How many volts would it take to push 1 amp through a resistance of 1 ohm?

7777Answer:

Explanation:

Answer:

kinematics explains the terms like acceleration, velocity, and position of the objects while in motion.

Some important parameters in kinematics are displacement, velocity, and time.

Explanation:

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thank me if it was correct for you too.

Answer:

Explanation:

If the person inserted a nail with a hammer instead of the screw with the screwdriver, the force applied would be greater, but the distance would be shorter. The correct option is A.

The action of push or pull in order to make a body change its state of motion or rest is called Force.

As the force is pressure per unit area. Force is inversely proportional to the area over which force is to applied.

The hammer would take more force to insert the nail. The screw has its helix which is to be inserted and application of force is small.

Thus, the force applied would be greater, but the distance would be shorter.  The correct option is A.

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t if the person inserted a nail with a hammer instead of the screw with the screwdriver?

Answer:

gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)

The federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.

The given parameters:

Biweekly amount earned by the single teacher, = $1,500

The federal tax rate for single workers is given as;

amount between $436 and $1,506 = $34.9 plus 15%

The federal income tax withholding for each biweekly paycheck for the single teacher is calculated as follows;

income tax withholding = $34.9  +  0.15($1,500)

income tax withholding = $34.9  +  $225

income tax withholding  = $259.9

Thus, the federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.

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you would die.

the core of the earth is as hot as the sun surface so you would be dead

Answer:

bro the way you worded it makes no since

Answer:

Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.

Explanation:

An object that weighs  75  N is pulled horizontally to the right with a force of  50  N. The force of friction on this object is  30  N to the left. What is the acceleration of the object?

The force on the object is  50  N to the right and  30  N to the left.

⇒  The net force on the object is,  =50−30=20  N to the right.

The weight of the object is,  =75  N.

⇒  The mass of the object is  ==759.8  kg.

⇒  The acceleration of the object is  ==20759.8=2.613  m/s 2.

The acceleration of the object is 10 [tex]m/s^2[/tex].

Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.

It can be expressed as:

a= v/t

where, a is the acceleration

v is the velocity

t is the time taken

It can also be expressed as F=ma

where, F= force applied

m= mass of the object

So, for above given information

The force on the object is 9N to the right and  30N to the left. The net force on the object is 21N to the left

The mass of the object is 2kg

So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]

Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].

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Answer:

ch3sh + 4O2 are the products

The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

The given parameters:

The normal reaction on the rough surface due to weight of the block is calculated as follows;

[tex]F_n = 40 \ N[/tex]

The static friction between the block and the plane is calculated as follows;

[tex]F_s = \mu_s F_n[/tex]

where;

Thus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

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The force on the truck is the same in magnitude as the force on the car.

The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.

J = Ft

where;

The increase in the force applied to an object causes an increase in the impulse experienced by the object.

Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.

Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.

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Answer:

translucent

Explanation:

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Answer:

[tex]88.3ms {}^{ - 2} [/tex]

or 88.3m/s^2

Explanation:

Using suvat where we list everything that we are given

s=49m

u=0m/s

v=93m/s

a=?

t=we are not given this value, so we don't use

using a formula that doesn't involve time:

[tex]v {}^{2} = u {}^{2} + 2as[/tex]

rearranging to find acceleration by subtracting u^2 on both sides

[tex]v {}^{2} - u {}^{2} = 2as[/tex]

then dividing 2s on both sides

[tex] \frac{v {}^{2} - u {}^{2} }{2s} = a[/tex]

[tex] \frac{(93) {}^{2} - (0) {}^{2} }{2 \times(49) } = 88.3ms {}^{ - 2} [/tex]

so the acceleration is 88.3ms^-2 (1dp)

Evaporation, or turning liquid to a gas, is first. Then it goes into the atmosphere and codensates, or turns back to a liquid, these water droplets form into clouds and come down as precipitation, rain, sleet, snow etc. Then the water cycle starts again

Answer:

X = 24.135 kilometres

Explanation:

Given the following data;

Distance = 15 miles

To convert the value in miles to kilometers;

Conversion:

1 mile = 1.609 kilometres

15 miles = X kilometres

Cross-multiplying, we have;

X = 1.609 * 15

X = 24.135 kilometres

Answer:

dam/hydro power

Explanation:

estuary is the place where rivers meet the ocean, there are a lot of currents there (waves...) so it likely means thery use a dam or some sort of way of collecting electricity from the motion of the water there. many birds live in estuaries because of being able to find fish to feed from

Method 3 is "Estuary." describes some features of methods used to generate electricity.

An estuary is a coastal area where freshwater from rivers meets and mixes with saltwater from the ocean. This mixing creates a unique and dynamic environment that can be harnessed for electricity generation using a method called "tidal energy" or "tidal power." Tidal energy is a renewable energy source that captures the kinetic energy generated by the ebb and flow of tides in estuaries.

Ideal Location: Estuaries are ideal locations for tidal energy generation because they experience regular and predictable tidal movements due to the gravitational pull of the moon and sun. The rise and fall of tides create kinetic energy in the moving water.

Method: Tidal energy is harnessed using underwater turbines that are placed in strategic locations within the estuary. As the tidal currents flow in and out, they drive the turbines, which generate mechanical energy. This mechanical energy is then converted into electricity using generators.

Possible Problem: One potential problem associated with tidal energy generation in estuaries is its impact on the local ecosystem. The underwater turbines and infrastructure could potentially disrupt marine life and habitats, affecting fish migration patterns and other aquatic species. It's important to carefully study and manage the environmental impact of tidal energy projects to minimize any negative consequences.

Overall, tidal energy from estuaries offers a renewable and predictable source of electricity, but it requires careful planning and environmental considerations to ensure sustainable and responsible energy production.

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Answer:

Momentum is directly proportional to the object's mass and also its velocity.

Explanation:

Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.

Answer:

Distance = 1489.5 meters

Explanation:

Given the following data;

To find how far away is the train;

Mathematically, the distance of an object is calculated using the formula;

Distance = speed * time

Distance = 331 * 4.5

Distance = 1489.5 meters

For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.

According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.

Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.

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Answer:

d

Explanation:

Given,

length of object, [tex]h_o = 3 cm[/tex]

We know, for flat refracting surface,  

Image distance = object distance

So,

magnification is = [tex]-1[/tex]

length of the image,

[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]

Here, negative sign means inverted image.

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Answer:the super villain would have the ability to control electricity and could take any Metal object or weapons that anyone points at him because he is magnetic

Explanation:

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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1. Frequency

2. Reflected

3. Absorbed

4. Black

The sled was launched with a velocity of 26.24 m/s

We'll begin by calculating the the time taken for the sled to land

Height (h) = 39 m

Acceleration due to gravity (g) = 9.8 m/s²

[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]

Time (t) = 2.82 s

Horizontal distance (s) = 74 m

[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]

Therefore, the sled was launched with a velocity of 26.24 m/s

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The smallest value of the force that will make the block not to slide down is 10 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

N = mg

N = 8 × 10

N = 80 N

Finally, we shall determine the frictional force.

F = μN

F = 0.4 × 80

F = 32 N

Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.

From the options given above, only option A has a force that is lesser than the frictional force.

Therefore, the correct answer to the question is Option A. 10 N

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Answer:

 F = 7.68 10¹¹ N,  θ = 45º

Explanation:

In this exercise we ask for the net electric force. Let's start by writing the configuration of the charges, the charges of the same sign must be on the diagonal of the cube so that the net force is directed towards the interior of the cube, see in the attached numbering and sign of the charges

The net force is

          F_ {net} = F₂₁ + F₂₃ + F₂₄

bold letters indicate vectors. The easiest method to solve this exercise is by using the components of each force.

let's use trigonometry

          cos 45 = F₂₄ₓ / F₂₄

          sin 45 = F_{24y) / F₂₄

          F₂₄ₓ = F₂₄ cos 45

          F_{24y} = F₂₄ sin 45

let's do the sum on each axis

X axis

          Fₓ = -F₂₁ + F₂₄ₓ

          Fₓ = -F₂₁₁ + F₂₄ cos 45

Y axis  

         F_y = - F₂₃ + F_{24y}

         F_y = -F₂₃ + F₂₄ sin 45

They indicate that the magnitude of all charges is the same, therefore

         F₂₁ = F₂₃

Let's use Coulomb's law

         F₂₁ = k q₁ q₂ / r₁₂²

the distance between the two charges is

         r = a

         F₂₁ = k q² / a²

we calculate F₂₄

           F₂₄ = k q₂ q₄ / r₂₄²

the distance is

           r² = a² + a²

           r² = 2 a²

we substitute

           F₂₄ = k  q² / 2 a²

we substitute in the components of the forces

          Fx = [tex]- k \frac{q^2}{a^2} + k \frac{q^2}{2 a^2} \ cos 45[/tex]

          Fx = [tex]k \frac{q^2}{a^2}[/tex]  ( -1 + ½ cos 45)

          F_y = k \frac{q^2}{a^2} ( -1 +  ½ sin 45)    

We calculate

            F₀ = 9 10⁹ 4.25² / 0.440²

            F₀ = 8.40 10¹¹ N

            Fₓ = 8.40 10¹¹ (½ 0.707 - 1)

            Fₓ = -5.43 10¹¹ N

remember cos 45 = sin 45

             F_y = - 5.43 10¹¹  N

We can give the resultant force in two ways

a) F = Fₓ î + F_y ^j

          F = -5.43 10¹¹ (i + j)   N

b) In the form of module and angle.

For the module we use the Pythagorean theorem

          F = [tex]\sqrt{F_x^2 + F_y^2}[/tex]

          F = 5.43 10¹¹  √2

          F = 7.68 10¹¹ N

in angle is

           θ = 45º