If astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years, how long would its semi-major axis length be as it orbited the Sun in AU?

If Astronomers Discovered A New Planet And Found Its Period Of Rotation Around The Sun To Be 105 Years,

Answers

Answer 1

From Kepler's third law, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C

Given that an astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years.

According to Kepler's third law,

[tex]T^{2} \alpha r^{3}[/tex]

Where

T = Period ( in earth years) = time to complete one orbit

r = Length of the semi major axis in Astronomical unit.

[tex]T^{2}[/tex] = [tex]\frac{4\pi ^{2} }{GM} * r^{3}[/tex]

convert years to seconds

105 x 365 day x 24 hours x 3600 s

T = 3311280000 seconds

Mass of the sun M = 1.989 × 10^30 kg

G = 6.67 x [tex]10^{-11}[/tex]N m^2/kg^2

Substitute all the parameters into the formula

[tex]T^{2}[/tex] = 1.096 x [tex]10^{19}[/tex] = [tex]\frac{4\pi ^{2} }{6.67 * 10^{-11} * 1.989 * 10^{30} } * r^{3}[/tex]

1.096 x [tex]10^{19}[/tex] = 2.976 x [tex]10^{-19}[/tex] [tex]r^{3}[/tex]

[tex]r^{3}[/tex] = 1.096 x [tex]10^{19}[/tex] / 2.976 x [tex]10^{-19}[/tex]

[tex]r^{3}[/tex] = 3.68 x [tex]10^{37}[/tex]

r = [tex]\sqrt[3]{3.68 * 10^{37} }[/tex]

r = 3.33 x [tex]10^{12}[/tex] m

1 AU = 1.5 x [tex]10^{11}[/tex] m

r = 3.33 x [tex]10^{12}[/tex] / 1.5 x [tex]10^{11}[/tex]

r = 22.18 AU

Therefore, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C

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Answer 2

Answer:

C. 22.3 AU

Explanation:

Not only is the above an unnecessarily complicated answer, it's not even fully correct, and definitely not what they want you to do.

T^2 = s^3, where T = orbital period and s = semi-major axis length.

Substitute T and you get 105^2 = s^3. Solve for s.

11025 = s^3

3√11025 = s

22.25663649 = s

Therefore, the answer is C. 22.3 AU


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Answer:

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Answers

The magnitude of the frictional force of the box is 65 N

From the question given above, the following data were obtained:

Mass (m) = 25 KgForce applied (Fₐ) = 135 NNet force (Fₙ) = 70 NFrictional force (Fբ) =?

The frictional force acting on the box can be obtained as follow:

Fₙ = Fₐ – Fբ

70 = 135 – Fբ

Collect like terms

70 – 135 = – Fբ

–65 = –Fբ

Multiply through by –1

Fբ = 65 N

Thus, the frictional force of the box is 65 N

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The viscous force ​refers to the resistance of a fluid to flow.  It is measured in Newton-second per square meter.

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Answer:

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Answer:

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Convert 500 joules to kilojoules.

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Joules to kilojoules conversion table

Energy (J) Energy (kJ)

1 J 0.001 kJ

2 J 0.002 kJ

3 J 0.003 kJ

4 J 0.004 kJ

5 J 0.005 kJ

6 J 0.006 kJ

7 J 0.007 kJ

8 J 0.008 kJ

9 J 0.009 kJ

10 J 0.01 kJ

20 J 0.02 kJ

30 J 0.03 kJ

40 J 0.04 kJ

50 J 0.05 kJ

60 J 0.06 kJ

70 J 0.07 kJ

80 J 0.08 kJ

90 J 0.09 kJ

100 J 0.1 kJ

200 J 0.2 kJ

300 J 0.3 kJ

400 J 0.4 kJ

500 J 0.5 kJ

600 J 0.6 kJ

700 J 0.7 kJ

800 J 0.8 kJ

900 J 0.9 kJ

1000 J 1 kJ

2000 J 2 kJ

3000 J 3 kJ

4000 J 4 kJ

5000 J 5 kJ

6000 J 6 kJ

7000 J 7 kJ

8000 J 8 kJ

9000 J 9 kJ

10000 J 10 kJ

100000 J 100 kJ

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Answers

The reading on the scale is equal to the weight of the student which is 646.8 N.

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The reading on the scale is determined by applying Newton's second law of motion as follows;

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Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.

The complete question is below:

A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?

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HELP ASAP WHOEVER ANSWERS FIRST WITH BE BRAINIEST PLEASE HELP!

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The answer is : A₃ = A₁ - A₂ = 3.0 - 2.0 =  1.0A

Ok done. Thank to me :>

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Answers

Answer:u=350m/sec

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= -350×1000/5

= -70×1000

= -70000 m/sec^2

Explanation: i think this will help you thankyou

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Answer:

HOPE THIS HELPS!!

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Velocity is speed as well as distance mentioned.

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Answers

Convergent boundaries are caused by the collision of two plates and can originate volcanoes. Transforming boundaries produce fractures by displacement. The correct option is D. Type A boundaries have fewer volcanoes.

----------------------------------------

The crust -the outermost layer of the earth- is divided into many plates that move over the mantle.

These plates are limited by three types of ridges or borders that differ in the movement they produce.

Boundaries types:

I. Divergent:

This boundary occurs when two plates separate and molten material rises from the mantle creating a new crust.

The hot material creates a new seabed between the separating plates, expanding the sea bottom.

II. Convergent.

Collision area between two plates.

Two oceanic plates might collide, or one oceanic plate with a continental one.

In this last case, the oceanic crust sinks under the continental plate, and magma rises to the surface by crevices.

The thicker and older plate subduces under the other plate.

Collisions create volcanic arches and continental arches.

III. Transforming.

The plates slide laterally with each other, and they are usually called faults.

It is associated, in general, with the oceanic ridge, although it might also occur in the continental plate.

No rocky material is either destroyed or formed.

When the plates move and produce a displacement of one transforming limits from side to side, earthquakes occur.

The movement breaks the crust and originates pronounced fractures.

In the attached images, we can see

image A representing transforming boundaries, image B representing Convergent boundaries.

Image B is the one that can originate volcanoes because transforming boundaries only produce fractures.

So the correct option would be D.

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Answer:

d

Explanation:

Help please physics work

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At any point along the track, the rollercoaster's mechanical energy is equal to the sum of its potential and kinetic energies,

M = P + K

and we assume the coaster's total mechanical energy is conserved throughout its motion along the track, so that M is the same at every point.

At the first point,

K + 75,000 J = 90,000 J   ⇒   K = 15,000 J

At the second point, since M = 90,000 J everywhere,

K + 45,000 J = M   ⇒   K = 45,000 J

At the third point,

K + 0 J = M   ⇒   K = 90,000 J

The same principles apply to the pendulum, so M = 5,100 J throughout its swing.

At the first point,

K + 4,500 J = 5,100 J   ⇒   K = 600 J

At the second point,

K + 0 J = M   ⇒   K = 5,100 J

At the third point,

600 J + P = M   ⇒   P = 4,500 J

An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?

Answers

Answer:

I = 250N*s

Explanation:

I = F*t

I =  impulse or momentum

F = Force

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I = 25N*10s

I = 250N*s

What is the density of a substance that has a volume of 30ml and a mass of 20g?

Answers

Answer:

0.67 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]d = \frac{m}{v} \\ [/tex]

m is the mass

v is the volume

From the question

m = 20 g

v = 30 mL

We have

[tex]d = \frac{20}{30} = \frac{2}{3} \\ = 0.66666...[/tex]

We have the final answer as

0.67 g/mL

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Answers

Answer:

see explanation

Explanation:

by my calculations, i believe it may be because they have to pretend to be in space.

one of them is Space & Interstellar Travel

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