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I need about 5 advantages of E-learning​

Answer:

a then c

Explanation:

Without an operating system you just have a pile of metal, and the program contains code, which is just a series of commands

Answer:

d.) The operating system, the application software

Answer:

Code:

CREATE TABLE student (

stu_code INTEGER PRIMARY KEY,

prof_code INTEGER

);

INSERT INTO student VALUES (100278,null);

INSERT INTO student VALUES (128569,2);

INSERT INTO student VALUES (512272,4);

INSERT INTO student VALUES (531235,2);

INSERT INTO student VALUES (531268,null);

INSERT INTO student VALUES (553427,1);

CREATE TABLE professor (

prof_code INTEGER PRIMARY KEY,

dept_code INTEGER

);

INSERT INTO professor VALUES (1,2);

INSERT INTO professor VALUES (2,6);

INSERT INTO professor VALUES (3,6);

INSERT INTO professor VALUES (4,4);

The SQL NATURAL JOIN is a type of EQUI JOIN and is structured in such a way that, columns with the same name of associated tables will appear once only. In our Example, Prof_code will appear only once and it will be matched in both the table;  

SELECT * FROM Student natural join Professor on student.prof_code=Professor.prof_code ;  

Stud_code   Prof_code  Dept_code

128569        2           6

512272        4           4

531235        2           6

553427        1           2

EQUI JOIN performs a JOIN against equality or matching column(s) values of the associated tables and an equal sign (=) is used as a comparison operator in the where clause to refer to equality. In our example, it will only show the result with prof_code=2 from the natural join result.

SELECT * FROM Student join Professor on student.prof_code=Professor.prof_code where student.prof_code=2;

Stud_code Prof_code Prof_code Dept_code

128569     2         2         6

531235     2         2         6

In SQL the FULL OUTER JOIN combines the results of both left and right outer joins and returns all (matched or unmatched) rows from the tables on both sides of the join clause.

SELECT * FROM professor full outer join student on professor.prof_code=student.prof_code ;

Stud_code Prof_code Prof_code Dept_code

100278                

128569    2          2         6

512272    4          4         4

531235    2          2         6

531268    

                    3         6

553427    1          1         2

Answer:

package GUI;  

import java.awt.*;  

import java.awt.event.*;  

import javax.swing.*;

// Class SandwichShop definition

public class SandwichShop

{

// Creates a string array for sandwich ingredients  

String sandwichIngredients [] = {"Chicken", "Mutton", "Veg"};

// Creates a string array for bread types

String breadTypes[] = {"Bloomer", "Cob", "Plait"};

// Container object declared

JFrame jf;

JPanel p1, p2, p3, p4, mainP;

// Component object declared

JList ingredient, bread;

JLabel ingL, breadL, amountL;

JTextField amountT;

JButton amountB, exitB;

// Default constructor definition

SandwichShop()

{

// Creates frame

jf = new JFrame("Sandwich Shop");

// Creates panels

p1 = new JPanel();

p2 = new JPanel();

p3 = new JPanel();

p4 = new JPanel();

mainP = new JPanel();

// Creates list box and adds string array

ingredient = new JList<String>(sandwichIngredients);

bread = new JList<String>(breadTypes);

// Creates labels

ingL = new JLabel("Select Sandwich Ingredients");

breadL = new JLabel("Select Bread Types");

amountL = new JLabel("Amount: ");

// Creates text field

amountT = new JTextField(5);

// Creates buttons

amountB = new JButton("Check Amount");

exitB = new JButton("Exit");

// Adds components to panels

p1.add(ingL);

p1.add(ingredient);

p2.add(breadL);

p2.add(bread);

p3.add(amountL);

p3.add(amountT);

p4.add(amountB);

p4.add(exitB);

// Adds panels to main panel

mainP.add(p1);

mainP.add(p2);

mainP.add(p3);

mainP.add(p4);

// Set the main panel layout to 4 rows and 1 column

mainP.setLayout(new GridLayout(4, 1));

// Adds main panel to frame

jf.add(mainP);

// Sets the frame visible property to true

jf.setVisible(true);

// Set the size of the frame to width 400 and height 150

jf.setSize(400, 300);

// Registers action listener to exit button using anonymous class

exitB.addActionListener(new ActionListener()

{

// Overrides the actionPerformed() method

public void actionPerformed(ActionEvent ae)

{

System.exit(0);

}// End of method

});// End of anonymous class

// Registers action listener to amount button using anonymous class

amountB.addActionListener(new ActionListener()

{

// Overrides the actionPerformed() method

public void actionPerformed(ActionEvent ae)

{

// Extracts index of the selected item from the list box

int indexIngredient = ingredient.getSelectedIndex();

int indexBread = bread.getSelectedIndex();

// Checks if ingredient index is 0 and bread index is 0

// then set the amount 100 in text field

if(indexIngredient == 0 && indexBread == 0)

amountT.setText("100");

// Checks if ingredient index is 0 and bread index is 1

// then set the amount 120 in text field

if(indexIngredient == 0 && indexBread == 1)

amountT.setText("120");

// Checks if ingredient index is 0 and bread index is 2

// then set the amount 160 in text field

if(indexIngredient == 0 && indexBread == 2)

amountT.setText("160");

// Checks if ingredient index is 1 and bread index is 0

// then set the amount 190 in text field

if(indexIngredient == 1 && indexBread == 0)

amountT.setText("190");

// Checks if ingredient index is 1 and bread index is 1

// then set the amount 205 in text field

if(indexIngredient == 1 && indexBread == 1)

amountT.setText("205");

// Checks if ingredient index is 1 and bread index is 2

// then set the amount 210 in text field

if(indexIngredient == 1 && indexBread == 2)

amountT.setText("210");

// Checks if ingredient index is 2 and bread index is 0

// then set the amount 97 in text field

if(indexIngredient == 2 && indexBread == 0)

amountT.setText("97");

// Checks if ingredient index is 2 and bread index is 1

// then set the amount 85 in text field

if(indexIngredient == 2 && indexBread == 1)

amountT.setText("85");

// Checks if ingredient index is 2 and bread index is 2

// then set the amount 70 in text field

if(indexIngredient == 2 && indexBread == 2)

amountT.setText("70");

}// End of method

});// End of anonymous class

}// End of default constructor

// main function definition

public static void main(String[] args)

{

// Creates an anonymous object by calling default constructor

new SandwichShop();

}// End of main method

}// End of class

Output:

Answer:

i don't know the answer please tell me

Answer:

........

Explanation:..........

Answer:

The program in Python is as follows:

A = int(input("A: "))

B = int(input("B: "))

C = int(input("C: "))

while A<=0 or B <= 0 or C <= 0:

   A = int(input("A: "))

   B = int(input("B: "))

   C = int(input("C: "))

print("Valid inputs")

Explanation:

Get input for A, B and C

A = int(input("A: "))

B = int(input("B: "))

C = int(input("C: "))

The loop is repeated until inputs for A, B and C are above 0

while A<=0 or B <= 0 or C <= 0:

Get input for A, B and C

   A = int(input("A: "))

   B = int(input("B: "))

   C = int(input("C: "))

Print valid inputs when user inputs are correct

print("Valid inputs")

Answer:

ae

Explanation:

The pseudo-code that corresponds to the given assembly code is:

b) if (c < 0)

print (yes);

else

print (maybe);

In assembly code, the command cmp AH, c checks if the high byte of the EAX register (AH) has the same value as the variable c. Then, if the value in AH is more than the value in c, the instruction jg option1 will move to option1.

Therefore, In the pseudo-code, one can check if c is smaller than 0. If it happens, we say "yes". If not, we say "maybe"

Read more about   pseudo-code here:

https://brainly.com/question/24953880

#SPJ2

Answer:

Hence the correct option is option a) define both structures and then create a data member of the nested structure type within the other structure.

Explanation:

To make Address nested to Employee, we've to define Address structure before and out of doors Employee structure and make an object of Address structure inside Employee structure.

For example, we may need to store the address of an entity employee in a structure.

Answer:

false the creator of adobe photoshop was microsoft adobe photoshop is a popular photo editing software which was developed by a company named as adobe inc.

Answer:

Photoshop is created by Adobe, and Adobe is an independent company started by Jhon Warnockand.

Answer:

all of the above

Answer:

Creating and maintaining a healthy sales pipeline is challenging but not impossible.  

The B2B world has changed, and you need to adopt new strategies to build a healthy pipeline. Choose the best LinkedIn automation tool, optimize your profile, know your audience and share personalized content for quick outcomes.

Answer:

Hence the answer is given as follows,

Answer:

explain all background information first.

Explanation:

Now if you are to deliver a message and you have suspicions that the person who is to read it might be uninterested, unwilling, hostile or displeased, you should put the main idea later in the message. That is, it should come after you have provided details given explanations or evidence.

It is not right to start with bad news. As a matter of fact bad news should not be shared through mails, IM or texts.

Answer:

Right click anywhere on your taskbar, and then click Properties. Step 2: Find and click the Notification Area tab on the top bar, and then find the section labeled with System icons, check the checkbox for Network. Last, click OK to finish it.

Answer:

The answer is below

Explanation:

Usability is a term that describes the assessment of the performance of a system in assisting the task of the user, or how effective a certain product system or design supports the task of a user in accomplishing a set out objective as desired.

The characteristics of an interface that are used to assess a system’s usability are:

1. Effectiveness

2. Efficiency

3. Error Tolerance

4. Engagement

5. Ease of Learning and Navigation

Answer:

101001

1000011

1010110

1100100

1101111

1111111

10010000

10111101

11001000

11111111

Question Completion with Options:

A. device flow correlation

B. simple detections

C. application blocking list

D. advanced custom detections

Answer:

The outbreak control method that is used to accomplish the task of configuring AMP for endpoints and to block certain files from executing is:

C. application blocking list

Explanation:

The application blocking list creates a list of application files, which the AMP continuously tracks and analyzes to compare the file activities with previous cyber attacks.  Specifically, the AMP for Endpoints is a cloud-managed endpoint security solution, which provides a retrospective alert to prevent cyber-security threats, and rapidly detects, contains, and remediates malicious files on the endpoints.

continuously tracks and analyzes files and file activities across your systems, and compares these events to what preceded or happened in past attacks. If a file exhibits malicious behavior, the AMP provides you with a retrospective alert which enables you to stop a potential threat from succeeding.

Answer:

E. All of the listed ​

Explanation:

For compute-optimized cloud offerings like AWS, suitable use cases are - gaming, distributed analytics, and scientific modeling. Since all these are suitable, the correct answer is E.

Answer:

Explanation:

The following code is written in Java. It randomly generates 10 integers and adds them to an integer array called myArr. Then it loops through the array calculating if each number is even or odd. If it is even it adds 1 to the evenCount variable and prints out the number saying that it is even. Otherwise it adds 1 to the oddCount variable and prints the number saying that it is odd. The program was tested and the output can be seen in the attached image below.

import java.util.*;

class Brainly {

   // Main Method

   public static void main(String[] args) {

       Random rand = new Random();

       int[] myArr = new int[10];

       for (int i = 0; i<10; i++) {

           int n = rand.nextInt(101);

           myArr[i] = n;

       }

       int evenCount = 0;

       int oddCount = 0;

       for (int x : myArr) {

           if ((x % 2) == 0) {

               evenCount += 1;

               System.out.println(x + " is Even");

           } else {

               oddCount +=1;

               System.out.println(x + " is Odd");

           }

       }

       System.out.println("The Array has a total: ");

       System.out.println(evenCount + " Even Numbers");

       System.out.println(oddCount + " Odd Numbers");

   }

}

Answer:

Error reports

Explanation:

Answer:

The answer is "True".

Explanation:

Following are the responses to this question:

Creating users:

We will use the useradd command to achieve this. Using that same command, you can create users who would log in or customers who would log in (in the case of creating a user for a software installation).

In its basic form, the command is as follows:

Take this user olivia, for instance. Assuming that you had been to issue the command prompt:

Users are added to the system without the need for a home directory and are unable to log on. It if we were using this rather than running the command without arguments?

Using the command above, a new user would be created, including a home directory that corresponded to the username. That means that you might now see the name "olivia" in the directory "/home".

But what about the lockout concern that was raised earlier? Both these methods are possible. After creating the user, you can enter the following command:

You'll be requested to enter & verify your new password once you've completed the process. This unlocks the user profile, allowing them to log in.

This command might look like if you wanted to accomplish it in one go:

You should be using Passcodes as the login for the user olivia.

As soon as the user logs in, he or she can update their account password by using the password command to input their current password, and afterward entering/verifying their new one.

To create a user that has no personal account and cannot log in, execute the following instructions:

The user to be added is identified by USERNAME.

It establishes a user with really no root folder and prevents them from signing in with a second operation.

To add an existing user to a group on Linux, follow the instructions:

Another way to add a user to a group under Linux would be to use the following syntax:

The following operations are performed when a new login is added to the system.

.bash_logout

.bash_profile

.bashrc

Learn more:

Linux system: brainly.com/question/13843535

Im gonna use python3 for this example

def encode(string):

if not string:

return string

new_string = []

last_char = ""

count = 1

for char in string:

if char == last_char:

new_string.pop(len(new_string)-1)

count += 1

elif char != last_char and count > 1:

new_string.append(str(count)+last_char)

count = 1

new_string.append(char)

last_char = char

else:

last_char = char

new_string.append(char)

return "".join(new_string)

print(encode("Hello There"))

Answer:

Managed devices

Explanation:

hope it helps u

Answer:

1.similarity:

3.ergonomics are designed keying devices that alleviates wrist strain experienced when using ordinary keyboard for long hours

4.

Answer:

Explanation:

Absconding

Answer:

Explanation:

The following program was written in Java. It asks the user to first enter the target sum. Then it creates a while loop that continues asking the user to either roll dice or quit. If they decide to roll, it rolls the dice and prints out both values. If the target sum was hit, it prints that out and exits the program otherwise it loops again. The code has been tested and can be seen in the attached image below.

import java.util.Random;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Random rand = new Random();

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Target Sum: ");

       int targetSum = in.nextInt();

       while (true) {

           System.out.println("r: Roll Again");

           System.out.println("q: Quit");

           String choice = in.next();

           char choiceModified = choice.toLowerCase().charAt(0);

           if (choiceModified == 'r') {

               int roll1 = rand.nextInt(6) + 1;

               int roll2 = rand.nextInt(6) + 1;

               int total = roll1 + roll2;

               System.out.println("Dice 1: " + roll1);

               System.out.println("Dice 2: " + roll2);

               if (total == targetSum) {

                   System.out.println("Target Sum of " + targetSum + " hit.");

                   break;

               }

           } else if (choiceModified =='q') {

               break;

           } else {

               System.out.println("Wrong choice");

           }

       }

   }

}

Answer:

Reset

Explanation:

Answer:

The red Mustang should be given the right-of-way at this intersection because:

The red Mustang arrived first before the blue Prius and is closer to the stop sign before the arrival of the blue Prius.  This implies that the red Mustang must have waited for its turn, unlike the blue Prius that just arrived at the intersection.

Explanation:

Traffic laws, regulations, and IPDE defensive driving strategy require that drivers always give way to the vehicle that arrived before them at an intersection.   Assuming that multiple vehicles reach the intersection simultaneously, then the vehicle must be given the right-of-way.  Alternatively, the traffic lights at the intersection should be obeyed and be allowed to regulate the movement of vehicles.  IPDE defensive driving strategy requires drivers to be watchful of their driving spaces to determine the appropriate time to move.