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Answer:

2/3 Rupees

Step-by-step explanation:

Lets say Chocolate is C and a rupee is R.

Then, 15C = 10R. We can simplify to 3C = 2R. Now we divide both sides by Three to get C = 2/3R, which means a chocolate is 2/3 of a rupee!

Answer:

1/2      50%      $250

Step-by-step explanation:

Answer:

250$, or in fraction form, 1/2

Step-by-step explanation:

There are 2 people, so divide 1 whole by 2. Which is .5, or 1/2

Answer:

The answer is (x, y) = (x + 3, y-5)

Step by step explanation:

So y is the up and down axis while x it the side to side axis, so for y it would be 5 down (-5) and for x it would be 3 to the right (3).

Your Welcome. :)

The required solution of the equation is (2,5). The correct option is A. (2,5).

[tex]y=x+3.....(1)\\2x+y=9......(2)[/tex]

putting the value of y from eq. 1 in eq. 2 we get,

[tex]2x+x+3=9\\3x=9-3\\3x=6\\x=2[/tex]

putting the value of x=2 in eq. 1 we get,

[tex]y=2+3\\y=5[/tex]

Hence, the required solution of the equation is (2,5).

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Answer:

She would have written 6 2/3 pages.

Step-by-step explanation:

2 2/3 pages = 1 hour

6 2/3 pages = 2 1/2 hours

Answer:

(-3,8)

Step-by-step explanation:

Lets say two points are (x1,y1) and (x2,y2), the midpoint will be:

((x1+x2)/2,(y1+y2)/2)

Plugging the point A in, we get: the midpoint, (3,5) as (((9+x2)/2),(2+y2)/2)

We can assign x2 and y2 as variables.

(9+x2)/2=3

9+x2=6

x2= -3

(2+y2)/2=5

2+y2=10

y2=8

therefore we get the point (-3,8)

There are better ways and this is the "formulaic (ig) way" to do this

The midpoint of a line segment means a point which lies in the mid of the given line segment. The coordinate of point B is (-3,8).

The midpoint of a line segment means a point which lies in the mid of the given line segment.

Suppose we've two endpoints of a line segment:

A(p,q), and B(m,n)

Then let the midpoint be M(x,y) on that line segment. Then, its coordinates are:

 x = (p+m)/2

and

y = (q+n)/2

The coordinate of the midpoint (x,y)=(3,5), while the coordinate of A(p,q)=(9,2). Thus, the coordinate of point A are,

x=(p+m)/2

3=(9+m)/2

6=9+m

m = -3

y = (q+n)/2

5 = (2+n)/2

10=2+n

n=8

Hence, the coordinate of point B is (-3,8).

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Answer:

x=22, y=35

Step-by-step explanation:

since this is an isosceles triangle, 3x-11 = 2x+11. so x=22

since this is a triangle 3x-11 + 2x+11 + 2y = 180. plug in x and simplify to get 2y+110=180, so 2y=70 and y=35

Let the ceilings be a & b

and the distance from one corner of the ceiling to the opposite be c

then using Pythagoras theorem

[tex]c = \sqrt{a {}^{2} + b {}^{2} } \\ c = \sqrt{16 {}^{2} + 12 {}^{2} } \\ c = \sqrt{256 + 144 } \\ c = \sqrt{400} \\ c = 20[/tex]

hence ,c .°. the distance from one corner of the ceiling to the opposite is 20

Answer:

x =10

Step-by-step explanation:

In a parallelogram, opposite sides are congruent

QT = RS

2x - 10 = x

Add 10 to both sides

2x = x + 10

subtract 'x' from both sides

2x -x = 10

x = 10

Answer:

75. is yr correct ans.

Step-by-step explanation:

hope it helps.

stay safe healthy and happy.

Answer:

x = 75

Step-by-step explanation:

The triangle has 2 congruent sides and is therefore isosceles with 2 congruent base angles, both of measure x

The sum of the 3 angles = 180° , that is

x + x + 30 = 180

2x + 30 = 180 ( subtract 30 from both sides )

2x = 150 ( divide both sides by 2 )

x = 75

Answer:

70-x

Step-by-step explanation:

The expression which represents the change that Ingrid will get back for purchasing for $x will be 70 - x thus option (C) is correct.

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

A statement expressing the equality of two mathematical expressions is known as an equation.

As per the given,

Amount of money that Ingrid have = $70

Amount of money Ingrid purchased = $x

Change back = 70 - x

Hence "The equation that describes the change Ingrid will receive for spending $x is 70 - x".

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Answer:

20, 250

Step-by-step explanation:

3:3:2

u will first need to find the addition of all the ratio and divide each ratio by the sum

3+3+2=8

the u will; 3/8×54000=20,250

3/8×54000=20,250

2/8×54000=13500

Answer:

108 g of water

Hope This Helps!!!

Answer:

a constant is a data item whose value cannot change during the program execution just as its name implies that the value is constant a variable is a data item whose value can change during the program's execution . Thus as its name implies the the value can vary

Answer: where’s the question??

Answer:

He obtained 11.2 points

Step-by-step explanation:

He obtained 20 balls and was penalized 3 points.

If each red ball is 0.5 points off, then 3/0.5=6

6 of his obtained balls were red balls, penalizing 3 points.

So, 20-6=14

The rest of his 14 balls were green balls, each worth 0.8

So, 14 × 0.8 = 11.2

So he obtained a total of 11.2 points

Answer:

f(x)=12(1.2)x

Step-by-step explanation:

Answer:

she sold 680 chocolate chip cokies

Step-by-step explanation:

Answer:

22 years old

Step-by-step explanation:

Sarah - 49 years old

Leo - 38 years old

Mary - 22 years old

Jordan - 41 years old

 I think I'm right

Answer:

$466.62

Step-by-step explanation:

Balance = $175 - $24.39 - $65.21 + $381.22

Use your calculator to add or subtract each new term as indicated:

$175 - $24.39 = $150.61

Next, subtract $65.21:  $150.61 - $65.21 = $85.40

Finally, add $381.22:  $85.40 + $381.22 = $466.62

on November 27 the new balance in rob's account became $466.62.

Answer:

B save your time its the same answer

Step-by-step explanation:

Good Luck!

Answer:

No, it's not a solution

Step-by-step explanation:

Solve by plugging in the values x=-2 and y=2 that are from your point (-2,2):

y<3x+2    

2<3(-2)+2          

2<-4 This inequality is false, so no, it's not a solution

Answer:

not a solution

Step-by-step explanation:

y<3x+2

2<3(-2)+2..........plug in values

2<-6+2................multiply

2<-4......................add

2<-4 is false

Answer:

x = 125

Step-by-step explanation:

Given equation:

[tex]\log_224-\log_23=\log_5x[/tex]

[tex]\textsf{Apply the Quotient log law}: \quad \log_ax - \log_ay=\log_a\frac{x}{y}[/tex]

[tex]\implies \log_2\left(\dfrac{24}{3}\right)=\log_5x[/tex]

[tex]\implies \log_28=\log_5x[/tex]

Rewrite 8 as 2³:

[tex]\implies \log_2(2^3)=\log_5x[/tex]

[tex]\textsf{Apply the Power log law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 3\log_22=\log_5x[/tex]

[tex]\textsf{Apply log law}: \quad \log_aa=1[/tex]

[tex]\implies 3(1)=\log_5x[/tex]

[tex]\implies \log_5x=3[/tex]

[tex]\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b[/tex]

[tex]\implies 5^3=x[/tex]

[tex]\implies x=125[/tex]

Answer:

x = (180 - [71 + 9]) ÷ 2

Step-by-step explanation:

71 + 9 = 80

180 - 80 = 100°

100° ÷ 2 = 50°

We have ( 4x + 3y ) : ( 3x + 4y ) = 24 : 25

[tex]\\ \sf\longmapsto \: \frac{4x + 3y}{3x + 4y} = \frac{24}{25} [/tex]

[tex]\\ \sf\longmapsto \: 25(4x + 3y) = 24(3x + 4y)[/tex]

[tex]\\ \sf\longmapsto \: 100x + 75y = 72x + 96y[/tex]

[tex]\\ \sf\longmapsto \: 100x - 72x = 96y - 75y[/tex]

[tex]\\ \sf\longmapsto \: 28x = 21y[/tex]

[tex]\\ \sf\longmapsto \: \frac{x}{y} = \frac{21}{28} = \frac{3}{4} [/tex]

Hence ,

[tex]\\ \sf\longmapsto \dfrac{4x+3y}{3x+4y}=\dfrac{24}{25}[/tex]

[tex]\\ \sf\longmapsto 24(3x+4y)=25(4x+3y)[/tex]

[tex]\\ \sf\longmapsto 72x+96y=100x+75y[/tex]

[tex]\\ \sf\longmapsto 96y-75y=100x-72x[/tex]

[tex]\\ \sf\longmapsto 21y=28x[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{21}{28}[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto x:y=3:4[/tex]

The value of cement mixer after t year is [tex]f(t) = 54,205(0. 87)^{t}[/tex]

Given to us

The value of cement mixer when bought, [tex]P[/tex]= $ 54,205

the value of cement mixer after 1 year, [tex]P_1[/tex]=   $ 47,158. 35

the value of cement mixer after 2 year,[tex]P_2[/tex]=  $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

[tex]P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years[/tex]

By putting the value, in the formula we get,

[tex]P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13[/tex]

Therefore, putting the value of [tex]r[/tex] and [tex]P[/tex] in depreciation formula for [tex]t[/tex] years we get,

[tex]P_n= P(1-r)^n[/tex]

[tex]f(t) = 54,205(0. 87)^{t}[/tex]

Hence, the value of cement mixer after t year is [tex]f(t) = 54,205(0. 87)^{t}[/tex].

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