How many molecule are in 1.80mol of water

Explanation:

kinetic energy Increases due to gravity. A rock being pushed down a hill increases in speed, due to gravity, what goes up must come down....

Answer:

polar

Explanation:

Answer:

If the electronegativity difference between the atoms is greater than 2.0, the bond is ionic. Ionic compounds are extremely polar molecules.

Explanation:

Answer:

12.39 x 10⁷ kg

Explanation:

A typical new household refrigerator uses about 700 kWh of electricity per year.

No of household = 300000

Total energy  used up = 300000 x 700 kWh

= 21 x 10⁷ kWh .

Production of each kWh energy produces .59 kg of CO₂

Production of 21 x 10⁷  kWh energy produces .59 x 21 x 10⁷ kg of CO₂

CO₂ produced =  .59 x 21 x 10⁷ kg

= 12.39 x 10⁷ kg

Answer:

0.011mole

Explanation:

Given parameters:

Mass of potassium in the banana = 0.42g

Unknown:

Number of moles of potassium in the banana = ?

Solution:

To solve this problem, we use the expression below:

     Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

Molar mass of K  = 39g/mol

   Number of moles  = [tex]\frac{0.42}{39}[/tex]   = 0.011mole

the answer Is A hope it helps

The food has 23629.64 cal

Given

mass = 1000 g of water

temperature increases 23.65 * C

Required

The energy of the food

Solution

Heat absorbed by water :

Q = m . c . Δt

Q = 1000 g x 4.184 J/g°C x 23.65 °C

Q = 98951.6 J

1 Joules = 0.2388 Calories

98951.6 J = 23629.64 cal

Answer:

Nickel

Explanation:

Given data:

Density of iron = 7.9 g/cm³

Density of lead = 11.3 g/cm³

Density of nickel = 8.9 g/cm³

Mass of sample = 134 g

Volume of sample = 15 cm³

Which metal it is = ?

Solution:

First of all we will calculate the density of sample and then match it with the density of given metals.

Formula:

d = m/v

by putting values,

d = 134 g/ 15 cm³

d = 8.9 g/cm³

The weighted sample is nickel metal.

The molarity = 1.716 M

Given

25 ml ethanol

d = 0.789 g/ml

250 ml solution

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

mass of ethanol :

= 25 ml x 0.789 g/ml

= 19.725 g

mol ethanol :

= 19.725 g : 46 g/mol

= 0.429

The molarity :

= 0.429 : 0.25 L

= 1.716 M

The molarity of ethanol in the solution is 1.716M

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Determine the mass of ethanol :

Mass of ethanol = 25 ml x 0.789 g/ml

Mass of ethanol = 19.725 g

Determine the moles of ethanol

Moles = Mass/Molar mass

Moles = 19.725 g/46 g/mol

Moles of ethanol = 0.429moles

Calculate the molarity using the formula below;

Molarity = Moles/Volume

Molarity = 0.429/0.25 L

Molarity = 1.716 M

Hence the molarity of ethanol in the solution is 1.716M

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Answer:

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Explanation:

In this case, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

Being the molar mass of each compound:

Then, by stoichiometry, the following quantities of mass participate in the reaction:

So you can apply the following rules of three:

[tex]mass of CO_{2} =\frac{2.55 moles of C_{3} H_{8}*132 gramsof CO_{2} }{ 1 mole of C_{3} H_{8}}[/tex]

mass of CO₂= 336.6 grams

[tex]mass of H_{2}O =\frac{2.55 moles of C_{3} H_{8}*72 gramsof H_{2}O }{ 1 mole of C_{3} H_{8}}[/tex]

mass of H₂O= 183.6 grams

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Answer:

68.1% is percent yield of the reaction

Explanation:

The reaction of methane with oxygen is:

CH₄ + 2O₂ → CO₂ + 2H₂O

Where 2 moles of oxygen react per mole of CH₄

Percent yield is:

Actual yield (28.2g CO₂) / Theoretical yield * 100

To solve this question we need to find theoretical yield finding limiting reactant :

Moles CH₄:

15.1g CH₄ * (1mol / 16.04g) = 0.9414 moles

Moles O₂:

81.2g * (1mol / 32g) = 2.54 moles

For a complete reaction of 0.9414 moles of CH₄ are needed:

0.9414 moles CH₄ * (2 mol O₂ / 1mol CH₄) = 1.88 moles of O₂. As there are 2.54 moles, O₂ is in excess and CH₄ is limiting reactant

In theoretical yield, the moles of methane added = Moles of CO₂ produced. That is 0.9414 moles CO₂. In grams = Theoretical yield:

0.9414 moles CO₂ * (44.01g / mol) = 41.43g CO₂

Percent yield: 28.2g CO₂ / 41.43g CO₂ * 100=

Answer: it's 4nitrogen

denotes two nitrogen atoms. 2. N 2 denotes one molecule of nitrogen gas.

Explanation:

Answer:

Simple carbs break down easier and contain sugars. Complex carbs contain starch and fiber.

Explanation:

Answer Image result for What is the difference between the structure of simple and complex carbohydrates?

Simple vs Complex Carbs. Carbohydrates are sugars that come in 2 main forms – simple and complex. This is also referred to as simple sugars and starches. The difference between a simple and complex carb is in how quickly it is digested and absorbed – as well as it's chemical structure.

The numbers inside the box represent the number of protons or atomic number while the circles represent the energy levels or shells in the atom. The dots represent the electrons occupying those shells.

The atomic number refers to the number of protons in the nucleus of an atom. It is shown as the number inside the boxes. It serves as the identity of an element.

The electrons occupy shells of particular energy levels according to Bohr model. The circles represent these energy levels. The dots in the circles represent the electrons that occupy those energy levels.

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Answer:

1.34 * 10^-7 M

Explanation:

The Ksp of lead II chromate is 1.8 x 10^-14

So, we have that;

PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)

                             s                  s

Where s = molar concentration of Pb^2+(aq) and  CrO4^2-(aq)

and;

[Pb^2+] = [CrO4^2-]

This implies that Ksp = s^2

s = √Ksp

s = √1.8 x 10^-14

s = 1.34 * 10^-7 M

it is cooled to a liquid

Answer:

Density, d = 5.96 g/mL

Explanation:

Given that,

Mass, m = 105 g

Volume, V = 17.6 mL

We need to find the density of the substance. So,

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{105\ g}{17.6\ mL}\\\\d=5.96\ g/mL[/tex]

So, the density of the substance is 5.96 g/mL.

Answer:

Carboxylic acid

Explanation:

Asprin is a drug that contains the carboxylic acid functional group (R-COOH), ester functional group (R-O-CO-R') and the aromatic group (benzene ring).

When we take in aspirin, it becomes salicylic acid. This metabolite irreversibly inhibits the enzyme cyclooxygenase. Hence the the production of protective prostaglandins is blocked causing inflammation and pain.

Answer:

one mole of oxygen will produce [tex]0.4[/tex] moles of water

Explanation:

The balanced chemical reaction is as follows -

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

As we can see in this reaction

5 mole of oxygen (on the reactant side) will produce 2 mole of water (on the product side)

Hence, one mole of oxygen will produce [tex]\frac{2}{5} =0.4[/tex] moles of water

Mass of Potassium : 116.1 g

Given

38.7% potassium in Potassium nitrate

300 g of KNO3

Required

mass of potassium

Solution

%mass of element = (mass of an element in 1 mole of compound/mass of 1 mole compound) x 100%

mass of K(potassium) in 300 g KNO3 :

= 38.7% x 300 g

= 116.1 g

Answer:

See explanation below

Explanation:

In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:

P₁V₁ = P₂V₂    (1)

You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.

So using the above expression, we can solve for P₂:

P₂ = P₁V₁ / V₂    (2)

In this case, we already have the values of presures and volume, so replacing in this expression:

P₂ = 34.5 * 5 / 214

This should be the pressure of the liquid.

Hope this helps

Answer:

56/hr

Explanation:

Answer:

B. Velocity has direction, and speed does not.

Explanation:

Velocity is a vector, meaning it has both a magnitude and direction. Speed is a scalar, meaning it only has a magnitude and no direction.

Answer:

The final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Explanation:

It is given that sodium hydroxide is added to collect the solid nickel(II) hydroxide product

The empirical equation for this statement is

Ni2+ + NaOH --> Ni (OH)2 + Na+

We will first balance the hydroxide molecule. On the right side there are two OH molecules.

Thus, on the left side we will take 2 sodium hydroxide

Ni2+ + 2NaOH --> Ni (OH)2 + Na+

Now we will balance the sodium ion which are 2 in numbers on the left side and 1 on the right side

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

So, the final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

Answer: A: Has little to no reaction; might turn slightly red in color. B: The liquid grows darker in color to a more reddish tone.

Explanation: I didn’t have the necessary materials to complete the experiment so the teacher told me and I put it in my own words.

Answer: D. The exponents determine how much concentration changes affect the reaction rate.

Explanation: This is correct. The exponents in the rate law do determine how much the concentration changes impact the reaction rate.

Option A i.e. The effect of concentration changes on the rate constant affects the reaction rate.

what is rate constant?

The proportionality constant, which explains the link between the molar concentration of the reactants and the pace of a chemical reaction, is known as the rate constant. The rate constant, also known as the reaction rate constant or reaction rate coefficient, is indicated by the letter k. Because reactant concentrations decrease as reactants are transformed to products, reaction speeds typically decrease over time. When reactant concentrations are raised, reaction rates generally increase. The temperature has an impact. The following are two methods for calculating rate constant:

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Answer:

the invention of the microscope has made seeing bacteria/cells, examining forensic evidence (such as fingerprints), studying atomic structure, tissue analysis, and the study of our ecosystem possible to the naked eye

Explanation:

hope this helps