The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.
The period of pendulum can be calculated by
[tex]T = 2\pi \sqrt {\dfrac Lg}[/tex]
Where,
[tex]T[/tex] - period
[tex]L[/tex] - length = 12 inches
[tex]g[/tex]- gravitational acceleration = [tex]\bold {9.8\rm \ m/s^2}[/tex]
Put the values,
[tex]T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191[/tex]
Now, the angular displacement of the pendulum can be calculated by,
[tex]\theta = A\times\rm \ cos(\omega T)[/tex]
Where,
[tex]A[/tex]- amplitude
[tex]\theta[/tex] - angle = [tex]75^o[/tex]
[tex]\omega[/tex] - angular displacement = [tex]2\pi/T[/tex] = 2.866 m
Put the values and calculate for [tex]\omega[/tex],
[tex]75 = A\times{\rm \ cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches[/tex]
Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.
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the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?
Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.
The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
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A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of the stone if it hit the plane a distance L down the slope from the point of launch?
Answer:
S = V t where S is the horizontal distance traveled
1/2 g t^2 = H where H is the vertical distance traveled
t^2 = 2 H / g
V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations
tan theta = H / S
V^2 = S g / (2 tan theta)
Using S = L cos theta
V^2 = L g cos theta / (2 tan theta)
Giving V in terms of L and theta
If a category 6 hurricane would exist how fast do you think it would be?
After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).
There is no such thing as a Category 6 hurricane. When Hurricane Irma was headed toward the coast of southern Florida in August, it had maximum wind speeds of 185 mph, according to the New York Times. But the Saffir-Simpson scale only goes up to 5.Hope it helps(◠ᴥ◕ʋ)Why are movie scenes in outer space often unrealistic?
Answer:
see explanation
Explanation:
by my calculations, i believe it may be because they have to pretend to be in space.
one of them is Space & Interstellar Travel
Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s
Answer:
The car that is hald as massive
Explanation:
We can use the eqation for kinetic energy to solve this problem
KE = 1/2mv^2 (where m is mass and v is velocity/speed)
Lets give the original car a mass of 100kg and use the equation
KE = 1/2(100kg)(16m/s)^2 = 12800J
and now lets find kinetic energy of the half as massive car
KE2 = 1/2(50kg)(32m/s)^2 = 25600J
From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity
The magnitude of acceleration due to gravity is
Select one:
a. 9.8 m/s
b. 8.9 m/s?
c. 4.6 m/s?
d. 9.8 m/s2
Answer:
The magnitude of acceleration is 9.8 m/s
Explanation:
Its not always in m/s^2 but in m/s due to the unit of distance and time
a car collides with a wall. compare the forces exerted by the car on the wall and the wall on the car
Answer:
Newton’s third law states that for every action there is an equal and opposite reaction. Based on this you can say that the car crashing into the wall would put force into the wall. However, because the wall didn’t move it gives an equal force back to the car, probably causing it to crumple.
Explanation:
Mass multiplied by acceleration produces force.
The acceleration is (v - 0)/t in this situation, where t seems to be the time it takes automobile A to come to a stop. According to Newton's third law of motion, the automobile produces this turning force of the wall, however the wall, which really is static and indestructible, forces an equal force back on the car.
According to Newton's third law, each action has an equal and opposite response. On this basis, you may deduce that a car driving into a wall would exert force on the wall. However, since the wall did not move, the automobile receives an equivalent force, causing it to collapse.
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Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?
To make a higher pitch, stretch the rubber band more.
To make a higher pitch, pluck the rubber band less hard.
To make a higher pitch, stretch the rubber band less.
To make a higher pitch, pluck the rubber band harder.
Answer:
I think it is To make a higher pitch, stretch the rubber band more
Explanation:
I'm not too sure. Sry if u got it wrong
Answer:
To make a higher pitch ,pluck the rubber band more
Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks.
Answer:
2:3
Explanation:
mathqway
a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be
Answer:
HOPE THIS HELPS!!
Explanation:
Velocity is speed as well as distance mentioned.
The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.
So,it is at constant speed but not constant velocity.
If you have a train traveling 750 m in 63
seconds how fast is the train travelling?
Answer:
The train would be moving 47,250 mph
Convert: 12 km/hr =
m/s
[tex]12~ \text{km} ~ \text{h}^{-1} = \dfrac{12 \times 1000}{3600} ~~ \text{m s}^{-1} = 3.33 ~~ \text{m s}^{-1}[/tex]
Answer:
3 1/3 or 3.3333....
Explanation:
You multiply the kilometres by 1,000 because there are 1,000 metres in a kilometre. Then you divide by 60 because there are 60 minutes per hour, and then again by 60 because 60 seconds per minute.
12,000 / 60 = 200
200 / 60 = 3.333
How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m?
Answer:
95 N
Explanation:
NEES HELP!!!!
Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory
Answer:
Doppler Theory
Explanation:
it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.
HELP ASAP WHOEVER ANSWERS FIRST WITH BE BRAINIEST PLEASE HELP!
The answer is : A₃ = A₁ - A₂ = 3.0 - 2.0 = 1.0A
Ok done. Thank to me :>
Anyone please.??????
Answer:
468.42572 Wavelength In Metres
Explanation:
Answer:
[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]
Explanation:
Given Data:
Speed of light = c = 3 × 10⁸ m/s (Constant)
Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz
Required:
Wavelength = λ = ?
Formula:
λ = c / f
Solution:
λ = 3 × 10⁸ / 6.4 × 10⁵
λ = 0.47 × 10³
λ = 4.7 × 10² m
λ = 470 m
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807will mark brainliest if answer
I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.
A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.
a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?
Answer:u=350m/sec
v=0m/sec
t=0.005sec
a=v-u/t
=0-350/0.005
= -350/0.005
= -350×1000/5
= -70×1000
= -70000 m/sec^2
Explanation: i think this will help you thankyou
Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?
Answer:
24 miles.
Explanation:
3 hours=180 minutes
180÷30=6
6x4=24
Explain why the formation of sand is a physical change.
Answer:
The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.
If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?
A) 0.31
B) 2.5
C) 1.25
D) 0.62
Answer:
Option A, 0.31
Explanation:
n = Time taken / half life
n = 32/ 8
= 4
Remaining fraction = 1/2^n
= 1/2⁴
= 1/16
Amount of iodine-131 left = 1/16 × 5
= 0.3125
A car that's initially traveling at 10 m/s acceleration uniformly for 4 seconds at a rate of 2 m/s?in a straight line. How far does the car travel during this time?
Answer:
Explanation:
The answer is -2m/s²
a 1.0 kg ball falls from rest a distance of 15 m. what was its change in potential energy?
Answer:
147 J
Explanation:
PE = mgh
PE = (1.0)(9.8)(15)
PE = 147 joules
a car is travelig at 20.0 m/s when the driver applies the brakes and comes to a stop. if the car slows down uniformly with an acceleration of -4.20 m/s, about how far does the car travel before coming to a rest
Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
a flashlight operates with a current of 3.0 a and a power of 4.5 W. what is the voltage of the flashlights battery?
Answer:
V=1.5V
Explanation:
p=I×V
4.5=3×V
[tex]v = \frac{4.5}{3} [/tex]
[tex]v = \frac{3}{2} [/tex]
v=1.5
Need
Help answering the questions
What should you do before inserting a wire into an outlet box?
A. Place a bushing inline.
B. Remove a foot of the outer covering.
C. Clean the terminals.
D. Strip at least three inches and re-twist the strands to retighten.
The first thing that you should do before inserting a wire into an outlet box is to remove a foot of the outer covering.
What is an outlet box?The outlet box is sometimes called the junction box. It is from this point that power is distributed to appliances in the home. Its main function is to protect against short circuits.
The first thing that you should do before inserting a wire into an outlet box is to remove a foot of the outer covering.
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Explain the function and the difference between figure 1 and 2
Answer:
figure one (step up transformer) helps in increasing the output voltage
figure two (step down transformer) helps in decreasing the output voltage
A medieval instrument used to determine the position of the sun:
Answer: astrolabe
Explanation:
please help me please please, i will brainliest the right answer
