Round off your answer to one decimal place.

Round Off Your Answer To One Decimal Place.

Answers

Answer 1

Answer: 10.4

Explanation:

ph is just as follows:

[tex]pH = -log[H_{3}O^{+}][/tex]

So plugging in our concentration we get:

[tex]-log(4.45*10^{-11})=10.35163999...[/tex]

Then rounding to one decimal place takes us to pH = 10.4


Related Questions

Define an ideal gas and explain under which conditions you may reasonably approximate a real gas as an ideal gas. Also mention conditions under which it would be inappropriate to approximate a real gas as an ideal gas. (you may need to use a search engineto help you out here)

Answers

Answer:

High temperature and low pressure

Explanation:

According to the kinetic molecular theory, gases are composed of small particles called molecules which are in constant motion.

At high temperature and low pressure, gas molecules possess high kinetic energy and move at high velocities hence intermolecular interaction is almost none existent and real gases approach the behavior of ideal gases.

What is the solubility of salt at 60°C if 2 gm of the salt is left behind when 7 gm of its saturated solution at that temperature dried?
a) 20
b) 40
c) 60
d) 80 ​

Answers

40

Explanation:

because its Saturated

For the metal Mg 109.5g solution HCl 10%. a) Case of metal b) Its properties

Answers

Answer:

Explanation:

mg +2hcl=mgcl2 +h2

mhcl=10.95g

nhcl==0.3

nmg=1/2nhcl=0.15

mMg=3.6g

m mgcl2=14.25

what volume of 2.0 m hcl contains 0.50 mol hcl?

Answers

Answer:

the volume of the acid is 250 mL.

Explanation:

Given;

number of moles of the Hcl acid, n = 0.5 mol

concentration of the acid, C = 2.0 M = 2 mol/L

let the volume of the acid = V

The volume of the acid is calculated by applying the following equation;

n = CV

V = n/C

[tex]V= \frac{0.5 \ mol}{2 \ mol/L}[/tex]

V = 0.25 L

V = 250 mL

Therefore, the volume of the acid is 250 mL.

Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.

Answers

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

Equivalentes KOH:

0.100L * (1eq / L) = 0.100eq = 0.100moles

Gramos KOH -Masa molar: 56.1056g/mol-:

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

KOH 90%:

5.61g KOH * (100g KOH 90% / 90g KOH) =

6.23 KOH 90% son necesarios

(Q008) Two physical properties of minerals both result in smooth, flat surfaces with specific angles between them. The first property is externally visible and is the result of how the mineral forms; the second is inherently internal and is the result of breaking a sample of the mineral. These properties are called

Answers

Answer: Crystal habit and cleavage.

Explanation:

When two physical properties of minerals both bring about smooth, flat surfaces that has specific angles between them.such that the first property is externally visible and is the result of how the mineral forms while the second property is internal and is the result of breaking a sample of the mineral, it should be noted that the properties are refered to as the crystal habit and cleavage.

It should be noted that the cleavage refers to the tendency of crystalline materials to be able to split along the structural planes.

Which group of elements is generally unreactive? O A. Noble gases O B. Halogens O C. Alkali metals D. Nitrogen family

Answers

Answer:

Nobles Gases Are the group of elements which are generally unreactive

I Hope its right if not then Sorry, have a wonderful day :)

What volume of O2 is required to completely burn 15cm3 of pentane? Equation - C5H12 + O2 - CO2 + H2O.​

Answers

Answer:

The volume of [tex]\rm O_2[/tex] required would be [tex]120\; \rm cm^{3}[/tex], assuming that both the pentane and the [tex]\rm O_2\![/tex] in this question are ideal gases and are under the same temperature and pressure.

Explanation:

Balance the equation for the reaction:

[tex]\rm ?\; C_{5}H_{12} + ?\; O_2 \to ?\; CO_{2} + ?\; H_{2}O[/tex].

Start by setting the coefficient of the molecule with the largest number of atoms to [tex]1[/tex].

In the combustion of alkanes (including pentane,) consider setting the coefficient of the alkane to [tex]1\![/tex].

[tex]\rm 1\; C_{5}H_{12} + ?\; O_2 \to ?\; CO_{2} + ?\; H_{2}O[/tex].

Number of carbon atoms among the reactants: [tex]5[/tex].

Number of hydrogen atoms among the products: [tex]12[/tex].

By the conservation of atoms, there would need to be the same number of carbon and hydrogen atoms (along with the oxygen atoms) among the products.

Hence, the coefficient of [tex]\rm CO_2[/tex] would be [tex]5[/tex] while the coefficient of [tex]\rm H_2O[/tex] would be [tex]12 / 2 = 6[/tex].

[tex]\rm 1\; C_{5}H_{12} + ?\; O_2 \to 5\; CO_{2} + 6\; H_{2}O[/tex].

There would be [tex]5 \times 2 + 6 \times 1 = 16[/tex] oxygen atoms among the products. Also by the conservation of atoms, there would be the same number of oxygen atoms among the reactants.

Hence, the coefficient of [tex]\rm O_2[/tex] would be [tex]16 / 2 = 8[/tex].

[tex]\rm 1\; C_{5}H_{12} + 8\; O_2 \to 5\; CO_{2} + 6\; H_{2}O[/tex].

The ratio between the coefficient of [tex]\rm O_2[/tex] and [tex]\rm C_{5}H_{12}[/tex] in the balanced equation is:

[tex]\displaystyle \frac{n({\rm O_2})}{n({\rm C_{5}H_{12}})} = \frac{8}{1} = 8[/tex].

In other words, it would take eight [tex]\rm O_2[/tex] molecules to react with one [tex]\rm C_{5}H_{12}[/tex] molecule.

Assume that both [tex]\rm O_2[/tex] and [tex]\rm C_{5}H_{12}[/tex] are ideal gases. Under the same temperature and pressure, the volume of the two gases would be proportional to the number of molecules in each gas:

[tex]\displaystyle \frac{V({\rm O_2})}{V({\rm C_{5}H_{12}})} = \frac{n({\rm O_2})}{n({\rm C_{5}H_{12}})} = \frac{8}{1} = 8[/tex].

In other words, it would take [tex]8\; \rm cm^{3}[/tex] of [tex]\rm O_2[/tex] to react with [tex]1\; \rm cm^{3}[/tex] of [tex]\rm C_{5}H_{12}[/tex] under these assumptions. It would then take [tex]8 \times 15\; \rm cm^{3} = 120\; \rm cm^{3}[/tex] of [tex]\rm O_2\![/tex] to react with [tex]15\; \rm cm^{3}\![/tex] of [tex]\rm C_{5}H_{12}\![/tex].

I need help getting this done

Answers

Answer:

I put the right structures in the pictures for you

what is true about solubility

Answers

Explanation:

Solubility is defined as a property of solutes by virtue of which they get dissolved in a favorable solvent. The solute can only be dissolved in any suitable solvent up to a limit at a given temperature. This is a characteristic of the the solute-solvent pairing.

What is the standard reduction potential, E, for the half-reaction Al3+ (aq)

3e- -> Al(s)?

Answers

Answer:

E° = -1.66 V

Explanation:

The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.

From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;

E° = -1.66 V

What is the molecular geometry of a molecule made of two atoms that share one pair of electrons and have no lone electrons pairs?

trigonal pyramidal
linear
trigonal planar
bent

Answers

Answer:

linear

Explanation:

Actually I consulted various sources too and that was the most sought answer,I just decided to answer you before studying it too

Freezing point depression is:

A. When a substance freezes and then quickly drops in temperature.
B. When a substance drops in temperature until it freezes, then quickly rises in temperature but stays frozen.
C. When a substance does not need to be as cold as normal in order to freeze.
D. When a substance must be colder than normal in order to freeze.

Answers

Freezing point depression is when a substance must be colder than normal in order to freeze.

Freezing point is that temperature where a liquid substance becomes a solid i.e. freezes. Freezing point depression is the process whereby the temperature at which a substance freezes is lowered.

Freezing point depression often occurs when a solute is added to a solvent. This reduces its freezing point. Since temperature is reduced, in other words, this means that the substance must become colder than normal for it to start freezing.

Hence, freezing point depression is when a substance must be colder than normal in order to freeze.

Learn more at: https://brainly.com/question/2785367

D. When a substance must be colder than normal in order to freeze.

Explanation:

hey love, I just took the quiz on this for founder's education. I hope this helped.

Is the following change an oxidation or reduction?

manganese (IV) oxide to manganese (III) oxide.​

Answers

Answer:

12113

Explanation:

step by step:no

Unknown # 29

Flame Test Color: Green
Addition of HCl(aq): Bubbles
Addition of HCl(aq) and BaCl2(aq): NR (No Reaction)
Addition of HNO3(aq) and AgNO3(aq): White precipitate

What is the unknown ionic compound molecular formula?

Answers

Answer:

I think it's a sulphate ion, because when you add hydrochloric acid to it it produces bubbles and when you add barium chloride it then produces a white precipitate.its formula is SO4

I hope this helps

Chất tinh khiết là:

A. Có tính chất thay đổi

B. Có lẫn thêm vài chất khác

C. Gồm những phân tử đồng dạng

D. Không lẫn tạp chất

Answers

Answer:

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over.

fd

Which of the following describes metallic character on the periodic table? Question 1 options: A) It increases as you move right to left within a period and down a group on the periodic table. B) It increases as you move left to right within a period and down a group on the periodic table. C) It increases as you move left to right within a period and up a group on the periodic table. D) It increases as you move right to left within a period and up a group on the periodic table.

Answers

Answer:

D

Explanation:

Metallic character decreases as you move across a period in the periodic table from left to right. This occurs as atoms more readily accept electrons to fill a valence shell than lose them to remove the unfilled shell. Metallic character increases as you move down an element group in the periodic table. This is because electrons become easier to lose as the atomic radius increases, where there is less attraction between the nucleus and the valence electrons because of the increased distance between them.

Where does reduction occur in an electrochemical cell?

Answers

Answer:

The cathode is the electrode where reduction takes place.

so

reduction occur in Cathode in an electrochemical cell.

Answer: Cathode

Explanation:

.

C4H9OH have several isomers. Draw structure and IUPAC names of its three isomers.​

Answers

Answer:

.

Explanation:

11. A mixture of magnesium powder and lead (II) Oxide will react vigorously when heated but no reaction occurs when a mixture of magnesium oxide and lead powder are heated, a) Explain the observation. b Which of the two substances, magnesium or lead(IT) Oxide is; i) Oxidized in the reaction? ii) Oxidizing agent? C Which is the most reactive metal Please helpA

Answers

Answer:

17

Explanation:

i need points

Which statement is true?

A. In an exothermic reaction, the energy of the products is the same as the energy of the reactants.

B. In an endothermic reaction, the energy of the products is the same as the energy of the reactants.

C. In an endothermic reaction, the energy of the products is greater than the energy of the reactants.

D. In an exothermic reaction, the energy of the products is greater than the energy of the reactants.

Answers

Exothermic reaction is where there is release of energy during a reaction

The enthalpy of exothermic reaction is negative

The relation between energy of products, reactants and enthalpy of reaction is

Enthalpy of reaction =  sum of enthalpy of formation of products - sum of enthalpy of formation of reactants .

As enthalpy of reaction is negative, it means the enthalpy of products is less than the enthalpy of reactants  so answer is :

In an exothermic reaction the energy of the product is less than the energy of the reactants.

C.

An endothermic reaction is a reaction that absorbs heat from the surroundings. That means that the energy of the system must increase. Therefore, the answer must be C as the products should have higher energy than the reactants.

19. If 23.4 grams of hydrogen gas were produced by the reaction below, how many grams of aluminum chloride were produced? (2 points) 2 Al + 6 HCl yields 2 AlCl3 + 3 H2 516 g AlCl3 774 g AlCl3 1030 g AlCl3 1550 g AlCl3

Answers

Answer:

1040

Explanation:

you can use the mole to mole ratios of aluminum chloride and hydrogen gas,you first have to find the number of moles of hydrogen gas..the number of moles of hydrogen gas are 11.7(23.4/2)

2AlCl3+3H2

2 : 3

x :11.7

3x/3=23.4/3

x=7.8g/mol

then find the number of grams of aluminum chloride

m=n×mr

=7.8×133.341

=1040g

I hope this helps and sorry if it's wrong

Each orbital can contain no more than 2 electrons. This is:
O A. Conservation of energy
OB. The Pauli exclusion principle
C. None of these
D. Hund's rule

Answers

The Pauli exclusion principle.

Answer: B. The Pauli exclusion principle.

Explanation: Founders Educere answer ;)

3. What would be the freezing point for a 5.7 molal aqueous sucrose (C12H22O) solution? The freezing
point depression constant for water = 1.86°C/m. Show your work.

Answers

Answer:

- 10.6° C

Explanation:

Given that,

In the aqueous sucrose solution,

Molality of the solution (m) = 5.7

Freezing point constant (K) = 1.86

To find,

The freezing point of the solution = ?

Method:

To find its freezing point, we will first find out if the solute demonstrates an electrolyte or not.

In case it is not, the van't Hoff factor i.e. ration of particles' concentration denoted by (i) would be taken as 1. So,

ΔT(change in temperature) = i * m * K              (putting the given values)

= 1 * 5.7 * 1.86

= 10.6° C

Thus, the freezing point equals to 0 - 10.6° C = -10.6° C.

from the equation 2PbO + C = 2Pb + CO2, detemine which one is reactant is oxidised and which is reduced.​

Answers

Answer:

Explanation:

C is oxidised because C up to C+4

PbO is reduced because PbO from Pb2+ down to Pb0

Answer:

lead (Pb) is reduced carbon is oxidized

How many grams of solute is there in 250 mL of a 0.10M CaCl2 solution ?

Answers

Answer:

2.775 g

Explanation:

Given that;

Number of moles = concentration × volume

Concentration = 0.10M

Volume =250 mL

Number of moles = 250/1000 × 0.10

Number of moles = 0.025 moles

Also;

Number of moles = mass/molar mass

Molar mass of CaCl2= 111 g/mol

Mass = Number of moles × molar mass

Mass = 0.025 moles × 111 g/mol

Mass= 2.775 g

A student is asked to convert measurements from meters to millimeters and from millimeters to meters. His answers are
shown in bold in the choices shown below. On which choite did he make a mistake?
9070 mm = 90.7 m
652,222 mm= 652.222 m
37,500 mm = 37.5 m
1.02 x 106 mm = 1020 m

Answers

Answer:

The first one

Explanation:

9070 mm = 90.7 m

9070mm is actually equal to 9.07m

A 240g hydrated sodium sulphide contains 162g of water of crystallisation. What is the correct molecular formula for this compound?
What is the answer and working

Answers

Answer:

Explanation:

First of all, 1 mol of Sodium Sulphide has molecular mass of

S = 32

Na2 = 2*23 = 46

The formula of NaS is actually Na2S. It's molecular mass = 78

How many grams of Na2S are present

Grams present = 240 - 162 = 78 which is exactly 1 mol.

The remainder is water.

The molecular mass of water = 2 + 16 = 18

162 grams of water = 162/18 = 9 mols of water.

So the correct formula is Na2S*9H20

What is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water?

Answers

The answer is 29.7% view on how to solve

The mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water is 29.7%.

What is mass percent ?

Mass percent is a means to describe a component in a specific combination or to convey a concentration. The mass percentage used to describe the solution composition indicates the mass of solute contained in a given mass of solution.

To determine the mass percent of an element in a compound, we divide the mass of the element in one mole of the compound by the compound's molar mass and multiply the result by 100.

Given:

Number of moles = 0.64 moles

Moles of sodium fluoride = Given mass/molar mass

0.64 moles = Mass / 42

Mass = 26.88gram

Mass % = Mass of solute/ mass of solution × 100

= 26.88/90.48 × 100

= 29.7 %

Thus, 29.7 % is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water

To learn more about the mass percent, follow the link;

https://brainly.com/question/5394922

#SPJ6

calculate molarity, molality and mole fraction of 28 percent aqueous solution of a solute with molar mass 11.5 g per mole and density is 1.25 g per mole

Answers

Explanation:

Aight, I'mma give tell ya an easy way for this question. look at this Forumla

M=

[tex] \frac{10ad}{m} [/tex]

a explains the percentage of aqueous solution

d is the density

m is the molar mass

right, let's just hop to it

M=10×28×1.25/11.5====> M=30.43

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