Please answer the question

Answer:

Meandering valley like features on the Moon's surface are called rilles

Explanation:

NOUN

rilles (plural noun)

a fissure or narrow channel on the moon's surface.

Answer:

84.1 m

Explanation:

Given :

The distance from the ship to submarine :

20 + y

Using Pythagoras :

Tan θ = opposite / Adjacent

Tan θ = 20 / 12

12 tan θ = 20

θ = tan^-1(20/12)

20

θ = 59.036°

The angle phi;

n1sinθ1 = n2sin θ

Sin 59.036 = 1.33 * sin phi

Sin phi = sinsin(59.04) ÷1.33

0.8574907 = 1.33 * sin phi

Sin phi = 0.8574907 / 1.33

Sin phi = 0.6447298

phi = sin(0.6447298

Phi = 40.15°

From Pythagoras :

y = 76tan40.15°

y = 76 * 0.8435707

y = 64.11

20 + y

20 + 64.11 = 84.11

Answer:

It increases because fg means Force of gravity so When the mass of the two objects  increases with mass and increases the distance between an object

There you go!!!

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

The gravitational  force : 3.125 N

Given

F₁ = 50 N

Required

F₂

Solution

Newton's Gravity Law:  

[tex]\rm F=G.\dfrac{m_1.m_2}{r^2}[/tex]

with F = gravitational force,  

G = gravitational constant,  

m1, m2 = mass of object,  

r = distance between two objects.  

The value of m and G are the same , so :

F₁ ≈ 1/r₁²

The distance between the two is increased to four times:

r₂ = 4r₁

F₂ = 1/(4r₁)²

F₂ = 1/16r₁²

F₂ = F₁ x 1/16

F₂ = 50 : 16

F₂ = 3.125 N

Answer:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.

Explanation:

The formulas of Electric and gravitational fields are as follow

Electric Field

F(electric)=kq1q2/r^2

Gravitationlal Fieeld

F(grav)=GMm/r^2

As you see both follow the inverse square law in the formula

Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.

The gravitational field can only attractive while the electric field can be attractive or repulsive.

Normally electric field is stronger than the gravitational field.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Electric and gravitational forces have many similar features because they follow identical mathematical formulas.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,

but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,

which means gravity is always attractive, but electricity could be attractive and repulsive.

Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

To learn more about the gravitational force refer to the link;

https://brainly.com/question/24783651

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

Answer: On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet.

Explanation:

Answer:

the rotation of earth on its axis causes electric currents to form a magnetic field which extends around the planet

Answer:

Its C

Explanation:

Because I got it wrong for you

Wave B has about 1.6 times more energy than wave A.

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

The amplitude and energy of a mechanical wave. If mechanical wave A has an amplitude of 4 cm and mechanical wave B has an amplitude of 5 cm wave B has about 1.6 times more energy than wave A.

Wave B has about 1.6 times more energy than wave A.

To learn more about energy refer to the link:

brainly.com/question/1932868

 #SPJ5

Answer:

0.392

Explanation:

Mm = 0.11Me

Rm = 0.53Re

g = GM / r^2

G = 6.67 * 10^-11

gmars = (G * 0.11Me) / (0.53Re)^2

Recall:

gearth = GMe /Re^2

Hence, gmars in terms of gearth equals

gmars = gearth * (0.11 / 0.53^2)

gmars = gearth * 0.3915984

gmars = 0.392gearth

Answer:

Ep = 117600 J

Explanation:

Data:

Use formula:

Replace:

Multiply operations, and units:

What is the potential energy?

The potential energy is 117600 Joules.

Answer:

a required or allowed amount, especially an amount of money legally payable in damages.

OR

In physics it means a discrete quantity of energy proportional in magnitude to the frequency of the radiation it represents.

Explanation:

Answer:

Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.

Answer:

D

Explanation:

He walked a shorter distance, she walked a longer distance but got that wing thingies

Answer:

X axis   F=0

Y axis    Fg = - 2.94 j ^

Explanation:

The motion of a ball in air where the air residence is indicated to be negligible can be analyzed using Newton's second law.

We set a reference system, where the x-axis is horizontal and the y-axis vertical.

X axis

There are no forces on this axis, therefore the ball goes at constant speed.

Force is zero

Y axis  

In this axis it is subjected to the acceleration of gravity that creates a force equal to the weight of the body, in a vertical direction.

           Fg = m g

           Fg = 0.3 9.8

           Fg = 2.94 N

           Fg = - 2.94 j ^

the boold are vectors; negative sign indicates that the force eta directed vertically downward

Answer:

BET, & done ✌

Answer:

boop

Explanation:

Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

Answer:

2 m/s^2

Explanation:

Acceleration = Force/mass

= 2,000/1,000

= 2

Answer:

38.09 m

Explanation:

We'll begin by calculating the distance travelled by the car during the reaction time. This can be obtained as follow:

Reaction time (tᵣ) = 0.404 s

Initial velocity (u) = 22.8 m/s,

Distance travelled during the reaction time (sᵣ) =?

sᵣ = utᵣ

sᵣ = 22.8 × 0.404

sᵣ = 9.21 m

Next, we shall determine the distance travelled by the car when the brake was applied. This can be obtained as follow:

Initial velocity (u) = 22.8 m/s

Acceleration (a) = –9 m/s² (since the car is decelerating)

Final velocity (v) = 0 m/s

Distance travelled when the brake was applied (s₆) =?

v² = u² + 2as₆

0² = 22.8² + (2 × –9 × s₆)

0 = 519.84 – 18s₆

Collect like terms

0 – 519.84 = –18s₆

–519.84 = –18s₆

Divide both side by –18

s₆ = –519.84 / –18

s₆ = 28.88 m

Finally, we shall determine the stopping distance of the car, as measured from the point where the driver first notices the red light. This can be obtained as follow:

Distance travelled during the reaction time (sᵣ) = 9.21 m

Distance travelled when the brake was applied (s₆) = 28.88 m

Stopping distance =?

Stopping distance = sᵣ + s₆

Stopping distance = 9.21 + 28.88

Stopping distance = 38.09 m