  x^2

x^2 + 10 = 9

x^2 = 1

x = +/- 1

Answer:

[tex]\displaystyle b = -22[/tex]

Step-by-step explanation:

We are given the function:

[tex]\displaystyle f(x) = (x^3+bx+6)(g(x))[/tex]

Where b is a constant and g is a differentiable function.

And we want to determine the value of b such that f'(2) = 0.

Find f' using the product rule:

[tex]\displaystyle \begin{aligned} f'(x) & = \frac{d}{dx}\left[ (x^3+bx+6)(g(x))\right] \\ \\ & = \frac{d}{dx}\left[ x^3 + bx + 6\right] g(x) + (x^3+bx+6)\frac{d}{dx}\left[ g(x)\right] \\ \\ & = (3x^2+b)(g(x)) + (x^3 + bx + 6)(g'(x))\end{aligned}[/tex]

Substitute using known values and solve for b:

[tex]\displaystyle \begin{aligned}f'(2) = 0 & = (3(2)^2+b)(g(2)) + ((2)^3+b(2)+6)(g'(2)) \\ \\ 0 & = (12+b)(3) + (14+2b)(-1) \\ \\ 0 & = 22 +b \\ \\ b & = -22\end{aligned}[/tex]

In conclusion, the value of b is -22.

The function f is given b is a constant and g is a differentiable function the value b (-8.4),

Let's start by finding the derivative of the given function f(x) with respect to x:

f(x) = (x³ + bx + 6) × g(x)

Using the product rule for differentiation, the derivative of f(x) is:

f'(x) = (x³ + bx + 6) × g'(x) + g(x) × (3x² + b)

Now we are interested in finding the value of b for which f'(2) = 0. So, let's plug in x = 2 and use the information given about g(2) and g'(2):

f'(2) = (2³ + 2b + 6) × g'(2) + g(2) × (3 × 2² + b)

Since g(2) = 3 and g'(2) = -1,

f'(2) = (8 + 2b + 6) × (-1) + 3 × (3 × 4 + b)

= (2b + 14 - 8) + 3× (12 + b)

= 2b + 6 + 36 + 3b

= 5b + 42

Now, we want to find the value of b for which f'(2) = 0:

5b + 42 = 0

Subtracting 42 from both sides:

5b = -42

Dividing both sides by 5:

b = -8.4

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Complete question:

The function f is given by f(x)=(x^{3}+bx+6)(g(x)), where b is a constant and g is a differentiable function satisfying g(2)=3 and g′(2)=−1. For what value of b is f′(2)=0?

7

10

12

22

-8.4

Answer:

000

Step-by-step explanation:

000

Answer:

[tex]$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = -\infty$[/tex]

Step-by-step explanation:

[tex]$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = \lim_{x\to 0^+} \tan(x) - \lim_{x\to 0^+} \frac{1}{x^2} $[/tex]

and

[tex]$\lim_{x\to 0^+} \tan(x) = \tan(0) = 0$[/tex]

[tex]$\lim_{x\to 0^+} \frac{1}{x^2} = +\infty$[/tex]

Therefore,

[tex]$\lim_{x\to 0^+} \tan(x) - \frac{1}{x^2} = -\infty$[/tex]

Answer:

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Step-by-step explanation:

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