Lowest to highest degree of internal organization stomach

The sympathetic nervous system is responsible for the mouse's physiological state.

The nervous system divides into the central nervous system and peripheral nervous system.

In the central nervous system, we have the brain and the spinal cord.

The peripherical nervous system, which is all the nerves that are not in the spinal cord or the brain, is divided into:

-Sympathetic nervous system. It is the one that works under stress. It gives the fight or flight response preparing the body for a dangerous situation. It increases the heart rate and epinephrine's release. Epinephrine is a hormone that helps in this response stimulating the sympathetic system.

-Parasympathetic nervous system. It is the one that works in calm situations, like after we ate, regulating digestion, and trying to save energy for any upcoming event.

In conclusion, as there is an increase in epinephrine and heart rate, and the mouse is "fighting" against a scorpion, the nervous system division responsible for this physiological state is the sympathetic nervous system.

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Answer:

The greenhouse effect is a natural process that warms the Earth's surface.

When the Sun's energy reaches the Earth's atmosphere, some of it is reflected back to space and the rest is absorbed and re-radiated by greenhouse gases.

The absorbed energy warms the atmosphere and the surface of the Earth causing green house effect .

Answer:

The greenhouse effect occurs when radiation from a planet's atmosphere warms the planet's surface to a higher temperature than it would be without the atmosphere. Radiatively active gases emit energy in all directions from a planet's atmosphere.

OAmalOHopeO

Answer:

发发发 发斯蒂芬

Explanation:

Presence of capsule. Therefore, option (B) is correct.

Griffith's experiment of transformation is a landmark experiment in microbiology conducted in 1928 by British bacteriologist Frederick Griffith. The experiment aimed to determine the nature of the "transforming principle" responsible for transferring genetic material between bacteria.

Griffith used two strains of Streptococcus pneumoniae, one that was virulent and had a polysaccharide capsule (S strain) and another that was non-virulent and lacked the capsule (R strain). He found that when he injected mice with the heat-killed S strain and live R strain, the mice died, and live S strain was found in their blood. This suggested that the R strain had been transformed into the S strain, and the genetic material was responsible for the transformation.

Griffith's experiment provided the first evidence of bacterial transformation and paved the way for future research on the molecular basis of genetics.

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Answer:

The citric acid cycle is the final common oxidative pathway for carbohydrates, fats and amino acids. It is the most important metabolic pathway for the energy supply to the body.

Answer: The number of H+ ions moving down the channel

Explanation:

Answer:

Interphase - There are 3 subphases called - G1 , S and G2 . In these subphases, DNA material is duplicated, and essential proteins for cell division are formed.

Prophase - the nuclear envelop and nucleolus disappears and condensed DNA forms chromosomes that are short in size.

Metaphase - the form of two sister chromatids are arranged in the middle of the metaphase/equatorial line. Two centrioles are found at two poles of the cell which initiate the formation of spindle fibers.

Anaphase - spindle fibers are formed and can be observed. These fibres attach with the kinetochore present in the centromere of chromosomes and these chromatids now start separated by pulling and pushing force of spindle fibers in opposite poles

Telophase -  chromatids reach at destination pole and then nuclear envelop starts creating again in both poles. Nucleolus reappears and now in a cell two nucleus are found.

Answer:

answer: c

Explanation:

A hemoglobin molecule is made up of four

polypeptide chains, two alpha chains of 141

amino acid residues each and two beta

chains of 146 amino acid residues each . In the complete molecule, four subunits are closely joined, as in a three-dimensional jigsaw puzzle, to form a tetramer.

it also have a structure called quaternary structure, in which two or more polypeptide chains folded in to tertiary structure become associated in the final structure of the protein.

hope this will help !

Answer:

Option C

Explanation:

4 subunits (2 alpha and 2 beta)

Answer:

answer is A.) The population comes to be dominated by smaller, slower- growing individuals

The correct energy flow during aerobic respiration is ATP, Glucose, and cells. Thus, the correct option is B.

Aerobic respiration may be defined as the process of conversion of glucose into carbon dioxide, water, and energy via the intermediate product of pyruvate in presence of air.

The release of energy in aerobic respiration is found to be greater as compared to anaerobic respiration.

This released energy is immediately used to synthesize a molecule called ATP via glucose that fuels the cells for metabolic activities.

Therefore, the correct option for this question is B.

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Answer:

c. Lane 2, 4 and 5.

Explanation:

Two bands will be seen when a fraction of DNA added to gel is bound by Lac repressor protein. Radiolabeled LacO DNA will have two bands. Lac repressor is encoded with lacl gene. It has binding ability due to allolactose formation.

Answer:

Freezing

Explanation:

I got 123% on the quiz (Jokes aside yes it is freezing)

Answer:

Explanation: Protein digestion occurs in the stomach and the duodenum through the action of three main enzymes: pepsin, secreted by the stomach, and trypsin and chymotrypsin, secreted by the pancreas. During carbohydrate digestion the bonds between glucose molecules are broken by salivary and pancreatic amylase.

Answer:

ATP hydrolyzation is a process ( catabolic ) whereby chemical energy previously stored in phosphoanhydride bonds will be released by the process of bond splitting

R = Vesicle velocity / step size

Explanation:

The rate of ATP hydrolyzation can be explained  by relating ΔG ( Gibbs free energy)  and Q using this equation :  ΔrGo + RT ln(Q).   where ΔrGo = standard  Gibbs energy change.

while ATP hydrolyzation is a process ( catabolic ) whereby chemical energy previously stored in phosphoanhydride bonds will be released by the process of bond splitting

Calculating R

R = Vesicle velocity / step size

According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.

When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.  

A) Option 7 is the correct answer ⇒ 0.41

B) Option 6 is the correct answer ⇒ 120

C) Option 7 is the correct answer ⇒ 3.84

D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium

E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Allelic frequencies in a locus are represented as p and q, referring to the

allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us  dominant), 2pq (H3ter0zygous), q² (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same

allelic frequencies generation after generation.

The sum of the allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

 p the dominant allelic frequency,

 q the recessive allelic frequency,

 p² the h0m0zyg0us dominant genotypic frequency

 q² the h0m0zyg0us recessive genotypic frequency

 2pq the h3ter0zyg0us genotypic frequency

Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:

 H4/H4 = 125 individuals;

 H4/H5 = 85 individuals;

 H5/H5=24 individuals.

⇒ Total number of individuals= 125 + 85 + 24 = 234

⇒ Genotypic frequencies, F(xx):

 F(H4/H4) = 125/234 =0.534

 F(H4/H5) = 85/234 = 0.363

 F(H5/H5) = 24/234 = 0.102

⇒ Allelic frequencies, f(x):

 f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716

 f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284

Questions:

A)  According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,  

F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.

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B)  According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,

p = 0.716

p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.

To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of

individuals.

H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120

Option 6 is the correct answer.

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C)  Up to here we know that 2pq = 0.41 and p² = 0.513

Now we need to calculate q ²

q = 0.284, then q² = 0.284² = 0.08

These are the expected frequencies if the population was in H-W equilibrium.

The expected number of individuals with each genotype are:

 H4/H4 = 0.513 x 234 = 120 individuals

 H4/H5 = 0.41 x 234 = 96 individuals

 H5/H5= 0.08 x 234 = 18 individuals

The observed number of individuals with each genotype are:

 H4/H4 = 125 individuals

 H4/H5 = 85 individuals

 H5/H5=24 individuals

X² = ∑ (Observed - Expected)²/Expected)

X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)

X² = 0.21 + 1.26 + 2 =

X² = 3.47

The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.

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D)  The correct answer is  1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium

The null hypothesis always predict that populations are in H-W equilibrium.

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E)  

 X² = 3.47

 Freedom degrees = n - 1 = 3 - 1 = 2

 Table p value: 7.82

 Significance level, 5% = 0.05

 Table value/Critical value = 5.991

5.991 > 0.347

Meaning that the difference between the observed individuals and the expected individuals is statistically  significant. Not probably to have differe by random chances. There is enough evidence to reject the null

hypothesis.

Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Answer:

what...

Explanation:

Answer:

Species are as specific as you can get. It is the lowest and most strict level of classification of living things. The main criterion for an organism to be placed in a particular species is the ability to breed with other organisms of that same species.

Answer:

Gw

Explanation:

Answer:

The three ways by which bacteria obtain food are photosynthesis, chemosynthesis, and symbiosis.

Explanation:

Answer:

я не знаю ответа извините

Explanation:

Answer:

B

Explanation:

They divide to form more cells called daughter cells under proper conditions

Answer:

The main cause of constipation is intake of a low fiber diet.the bulk and soft texture of fibre helps prevent hard dry stools that are difficult to pass thereby reducing constipation.

I hope this helps

Answer:

In serious cases, your doctor might suggest that you have your spleen removed, which is called a splenectomy. It's entirely possible to live a normal, healthy life after having your spleen removed. Your risk of developing infections throughout your life may increase.

Answer:

Yes.

Explanation:

I will put the enzymes of the citric acid cycle in this organism so that in the absence of sunlight, it also produces energy to grow quickly. Citric acid cycle is a series of chemical reactions which release stored energy through the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins. This cycle is also called Krebs cycle so incorporation of this cycle is good for the organism.

Answer:

La oscuridad de una mancha solar es solamente un efecto de contraste; si pudiéramos ver una mancha tipo, con una umbra del tamaño de la Tierra, aislada y a la misma distancia que el Sol, brillaría unas 50 veces más que la Luna llena. Las manchas están relativamente inmóviles con respecto a la fotosfera y participan de la rotación solar. El área de la superficie solar cubierta por las manchas se mide en términos de millonésimas de hemisferio solar visible.

Answer:

C

Explanation:

it's about 20%-30%, so C would appropriately about that range since it the best answer :)

hope it helps

Answer:

Match the items of column 'A' with those of column 'B':

Turbidity

Reduces the light in the water column

Natural pollution

Choose

Nitrates and phosphates

Air pollution

Biochemical demand for oxygen

Contaminants into a natural environment

Chemical fertilizers

Pollution

Floating materials

Industrial wastes

Emissions pollution

Reduces the light in the water column

Concentration of hydrogen pH

Eutrophication

CFCS

New species invasion

Temperature

Harmful algal blooms

Oils fats, and foam

Please answer all parts of th Hypertrophication

Toxicity

Volcanic

In crude oil affect eggs and larvae of fish a

Atomic number

a. Hydrocarbon

The correct answer is C.

Explanation

According to the information provided, a bar graph (option C) is needed since this type of graph allows us to express the variation in time, distance, temperature, quantities, weight, among others. In this specific case, a bar graph allows students to analyze the time that each type of seed takes to fall from the second floor. Additionally, this is the only graph that shows the data of the chart. For example, the first bar represents the black walnut and its time is 0,6 seconds, and this value is shown by the light blue bar in the graph, which represent the same seed. According to the above, the correct answer is C.

Answer:

1000 MM individuals; 2000 MN individuals; 1000 NN individuals

Explanation:

The Hardy-Weinberg principle states that, under certain conditions, the frequency of alleles and genotypes in a sexually reproducing population will remain constant over generations. The Hardy-Weinberg assumptions include random mating, sexual reproduction, and the absence of evolutionary forces such as mutation, natural selection, and genetic drift (as in the example above). Under these conditions, the frequency of alleles and genotypes in a population will not change and tend to the equilibrium. In this case, under Hardy-Weinberg equilibrium, the frequency of the M allele or 'p' must be equal to 0.5, and the frequency of the N allele or 'q' must be equal to 0.5 (i.e., the sum of all allele frequencies in the population must be equal to 1). Moreover, the frequencies of the genotypes will be p², 2pq, and q² >> p² (MM genotype) = (0.5)² = 0.25; q² (NN genotype) = (0.5)²  = 0.25; and 2 x p x q (MN genotype) = 2 x 0.5 x 0.5 = 0.50. In consequence, under Hardy-Weinberg equilibrium, in a population of 4000 diploid individuals (8000 alleles), we have

- 4000 M alleles (M = 0.5) and 4000 N alleles (N = 0.5);  

- 1000 MM individuals [p² >> (0.5)² = 0.25]; 2000 MN individuals (2pq >> 2 x 0.5 x 0.5 = 0.5) and 1000 NN individuals [q² >> (0.5)² = 0.25].

Answer: The answer is false