need help on these 2 questions

Answer:

26

Step-by-step explanation:

[tex]8^{2} + 20^{2} = 21.5^{2}[/tex]

[tex]21.5^{2} + 14^{2} = 25.7^{2} \\x = 25.7[/tex]

Answer:

Step-by-step explanation:

If x represents the number of long-sleeved shirts and each of these cost $14, then the expression for that is 14x; likewise for short-sleeved shirts that are represented by y. The expression for short-sleeved shirts that cost $10 apiece is 10y. Putting that together with the fact that they earned less than $200 when selling these at the same time, the inequality is

14x + 10y < 200

Answer:D i just got it right trust mw

Step-by-step explanation:i

Answer:

48

Step-by-step explanation:

9,18

6,12,18,24,30

18 + 30 = 48

Answer:

HOPE IT HELP YOU....

if it is right plz comment me .

Answer:

The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.

[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]

You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.

If you would like to find it mathematically, this is the way to do it

[tex]\theta = atan(y/x) = -45[/tex]

Notice that -45 degrees is just 360 - 45 = 315

Your answer would be

[tex](\sqrt{2}, 315)[/tex]

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

$\sf\underline\bold{Answer:}$

$\space$

$\sf\underline\bold{Step-by-Step:}$

$\space$

$\sf\bold{Given(In \:the\:Q):}$

$\space$

$\sf\bold{To \: find:}$

$\space$

$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$

$\space$

$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$

$\space$

Use heron's formula to find the area of the triangle.

$\space$

$\mapsto$ $\sf\small{Heron's\:formula=}$

[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]

$\space$

$\sf\bold{Now,find\:semi\:parameter:-}$

$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$

$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$

$\space$

$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$

$\sf{Area\:of\:the\:∆:-}$

$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]

$\space$

$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$

$\space$

$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$

______________________________

$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$

$\sf{Cost\:of\:fencing-}$

$\space$

$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$

$\space$

So,total cost of fencing at the rate of Rs.20 per m:-

___________________________________

Answer:

The product of 16 and 26 would be 16 * 26

Step-by-step explanation:

This is because "the product of" means multiplication so *. Making it 16 * 26.

Answer:

No, because they are parallel.

Step-by-step explanation:

The lines [tex]p[/tex] and [tex]m[/tex] will not intersect, so Kevin is not correct.

It is given that planes A and B intersects. The plane A contains the line p, m and n on its plane. The lines p and m are parallel to each other. They are identical and move in the same direction.

Since the line p and m are parallel, they will not meet each other at any point because parallel lines does not intersect or meet at a point, they run parallelly along each other.

So, line p and m will not intersect.

Thus the answer is " No, because they are parallel."

Answer:

Step-by-step explanation:

no, because they are parrallel.

Using the definition of the derivative,

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}[/tex]

[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}[/tex]

Answer:

a = 3 [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Given

a + 5 [tex]\frac{2}{3}[/tex] = 9 ← change mixed number to improper fraction

a + [tex]\frac{17}{3}[/tex] = 9 ( multiply through by 3 to clear the fraction )

3a + 17 = 27 ( subtract 17 from both sides )

3a = 10 ( divide both sides by 3 )

a = [tex]\frac{10}{3}[/tex] = 3 [tex]\frac{1}{3}[/tex]

Answer:

i don't know sorry

Answer:

a

Step-by-step explanation:

-5 shifts the y-intercept down, and it needs to be outside of the modulus as if its in the modulus, the graph would shift 5 units to the right instead

Answer:

here I'm confused that whether the selling price is Rs.9,200 or Rs.9.200

any ways you can take the help of below procedure

Step-by-step explanation:

here,

let marked price be X

discount(d)=20%

VAT=15%

SP with VAT= 9200

now,

SP without VAT= SP - VAT of SP

= 9200-15/100 ×9200

= 9200- 1380

=Rs. 1380

again,

SP= MP - D of MP

or,7820= x- 20/100 × x

or, 7820× 100 = 100x- 20x

or,782000=80x

or, 782000/80=X

or, X= 9775.

hence MP is Rs 9775

Answer:

B. 64:25

Step-by-step explanation:

the ratio of the surface areas =

(8)² : (5)² = 64 : 25

Answer:

A' (8,16)

B' (8,-4)

C' (-16,4)

Answered by GAUTHMATH

Answer:

-19>t

Step-by-step explanation:

-6>t-(-13)

-6>t +(13)

Subtract 13 from each side

-6-13 > t+13-13

-19>t

Answer:

The restrictions are x≠2,4,5

Step-by-step explanation:

First the denominators cannot be zero

x-2 ≠0  so x≠2

Then x-4 ≠0  so x≠4

Also, since we are dividing, when we flip the second expression, the numerator becomes the denominator, so it cannot be zero

2x-10≠0

2x≠10

x≠5

The restrictions are x≠2,4,5

Answer:

I say it's a

Step-by-step explanation:

I hope this help

9514 1404 393

Answer:

  D.

Step-by-step explanation:

The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)

When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.

The only reasonable choice is D.

__

Your calculator can check this for you.

  √12/(√3 +3) ≈ 3.4641/(1.7321 +3)

  = 3.4641/4.7321 ≈ 0.7321 = -1 +√3

__

If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.

  [tex]\displaystyle\frac{\sqrt{12}}{\sqrt{3}+3}=\frac{\sqrt{12}}{(\sqrt{3}+3)}\cdot\frac{(\sqrt{3}-3)}{(\sqrt{3}-3)}=\frac{\sqrt{36}-3\sqrt{12}}{3-9}\\\\=\frac{6-3\cdot2\sqrt{3}}{-6}=\boxed{-1+\sqrt{3}}[/tex]

_____

Additional comment

We "rationalize the denominator" in this way to take advantage of the relation ...

  (a -b)(a +b) = a² -b²

Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.

We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).

[tex]\boxed{\sf tan\theta=\dfrac{p}{b}}[/tex]

[tex]\\ \sf\longmapsto tan\theta=\dfrac{13}{20}[/tex]

[tex]\\ \sf\longmapsto tan\theta=0.6[/tex]

[tex]\\ \sf\longmapsto tan\theta\approx\dfrac{1}{\sqrt{3}}[/tex]

[tex]\\ \sf\longmapsto tan\theta\approx tan60[/tex]

[tex]\\ \sf\longmapsto \theta\approx 60°[/tex]

Answer:

Slope is (1/4)

Step-by-step explanation:

The slope is calculated by (6-5)/(5-1)=1/4

Answer:

The correct solution is "(0.092, 0.148)".

Step-by-step explanation:

Given:

Sample size,

n = 500

True proportion,

[tex]\hat {p} = \frac{60}{500}[/tex]

  [tex]=0.12[/tex]

The standard error will be:

[tex]SE=\sqrt{\frac{\hat p(1-\hat p)}{n} }[/tex]

     [tex]=\sqrt{\frac{0.12(1-0.12)}{500} }[/tex]

     [tex]=\frac{0.12(0.88)}{500}[/tex]

The confidence interval is "1.96".

hence,

The required confidence interval will be:

= [tex](\hat p - 1.96 SE, \hat p + 1.96 SE)[/tex]

By substituting the values, we get

= [tex](0.12-1.96\sqrt{\frac{0.12(0.88)}{500} }, 0.12+1.96\sqrt{\frac{0.12(0.88)}{500} } )[/tex]

= [tex](0.092, 0.148)[/tex]

Answer:

hijjijkkkmmkmjjjjjjjjjijjji

Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2) , Given volume and lateral area: r = 2 * V / A_l , Given base area: r = √(A_b / (2 * π)) , Given lateral area and total area: r = √((A - A_l) / (2 * π)) .

Answer:

Answer is b

Step-by-step explanation:

cuh cuh cuh cuh cuh cuh , , , , , ,,

Answer:

Step-by-step explanation:

A=2  ,B=4  ,C=?

[tex]C^{2}[/tex]=[tex]A^{2}[/tex]+[tex]B^{2}[/tex]

[tex]C^{2}[/tex]=[tex]2^{2}[/tex]+[tex]4^{2}[/tex]

[tex]C^{2}[/tex]=4+16

[tex]C^{2}[/tex]=20

C=[tex]\sqrt{20}[/tex]

Answer:

C = 100 + 0.20d

Step-by-step explanation:

Let

C = Total cost

d = distance driven(km)

$100 = fixed cost

$0.20 = additional cost

The algebraic model of the relationship:

Total cost = fixed cost + (additional cost * distance driven(km))

C = 100 + (0.20 * d)

C = 100 + 0.20d

Answer:

Step-by-step explanation:

I think you mean 35 seconds because if it was 36 then the answer would be too long so assuming it is 35 seconds the answer is 1 minute or 60 seconds

Answer:

Its that squiglly one on top

Step-by-step explanation:

cuh cuh cuh cuh cuhc

Given:

The sum of the cubic powers of three rational numbers is -1009.

The ratio between the first number and the second number is [tex]\dfrac{2}{3}[/tex].

The ratio between the first number and the third number is [tex]\dfrac{4}{9}[/tex].

To find:

The three numbers.

Solution:

Let [tex]x,y,z[/tex] be the three numbers, then

[tex]x^3+y^3+z^3=-1009[/tex]                ...(i)

[tex]\dfrac{x}{y}=\dfrac{2}{3}[/tex]

[tex]3x=2y[/tex]

[tex]\dfrac{3}{2}x=y[/tex]                        ...(ii)

[tex]\dfrac{x}{z}=\dfrac{4}{9}[/tex]

[tex]9x=4z[/tex]

[tex]\dfrac{9}{4}x=z[/tex]                         ...(iii)

Using (i), (ii) and (iii), we get

[tex]x^3+\left(\dfrac{3}{2}x\right)^3+\left(\dfrac{9}{4}x\right)^3=-1009[/tex]

[tex]x^3+\dfrac{27}{8}x^3+\dfrac{729}{64}x^3=-1009[/tex]

[tex]\dfrac{64+216+729}{64}x^3=-1009[/tex]

[tex]\dfrac{1009}{64}x^3=-1009[/tex]

[tex]x^3=\dfrac{-1009\times 64}{1009}[/tex]

On simplification, we get

[tex]x^3=-64[/tex]

[tex]x^3=-4^3[/tex]

[tex]x=-4[/tex]

Substituting [tex]x=-4[/tex] in (ii), we get

[tex]\dfrac{3}{2}(-4)=y[/tex]

[tex]-6=y[/tex]

Substituting [tex]x=-4[/tex] in (iii), we get

[tex]\dfrac{9}{4}(-4)=z[/tex]

[tex]-9=z[/tex]

Therefore, the three numbers are -4, -6 and -9 respectively.