A car and a truck collide in an intersection and the merged wreck continues along. During the collision. both kinetic energy and momentum are conserved.B. neither kinetic energy not momentum is conserved.C. momentum is conserved but not kinetic energy.D. kinetic energy is conserved but not momentum.E. conservation depends upon the details of the collision.
Answer:
C. Momentum is conserved but not kinetic energy.
Explanation:
This case represents an entirely inelastic collision, that is, a collision between the car and the truck that reduces total kinetic energy of the entire system, whereas linear momentum is conserved. Hence, correct answer is C.
Which of the following statements are true when it comes to impairment?
Answer:
Reduction in recoverable amount
Explanation:
Impairment of an asset happens when there is drastic reduction in recoverable amount of the asset. Long term assets are at risk of impairment because their carrying values may exceed the fair value. The business record it as a loss in assets value.
PLS PLS PLS HELP ME! IT IS DUE IN TEN MINUTES
For his next stunt, Super Dave (80 kg) starts running at 2.00 m/s, then slides down a frictionless slide which is elevated 12.0 m above the ground, then slides across the rough asphalt ground to slow him to a stop (ouch!) He slides across the asphalt for 8.00 m before coming to a stop. What is the coefficient of friction between Super Dave and the ground?
Answer:
Preface to Students: Welcome to Physics! iv. 1 Motion. 1. 1-1 Speed, Velocity, and. Acceleration. 1. 1-2 Free Fall. 8. 2 Vectors and Projectiles.
257 pages·3 MB
Explanation: I hope this helpssss!!!
state physical quantity represented by the gradient of a displacement - time graph
Answer:
velocity
Explanation:
this is because velocity has both magnitude and direction
Will mark brainlest helpp!!!!!!
Answer:
I don't know if it is correct or not.
Convert to m/s
[tex]\\ \Large\sf\longmapsto v=60\times \dfrac{5}{18}=16.6m/s[/tex]
Time=t=5min=5×60=300sWe know
[tex]\boxed{\Large{\sf Acceleration=\dfrac{v-u}{t}}}[/tex]
[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6-0}{300}[/tex]
[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6}{300}[/tex]
[tex]\\ \Large\sf\longmapsto Acceleration=0.05m/s^2[/tex]
Distance=sUsing second equation of kinematics
[tex]\boxed{\Large{\sf s=ut+\dfrac{1}{2}at^2}}[/tex]
[tex]\\ \Large\sf\longmapsto s=0(300)+\dfrac{1}{2}(0.05)(300)^2[/tex]
[tex]\\ \Large\sf\longmapsto s=0.05\times 150^2[/tex]
[tex]\\ \Large\sf\longmapsto s=0.05\times 22500[/tex]
[tex]\\ \Large\sf\longmapsto s=1125m[/tex]
Think of a body which is at rest but not in equilibrium
Answer:
I think the sun is the right answer
A particle makes 800 revolution in 4 minutes of a circle of 5cm. Find
i. it's period
ii. Angular Velocity
iii. Linear Velocity
iv. It's acceleration
PLEASE FORMULAE SHOULD BE WRITTEN CLEARLY.
YOU CAN SNAP AND SEND
Answer:
i) The period of the particle is 0.3 seconds
ii) The angular velocity is approximately 20.94 rad/s
iii) The linear velocity is approximately 1.047 m/s
iv) The centripetal acceleration is approximately 6.98 m/s²
Explanation:
The given parameters are;
The number of revolution of the particle, n = 800 revolution
The time it takes the particle to make 800 revolutions = 4 minutes
The dimension of the circle = 5 cm = 0.05 m
Given that the dimension of the circle is the radius of the circle, we have;
i) The period of the particle, T = The time to complete one revolution
T = 1/(The number of revolutions per second)
∴ T = 1/(800 rev/(4 min × 60 s/min)) = 3/10 s
The period, T = 3/10 seconds = 0.3 seconds
ii) The angular velocity, ω = Angle covered/(Time)
800 revolutions in 4 minutes = Angle of (800 × 2·π) in 4 minutes
∴ ω = (800 × 2·π)/(4 × 60) = 20·π/3
The angular velocity, ω = 20·π/3 rad/s ≈ 20.94 rad/s
iii) The linear velocity, v = r × ω
∴ The linear velocity, v = 0.05 m × 20·π/3 rad/s = π/3 m/s ≈ 1.047 m/s
iv) The centripetal acceleration, [tex]a_c[/tex] = v²/r
∴ The centripetal acceleration, [tex]a_c[/tex] = (π/3)²/(0.05) = 20·π/9
The centripetal acceleration, [tex]a_c[/tex] = 20·π/9 m/s² ≈ 6.98 m/s²
What is the right hand rule for magnetic Force?
Answer:
The right hand rule states that, to find the direction of the magnetic force on a positive moving charge, the thumb of the right hand point in the direction of v, the fingers in the direction of B, and the force (F) is directed perpendicular to the right hand palm.
Explanation:
pls mark brainliest
Hope this helps u
Muốn đun sôi 200g nước từ 30 độ cần cung cấp nhiệt lượng bao nhiêu :
Answer:
cần cung cấp 70 độ vì nước sôi ở 100°C
Explanation:
Ра:
5. Mass of the earth is 6x10-kg and its radius is 6400km. What is the
mass of a man weighting 977N?
(99.99kg)
ma
Orth
be
Answer:
what do u need help with
Explanation:
Pа: 5. Mass of the earth is 6x10-kg and its radius is 6400km. What is the mass of a man weighting 977N? (99.99kg) ma. Orth be.
Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family
Answer:
Momentum of system = 37.2 Kgm/s.
Explanation:
Given the following data;
Mass A = 5 kgVelocity A = 6 m/sMass B = 12 kgVelocity B = 0.6 m/sTo find the momentum of the system;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Momentum = mass * velocity
For object A;
Momentum A = 5 * 6
Momentum A = 30 Kgm/s
For object B;
Momentum B = 12 * 0.6
Momentum B = 7.2 Kgm/s
Next, we would determine the momentum of this system using the formula;
Momentum of system = Momentum A + Momentum B
Substituting the values into the formula, we have;
Momentum of system = 30 + 7.2
Momentum of system = 37.2 Kgm/s.
5. Tại sao khi lặn ta luôn cảm thấy tức ngực và càng lặn sâu thì cảm giác tức ngực càng tăng? A. Ap suất của nước giảm B. Ap suất không khí tăng C. Ap suất không khí giảm D. Ap suất của nước tăng
Answer:
c and d
Explanation:
obviously kksxsxksxkskxkskxksxksxsxsxsxsxsxsxs
4. diference between VR and efficiency
Answer:
Velocity ratio of simple machine is the ratio of distance travelled by effort to the distance travelled by load in the machine. The efficiency of a simple machine is defined as the ratio of useful work done by machine (output work) to the total work put into the machine (input work).
joule is a unit of_____and_____
Answer:
Energy and work
.........
Answer:
Work EnergyExplanation:
Joule is a unit of Work and energy .Hope my answer is helpful to you ✌️❣️☪️❇️☪️❣️✌️
3.7 kg of a saturated water vapor at 0.4 MPa is isothermally cooled until it is a saturated liquid. Calculate the amount of heat rejected during this process in MJ. (Report your answer in 3 decimal places.)
Answer:
7.894 MJ
Explanation:
Given that:
The mass of the saturated water vapor = 3.7 kg
The pressure of the saturated water vapor = 0.4 MPa
From saturated properties of steam tables when the pressure is at 0.4 Mpa
The enthalpy in (kJ/kg);
hf = 604.7 kJ/kg
hg = 2738.1 kJ/kg
The rejected heat during this process is:
Q = m(hg - hf)
Q = 3.7(2738.1 - 604.7) kJ/kg
Q = 3.7(2133.4) kJ/kg
Q = 7893.58 kJ/kg
Q = 7.894 MJ
why do flames go upwards
Answer:
Easy search it on g o o g l e
A 750 kg National Geographic Drone is rising vertically up into the atmosphere at constant speed. The lift force pushing it upward is 125% of its weight. The drone reaches the cruising speed almost immediately. It takes 25 seconds for the drone to reach a height of 250m starting from the surface.
a. What is the mechanical energy of the drone at the surface?
b. What is the mechanical energy of the drone at the 150 m height?
c. Is the mechanical energy of the drone conserved, increased, or decreased. Explain your choice.
d. What is the work done by each force acting on the drone?
Answer:
a. 0
b. 1.103625 MJ
c. Conserved
d. 1.103625/n MJ where n = The number of forces
Explanation:
The mass of the drone, m = 750 kg
The upward lift force = 125% of the weight of the drone
The time it takes the drone to reach a height of 250 m = 25 seconds
a. The mechanical energy = The kinetic energy + Potential energy
Therefore, given that the drone stars motion from the surface and was initially at rest, the mechanical energy at the surface = 0
b. The mechanical energy at height, h = 150 m, ME₁₅₀ = The potential energy gained = m·g·h
Where;
g = The acceleration due to gravity = 9.81 m/s²
∴ ME₁₅₀ = 750 kg × 9.81 m/s² × 150 m = 1103625 J = 1.103625 MJ
c. The mechanical energy is equivalent to the potential energy of the drone at the 150 m height, therefore, it is conserved
d. The work done by the force = The energy gained
Therefore, where there are n number of forces, the work done by each force = 1.103625/n MJ
A golf club hits a 0.04551 kg golf ball off a golf tee. The club is in contact with the ball for 0.020 s, and the force applied by the club is 115 N. What is the speed of the ball as it leaves the tee
Answer:
v = 50.5 m/s
Explanation:
F = (m)(^v/^t)
115N = (0.04551kg)(v/(0.020s))
2,526.917161 m/s² = v/(0.020s)
v = 50.53834322 m/s
v = 50.5 m/s
A tennis player hits a ball hard and 0.80 seconds later hears the echo from a wall. The speed of sound in air is 340m/s how far away is the player from the wall
Answer:
136 m.
Explanation:
From the question given above, the following data were obtained:
Time (t) = 0.80 s
Speed of sound (v) = 340 m/s
Distance (x) =?
The distance of the player from the wall can be obtained as follow:
v = 2x / t
340 = 2x / 0.80
Cross multiply
2x = 340 × 0.80
2x = 272
Divide both side by 2
x = 272 / 2
x = 136 m
Thus, the distance of the player from the wall is 136 m
Name the type of motion executed by the motion of the moon around the earth.
Answer:
The motion of the moon around the earth is circular motion
Explanation:
Plutonium-32 has a half-life of 14.2 days. After 99.4 days, how much of what was originally a 499.2 gram sample remains?
14 grams
3.9 grams
35.7 grams
0.71 grams
Answer:
3.9 gm remains
Explanation:
499.2 ( 1/2)^(99.4/14.2) = 3.9 gm
An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complete swings in a time of 257 seconds. From this measurement she calculates the acceleration due to gravity on Pluto. What is her result
Answer:
The acceleration due to gravity at Pluto is 0.0597 m/s^2.
Explanation:
Length, L = 1 m
10 oscillations in 257 seconds
Time period, T = 257/10 = 25.7 s
Let the acceleration due to gravity is g.
Use the formula of time period of simple pendulum
[tex]T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2[/tex]
A bullet of mass of 50g is moving with the velocity of 200km/h .calculate the kinetic energy of the bullet .
Answer:
is 10³
Explanation:
cuz the formula of KE is 1/2mv²
covert 50g to kg first then plug in the formula
1/2 × 0.05 × 200 = 10³ J
A train travels 600 kilometers in 1 hour. What is the train's velocity in meters/second?
here's the answer to your question
A 250–g piece of gold is at 19 °C. 5.192 kJ of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature.
We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat. Calculate
the specific heat of the metal.
Answer:
A. DT is given by Q= MCs DT
m = mass of the substances
Cs= is it's specific heat capacity
Ck= Q
Mk ×DTk
=250 × 9 × 5
129
=Dt = 180.1085271
answer is 180degree C.
Explanation:
B. = 25×10 ×100
1.082
=2500
1.082
= 23105.360 g/kj.
The final temperature is 180 degree. and the specific heat of the metal is 23105.360 g/kj.
How to calculate the specific heat?Q = m . C . ΔT
Q = heat; m = mass; C is the specific heat and
ΔT = Final T° - Initial T°
Q = C lat . m
Q = Heat
m = mass
C lar = Latent heat of fusion
A) DT is given by Q= M Cs DT
where, m = mass of the substances
Cs= is it's specific heat capacity
Ck= Q
Mk × DTk
=250 × 9 × 5
129 =Dt = 180.1085271
Thus, the final temperature is 180 degree.
B) We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat = 25×10 ×100
=2500
1.082
Q = 23105.360 g/kj
Hence, the specific heat of the metal is 23105.360 g/kj.
Learn more about heat here;
https://brainly.com/question/12909121
#SPJ2
What comes before Action-reaction?
These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.
what is the economic application of changes in states of matter
Answer:
Changes of state are physical changes in matter. They are reversible changes that do not change matter's chemical makeup or chemical properties. For example, when fog changes to water vapor, it is still water and can change back to liquid water again.
Turbine blades are rotated by the steam in the steam turbine.The water at the high temperature get converted into the steam used to rotate the turbine blades.
What is state?The property of any system on a specified point is known as the state of the system.Pressure,temperature are the properties of the system.
They are reversible modifications that do not alter the chemical composition or characteristics of matter.
The steam turbine blades are turned by the steam. The high-temperature water is turned to steam, which is utilized to rotate the turbine blades.
When fog transforms into water vapor, for example, it is still water and may transform back into liquid water.
Hence the steam turbine is the economic application of changes in states of matter.
To learn more about the state refer to the link;
https://brainly.com/question/15858706
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A decorative plastic film on a copper sphere of 10 mm diameter in an oven at 750C. Upon removal from the oven, the sphere is subjected to an air stream at 1 atm. , and 230C having a velocity of 10 meter/sec. Estimate how long it will take to coal the sphere to 350C? Density of copper is 8933 kg/m3 , thermal conductivity k = 399 W/m.K and specific heat Cp = 387 J/kg.K. for Air at an average temperature of T[infinity] = 296 K has viscosity µ= 181x10-7 N.s/m2 , kinematic viscosity ν = 15.36x10-6 m2/s and thermal conductivity k = 0.0258 W/m.K and Prandtl No. Pr = 0.709 and air at surface temperature Ts = 328 K will have viscosity µs = 197x10-7 N.s/m2
Answer:
3.26 secs
Explanation:
Diameter of sphere ( D )= 10 mm
T1 = 75°C
P = 1 atm
T∞ = 23°C
T2 = 35°c
Velocity = 10 m/s
Determine how long it will take to cool the sphere to 35°C
Using the properties of copper and air given in the question
Nu = 2 + (Re)^0.8 (Pr)^0.33
hd / k = 2 + ( vd/v )^0.8 (Pr)^0.33
∴ h ≈ 2594.7 W/m^2k
Given that :
(T2 - T∞) / ( T1 - T∞ ) = exp [ ( -hA / pv CP ) t ]
( 35 - 23 ) / ( 75 - 23 ) = exp [ - 2594.7 * 6 * t / 8933 * 387 * 10 * 10^-3 ]
= ln ( 12/52 ) = -1.466337069 = - 0.45032919 * t
∴ t ≈ 3.26 secs ( -1.466337069 / -0.45032919 )
Question 7 of 25
Which two chemical equations are balanced?
O A. 2PBrg + 3Cl2 - 2PC13 + 3Br2
O B. 2Na+ MgCl2
2NaCl + Mg
-
C. 2LIOH + 2H2S - Li2S + 2H20
D. 2AgNO3 + NaCl - NaNO3 + 2AGCI
Answer:
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
2Na + MgCl₂ → 2NaCl + Mg
Explanation:
A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation
Among the given chemical reactions, we have;
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
In the above reaction;
The number of phosphorus, P, on either side of the equation = 2
The number of bromine atoms, Br, on either side of the equation = 6
The number of chlorine atoms, Cl, on either side of the equation = 6
Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced
The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg
In the above reaction, there are two sodium atoms, Na, one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced
how can we maintain peace in the nature and surrounding
Answer:
6 Ways To Promote Peace
Treat all people with kindness, regardless of race, gender orientation, sexual orientation, religion, etc.
Attend a peace rally.
Write to your government (local and federal)
Create a peaceful affirmation/mantra.
Don't engage in violence of any kind.
Don't purchase weapons.
