in the figure above, three congruent circles are tangent to eachother and have centers that lie on the diameter of a larger circle. if the area of each of these small circles is 9pi, what is the area of the larger circle?
a) 36pi
b) 49pi
c) 64pi
d) 81pi

Answer: 7 / 8 should be added

Step-by-step explanation:

Let x be the number that should be added

Write the equation

-3/2 + x = -5/8

Add -3/2 on both sides

-3/2 + x + 3/2 = -5/8 + 3/2

x = -5/8 + 3/2

Change the denominator of 3/2 to 8 in order to do addition

x = -5/8 + 12 / 8

x = 7 / 8

Hope this helps!! :)

Please let me know if you have any questions

Answer:

2(1)+y =1 for × intercept

2x+(1)=1 for y intercept

Answer:  

STEP 1  

M_{4,2} is set of 4x2 matrices hence each matrix has 4*2=8 entries. Each entry can be filled independently.  

Hence its basis has 8 linearly independent vectors.  

STEP 2  

Dimension= cardinality of basis = 8.

Answer:

3*10=30 gallons after 10 hours

minus 1 gal/hr for 5 hours=25 gallons.

If the animals are still drinking, the pool is effectively filling at 1 gal/hr, 2-1, and it will take 35 more hours to fill.

If the animals aren't drinking, the pool will fill at 2 gal/hour and it will be full in 35/2 hours or 17.5 hours.

Step-by-step explanation:

Answer:

a first degree equation

Answer:

$25.80

Step-by-step explanation:

First, let's find the cost of one bag of chip:

10.32/8 = 1.29

If one bag costs $1.29, simply multiply the number of bags (20) by 1.29

1.29 x 20 = 25.80

               = $25.80

Answer:

25.80

Step-by-step explanation:

We can use a ratio to solve

8 bags             20 bags

-------------   = ----------------

10.32               x dollars

Using cross products

8x = 10.32 * 20

8x =206.40

Divide each side by 8

8x/7 = 206.40/8

x =25.80

Answer:

B.

Step-by-step explanation:

The answer is B.

Answer:

[0.6969, 0.7695]

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

They randomly survey 401 drivers and find that 294 claim to always buckle up.

This means that [tex]n = 401, \pi = \frac{294}{401} = 0.7332.

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7332 - 1.645\sqrt{\frac{0.7332*0.2668}{401}} = 0.6969[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7332 + 1.645\sqrt{\frac{0.7332*0.2668}{401}} = 0.7695[/tex]

The 90% confidence interval for the population proportion that claim to always buckle up is [0.6969, 0.7695]

Answer: 85 i think

Step-by-step explanation:

Answer:

The  proportions of the diameters that are greater than 25.4 millimeters is 5%.

Step-by-step explanation:

Given;

mean of the normal distribution, m = 25.1 millimeters

standard deviation, d = 0.08 millimeter

1 standard deviation above the mean = m + d = 25.1 + 0.08 = 25.18

2 standard deviation above mean =  m + 2d = 25.1 + 2(0.08) = 25.26

3 standard deviation above the mean = m + 3d = 25.1 + 3(0.08) = 25.34

4 standard deviation above the mean = m + 4d = 25.1 + 4(0.08) = 25.42

To obtain a diameter greater than 25.4, we select data after 4 standard deviation above the mean.

Data within 4 standard deviation above the mean is 95%

Data outside 4 standard deviation above the mean is 5%

Therefore, the  proportions of the diameters that are greater than 25.4 millimeters is 5%.

Answer:

[tex]A" = (7,-2)[/tex]

[tex]B" = (10,0)[/tex]

[tex]C"= (12,-3)[/tex]

Step-by-step explanation:

Given

[tex]A = (4,2)[/tex]

[tex]B = (7,0)[/tex]

[tex]C =(9,3)[/tex]

a: Reflect over x-axis

The rule of this is:

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]A' = (4,-2)[/tex]

[tex]B' = (7,0)[/tex]

[tex]C' = (9,-3)[/tex]

b: Shift 3 units left

The rule of this is:

[tex](x,y) \to (x+3,y)[/tex]

So, we have:

[tex]A" = (4+3,-2)[/tex]

[tex]A" = (7,-2)[/tex]

[tex]B" = (7+3,0)[/tex]

[tex]B" = (10,0)[/tex]

[tex]C"= (9+3,-3)[/tex]

[tex]C"= (12,-3)[/tex]

Answer:

They will blink together at 24minutes

Step-by-step explanation:

Using product of primes

4 = 2²

6 = 2 × 3

8 = 2³

Prime numbers with highest power

2³ × 3

8 x 3

24 minutes.

x= 55°

according to the picture .........

Answer:

8 months 11 days 1 year

Answer:

0.002

Step-by-step explanation:

2 in 4.502 is in the thousandths place

Value is 0.002

Answer:

answer is 12

Step-by-step explanation:

gcf = 3

lcm = 180

let 45 be y

let unknown be X

to get x

X=( lcm * gcf) / y

X=(180*3)/45

X=(540)/45

X=12

the other number is 12

Answer:

a. The number of pounds of the meat required is 3 pounds and the number of pounds of cheese required is 2 pounds.

b. $ 16.7

Step-by-step explanation:

a. How many pounds of each are needed in order to minimize the cost and still meet the minimum requirements?

Let c represent the carbohydrate units and p the protein units.

For the meat portion M, we have 2 units of carbohydrates and 2 units of protein per pound. So, M = 2c + 2p

For the cheese portion K, we have 3 units of carbohydrates and 1 units of protein per pound. So, K = 3c + p.

Let x be the number of pounds of meat required and y be the number of cheese pounds required. The total number of pounds required is T

So, we have xM + yK = x(2c + 2p) + y(3c + p)

= 2xc + 2xp + 3yc + yp

= 2xc + 3yc + 2xp + yp

= (2x + 3y)c + (2x + y)p

Since the required number of units, R is 12 units of carbohydrates and 8 units of protein, we have R = 12c + 8p

Since T = R, we have

(2x + 3y)c + (2x + y)p = 12c + 8p

Equating coefficients, we have

2x + 3y = 12 (1) and 2x + y = 8 (2)

Subtracting (2) from (1), we have

2x + 3y = 12 (1)

-

2x + y = 8 (2)

2y = 4

y = 4/2

y = 2

Substituting y = 2 into (2), we have

2x + y = 8

2x + 2 = 8

2x = 8 - 2

2x = 6

x = 6/2

x = 3

Since x = 3 and y = 2

The number of pounds of the meat required is 3 pounds and the number of pounds of cheese required is 2 pounds.

What is the minimum cost?​

Since meat costs $3.70 per pound and the cheese costs $2.60 per pound and we have 3 pounds of meat and 2 pounds of cheese, the total cost of meat is C = $3.70/pound × 3 pounds = $ 11.1.

The total cost of cheese is C' = $2.60/pound × 2 pounds = $ 5.2.

So, the minimum cost C" = C + C' = $ 11.1 + $ 5.2 = $ 16.7

Answer:

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Let x represent the total number of people. Let C represent those that like cake and let I represent those that like ice cream. Given:

C = (1/4)x = 0.25x, I = 0.5x, (C ∪ I)' = 12, C' = 20

Therefore:

C ∩ I' = C' - (C ∪ I)' = 20 - 12 = 8

C ∩ I = C - C ∩ I' = 0.25x - 8

C' ∩ I = I - C ∩ I = 0.5x - (0.25x - 8) = 0.25x + 8

The total students = (C ∩ I) + (C' ∩ I) + (C ∩ I') + (C ∪ I)'

x = 0.25x - 8 + 0.25x + 8 + 8 + 12

x = 0.5x + 8 + 12

x = 0.5x + 20

0.5x = 20

x = 40

Students that liked both = C ∩ I = 0.25(40) - 8 = 2

Answer:

0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].

150 guests booked:

This means that [tex]n = 150[/tex]

85% of booked guests show up for their room.

This means that [tex]p = 0.85[/tex]

Is the normal approximation suitable:

[tex]np = 150(0.85) = 127.5[/tex]

[tex]n(1-p) = 150(0.15) = 22.5[/tex]

Both greater than 10, so yes.

Mean and standard deviation:

[tex]\mu = E(X) = np = 150*0.85 = 127.5[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150*0.85*0.15} = 4.3732[/tex]

Find the probability that if the motel books 150 guests, not enough seats will be available.

More than 140 show up, which, using continuity correction, is [tex]P(X > 140 + 0.5) = P(X > 140.5)[/tex], which is 1 subtracted by the p-value of Z when X = 140.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{140.5 - 127.5}{4.3732}[/tex]

[tex]Z = 2.97[/tex]

[tex]Z = 2.97[/tex] has a p-value of 0.9985.

1 - 0.9985 = 0.0015.

0.0015 = 0.15% probability that if the motel books 150 guests, not enough seats will be available.

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}[/tex]

[tex]\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}[/tex]

[tex]\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}[/tex]

[tex]\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}[/tex]

[tex]\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}[/tex]

[tex]\mathsf{= \dfrac{27+14}{30}}[/tex]

[tex]\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}[/tex]

[tex]\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

-9

Step-by-step explanation:

-2 3 + |7| - 4 · 2

I assume -2 3 means -2^3.

-2^3 + |7| - 4 · 2 =

= -8 + 7 - 8

= -1 - 8

= -9

Answer:

-9

Step-by-step explanation:

-2^ 3 + |7| - 4 · 2

Parentheses first and an absolute value is considered parentheses

-2 ^3 + 7 - 4 · 2

Then exponenets

Since the sign is outside of the exponent it is considered multiplication

-1 * (2^3)+ 7 - 4 · 2

-1 *8 + 7 - 4 · 2

Then multiply

-8 +7 -8

Then add and subtract from left to right

-1-8

-9

Answer:

it should be letter c

Step-by-step explanation:

I hope this help

Answer:

Step-by-step explanation:

One way of solution is to plot the lines and points and confirm the answer visually.

See attached.

Another way is to substitute the coordinates and verify if they satisfy both of the inequalities.

Each of the methods gives us the correct answer choice of D.

Step-by-step explanation:

well, what does the word "constant" tell you ?

e.g. "this is a constant reminder of ..."

a constant is steady and unchanging. always the same.

so, what could be the constant part/term in the expression ?

-3xy ? is that always the same value ? no matter what values you assign to x, y (and whatever other variables there might be in the system)?

or

10 ? is that always the same value, no matter what values are assigned to x, y, ... ?

there are no other parts/terms I can see here.

so, please use your common sense and pick the right one. you can do that !

this is so simple. to outright write the answer to this feels like an offense. also against your own intelligence.

Answer:

3 seconds

Step-by-step explanation:

First, let's calculate the approximate speed of light.

3 · 10^14 = 3 · 100,000,000,000,000

              = 300,000,000,000,000

Approximately, light travels 300,000,000,000,000 centimeters per second.

Now, let's simplify 9x10^14.

9 · 10^14 = 9 · 100,000,000,000,000

              = 900,000,000,000,000

To find out how many seconds light takes to travel 900,000,000,000,000 centimeters, we have to divide this number by 300,000,000,000,000, the approximate speed of light.

900,000,000,000,000/300,000,000,000,000 = 3

Therefore, it will take 3 seconds for light to travel 900,000,000,000,000 centimeters.

It will take 3 seconds to cover the distance of 9×10¹⁴ cm.

We use the scientific notation of numbers to write very large numbers in compact form.

In the scientific form, we write a number in the form of base×10ⁿ.

Where 0 ≤ base < 10 and n can be any rational number.

Given the speed of light s approximately 3×10¹⁴ cm/sec.

∴ It will take (9×10¹⁴/3×10¹⁴) = 3 seconds.

We know that exponents are added when the same base is multiplied and exponents are subtracted when the same base or integral multiple of the same base is divided.

learn more about scientific notation here :

https://brainly.com/question/18073768

#SPJ2

Answer:

<a=55° ,< b=55° and <c=70°

Answer:

9/4

Step-by-step explanation:

f(x) is continuous and differentiable on (0,9).

We want to find c using the following equation.

f'(c)=(f(9)-f(0))/(9-0)

This will require us to find f'(x) first.

f(x)=sqrt(x) is the same as   f(x)=(x)^(1/2)

Using power rule to differentiate this gives f'(x)=(1/2)(x)^(1/2-1) or simplified f'(x)=(1/2)x^(-1/2) or f'(x)=1/(2x^(1/2)).

So we want to solve:

(1/2)c^(-1/2)=(f(9)-f(0))/(9-0)

Simplify denominator on right:

(1/2)c^(-1/2)=(f(9)-f(0))/9

This will require us to find f(9) and f(0).

If f(x)=sqrt(x), then f(9)=sqrt(9)=3 and f(0)=sqrt(0)=0.

So we have the following equation so far:

(1/2)c^(-1/2)=(3-0)/9

Simplify numerator on right:

(1/2)c^(-1/2)=3/9

Multiply both sides by 2:

c^(-1/2)=6/9

Raise both sides to the -2 power:

c^(1)=(6/9)^(-2)

Note c^1=c:

c=(6/9)^(-2):

Note negative exponent means to find reciprocal of base to change exponent to opposite

c=(9/6)^2

Apply the second power:

c=81/36

Reduce by dividing top and bottom by 9:

c=9/4

This means the slope of the tangent to the curve f at x=9/4 is the same value as the slope of the secant line going through points (0,0) and (9,3).

Also 9/4 is between 0 and 9... According to the theorem we were suppose to get a value c between x=0 and x=9.

Confirmation:

Slope of the secant line is (3-0)/(9-0)=3/9=1/3.

Slope of the tangent line to curve f at x=9/4.

f'(x)=(1/2)x^(-1/2)

f'(9/4)=(1/2)(9/4)^(-1/2)

f'(9/4)=(1/2)(3/2)^(-1)

f'(9/4)=(1/2)(2/3)

f'(9/4)=1/3

They are indeed equal values (talking about the 1/3 from the secant and the tangent.)

Answer:

=3/8×1 1/2×1 1/2

=3/8 ×3/2×3/2                                            ∴ 1 1/2 =2×1+1/2=3/2

=27/32                                                        ∴3×3×3=27   ∴8×2×2=32

Answer: guess it your self

Step-by-step explanation:

Answer:

theres no question....

Step-by-step explanation:

???