Please use the accompanying Excel data set or accompanying Text file data set when completing the following exercise. A machine produces metal rods used in an automobile suspension system. A random sample of 15 rods is selected and the diameter is measured. The resulting data (in millimeters) are as follows: No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Dia. 8.23 8.16 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24 Use the data above to calculate a 95% two-sided confidence interval on the mean rod diameter. Assume the data are normally distributed. (a) Calculate the sample mean and standard deviation. Round the sample mean and the sample standard deviation to 2 and 3 decimal places respectively (e.g. 98.76 and 98.765). (b) Calculate the 95% two-sided confidence interval on the true mean rod diameter. Round your answers to 3 decimal places (e.g. 98.765).

Answer:

Y =-4X +21

Step-by-step explanation:

x1 y1  x2 y2

4 5  3 9

(Y2-Y1) (9)-(5)=   4  ΔY 4

(X2-X1) (3)-(4)=    -1  ΔX -1

slope= -4          

B= 21          

Y =-4X +21    

12321-3x3x37x37

(3)^2×(37)^2

square root = 3×37=111

Hope it helps you..!!

Answers:

The areas from left to right are:  13 m^2, 49 m^2, 24 m^2, 14 m^2

The largest area occurs when the rectangle is a square

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Explanation:

The area rectangle formula is base*height, or length*width, whichever you prefer.

From left to right, we have these areas:

We get the largest area (49 m^2) when the figure is a square. This happens with any problem in which we have a fixed amount of fencing and we want to max out the area. So it's not particular to this specific problem only.

Why a square? Well an informal way to think of it would be to consider that as one dimension goes up, the other goes down, and vice versa. Think of it like a see-saw. As the examples show, if one dimension is particularly large, then its area wont be as big compared to when the dimensions are closer together. It's only when all dimensions are equal is when we max the area out entirely.

I am sry but he has don wrong calculation the answer is last one 9*5=45m and its the answer.

and the noticiable thing is the larger the shape is the area increases.

shaded area = area of outer figure - area of inner figure........

Answer:

i gues none... bcuz its irregular symmetry shape

Answer:

1 because it takes a full rotation to get back to a symmetrical shape. or 2 because it is the same halfway around.

Answer:

a. 8

Step-by-step explanation:

1+1 = 2

1+2 = 3

2+3 = 5

3+5 = 8

Answer:

f(3) = 6

Step-by-step explanation:

If f(1)=10, then f(1+1)=f(1)-2

f (2) = 10 - 2 = 8

Therefore f(3) = f(2) - 2 = 8 - 2 = 6

Answer:

Step-by-step explanation:

Short of taking 3 hours to type out the way that I did this, let me just tell you the process. Square both sides and multiply to distribute. You end up with radicals still, so square both sides again and multiply to distribute. What you end up with is a 6th degree polynomial that has to be factored. What I got in the end were these zeros:

x = 21.41917943

x = 1.306542114+/-7186864435i

x = -1.066667927

x = 1.28038353

x = 1.28038353

x = -.2459792634

Answer:

1

Step-by-step explanation:

the maximum of f(X)=sin(X) is 1

Answer:

240000

Step-by-step explanation:

Represent the exponential equation.

[tex]10000 (5 {t}^{ \frac{2}{3} } + 4) = [/tex]

Replace 8 with t

[tex]10000(5(8) {}^{ \frac{2}{3} } + 4)[/tex]

[tex]10000(5 \times 4 + 4) [/tex]

[tex]10000(24) = 240000[/tex]

The population of the town after 8 month will be 2,40,000.

Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.

Let P be the population of the town after 8 months

According to the given question

The current population of the town = 10,000.

Also, the population of the town is changing at the rate of [tex]4+5t^{\frac{2}{3} }[/tex].

Therefore, the population of the town after 8 month is given by the exponential function

[tex]P = 10000(4+5t^{\frac{2}{3} } )[/tex]

Substitute t =8 in the above equation

⇒[tex]P = 10000(4 + 5(8)^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4 + 5(2^{3}) ^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4+5(4))[/tex]

⇒[tex]P = 10000(24)[/tex]

⇒[tex]P = 240000[/tex]

Hence, the population of the town after 8 month will be 2,40,000.

Find out more information about exponential growth here:

https://brainly.com/question/11487261

#SPJ2

Answer:

7 7/80 or 7.0875

Step-by-step explanation:

product is the result of multiplication

7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875

Answer:

.35 miles per minute

3.5 miles in 10 minutes

Step-by-step explanation:

21 ÷ 60= .35

.35 × 10 = 3.5

Answer:

A

Step-by-step explanation:

The answer is choice A.

The two angles are alternate exterior angles of lines LG and KH cut by transversal JF.

Answer:

8

Step-by-step explanation:

Answer:

ayyyy i go to RSM too? Which location r u at? ANyways the answer is

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 45: 1, 3, 5, 9, 15, 45

The common factors between the two numbers are 1, 3, 5, 15.

Hope this helps!

(n-1) where n= 3

Answer is 2

(n - 1)!

n = 3

( 3 - 1)!

2!

= 1 × 2

= 2

n = 2

(2 - 1)!

1!

= 1

n = 5

(5 - 1)!

4!

= 1 × 2 × 3 × 4

= 24

n = 6

(6 - 1)!

5!

= 1 × 2 × 3 × 4 × 5

= 120

Answered by Gauthmath must click thanks and mark brainliest

Answer:

Speed of car = 49 mph (Approx.)

Step-by-step explanation:

Given:

Length of skid marked = 115 ft

Formula for skid mark = S = √21d

Where d = Length of skid marked

Find:

Speed of car

Computation:

Speed of car = √21d

Speed of car = √21(115)

Speed of car = √2,415

Speed of car = 49.1426

Speed of car = 49 mph (Approx.)

Answer:

x+ 4

Step-by-step explanation:

      ____x__+4___

x+2 | [tex]x^2 + 6x + 8[/tex]

        [tex]x^2 + 2x[/tex]

        ------------

                [tex]4x + 8\\[/tex]

                 [tex]4x + 8\\[/tex]

                  --------

                     0

Answer:

x+4

Step-by-step explanation:

Answer:i think it is b not really sure      

Step-by-step explanation:

Answer:

(1,0) and (0,4)

Step-by-step explanation:

When f(x) will cross the x axis, the y coordinate will turn 0, so 0=-5^(x)+5, 5=5^(x) Which is possible when x=1. So (1,0)

When f(x) will cross the y axis, the x coordinate will turn 0, so f(0)=-5^(0)+5, f(0)=-1+5=4. So (0,4)

Answer:

See Below.

Step-by-step explanation:

We are given the function:

[tex]\displaystyle y=\sqrt{\sin x}[/tex]

And we want to show that:

[tex]\displaystyle 4y^3\frac{d^2y}{dx^2}+y^4+1=0[/tex]

Find the first derivative of y using the chain rule:

[tex]\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{\sin x}}\cdot \cos x = \frac{\cos x}{2\sqrt{\sin x}}[/tex]

And find the second derivative using the quotient and chain rules:

[tex]\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{1}{2}\left(\frac{(\cos x)'(\sqrt{\sin x})-(\cos x)(\sqrt{\sin x})'}{(\sqrt{\sin x})^2}\right) \\ \\ &=\frac{1}{2}\left(\frac{-\sin x\sqrt{\sin x} - \left(\cos x\right) \left (\dfrac{\cos x}{2\sqrt{\sin x}}\right)}{\sin x}\right) \\ \\ & = \frac{1}{2}\left(\frac{ -\sin x(2\sin x) -\cos x(\cos x) }{\sin x \left(2\sqrt{\sin x}\right) }\right) \\ \\ &= -\frac{1}{2} \left(\frac{2\sin^2 x + \cos^2 x}{2\sin^{{}^{3}\!/\! {}_{2}}x}\right)\end{aligned}[/tex]

Find y³:

[tex]\displaystyle y^3 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right) ^3= \sin^{{}^{3}\! / \! {}_{2} }x[/tex]

And find y⁴:

[tex]\displaystyle y^4 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right)^4 = \sin^2 x[/tex]

Substitute:

[tex]\displaystyle 4\left( \sin^{{}^{3}\! / \! {}_{2} }x\right)\left(-\frac{1}{2}\left(\frac{2\sin ^2x + \cos ^2 x}{2\sin^{{}^{3}\!/ \! {}_{2}}x}\right)\right)+\left(\sin ^2 x\right) + 1= 0[/tex]

Simplify:

[tex]-\left(2\sin^2 x + \cos^2 x\right) + \sin ^2 x + 1=0[/tex]

Distribute:

[tex]-2\sin ^2 x - \cos^2 x + \sin ^2 x + 1=0[/tex]

Simplify:

[tex]-\sin ^2 x - \cos^2 x + 1= 0[/tex]

Factor:

[tex]-(\sin ^2 x + \cos^2 x ) + 1=0[/tex]

Pythagorean Identity:

[tex]-(1)+1=0\stackrel{\checkmark}{=}0[/tex]

Q.E.D.

9514 1404 393

Answer:

  C. 4 +√(x+5)

Step-by-step explanation:

The sign between the terms changes to form the conjugate. The radical contents are unchanged.

The conjugate of 4 -√(x+5) is 4 +√(x+5).

_____

Additional comment

The utility of a conjugate is that the product of a number and its conjugate is the difference of two squares. The squares are intended to remove an undesirable feature of the number, its imaginary part or its irrational part, for example. Here, the product of the number and its conjugate would be ...

  (a -b)(a +b) = a² -b²

  4² -(√(x+5))² = 16 -(x +5) = 11 -x . . . . no longer contains a root

Answer:

384 cubic inches

Step-by-step explanation:

first find the volume of the fish tank by multipying the length, width, and height.

v=lwh

 =(16in)(4in)(12in)

 = 768 cubic inches (This answer is equal to the volume of the entire fish tank, however we need to find how much water half the tank can hold. To figure this out, we need to divide 768 by 2. And you should get 384 cubic inches)

Answer:

384

Step-by-step explanation:

took the quiz

Answer:

Rs. 80

Step-by-step explanation:

Given that :

Purchase price = 70

Profit = 6

Discount = 5%

Let selling price = x

Selling price * (1 - discount) = (purchase price + profit)

x * (1 - 5%) = (70 + 6)

x * (1 - 0.05) = 76

x * 0.95 = 76

0.95x = 76

x = 76 / 0.95

x = 80

Hence, selling price = Rs. 80

Answer:

Step-by-step explanation:

For the question 1:

The given is a special right triangle with angle measures of

90-60-30 and side lengths represented by :

a - a[tex]\sqrt{3}[/tex] and 2a

The side length that sees 90 degrees is represented with a

The side length that sees 60 degrees is represented with a[tex]\sqrt{3}[/tex]

The side length that sees 30 degrees is represented with 2a

Here the side length that sees angle measure 60 is given as [tex]\sqrt{6}[/tex]

so a[tex]\sqrt{3}[/tex] =  [tex]\sqrt{6}[/tex] to find the value of a we divide  [tex]\sqrt{6}[/tex] with [tex]\sqrt{3}[/tex]

[tex]\frac{\sqrt{6} }{\sqrt{3} }[/tex] = [tex]\sqrt{2}[/tex]

so y = [tex]\sqrt{2}[/tex] and x = 2[tex]\sqrt{2}[/tex]

for second question

the square value of hypotenuse is equal to sum of other two side length's square value

10^2 + 6^2 = x^2

100 + 36 = x^2

136 = x^2

[tex]\sqrt{136}[/tex] = x

4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))

= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)

= 4 (√x + √(x - 2)) / (x - (x - 2))

= 4 (√x + √(x - 2)) / (x - x + 2)

= 4 (√x + √(x - 2)) / 2

= 2 (√x + √(x - 2))

Answer:

Step-by-step explanation:

ABCD is a square.

side = 24 cm

Area of square = side  * side = 24 * 24 = 576 cm²

Semicircle:

d = 24 cm

r = 24/2 = 12 cm

Area of semi circle =πr²

                               = 3.14 * 12 * 12

                               = 452.16 cm²

Area of shaded region = area of square - area of semicircle  + area of semicircle

  = 576  - 452.16 + 452.16

  = 576 cm²

Perimeter:

Circumference of semicircle = 2πr

               = 2 * 3.14 * 12

               = 75.36

Perimeter = 2* circumference of semicircle + 24 + 24

                = 2 * 75.36 + 24 + 24

                = 150.72 + 24 + 24

                 = 198.72 cm