Simplify the given equation.
6 - (3x+10) + 4(2 - x) = 15
O 4-7 x = 15
O4 - 4 x= 15
O 12 - 7 x= 15

Answer:

2/52=1/26

Step-by-step explanation:

Answer:

D. There is no x value as there is no solution to this system

Step-by-step explanation:

2x − 3y = 3                                  5x − 4y = 4

5x - 4y = 4               -4y = -5x + 4                         y = 5/4x - 1

2x - 3(5/4x - 1) = 3

2x - 15/4x + 3 = 3

-7/4x = 0

x = 0

Answer:

x = 19.2

Step-by-step explanation:

tan(58)=x/12

x=12×tan(58)

x=19.2

Answered by GAUTHMATH

Answer:

The amount of money that must be invested is $252.

Step-by-step explanation:

Present value formula:

The present value formula is given by:

[tex]P = \frac{F}{(1+r)^n}[/tex]

In which:

P is the present value.

F is the future value.

r is the interest rate.

n is the number of periods.

9% ANNUALLY

This means that [tex]r = 0.09[/tex]

COMPOUNDED QUARTERLY TO OBTAIN 1,000 IN 4 YEARS.

Obtain 1000 means that [tex]F = 1000[/tex]

Compounded quarterly in 4 years, so 4*4 = 16 periods and [tex]n = 16[/tex].

Amount of money that must be invested:

[tex]P = \frac{F}{(1+r)^n}[/tex]

[tex]P = \frac{1000}{(1+0.09)^{16}}[/tex]

[tex]P = 252[/tex]

The amount of money that must be invested is $252.

Answer:

D. 77

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The population standard deviation is estimated to be $300

This means that [tex]\sigma = 300[/tex]

If a 98% confidence interval is used and the maximum allowable error is $80, how many cardholders should be sampled?

This is n for which M = 80. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]80 = 2.327\frac{300}{\sqrt{n}}[/tex]

[tex]80\sqrt{n} = 2.327*300[/tex]

[tex]\sqrt{n} = \frac{2.327*300}{80}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.327*300}{80})^2[/tex]

[tex]n = 76.15[/tex]

Rounding up:

77 cardholders should be sampled, and the correct answer is given by option d.

Answer:

Step-by-step explanation:

Let's fill that in with what the variables are "worth":

(3)(-3)+2(-2) and simplify to

-9 + (-4) which, when you add those 2 negatives, gives you

-13, choice B.

Answer:

[tex]x = 3 \\ y = - 3 \\ z = - 2 \\ xy + 2z = 3 \times - 3 + 2 \times - 2 \\ = - 9 - 4 \\ = - 13 \\ thank \: you[/tex]

Answer:

I think the anser is 667.50

Step-by-step explanation:

Answer:

(8.213 ; 8.247)

Step-by-step explanation:

Given the data :

No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Dia. 8.23 8.16 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24

Sanple size, n = 15

Sample mean, xbar = Σx / n = 123.45 / 15 = 8.23

The sample standard deviation, s = √(x -xbar)²/n-1

Using calculator :

Sample standard deviation, s = 0.03116

s = 0.031 (3 decimal places)

The 95% confidence interval :

C.I = xbar ± (Tcritical * s/√n)

Tcritical at 95%, df = 15 - 1 = 14

Tcritical = 2.145

C.I = 8.23 ± (2.145 * 0.031/√15)

C.I = 8.23 ± 0.0171689

C.I = (8.213 ; 8.247)

Answer:

a) 75.8% of students would score less than 550 in a typical year.

b) The comparable standard would be a minimum ACT score of 22.2.

c) 0.0139 = 1.39% probability that a randomly selected student will score over 700 on the SAT math test.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Question a:

SAT, so mean of 480 and standard deviation of 100, that is, [tex]\mu = 480, \sigma = 100[/tex]

The proportion is the p-value of Z when X = 550. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{550 - 480}{100}[/tex]

[tex]Z = 0.7[/tex]

[tex]Z = 0.7[/tex] has a p-value of 0.758.

0.758*100% = 75.8%

75.8% of students would score less than 550 in a typical year.

b. What would the engineering school set as comparable standard on the ACT math test?

ACT, with a mean of 18 and a standard deviation of 6, so [tex]\mu = 18, \sigma = 6[/tex]

The comparable score is X when Z = 0.7. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.7 = \frac{X - 18}{6}[/tex]

[tex]X - 18 = 0.7*6[/tex]

[tex]X = 22.2[/tex]

The comparable standard would be a minimum ACT score of 22.2.

c. What is the probability that a randomly selected student will score over 700 on the SAT math test?

This is 1 subtracted by the p-value of Z when X = 700, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{700 - 480}{100}[/tex]

[tex]Z = 2.2[/tex]

[tex]Z = 2.2[/tex] has a p-value of 0.9861.

1 - 0.9861 = 0.0139

0.0139 = 1.39% probability that a randomly selected student will score over 700 on the SAT math test.

Answer:

Should be (B)

01-1020

ED2021

The correct label for the population is 1 - 1020,

Option A is the correct answer.

It is the way of choosing a number of required items from a number of population given.

Each items has an equal probability of being chosen.

We have,

The population in this case refers to the entire group of interest, which is the entire student body of the school.

The total number of students is 1,020.

The population is usually labeled with a range or interval that includes all the possible values of the variable of interest.

In this case, the variable of interest is whether or not a student has an opinion on parking.

The correct label for the population is 1-1020, as this range includes all possible student identification numbers at the school.

The other options (01-1020, 001-1020, and 0001-1020) are not correct because they suggest that there are leading zeros in the student identification numbers, which is not usually the case.

Thus,

The correct label for the population is 1-1020,

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Bar graphs are used to represent data, where the vertical axis represents the frequency and the horizontal axis.

The percentage that is over 50 is 15.6%:

The data on the bar graph can be represented as:

Under 17 [tex]\to[/tex] 25

18 - 24 [tex]\to[/tex] 35

25 - 34 [tex]\to[/tex] 40

35 - 50 [tex]\to[/tex] 35

Over 50 [tex]\to[/tex] 25

So, the total customer surveyed are:

[tex]Total = 25 + 35 + 40 + 35 + 25[/tex]

[tex]Total = 160[/tex]

The percentage over 50 are:

[tex]\%Over\ 50 = \frac{Over\ 50}{Total } * 100\%[/tex]

[tex]\%Over\ 50 = \frac{25}{160} * 100\%[/tex]

[tex]\%Over\ 50 = 0.15625* 100\%[/tex]

[tex]\%Over\ 50 = 15.625\%[/tex]

Approximate

[tex]\%Over\ 50 = 15.6\%[/tex]

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Answer:

x = 74.74 m

Step-by-step explanation:

you need simple trigonometry to solve it

cosine of an angle is the ratio of the adjacent side to the hypotenuse

cos(42.2) is about 0.74

so X / Hypotenuse = 0.74

we know hypotenuse is 101 m

X / 101 = 0.74

x = 74.74 m

hope this helped!

Answer:

Cluster Sampling

Step-by-step explanation:

Cluster Sampling involves the random sampling of observation or subjects, which are subsets of a population. Cluster analysis involves the initial division of population subjects into a number of groups called clusters . From the divided groups or clusters , a number of groups is then selected and it's elements sampled randomly. In the scenario above, the divison of the population into towns where each town is a cluster. Then, the selected clusters (12) which are randomly chosen are analysed.

Answer:

7.5 pi

Step-by-step explanation:

The formula for arc length of a sector is denoted as

[tex]\frac{x}{360}2\pi r[/tex], where x is the central angle of the sector.

Since the sector is 3/4 of a circle, the central angle will be 3/4 of 360 degrees.

3/4 of 360 is 270, so we have our central angle. We also have our radius which we can plug into the formula.

[tex]\frac{270}{360}2(5)\pi[/tex]

2 times 5 is equal to 10, and 270/360 simplifies to 3/4. 3/4 times 10 is equal to 7.5, so the answer is 7.5 pi

9514 1404 393

Answer:

  D.  y=2x+6​

Step-by-step explanation:

The line cannot intersect the parabola if it has a y-intercept greater than 5 and a suitable slope. The only sensible answer choice is ...

  y = 2x +6

Answer:

D. y = 2x + 6.

Step-by-step explanation:

The required equation would not intersect the parabola at any point.

The only one to fit that is D.

9514 1404 393

Answer:

Step-by-step explanation:

The average cost is the total cost divided by the number of units produced:

  average cost = C/x = 100/x -5 +7x

__

The marginal cost is the derivative of the total cost function.

  marginal cost = -5 +14x

Answer:

Permutation. ; 83810 ways

Step-by-step explanation:

Permutation and combination methods refers to mathematical solution to finding the number of ways of making selection for a group of objects.

Usually, selection process whereby the order of selection does not matter are being treated using permutation, while those which takes the order of selection into cognizance are calculated using combination.

Here, selecting 2 members (president and vice president) from 290 ; since order of arrangement does not matter, we use permutation ;

Recall :

nPr = n! ÷ (n - r)!

Hence,

290P2 = 290! ÷ (290 - 2)!

290P2 = 290! ÷ 288!

290P2 = (290 * 289) = 83810 ways

Answer: [tex]90\sqrt[3]{90}+87[/tex]

Step-by-step explanation:

[tex]qqq=90\\q^3=90\\\sqrt[3]{q^3} =\sqrt[3]{90}\\q= \sqrt[3]{90}\\\\qqqq+87\\q^3q^1+87\\90\sqrt[3]{90}+87[/tex]

Answer: Choice A.)   88.2 < μ < 93.0

=============================================================

Explanation:

We have this given info:

Because n > 30 and because we know sigma, this allows us to use the Z distribution (aka standard normal distribution).

At 99% confidence, the z critical value is roughly z = 2.576; use a reference sheet, table, or calculator to determine this.

The lower bound of the confidence interval (L) is roughly

L = xbar - z*sigma/sqrt(n)

L = 90.6 - 2.576*8.9/sqrt(92)

L = 88.209757568781

L = 88.2

The upper bound (U) of this confidence interval is roughly

U = xbar + z*sigma/sqrt(n)

U = 90.6 + 2.576*8.9/sqrt(92)

U = 92.990242431219

U = 93.0

Therefore, the confidence interval in the format (L, U) is approximately (88.2, 93.0)

When converted to L < μ < U format, then we get approximately 88.2 < μ < 93.0 which shows that the final answer is choice A.

We're 99% confident that the population mean mu is somewhere between 88.2 and 93.0

Answer:

(-5,-37)

(-4,-34)

(-3,-31)

(-2,-28)

(-1,-25)

(0,-22)

(1,-19)

(2,-16)

(3,-13)

(4,-10)

(5,-7)

(6,-4)

Step-by-step explanation:

y - 10 = 3(x - 11)

y - 10 = 3x - 33

y = 3x -22

Answer:

II and II only.

Step-by-step explanation:

The first series converges because the common ratio r is 0.8 (<1).

II diverges as |r| > 1.

III is an alternating series with r = -4 - that is |r| = 4 so it diverges.

From the given-series, the series which diverges are : (ii) 4 + 8 + 16 + 32; and (iii) 2 - 8 + 32 - 128 + ..., So, correct option is (a) (ii) and (iii) only.

In option (ii), the series 4 + 8 + 16 + 32 is a geometric series with a common ratio of 2. We see that the "common-ratio" is greater than 1, this series diverges.

In option (iii), the series 2 - 8 + 32 - 128 is a geometric series with a common-ratio of |-4| = 4. We see that the "absolute-value" of the "common-ratio" is greater than 1, this series also diverges.

But, in option (i), the series -9.2 - 7.36 - 5.888 - 4.7104 is a geometric series with a common ratio of |-0.8| = 0.8. Since the "absolute-value" of the "common-ratio" is less than 1, this series converges.

Therefore, the correct answer is (a) (ii) and (iii) only.

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Answer:  [tex]P = \frac{25}{E^2}-Q\\\\[/tex]

Work Shown:

[tex]E = 5\left(\sqrt{\frac{1}{P+Q}}\right)\\\\5\left(\sqrt{\frac{1}{P+Q}}\right) = E\\\\\sqrt{\frac{1}{P+Q}} = \frac{E}{5}\\\\\frac{1}{P+Q} = \left(\frac{E}{5}\right)^2\\\\\frac{1}{P+Q} = \frac{E^2}{25}\\\\P+Q = \frac{25}{E^2}\\\\P = \frac{25}{E^2}-Q\\\\[/tex]

Step-by-step explanation:

Answer:

No solution.

Step-by-step explanation:

[tex]{ \sf{y = ±∞ \: \: and \: \: x = ±∞}}[/tex]

g(x) = (x - 13)^2 + 84

= x^2 - 26x + 169 + 84

= x^2 - 26x + 253