In the presence of an acid catalyst, cyclohexanol (100.16 g/mol) is dehydrated to give cyclohexene (82.14 g/mol) and water. Reaction scheme illustrating the dehydration of cyclohexanol in the prescence of acid catalyst to cylcohexene and water. A dehydration reaction starting with 4.1 g cyclohexanol produces 3.0 g cyclohexene. Calculate the percent yield for this reaction. Report your answer with two significant figures.

Answers

Answer 1

Answer:

88%

Explanation:

Step 1: Write the balanced equation

C₆H₁₁OH ⇒ C₆H₁₀ + H₂O

Step 2: Calculate the moles corresponding to 4.1 g of C₆H₁₁OH

The molar mass of C₆H₁₁OH is 100.16 g/mol.

4.1 g × 1 mol/100.16 g = 0.041 mol

Step 3: Calculate the theoretical yield, in moles, of C₆H₁₀

The molar ratio of C₆H₁₁OH to C₆H₁₀ is 1:1. The theoretical yield of C₆H₁₀, in moles, is 1/1 × 0.041 mol = 0.041 mol.

Step 4: Calculate the mass corresponding to 0.041 moles of C₆H₁₀

The molar mass of C₆H₁₀ is 82.14 g/mol.

0.041 mol × 82.14 g/mol = 3.4 g

Step 5: Calculate the percent yield of C₆H₁₀

We will use the following expression.

percent yield = experimental yield/theoretical yield × 100%

percent yield = 3.0 g/3.4 g × 100% = 88%


Related Questions

In a laboratory experiment, students synthesized a new compound and found that when grams of the compound were dissolved to make mL of a diethyl ether solution, the osmotic pressure generated was atm at K. The compound was also found to be nonvolatile and a non-electrolyte. What is the molar mass they determined for this compound

Answers

The question is incomplete, the complete question is;

In a laboratory experiment, students synthesized a new compound and found that when 12.23 grams of the compound were dissolved to make 228.1 mL of a benzene solution, the osmotic pressure generated was 4.55 atm at 298 K. The compound was also found to be non-volatile and a non-electrolyte. What is the molecular weight they determined for this compound?

Answer:

287.76 g/mol

Explanation:

From;

π = M R T

M = molarity

R= gas constant

T = temperature

number of moles = π * volume/RT

number of moles = 4.55 * 228.1/1000/0.082 * 298

number of moles = 1.037855/24.436

number of moles = 0.0425 moles

Molar mass = mass/number of moles

Molar mass = 12.23 grams/0.0425 moles

Molar mass = 287.76 g/mol

Energy can generally be considered to be either kinetic energy or potential energy. Some specific forms of energy, such as
electrical, magnetic, and gravitational energy, can operate in the space around objects and affect other objects that come near. In
these examples
A. energy is continuously created.
B. energy is continuously destroyed.
C. energy exists in a field.
D. all of these

Answers

Answer:

d hope it's right hope this helps

Answer:

Energy exists in a field.

Explanation:

Electrical field, magnetic field, and gravitational field.

A and B are wrong otherwise the law of conservation of energy would be violated

Hurry I need Now!!!In which biome would the climax species be reached most quickly following a fire?
A Taiga
B desert
C Grassland
D. deciduous forest
E tropical rain forest

Answers

Answer:

D. Deciduous Forest.

Explanation:

what is 78%
of 100? help​

Answers

78. Any percent of 100 is literally the number just wi th out the percent. Like 38 percent of 100 is 38. PLEASE MARK BRAINLIEST

Answer:

78

Explanation:

You have 100%, you take 22% and get 78%

PLEASE HELP it’s due in 30 minutes

Answers

Answer:

1-6

3 1 3 3 2 2

Explanation:

A student determines the chromium(III) content of a solution by first precipitating it as chromium(III) hydroxide, and then decomposing the hydroxide to chromium(III) oxide by heating. How many grams of chromium(III) oxide should the student obtain if her solution contains 56.0 mL of 0.600 M chromium(III) nitrate?

Answers

Answer:

Explanation:

Chromium nitrate Cr( NO₃ )₂

Chromium hydroxide Cr( OH)₃

Chromium oxide ( Cr₂O₃ )

1 mole of chromium nitrate will form 1 mole of chromium hydroxide

1 mole of chromium hydroxide will form one mole of chromium oxide .

Moles of chromium nitrate in 56 mL of .6 M solution

= .056 x .6 = .336 moles

.336 moles of chromium nitrate will produce .336 moles of chromium hydroxide and .336 moles of chromium hydroxide will produce .336 moles of chromium oxide .

So chromium oxide produced = .336 moles

Molecular weight of chromium oxide = 152

.336 moles of chromium oxide is equal to

.336 x 152 grams of chromium oxide

= 51.07 grams .

235U92 + 1N0 + 135Cs55 + 99Rb37 + x1n0

Answers

Es hora de comár. Es hora de comár :)

Help pls!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

D a compound

Explanation:

D.
it is a compound and D is the right answer

What type of equation is this?
AlCl3 + NaOH → Al(OH)3 + NaCL
double
single
synthesis
decomp
combustion

Answers

Double. I guess, I’m sorry.

Helppp plssss pls help it’s Science I will give Brainlyist no cap I will just plssss help

Answers

Answer:

I cant see it that well but id be happy to help if u post a clearer picture!

Explanation:

For the reaction of reducing benzil (MW 210.23 g/mol) with sodium borohydride (MW 37.83 g/mol), if 2.56 g of benzil and 0.38 g of sodium borohydride were used to make hydrobenzoin (MW 214.26 g/mol), and 2.22 g of hydrobenzoin was obtained, which chemical is limiting reagent

Answers

Answer:

NaBH₄

Explanation:

First, we need to write the chemical formula of all the compounds:

Benzil: C₁₄H₁₀O₂

Sodium Borhydride: C₁₄H₁₀O₂

Hydrobenzoin: C₁₄H₁₄O₂

Now, let's write the reaction that is taking place and write all the products:

C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH

We can see that the reaction is already balanced, so we don't need to do anything else.

The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)

According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:

moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles

moles NaBH₄ = 0.38 / 37.83 = 0.01 moles

moles  C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles

We have the moles of every species, now, let's see the mole ratio

If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄

Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄

Solving for X:

X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.

However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄

Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.

So, in conclusion, Limiting reagent NaBH₄

Hope this helps

The value of the rate constant for a gas phase reaction can be changed by increasing the A. temperature of the reaction vessel. B. volume of the reaction vessel. C. pressure of the reactant. D. amount of product.

Answers

Answer:

temperature of the reaction vessel

Explanation:

temperature of the reaction vessel

The value of the rate constant for a gas phase chemical reaction can be changed by increasing the: A. temperature of the reaction vessel.

What is the rate constant?

In Chemistry, rate constant is typically used with rate law to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.

The rate law equation.

Mathematically, the rate law is given by this formula:

[tex]R = k[A]^x[B]^y[/tex]

Where:

k is the rate constant.A is the concentration of reactant A.B is the concentration of reactant B.

Generally, the value of the rate constant for a gas phase chemical reaction can be changed by increasing the temperature of the vessel (container) that is used in conducting the chemical reaction.

Read more on rate constant here: brainly.com/question/24749252

A sample of compound A (a clear, colorless gas) is analyzed and found to contain 4.27g carbon and 5.69g oxygen. A sample of compound B (also a clear, colorless gas) is analyzed and found to contain 5.19g carbon and 13.84g oxygen. Are these data an example of the law of definite proportions, the law of multiple proportions, or neither? What do these data tell you about substances A and B?

Answers

Answer:

law of multiple proportions

Explanation:

The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in  simple multiple ratio.

We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.

The substances A and B must be CO and CO2 respectively.

What is the mass in grams of 2.5 mol of O2?

Answers

Answer:

80grams

Explanation:

RAM of O=16

molar mass of O2= 16×2=32g/mol

mass= mole × molar mass

= 2.5×32= 80g

50 points Two waves combine with constructive interference. What must be true of the
combined wave that forms?
A. It has a lower frequency than that of the original waves.
B. It has a higher amplitude than that of the original waves.
C. It has a higher frequency than that of the original waves.
D. It has a lower amplitude than that of the original waves.

Answers

Answer:B

Explanation:

Maybe

Answer:B is correct

Explanation:

Which of the following notations represents an alpha particle?
A. 2 He
C.B+
В. В
D. Y

Answers

Answer:

A. 2 He

Explanation:

The notation of an alpha particle is depicted as:

                     ₂He

An alpha particles is a nucleus of 2 protons and 2 neutrons. So it is actually a Helium cation.

Alpha particles are monoenergetic and they mostly have discrete energy.

So, the mass number of the particle is 4 and atomic number is 2

What is the mass of 5 liters of fluorine (F2) gas at STP?

Answers

Answer:

The molar density of any ideal gas at STP is:

1 mol / 22.4 L = 0.04464 mol / L

The molar mass of F2 is: 2(19) = 38 g/mol

0.04464 mol / L * (38 g / mol) = 1.70 g/L

Explanation:

what the the noble gas configuration for Boron

Answers

Answer:

[He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]

Explanation:

The electron configuration for Boron is 1[tex]s^{2}[/tex]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex], but you can also write it as the noble gas configuration, which is [He]2[tex]s^{2}[/tex]3[tex]p^{1}[/tex]

Note that helium has the configuration of 1[tex]s^{2}[/tex], so we instead of writing it, we write [He]. This can be useful when writing the configurations of elements from the later periods as it saves space.

Answer:-
Dude............G00gle the configuration

Identify the chromatography term that corresponds to each definition.
A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent Choose...
A method used to separate components of a mixture Choose...
The substance to which the sample is bound at the start of an experiment Choose...
The substance that carries the components of a mixture Choose...

Answers

Answer:

A value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent- Retention factor

The substance to which the sample is bound at the start of an experiment- stationary phase

The substance that carries the components of a mixture- mobile phase

Explanation:

The retention is defined as a value that quantifies the distance traveled by a substance relative to the distance traveled by the solvent. It shows us how effective a solvent is at separating a mixture.

The stationary phase is the the substance to which the sample is bound at the start of an experiment. The solvent pick up the substance to be analyzed from this stationary phase. The different components of the mixture are found to move up the stationary phase at different speeds, causing them to eventually  separate from each other.

The mobile phase is the substance that carries the components of a mixture during chromatography.

Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene

Answers

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

How many atoms are in 0.580 moles of CO2?

Answers

Answer:

[tex]1.05x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, according to the definition of the Avogadro's number, it is possible to realize that one molecule of CO2 contains 3 moles of atoms, one of carbon and two of oxygen, thus, we have:

[tex]0.580molCO_2*\frac{3mol\ atoms}{1molCO_2} =1.74mol\ atoms[/tex]

Then, we use the Avogadro's number to obtain:

[tex]1.74mol\ atoms*\frac{6.022x10^{23}atoms}{1mol\ atoms} \\\\1.05x10^{24}atoms[/tex]

Best regards!

How many moles of
salt (NaCl) is 28.7
grams?

Answers

Answer:

0.491 mol NaCl

Explanation:

Convert from grams to moles using the molar mass of NaCl:

28.7 g NaCl x 1 mol NaCl/58.44 g NaCl = 0.491 mol NaCl

The molar mass (58.44 g) can be found from adding the molar masses of the individual elements (Na and Cl); the g NaCl will cancel out (dimensional analysis), leaving you with mol NaCl.

Carbon monoxide and carbon dioxide have

Answers

Answer:

different chemical properties and the same physical properties

Explanation:

Both carbon monoxide and carbon dioxide are gases.

So physically, the two compounds have no fixed shape and volume and their molecules are far apart.

Therefore, they have similar physical properties.

Based on chemical properties, the compounds or molecules given are different.

They will combine chemically in diverse ways.

3. different chemical properties and the same physical properties

Physical properties:  

Both carbon monoxide and carbon dioxide are gases. So physically, the two compounds have no fixed shape and volume and their molecules are far apart.  Therefore, they have similar physical properties.

Chemical properties:

The compounds or molecules given are different.  They will combine chemically in diverse ways.Carbon Dioxide (CO₂) is a chemical compound consisting of one carbon atom and two oxygen atoms while Carbon Monoxide (CO) is a chemical compound which contains one carbon atom and one oxygen atom.CO is also a colorless and odorless gas while CO₂ is entirely human-made and is not naturally present in the atmosphere.Thus, both gases are chemically different.

Therefore, option 3 is correct.

Learn more:

brainly.com/question/15821287

What is a personal factor of resilience?

A. Feeling of belonging

B. Family and friends

C. Genetics

D. Coping Mechanisms

Answers

Answer:

B

Explanation:

B is a personal factor of resilience

Please help

15 points

Answers

Further explanation

Given

Atomic symbol

Required

Atomic composition

Solution

Atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Number of protons and Number of Neutrons  in nucleus

Number of electrons in the shell

From the picture:

protons = 3

neutrons = 4

electrons = 3

atomic number = protons = electrons = 3

mass number = protons + neutrons = 3+4 = 7

How many moles are in 3.69 x 1022 atoms of Ag?​

Answers

Answer:

I'm assuming that 1022 is supposed to be 10^22, or 10 to the 22nd power. If that is the case, then the answer is 0.0612956811 mol. Round it to the number that you are supposed to round it to.

metric conversion ( convert )

Answers

Answer:

13. 2g

14. 5000mL

15. 104,000m

16. 160mm

17. 5600000mg

18. 10hs

19. 0.250km

20. 1daL

Explanation:

13. 1000milligram (mg) = 1gram (g)

Hence, 2000mg = 2000/1000

= 2g

14. 1 litre (L) = 1000millilitre (mL)

Hence, 5L = 5 × 1000

= 5000mL.

15. 1kilometre (km) = 1000metre (m)

Hence, 104km = 104 × 1000

= 104,000m

16. 1 centimetre (cm) = 10millimeters (mm)

Hence, 16cm = 16 × 10

= 160mm

17. 1kilogram (kg) = 1000000 milligram (mg)

Hence, 5.6kg = 5.6 × 1000000

= 5600000mg

18. 1 second (s) = 0.01 hectosecond (hs)

Hence, 1000s = 1000 × 0.01

= 10hs

19. 1000metre (m) = 1kilometre (km)

Hence, 250m = 250/1000

= 0.250km

20. 1 centiliter (cl) = 0.001 Decaliter (daL)

Hence, 1000cl = 1000 × 0.001

= 1daL

Why is HCI a strong acid and HCIO a weak acid?

Answers

Strong Acid: dissolves and dissociates 100% to produce protons (H+) 1. seven strong acids: HCl, HBr, HI, HNO3, H2SO4, HClO4, & HClO3 2. ... Weak Acid: dissolves but less than 100% dissociates to produce protons (H+) 1.

Carbon dioxide non examples? Please and catalyst non examples?

Answers

Answer:

I guess you mean by non element example. Non element examples have more than one elements. Carbon dioxide is a non element example since caebon dioxide has 2 oxygen atoms + 1 carbon atom = carbon dioxide.

I think catalyst is also a non element example because catalyst is inorganic which means that it is not a living thing. Since catalyst is in brass and brass is a non element example, I think catalyst is also a non element example.

Hope that helps, thank you !!

Answer and I’ll give you brainliest!
What type of reaction is this *
N2 + H2 → NH3
O synthesis
O combustion
O decomp
O single
O double

Answers

Combustion. As they are heated at extreme temperatures to form ammonia through Haber process
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