Answer:
42
Step-by-step explanation:
We know that the mean of 6 numbers is 24. This means that
[tex] \frac{x}{6} = 24[/tex]
Solve for x.
[tex]x = 144[/tex]
If we add, x, (x+2), and (x-2). We will have 9 terms. The value of mean will change to 30. This also means that
[tex] \frac{270}{9} = 30[/tex]
[tex]144 + x + (x + 2) + (x - 2) = 270[/tex]
[tex]3x + 144 = 270[/tex]
[tex]3x = 126[/tex]
[tex]x = 42[/tex]
Four students drive to school in the same car. The students claim they were late to school and missed a test because of a flat tire. On the makeup test, the instructor asks the students to identify the tire that went flat; front driver's side, front passenger's side, rear driver's side, or rear passenger's side. If the students didn't really have a flat tire and each randomly selects a tire, what is the probability that all four students select the same tire
Hence, the probability that all four students select the same tire is [tex]\frac{1}{16}[/tex].
What is the probability?
Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
Probability has been introduced in Maths to predict how likely events are to happen. The meaning of probability is basically the extent to which something is likely to happen.
Here given that,
Four students drive to school in the same car. The students claim they were late to school and missed a test because of a flat tire.
On the makeup test, the instructor asks the students to identify the tire that went flat; front driver's side, front passenger's side, rear driver's side, or rear passenger's side.
So, the probability of one person picking the tire is [tex]\frac{1}{4}[/tex].
Here four students so their probability is
[tex]\frac{1}{4(4)}=\frac{1}{16}[/tex]
Hence, the probability that all four students select the same tire is [tex]\frac{1}{16}[/tex].
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90units needed 8 units per case what's the #of cases & # of additional units
Answer:
# of cases: 11
Additional units: 2
Step-by-step explanation:
If each case can hold 8 units, and we want to find the total # number of cases, we have to divide the # of units (8) for one case by the total # units (90).
As you can see, after dividing by 8, we have a total of 11 cases and a remainder of 2 units. The remainder will be the # of additional units because we cannot have another case filled with 8 units.
Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. A paper gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the postweaning period (P).
Subject
1 2 3 4 5 6 7 8 9 10
L 1928 2549 2825 1924 1628 2175 2114 2621 1843 2541
P 2126 2885 2895 1942 1750 2184 2164 2626 2006 2627
Required:
a. Does data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. [Note: The appropriate normal probability plot shows some curvature but not enough to cast substantial doubt on a normality assumption.]
b. Calculate a lower confidence bound using a 95% confidence level for the true average difference between TBBMC during postweaning and lactation.
Answer:
- 179.981
Step-by-step explanation:
The hypothesis :
H0 : μL - μP ≥ 25
H0 : μL - μP < 25
The sample mean difference ;Xd
d = L - P
Xd = Σd/n
d = -198,-336,-70,-18,-122,-9,-50,-5,-163,-86
Xd = - 1057 / 10
Xd = - 105.7
Using calculator ;
Standard deviation of difference, Sd = 103.845
The test statistic :
T = Xd ÷ (Sd/√n)
T = -105.7 ÷ (103.845/√10)
T = - 3.219
Decision region :
Reject H0 ; If Pvalue < α
The Pvalue : df = n - 1 ; 10 - 1 = 9
Pvalue(-3.219, 9) ; two-tailed = 0.00525
Hence, reject H0
B.) The confidence interval for difference in mean :
Xd ± Tcritical[Sd/√n]
Tcritical at 95%, df = 9
Tcritical = 2.262
C.I = -105.7 ± 2.262[103.845/√10]
C.I = -105.7 ± 74.281076
Lower boundary: - 105.7 - 74.281076 = - 179.9810
Find the function G defined by G(x) =5x+3 find G(-1)
Answer:
G(-1) = -2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Functions
Function NotationStep-by-step explanation:
Step 1: Define
Identify
G(x) = 5x + 3
Step 2: Evaluate
Substitute in x [Function G(x)]: G(-1) = 5(-1) + 3Multiply: G(-1) = -5 + 3Add: G(-1) = -2Answer:
G = -2
Step-by-step explanation:
Plug in -1 for x.
5(-1) + 3
-5 + 3
-2
G = -2
I need help please IVE BEEN AT THIS FOREVER
Answer:
.3
Step-by-step explanation:
Take path A = .5
Then Path D = .6
P(a and D) = .5 *.6 = .3
Can someone please do #3?❤️
Answer:
B, because it goes up by 8 until the last of because the jump from 24 to 30 is 6
Solve for x.
A. 1
B. 5
C. 3
D. 12
9514 1404 393
Answer:
A. 1
Step-by-step explanation:
Arc AB is twice the measure of the angle ABC. The sum of the arc measures around the circle is 360°.
2(43x)° +(272x +2)° = 360°
358x +2 = 360 . . . . . . . . . . . . divide by °, collect terms
358x = 358 . . . . . . . . subtract 2
x = 1 . . . . . . . . . . divide by 358
For each graph below, state whether it represents a function.
Answer:
graphs 1, 2, 3, and 4, can represent a function
graphs 5 and 6 can not represent a function.
Step-by-step explanation:
If for a given graph of a relationship you can draw a vertical line that intersects the graph in more than one point, then we can conclude that the graph does not represent a function.
Now, if we look at the first four graphs, we can see that no vertical line intersects more than one point, so the first four can represent functions.
The special case here is graph number 2, where we can see a white dot right below a colored dot, and if we draw a vertical line there, the line will touch both points. But, a white dot means that the exact point does not belong to the graph, so if the line passes through there, it will not intersect the graph.
For the last two, this is not the case, in graph 5 and graph 6 we could draw vertical lines that intersect the graphs twice
(any line like x = n, with n < 0, intersects two points in graph 5, while the line x = 0 intersects twice the graph number 6)
So graph 5 and graph 6 can't represent functions.
One number is 6 less than a second number.
Twice the second number is 9 less than 5 times
the first. Find the two numbers.
Answer:
-7
Step-by-step explanation:
x = y - 6
2x = 5y - 9
Use the internet for full steps
x = -7
y = -1
The train station clock runs too fast and gains 5 minutes every 10 days. How many minutes and seconds will it gain in 7 days
Answer: 210 secs (3 mins, 30 secs)
Step-by-step explanation:
No of minutes gained every 10 days = 5 mins
No of minutes gained every day = 5 ÷ 10
= 0.5 min (30 secs)
Amount of time gained in 7 days = 30 secs × 7
= 210 secs (3 mins, 30 secs)
If a normally distributed population has a mean (mu) that equals 100 with a standard deviation (sigma) of 18, what will be the computed z-score with a sample mean (x-bar) of 106 from a sample size of 9?
Answer:
Z = 1
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean (mu) that equals 100 with a standard deviation (sigma) of 18
[tex]\mu = 100, \sigma = 18[/tex]
Sample of 9:
This means that [tex]n = 9, s = \frac{18}{\sqrt{9}} = 6[/tex]
What will be the computed z-score with a sample mean (x-bar) of 106?
This is Z when X = 106. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{106 - 100}{6}[/tex]
[tex]Z = 1[/tex]
So Z = 1 is the answer.
A bag contains 8 red balls and 3 white balls. Two balls are drawn without replacement. (Enter your probabilities as fractions.) (a) What is the probability that the second ball is white, given that the first ball is red
Answer:
12/55
Step-by-step explanation:
Probability is the ratio of the number of possible outcomes to the number of total outcomes.
Given that the bag contains 8 red balls and 3 white balls, the probability of picking a red ball
p(r) = 8/(8+3) = 8/11
Probability of picking a white ball
= 3/11
when a red ball is picked first, the total number of balls reduces to 10 hence the probability that the second ball is white, given that the first ball is red
=8/11 * 3/10
= 24/110
= 12/55
Which values of x are solutions to this equation? -1/2x^2 + 5x = 8
A) -2
B) 2
C) -8
D) -1.5
E) 11.5
F) 8
Answer:
2, 8
Step-by-step explanation:
-1/2x^2 + 5x = 8
-x^2 + 10x = 16 (Multiplying both sides of the equation by 2)
-x^2 + 10x - 16 = 0
x^2 - 10x + 16 = 0 (changing the signs)
x^2 -2x -8x +16 = 0
x (x-2) -8 (x-2) = 0
(x-2) (x-8)
x-2 = 0
x = 2
or
x -8 = 0
x = 8
Answer from Gauthmath
The values of x are solutions to this equation that is 2, 8
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
We are given that the equation as;
-1/2x² + 5x = 8
-x² + 10x = 16
Now Multiplying both sides of the equation by 2;
-x² + 10x - 16 = 0
Or
x² - 10x + 16 = 0
x² -2x -8x +16 = 0
x (x-2) -8 (x-2) = 0
(x-2) (x-8)
The solution are;
x-2 = 0
x = 2
or
x -8 = 0
x = 8
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A nurse works for a temporary nursing agency. The starting hourly wages for the six different work locations are $12.50, $11.75, $9.84, $17.67, $13.88, and $12.98. As the payroll clerk for the temporary nursing agency, find the median starting hourly wage.
Shahril bought a CD, 2 T-shirts and a pair of jeans for $133. Each
T-shirt cost $13 more than the CD. The pair of jeans cost $30 more
than each T-shirt. Find the cost of the CD.
Step-by-step explanation:
Let the price of CD, tshirt and jeans be x,y and z respectively.
given:
x+2y+2z=133......(i)
y=x+13.......(ii)
2z=y+30....(iii)
in eqn (iii) ,
2z=y+30
or, 2z=x+13+30
or, z=(x+43)/2....(iv)
now in eqn (i),
x+2y+2z=133
or, x+2(x+13)+2((x+43)/2) =133
or, x+2x+26+x+43=133
or, 4x=133-69
or, x= 64/4
•°• x=$16
Find the missing side. Round your answer to the nearest tenth please help me
9514 1404 393
Answer:
16.9
Step-by-step explanation:
The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...
Sin = Opposite/Hypotenuse
Multiplying by the hypotenuse gives an equation for the opposite side.
x = 22·sin(50°)
x ≈ 16.9
I need help ASAP please
Answer:
5:10
6 (-2,0)
7 (-5,6)
8 (5,3)
9 No, ab=8 CD=6
Step-by-step explanation:
Which set of angles are complementary
Answer:
A. <ECF and <BCF
Step-by-step explanation:
Complementary angles are angles that add up to give 90°
m<BCE = m<BCA = 90° (right angles)
m<ECF + m<BCF = m<BCA
m<ECF + m<BCF = 90° (Substitution)
Therefore, <ECF and <BCF are complementary angles.
by solving a pair of linear equation X + Y is equal to 20 and x-y=10 the value of 'x' and 'y' are
Answer:
x=15, y=5
Step-by-step explanation:
x+y=20
x-y=10
Adding both equations;
(x+x) + (y-y) = 20+10
2x = 30
x = 30/2 = 15
Substitute x=15 into x+y=20
y= 20-x = 20-15= 5
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math problems. Chapter 12 part 2 PLEASE SHOW WORK!!!
4a. a_n = 2(1/3 + a_n-1), a_1 = 4
4b. a_n= n/(a_n-1), a_1 = 6
4c. 1/6, 2/3, 8/3, . . .
Problem 4a
The instructions are incomplete. You set up the recursive formula, but didn't ask any question about said formula.
I'll assume that your teacher wants you to list out a few terms. I'll list out the first five terms.
The notation a_1 = 4 is the same as writing [tex]a_1 = 4[/tex] where the '1' is a subscript. It tells us that the first term is 4.
The nth term a_n or [tex]a_n[/tex] is defined as such
[tex]a_n = 2*(1/3 + a_{n-1})\\\\[/tex]
Notice how if we replaced n with 2, then we get
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_2 = 2*(1/3 + a_{2-1})\\\\a_2 = 2*(1/3 + a_1)\\\\[/tex]
So the second term is directly tied to the first term, or it is dependent on it.
We'll replace a_1 with 4 to get the following
[tex]a_2 = 2*(1/3 + a_1)\\\\a_2 = 2*(1/3 + 4)\\\\a_2 = 2*(1/3 + 12/3)\\\\a_2 = 2*(13/3)\\\\a_2 = 26/3\\\\[/tex]
So the second term is 26/3.
As you can guess, the third term is going to be found in a similar fashion
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_3 = 2*(1/3 + a_{3-1})\\\\a_3 = 2*(1/3 + a_2)\\\\a_3 = 2*(1/3 + 26/3)\\\\a_3 = 2*(27/3)\\\\a_3 = 2*(9)\\\\a_3 = 18\\\\[/tex]
So 18 is the third term.
We'll repeat for n = 4 to get the fourth term.
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_4 = 2*(1/3 + a_{4-1})\\\\a_4 = 2*(1/3 + a_3)\\\\a_4 = 2*(1/3 + 18)\\\\a_4 = 2*(1/3 + 54/3)\\\\a_4 = 2*(55/3)\\\\a_4 = 110/3\\\\[/tex]
The fourth term is 110/3.
Lastly, we'll plug in n = 5
[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_5 = 2*(1/3 + a_{5-1})\\\\a_5 = 2*(1/3 + a_4)\\\\a_5 = 2*(1/3 + 110/3)\\\\a_5 = 2*(111/3)\\\\a_5 = 2*(37)\\\\a_5 = 74\\\\[/tex]
The fifth term is 74.
Answer: The first five terms are 4, 26/3, 18, 110/3, 74==============================================================
Problem 4b
Again, the instructions are missing. I'll assume the same thing as problem 4a.
[tex]a_1 = 6[/tex] is the first term
Plug n = 2 into the first equation to get
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_2 = \frac{2}{a_{2-1}}\\\\a_2 = \frac{2}{a_{1}}\\\\a_2 = \frac{2}{6}\\\\a_2 = \frac{1}{3}\\\\[/tex]
The second term is 1/3.
Repeat for n = 3
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_3 = \frac{3}{a_{3-1}}\\\\a_3 = \frac{3}{a_{2}}\\\\a_3 = \frac{3}{1/3}\\\\a_3 = 3\div\frac{1}{3}\\\\a_3 = 3\times\frac{3}{1}\\\\a_3 = 9\\\\[/tex]
The third term is 9
Repeat for n = 4.
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_4 = \frac{4}{a_{4-1}}\\\\a_4 = \frac{4}{a_{3}}\\\\a_4 = \frac{4}{9}\\\\[/tex]
The fourth term is 4/9
Repeat for n = 5
[tex]a_n = \frac{n}{a_{n-1}}\\\\a_5 = \frac{5}{a_{5-1}}\\\\a_5 = \frac{5}{a_{4}}\\\\a_5 = 5 \div a_{4}\\\\a_5 = 5 \div \frac{4}{9}\\\\a_5 = 5 \times \frac{9}{4}\\\\a_5 = \frac{5}{1} \times \frac{9}{4}\\\\a_5 = \frac{5*9}{1*4}\\\\a_5 = \frac{45}{4}\\\\[/tex]
Answer: The first five terms are 6, 1/3, 9, 4/9, 45/4==============================================================
Problem 4c
I'm not much help here for this problem. Not only are the instructions missing, but it's not clear how this sequence is set up. If I had to guess, it's somehow recursively defined. How exactly, I'm not sure. I would ask your teacher for any clarification.
Wires manufactured for use in a computer system are specified to have resistances between 0.14 and 0.16 ohms. The actual measured resistances of the wires produced by company A have a normal probability distribution with mean 0.15 ohm and standard deviation 0.005 ohm. (Round your answers to four decimal places.) (a) What is the probability that a randomly selected wire from company A's production will meet the specifications
Answer:
Hence the probability that a randomly selected wire from company A's production will meet the specifications is 0.95455.
Step-by-step explanation:
a)[tex]P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005) < (x - \mu) /\sigma < (0.16 - 0.15) / 0.005) ][/tex]
[tex]=P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005)< ((x - 0.15) /0.005) < (0.16 - 0.15) / 0.005) ][/tex]
[tex]=P(z<\frac{0.01}{0.005} )- P(z<-\frac{0.01}{0.005})[/tex]
Using z table,
= 0.9773 - 0.02275
= 0.95455.
3. An elevator is moving upward with a speed of 14.3 m/s . Two seconds later, the elevator is still moving upward, but its speed bas been reduced to 3.7 m/s . What is the average acceleration of the clevator during the 2.0 interval?
By definition of average acceleration,
a (average) = (3.7 m/s - 14.3 m/s) / (2.0 s) = -5.3 m/s²
I need to know the answer ASAP please
By observing the points you can learn a lot about a function. Concretely [tex]f(x)[/tex] passes through [tex](1,1)[/tex] but [tex]g(x)[/tex] passes through [tex](1,-\frac{1}{2})[/tex] that should give you a hint that [tex]g(x)=-\frac{1}{2}x^2[/tex].
Hope this helps :)
Each machine at a certain factory can produce 90 units per hour. The setup cost is 20 dollars for each machine and the operating cost is 26 dollars per hour (total, not 26 dollars per machine per hour). You would like to know how many machines should be used to produce 40000 units, with the goal of minimizing production costs.
First, find a formula for the total cost in terms of the number of machines, n:_______
TC = ______
machines for a total cost of The minimum total cost is achieved when using dollars.
Answer:
a) [tex]Total Cost=20n+\frac{(\frac{40000}{90}*26)}{n}[/tex]
b) [tex]n=24[/tex]
Step-by-step explanation:
From the question we are told that:
Rate r=90 units per hour
Setup cost =20
Operating Cost =26
Units=40000
Generally the equation for Total cost is mathematically given by
[tex]Total Cost=20n+\frac{(\frac{40000}{90}*26)}{n}[/tex]
[tex]T_n=20n+\frac{11556}{n}\\\\T_n=\frac{20n^2+11556}{n}.....equ 1[/tex]
Differentiating
[tex]T_n'=\frac{n(40n)-(40n^2+11556)}{n_2}\\\\T_n'=\frac{20n^2-11556}{n^2}.....equ 2[/tex]
Equating equ 1 to zero
[tex]0=\frac{20n^2+11556}{n}[/tex]
[tex]n=24[/tex]
Therefore
Substituting n
For Equ 1
[tex]T_n=\frac{20(24)^2+11556}{24}[/tex]
F(n)>0
For Equ 2
[tex]T_n'=\frac{20(24)^2-11556}{24^2}[/tex]
F(n)'<0
As an estimation we are told £3 is €4. Convert €36 to pounds.
Answer:
€36 = 30.62 pounds sterling
I need help ASAP please and thank you
Answer:
"a" is the answer because 3x+2 can not be equal to zero
Step-by-step explanation:
Help me please
Hurry
For all questions, use the concept of angles at a point (360°).
I also suggest and recommend that you specify the questions you need help with. It is best if you don't ask your homework here, because homework should be done by you yourself.
5. a) Find the difference between the place values of two 5's in 95237508.
Answer:
4999500
Step-by-step explanation:
first 5 = 5000000
second 5 = 500
difference = 5000000-500
8
6
4
2
6
8
-8 -6 -4 -2 0-3
21
.
-6
-8
O A. y -[x]-2
OB. y -[x]+3
O C. y = (x) - 3
O D. y = [x]+2
The required equation of the line is y = [x]+2
From the graph shown, we can see that the line dotted points forms a straight line. We are to find the required equation of the line formed.
The formula for calculating the equation of a straight line is expressed as
y = mx+b where
m is the slope b is the y-intercept
Get the slope 'm'
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Using the coordinate points (2, 0) and (4, 2)
[tex]m=\frac{2-0}{4-2}\\m=\frac{2}{2}\\m=1[/tex]
Get the y-intercept 'b'
Substitute m = 1 and (2, 0) into y = mx+b as shown;
[tex]2=1(0)+b\\2=0+b\\b=2[/tex]
Get the required equation. Recall that y = mx+b, hence;
[tex]y = 1x + 2\\y=x+2[/tex]
Hence the required equation of the line is y = [x]+2
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Naomi invested $3,425 in an account that
pays 3% simple interest. what was the total
balance of the account after 15 years?
Answer:
$4,966.25
Step-by-step explanation:
3 x 15 = 45
After 15 years, Naomi would have earned a total of 45% interest rate.
3,425 x 1.45 = 4,966.25
Don't use .45 as the multiplier
3,425 x .45 = 1,541.25 <- incorrect