Kate owns a shoe store in Los Angeles. Whenever she orders a new style of shoe, she orders 4 pairs of that style in each of the most popular sizes. The most popular sizes are 6, 7, 8, 9, and 10. She also orders 2 pairs in size 5 and 2 pairs in size 11.
For every new style, how many pairs of shoes does she need to order in total?

Answer:

a = StartFraction 11 over 88 EndFraction; b = 12.5 percent

a

because I did my research

Answer:

B. a=11/88 ; b=12.5%

Step-by-step explanation:

Answer:

That is the answer

The answer is

The measure of side x equivalent to RS is 42

Similar shapes are shapes that have both their sides and angles to be equal.

Since both quadrilaterals JKLM and PQRS are similar, we will take the ratio of the sides as shown;

4/24 = 7/x

1/6 = 7/x

Cross multiply

x = 42

Hence the measure of side x equivalent to RS is 42

Learn more on similar shapes here: https://brainly.com/question/12960403

Answer:

m + 8 ≥ -8

Step-by-step explanation:

Answer:

m+8≥-8

Step-by-step explanation:

Just ask.

Hope this helps!

Hello there, this is how we would solve this problem, we can see that angle KAE equals 90° and we have an angle that equals 62° now since angle GCJ or also known as x is a vertical angle with IAD we can make the following equation

[tex]x+62+90=180[/tex] subtract 62 and 90 from both sides and we get that [tex]x=28[/tex]°

Answer:

n=13

Step-by-step explanation:

39*5=15n

195=15n

13=n

Answer:

Midpoint : (4,3)

Step-by-step explanation:

midpoint = [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

Where the x and y values are derived from the given points.

We are given points H and K which are at (2,2) and (6,4)

We have (x1,y1) = (2,2) so x1 = 2 and y2 = 2

As well as (x2,y2) = (6,4) so x2 = 6 and y2 = 4

To find the midpoint we simply plug in the values of x and y into the formula

Recall the formula [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

x1 = 2 , x2 = 6 , y1 = 2 and y2 = 4

plug in these values into the formula

[tex](\frac{2+6}{2} ,\frac{2+4}{2} )[/tex]

add top values: 2 + 6 = 8 and 2 + 4 = 6

[tex](\frac{8}{2} ,\frac{6}{2} )[/tex]

simplify fractions : 8/2 = 4 and 6/2 = 3

The midpoint is at [tex](4,3)[/tex]

Answer:

[tex]y = -\frac{1}{6}x - 3[/tex]

Step-by-step explanation:

Slope Intercept Form :   [tex]y = mx + b[/tex]

Using our slope, -1/6, input it for m, then plug the point (-6, -2) for x and y

[tex]y = mx+b\\\\-2 = (-1/6)(-6) + b\\\\-2 = 1 + b\\\\b = -3[/tex]

Equation : [tex]y = -\frac{1}{6}x - 3[/tex]

-Chetan K

Answer: 5

Step-by-step explanation:

Answer:

3.25 blocks

Step-by-step explanation:

6.5 * 1.5 = 9.75 blocks

9.75 - 6.5 = 3.25blocks

Farther 3.25 blocks sue ellan need to ride than Bobby ride

Step-by-step explanation:

So another factor is option C.)

So another factor is option C.)(x-3)

Answer:Given that 3 persons can weave 168 shawls in 14 days. Then, Shawls are woven in 1 day by the 3 men = 168/14 = 12. Shawls are woven in 1 day ...

Step-by-step explanation:

Answer:

195 square centimeters per second

Step-by-step explanation:

Area growth rate = (9*10) cm^2 per s + (7*15) cm^2 per s = 195 square centimeters per second

Answer:

Step-by-step explanation:

Domain:  I don't see any restrictions on the domain, although at some point y will become exceedingly large.

Range:  -9 to infinity

Increasing Interval:  x>2

Decreasing Interval:  x <2

End behavior:

- as x ⇒∞, y⇒∞

Answer:

1 ft=18 in or 1ft=11in

Step-by-step explanation:

:D

Answer: 8

Step-by-step explanation:

PEMDAS

division first

6 + 2

8

Answer:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Step-by-step explanation:

6/3 = 2

6+2 = 8

HAVE A NICE DAY

Answer:

s= $5.25

Step-by-step explanation:

7-1.75=5.25

7=5.25+1.75

s=$5.25

Its the first equation, y < -1/3x +2

Answer:

c

Step-by-step explanation:

hope this helps

Answer:20 (p-3)

Step-by-step explanation:

Answer:

x = 5

Step-by-step explanation:

Δ EAB and Δ EDC are similar by the AA postulate , so the ratio of corresponding sides are in proportion , that is

[tex]\frac{AB}{DC}[/tex] = [tex]\frac{EA}{ED}[/tex] , substitute values

[tex]\frac{10}{4}[/tex] = [tex]\frac{2x+10}{x+3}[/tex] ( cross- multiply )

10(x + 3) = 4(2x + 10 ) ← distribute parenthesis on both sides

10x + 30 = 8x + 40 ( subtract 8x from both sides )

2x + 30 = 40 ( subtract 30 from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

Answer:

2p + 3e = 14

Step-by-step explanation:

The required equation is [tex]0.50\ p+0.75\ e= 3.50\\[/tex]

Given, Alejandro bought $3.50 worth of pencils and erasers at the school store.

The cost of each pencil is $0. 50.

The cost of each eraser is  $0. 75.

Since He denotes no. of pencil by p and no. of eraser by e, so the required equation will be,

[tex]0.50\ p+0.75\ e= 3.50\\[/tex].

Hence the required equation is [tex]0.50\ p+0.75\ e= 3.50\\[/tex]

For more details on Equation solving follow the link:

https://brainly.com/question/85774

[tex]2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or} ~~u =\dfrac{-4}{4} =-1\\\\[/tex]

[tex]\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\[/tex]

[tex]x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\[/tex]

[tex]\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right][/tex]