Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large run of resistors of 1,000 ohms each. Use Exhibit 10.13. To set up the machine and to create a control chart to be used throughout the run, 15 samples were taken with four resistors in each sample. The complete list of samples and their measured values are as follows: Use three-sigma control limits. SAMPLE NUMBER READINGS (IN OHMS) 1 1027 994 977 994 2 975 1013 999 1017 3 988 1016 974 997 4 998 1024 1006 1010 5 990 1012 990 1000 6 1016 998 1001 1030 7 1000 983 979 971 8 973 982 975 1030 9 992 1028 991 998 10 997 1026 972 1021 11 990 1021 1028 992 12 1021 998 996 970 13 1027 993 996 996 14 1022 981 1014 983 15 977 993 986 983 a. Calculate the mean and range for the above samples.

Answers

Answer 1

Answer:

See explanation

Step-by-step explanation:

Given

See attachment for proper presentation of question

Required

Mean and Range

To do this, we simply calculate the mean and the range of each row.

[tex]\bar x = \frac{\sum x}{n}[/tex] ---- mean

Where:

[tex]n = 4[/tex] ---- number of rows

[tex]R = Highest - Lowest[/tex] --- range

So, we have:

Sample 1

[tex]\bar x_1 = \frac{1027+ 994 +977 +994 }{4}[/tex]

[tex]\bar x_1 = 998[/tex]

[tex]R_1 = 1027- 994[/tex]

[tex]R_1 = 33[/tex]

Sample 2

[tex]\bar x_2 = \frac{975 +1013 +999 +1017}{4}[/tex]

[tex]\bar x_2 = 1001[/tex]

[tex]R_2 = 1017 - 975[/tex]

[tex]R_2 = 42[/tex]

Sample 3

[tex]\bar x_3 = \frac{988 +1016 +974 +997}{4}[/tex]

[tex]\bar x_3 = 993.75[/tex]

[tex]R_3 = 1016-974[/tex]

[tex]R_3 = 42[/tex]

Sample 4

[tex]\bar x_4 = \frac{998 +1024 +1006 +1010}{4}[/tex]

[tex]\bar x_4 = 1009.5[/tex]

[tex]R_4 = 1024 -998[/tex]

[tex]R_4 = 26[/tex]

Sample 5

[tex]\bar x_5 = \frac{990 +1012 +990 +1000}{4}[/tex]

[tex]\bar x_5 = 998[/tex]

[tex]R_5 = 1012 -990[/tex]

[tex]R_5 = 22[/tex]

Sample 6

[tex]\bar x_6= \frac{1016 + 998 +1001 +1030}{4}[/tex]

[tex]\bar x_6= 1011.25[/tex]

[tex]R_6= 1030-998[/tex]

[tex]R_6= 32[/tex]

Sample 7

[tex]\bar x_7 = \frac{1000 +983 +979 +971}{4}[/tex]

[tex]\bar x_7 = 983.25[/tex]

[tex]R_7 = 1000-971[/tex]

[tex]R_7 = 29[/tex]

Sample 8

[tex]\bar x_8 = \frac{973 +982 +975 +1030}{4}[/tex]

[tex]\bar x_8 = 990[/tex]

[tex]R_8 = 1030-973[/tex]

[tex]R_8 = 57[/tex]

Sample 9

[tex]\bar x_9 = \frac{992 +1028 +991 +998}{4}[/tex]

[tex]\bar x_9 = 1002.25[/tex]

[tex]R_9 = 1028 -991[/tex]

[tex]R_9 = 37[/tex]

Sample 10

[tex]\bar x_{10} = \frac{997 +1026 +972 +1021}{4}[/tex]

[tex]\bar x_{10} = 1004[/tex]

[tex]R_{10} = 1026 -972[/tex]

[tex]R_{10} = 54[/tex]

Sample 11

[tex]\bar x_{11} = \frac{990 +1021 +1028 +992}{4}[/tex]

[tex]\bar x_{11} = 1007.75[/tex]

[tex]R_{11} = 1028 -990[/tex]

[tex]R_{11} = 38[/tex]

Sample 12

[tex]\bar x_{12} = \frac{1021 +998 +996 +970}{4}[/tex]

[tex]\bar x_{12} = 996.25[/tex]

[tex]R_{12} = 1021 -970[/tex]

[tex]R_{12} = 51[/tex]

Sample 13

[tex]\bar x_{13} = \frac{1027 +993 +996 +996}{4}[/tex]

[tex]\bar x_{13} = 1003[/tex]

[tex]R_{13} =1027 -993[/tex]

[tex]R_{13} =34[/tex]

Sample 14

[tex]\bar x_{14} = \frac{1022 +981 +1014 +983}{4}[/tex]

[tex]\bar x_{14} = 1000[/tex]

[tex]R_{14} = 1022 -981[/tex]

[tex]R_{14} = 41[/tex]

Sample 15

[tex]\bar x_{15} = \frac{977 +993 +986 +983}{4}[/tex]

[tex]\bar x_{15} = 984.75[/tex]

[tex]R_{15} = 993-977[/tex]

[tex]R_{15} = 16[/tex]


Related Questions

Mrs. Harris treated her 1st period with donuts for averaging the highest on the midterm exam. She bought 25 donuts, By the end of the period, there were 3 donuts remaining. What is the percent decrease?

Answers

Answer:

88% decrease

Step-by-step explanation:

3 is only 12% of 25 so there was a 88% decrease

The Kicking Cacti and the Sprinting Stingrays met in their town's annual kickball championship this year. They were so evenly matched that the game lasted 11 innings! The Stingrays had 3 pitchers, and each of them pitched for the same number of innings.
How long did each of the pitchers for the Stingrays pitch?

Answers

Answer:

11/3 = 3 2/3 innings

Step-by-step explanation:

3 pitchers = 11 innings

1 pitcher = x innings

in the first equation, divide both sides by 3 to get 1 pitcher on one side

1 pitcher = 11/3 innings = 3 2/3 innings

What is the mean , median , and sum

Answers

Step-by-step explanation:

sum was the first name of integral

and the median is something in the middle

for example :

A . B . C

the median is B

Find x given the prism has a surface area of 286 in². Explain your thoughts

Answers

Answer:

h

=

3

r

=

4

h

=

2

r

=

6

h

=

4

l

=

4

w

=

4

Step-by-step explanation:

The variables x and y are directly
related. When x=15, y = 6. What is the
value of x when y = -4?

Answers

Answer: When y = -4, x = -10.

Explanation:
The equation for direct variation is y = kx^n, where k is the constant of variation. n is the exponent above the x value, but since this problem doesn’t involve exponents greater than one, we can ignore it.

First, find k.
y = kx
6 = k*15
k = 6/15 or 2/5

Now, we can solve for any x or y input. Let’s find x when y = -4.
y = kx
-4 = 2/5 * x
(to cancel out the fraction, multiply each side of the equation by its reciprocal, 5/2)
x = -4 * 5/2
x = -20/2
x = -10

what is 1/4 of 5/6???

Answers

you search the LCD then you subtracted the top and left the bottom the same

Step-by-step explanation:

im not sure

hi so my teacher gave me this and i am not sure if i did it right, this is what i put for the first Question
degree = 3
leading coefficient = 1
and the it is the arrows are going up/down so its a odd degree
and i put that the answer is d i did the rest like this please tell me where i went wrong/if i did

Answers

Answer:

First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients:❤

Which item produces the magnetic field in the electromagnet?
A-paperclips
B- a switch
C-paint brushes
D- a magnet

Answers

Answer:

Its ethier a switch or magnet

Pls answer will give brainiest

Answers

Answer:

8/15

Step-by-step explanation:

1/5 + 1/3 = 3/15 + 5/15 = 8/15

PLEASE ANSWER FOR 30 POINTS

Answers

Answer:

One Solution

Step-by-step explanation:

x + 3y = 3      

x - y = -3        

4y = 6           Subtract to solve by elimination.

y = [tex]\frac{3}{2}[/tex]              Divide by 4.

x - [tex]\frac{3}{2}[/tex]  = -3      Substitute [tex]\frac{3}{2}[/tex] for y in the original equation.

x = -[tex]\frac{3}{2}[/tex]            Add [tex]\frac{3}{2}[/tex].

7+x÷y is a ______( type of polynomial)​

Answers

Answer:
I’m pretty sure this would be classified as a binomial
Hope this helps!

Planes A and B are shown.
If a new line, p, is drawn parallel to line I, which
statement is true?
ZA
O Line p must be drawn in plane B.
O Line p must be perpendicular to line m.
O Line p must be drawn so that it can lie in the same
plane as line 1
O Line p must be drawn in the same plane as line n.
m

Answers

B. line p must be tge perpendicular to line M

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=−16x^2+160x+150

Answers

Answer:

Answer below

Step-by-step explanation:

Time can not be negative from any perspective. Hence, the correct answer is 10.16 seconds.

The equation of the path of a rocket is given that is  y= x^2 + 153x + 98

We need to determine the time that the rocket will hit the ground.

Now, if the rocket hits the ground after the launching then the overall displacement at the time of hitting the ground will be zero.

Therefore, the value of y is 0.

Thus,  -16x^2 +153x + 98 = 0

Now, the formula for finding the roots of the quadratic equation  

 ax^2 +bx +c = 0 is given as:

 [tex]x^{1} =\frac{-b+\sqrt{b^2 -4ac} }{2a}[/tex]

[tex]x^2 = \frac{-b -\sqrt{b^2 -4ac} }{2a}[/tex]

Comparing the expression with the standard form of the equation.

a = -16b = 153 and c = 98

By applying the formula there are two values are come that is,

x^1 = -0.602555

x^2 = 10.1651  

Time can not be negative from any perspective.

Hence, the correct answer is 10.16 seconds.

———————————————————————————————————————-

(Hope this helps can I pls have brainlist (crown)☺️)

HELP PLS, ill reward w brainlist or whatever those things r JUST HELP

Answers

Answer:

I am not exactly sure of the answer, i am just trying to help

I think the angle O is 135

The triangle BOC is a right angle triangle which means that O is 90 degrees so when K splits it in half it becomes 45 degrees in both BOK and COK. The triangle you are asked to find the angle of is AOK so the 45 degrees from the BOK triangle and add it to the the 90 degrees from the BOA triangle you will get 135 degrees for the angle O in the triangle AOK.

I dont know if you understan what i am trying to say

The hypotenuse is NOT located across from the right angle

True or false

Answers

The statement, The hypotenuse is NOT located across from the right angle is false.

What is a right angled triangle?

A right-angled triangle is a type of triangle that has an angle that measures 90 degrees. The triangle has three sides. The hypotenuse is the longest side of a right-angled triangle. Other sides are the base and the length. The sum of sides in a a right-angled triangle is 180 degrees.

Please find attached an image of a right-angled triangle. To learn more about  a triangle, please check: https://brainly.com/question/9329354


88, 89, 86, 90, 83, 81, 89
What is the median number
A 88
B. 89
C 90
D. 86

Please answer this I really need help

Answers

Answer:

The answer is 90.

Step-by-step explanation:

90 is in the middle

Answer:

d

Step-by-step explanation:

cause i said so

I was absentee and i dont know how to solve it help plz

Answers

Answer:

-1/3 or 1/-3 (it doesn't matter which one you pick because its still the same)

Step-by-step explanation:

You find slope by doing rise over run. Its left to right so you start on the left dot and go down one. This makes it -1 because you're going down, not up. You move 3 to the right which makes it positive. Once you do this itll lead you right the the 2nd point. 1 down= -1

                                       3 right=   3  

                                                -1/3

A shed has dimensions of 12m in length and 5 m in width. Both the length and width are increased by the same amount in order to increase the floor area by more than double the original area?

Answers

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

The amount that can be added to both the length and the width to increase the floor area by more than double the original area is more than 3 meters.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, the amount by which both the length and the width can be increased to more than double the area is x > 3 meters

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Can you help me w this

Answers

x/3-2=6

+2

x/3=8

*3

x=24

x/5+1=5

-1

x/5=4

*5

x=20

Answer:

Step-by-step explanation:

a)

(x / 3) - 2 = 6

add 2 to both sides

x / 3 = 8

multiply both sides by 3

x = 24

b)

(x / 5) + 1 = 5

subtract 1 from both sides

(x / 5) = 4

multiply both sides by 5

x = 20

7. (6 points) For the following geometric sequence, 3 ,- 1, 1/3,-1/9, …
Find the formula for the nth term

Answers

Answer:

The formula of the nth term is a₇=48(1/2)⁷⁻¹=48×1/64=3/4

Step-by-step explanation:

Big Sam, an engineer of the Oval Express says: "We blew off a cylinder head an hour after leaving the station and had to continue the trip at three-fifths of the former speed, which brought us in two hours late. If the accident had occurred fifty miles father on, the train would have arrived forty minutes sooner". Based on Sam's description, how long was the run between the two train stations?
A. 150 miles
B. 200 miles
C. 250 miles
D. 300 miles

Answers

Answer is B. 200 miles

{(y/50)+2} hour=y/30 hour gives y=150 miles. Since, the train already had covered 50 miles at full-speed before the cylinder blew, so the run between the stations was 50+150=200 miles.

Answer:

Ig 200 miles

Step-by-step explanation:

I am guessing

Ms.Gómez ran 3/5 of a mile in 5 minutes. Mr. Hernández ran 3/5 of a mile in 3 minutes. How far did Ms gomez and mr Hernandez each run in 1 minute?

Show work or explain

Answers

Answer:

Ms G ran 3/25 mile per minute

Mr H ran 1/5 mile per minute

Step-by-step explanation:

Ms G:

create a proportion from mile/minutes = mile/minutes

let 'm' = amount of miles

3/5÷5 = m÷1

cross-multiply to get:

3/5 = 5m

m = 3/5 × 1/5 = 3/25

Mr H:

3/5÷3 = m÷1

cross-multiply to get:

3/5 = 3m

15m = 3

m = 3/15 or 1/5

Help me with this question thanks so much

Answers

It would be 6^8 or 1,679,616
Since it’s times 6 each time and the base is 6 it can be written as an exponent 6*6*6...
Hope that helps :)

James is observing the population of the fish he put into a pond. He built a pond and
populated it with 700 fish. The population of the fish doubles every year.

Answers

The exponential equation is given by y = 700(2)ˣ

An exponential function is given by:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplier.

Let y represent the population of fish after x hours.

Given that he starts with 700 fishes, hence

a = 700

The population of the fish doubles every year, hence:

b = 2

The exponential equation becomes:

y = 700(2)ˣ

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If x is increasing at a
rate of 2 units per second,
find the rate of change of theta
at the instant when x= 12 units.

Answers

Answer:

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex] at [tex]x=12[/tex]

Step-by-step explanation:

[tex]\frac{dx}{dt}=2[/tex]

[tex]\frac{d\theta}{dt}=?[/tex]

[tex]x=12[/tex]

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]\frac{d}{dt}cos(\theta)=\frac{d}{dt}\frac{x}{13}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}\frac{dx}{dt}[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}(2)[/tex]

[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{2}{13}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]cos(\theta)=\frac{x}{13}[/tex]

[tex]cos(\theta)=\frac{12}{13}[/tex]

[tex]\theta=cos^{-1}(\frac{12}{13})[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(cos^{-1}(\frac{12}{13}))}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-13(\frac{5}{13})}[/tex]

[tex]\frac{d\theta}{dt}=\frac{2}{-5}[/tex]

[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex]

The value of θ is given by the inverse sine function, from which the rate of

change of θ with respect to x can be derived.

The rate of change of θ at the instant when x = 12 units is -0.4 rad/s

Reasons:

[tex]\displaystyle \frac{dx}{dt} = \mathbf{2 \ units \ per \ second}[/tex]

[tex]\displaystyle cos(\theta) = \frac{x}{13}[/tex]

[tex]\displaystyle \theta = arccos \left(\frac{x}{13}\right)[/tex]

[tex]\displaystyle \frac{d}{dx} \theta = \frac{d\left(arccos \left(\frac{x}{13}\right)\right)}{dx} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}}[/tex]

Using chain rule of differentiation, we have;

[tex]\displaystyle \frac{d\theta}{dt} = \mathbf{ \frac{d\theta}{dx} \times \frac{dx}{dt}}[/tex]

Therefore;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-x^2} }{x^2-169}\times \frac{dx}{dt} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}\times 2}[/tex]

When x = 12, we get;

[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-12^2} }{12^2-169}\times 2 = -\frac{2}{5} = -0.4[/tex]

The rate of change of the angle, θ, with time at the instant when x = 12 is -0.4 rad/s

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Which equation below represents an equation in standard form?

Answers

Answer:

C

Step-by-step explanation:

standard form is ax + by = c, which is true for the third option.

Someone help?
Find the problem:
-5x - 16 = 8x - 1

Fix the problem:
?

Answers

[tex]-5x -16 = 8x -1\\\\\implies 8x +5x = -16 +1 \\\\\implies 13x = -15\\\\\implies x = -\dfrac{15}{13}[/tex]

What is the change in elevation for
(3)(4)(-3.5)

Answers

Hey there!

(3)(4)(-3.5)

= 12(-3.5)

= -42

Therefore, your answer SHOULD be: -42

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Please help me! No links, cheaters, or rude comments please!

Answers

Answer:

hmm i would say its -2 and 1/2.. although i am a little rusty at this..but this is what i choose

Step-by-step explanation:

Answer:

a and d is correct I did the test and got 100 .

Work out the area of the shaded shape.

Answers

Answer:

61 m²

Step-by-step explanation:

Find the area of the whole rectangle and subtract the part that is cut off

Area =  [tex]11 *8 - 9 *(8-5)[/tex]

        = [tex]88 - 9*3[/tex]

        = [tex]88 - 27[/tex]

        = [tex]61[/tex]

Units = m * m or m²

61 m²

-Chetan K

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