ecology is the study of what​

Answer:

the molar mass of propane (c3H8) is

12*3+1*8

=36+8=44

The percent by weight (w/w%) of sugar in soda : 6.216%

Given

mass of sugar = 23 g

total mass = 370 g

Required

the percent weight

Solution

%weight = (mass of solute : mass of solution) x 100%

solute = sugar

solution = solvent + solute = water + sugar

percent weight of sugar in soda :

= (23 : 370) x 100%

= 6.216 %

Answer:

atoms

Explanation:

i hope that help you

Answer:

atoms

Explanation:

Given

Atomic symbol

Required

Atomic composition

Solution

Atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Number of protons and Number of Neutrons  in nucleus

Number of electrons in the shell

From the picture:

protons = 3

neutrons = 4

electrons = 3

atomic number = protons = electrons = 3

mass number = protons + neutrons = 3+4 = 7

Answer:

I think is D

Explanation:

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Answer:

water/d

Explanation:

Answer:

any gas takes up 22.4L per mole so 2.4*22.4=53.76

Explanation:

In 2.4 moles at STP, 53.79 litres of N2 gas are present.

Moles are defined as the amount of substance of a system that contain the same number of entities as the number of atoms in 12g of carbon 12.

STP is defined as the standard temperature and pressure. At STP, as system has s temperature of zero degree centigrade or 273 Kelvin and the pressure is 1 atm.

PV= nRT

P= 1 atm

V= ?

n= 2.4 moles

R= 0.0821 L atm /K/mol

1 x V = 2.4 x 0.0821 x 273

V = 53.79 litres

Hence, 53.79 litres of N2 gas is present in 2.4 moles at STP.

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Answer:

option C : cellular respiration

Explanation:

cellular respiration is taking place in this diagram .

as in respiration food get oxidised to release energy and it releases CO2 and water

Answer: the answer is C

Explanation:

Answer:C

Explanation:I got it correct

The question is incomplete, the complete question is;

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is:

Al(s) + 3/2 Br2(l)AlBr3(s)

We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) 2 AlBr3(s) 2 Al(s) + 3 Br2(l)

2) 2 Al(s) + 3 Br2(l) 2 AlBr3(s)

3) AlBr3(s) Al(s) + 3/2 Br2(l)

Answer:

See explanation

Explanation:  

We have that; Al(s) + 3/2 Br2(l)AlBr3(s)

So;

Al(s) + 3/2 Br₂(l) = AlBr₃(s)

K = [  AlBr₃] / [ Al] [  Br₂]³/²

K² =  [  AlBr₃]² / [  Al ] ² [ Br₂]³

Now;

1) 2 AlBr₃ = 2 Al(s) + 3 Br₂(l) =

K₁ =  [  Al ] ² [ Br₂]³ /  [  AlBr₃]²

K₁ =  ( 1 / K² ) = K⁻²

For the second reaction;

2 ) 2 Al(s) + 3 Br₂(l) = 2 AlBr₃(s)

K₂ = [ AlBr₃ ]² / [  Al ]² [  Br₂ ]³

K₂ = K²

For the third reaction;

3 )

AlBr₃(s) =   Al(s) + 3/2 Br₂(l)

K₃  = [ Al ] [ Br₂ ] ³/² / [ AlBr₃ ]

=  ( 1 / K ) = K⁻¹

Answer:

ccc

Explanation:

Answer:

A

Explanation:

trust

Answer:

Explanation:

From the information above:

The equation for the reactor volume of CSTR is given by the formula:

[tex]V = \dfrac{C_{Ao}V_o - C_A V_o }{-rA}[/tex]

[tex]V = \dfrac{C_{Ao}V_o (1 - 0.01)}{KC_A^2}[/tex]

The reaction rate of A is:

[tex]-r_A = kC_A^2[/tex] and k = 3 dm³/mol.h

replacing the values in the above equation to solve for v;

∴

[tex]V = \dfrac{(0.5 \ mol/dm^3) (10 \ dm^3/h) (1 - 0.01)}{ ( 3 \ dm^3/mol.h) (0.01 \times 0.5 \ mol/dm^3)^2}[/tex]

V = 66,000 dm³

Thus, the reactor volume of CSTR is 66000 dm³

Taking the differential mole balance equation for PFR is as follows:

[tex]\dfrac{d(C_AV_o)}{dV} = -r_A[/tex]

[tex]\dfrac{d(C_AV_o)}{dV} = Kc^2A[/tex]

Taking the integral between initial and final concentrations;

[tex]\dfrac{v_o}{k} \int ^{C_A}_{C_{Ao}} \dfrac{dC_A}{C^2A}= - \int ^V_o \ dV[/tex]

[tex]V = \dfrac{V_o}{K} \Big [\dfrac{1}{C_A}- \dfrac{1}{C_{Ao}} \Big ][/tex]

replace the values in the above equation;

[tex]V= \dfrac{(10 \ dm^3/h) }{(3 \ dm^3/mol.h)}\Big [ \dfrac{1}{0.01(0.5 \ mol/dm^3)} - \dfrac{1}{0.5 \ mol/dm^3} \Big ][/tex]

[tex]\mathbf{V = 66 0 \ dm^3}[/tex]

Thus, the reactor volume of PFR is 660 dm³

Answer:

C. It may act as an insulator or a conductor.

Explanation:

Group B are the metalloids, so they have properties of both metals and nonmetals.

The statement which is most likely true for an element present in section B is: C. It may act as an insulator or a conductor.

A periodic table can be defined as an organized tabular array of all the chemical elements, which is typically arranged in order of increasing atomic number or number of protons (in rows).

In this diagram, the chemical element that is present in section B of the periodic table is a metalloid.

A metalloid can be defined as a chemical element that are typically intermediate between those of semiconductors, non-metals and metals.

In this context, the statement which is most likely true for an element present in section B is that it may act as an insulator or a conductor because it is a metalloid.

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Answer: 0.377 moles of calcium chloride will be formed.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Ca(OH)_2=\frac{27.9g}{74g/mol}=0.377moles[/tex]

The balanced chemical reaction is:

[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]  

According to stoichiometry :  

As 1 mole of [tex]Ca(OH)_2[/tex] give = 1 mole of [tex]CaCl_2[/tex]

Thus 0.377 moles of [tex]Ca(OH)_2[/tex] give =[tex]\frac{1}{1}\times 0.377=0.377moles[/tex]  of [tex]CaCl_2[/tex]  

Thus 0.377 moles of calcium chloride will be formed upon the complete reaction of 27.9 grams of calcium hydroxide with excess hydrochloric acid

Answer:

the answer is D . our galaxy

Answer:

our galaxy of course

When hydrogen is passed over hot ferric oxide (FeO) hydrogen reacts with oxygen present in the compound and forms water (H2O) and pure Iron

Answer:

the answer is second option. with 2 models

Explanation:

2H2 + O2 gives 2H2O

so there's two models

Answer:bromine

Explanation:

Answer:

Plants release oxygen in the process of Photosynthesis

Explanation:

Answer:

[tex]Li_2O[/tex]

Explanation:

Hello!

In this case, when looking over the chemical formula of a compound formed when two elements interact, we need to realize about their location in the periodic table; thus, since lithium is a metal and oxygen a nonmetal, we infer lithium turns out the cation and oxygen the anion. Moreover, as the oxidation state of lithium is 1+ and that of oxygen is 2-, we can set up the chemical formula as follows:

[tex]Li^+O^{2-}\\\\Li_2O[/tex]

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Answer:

26.982 g

i think so..........

Answer:

the answer is 64 moths are dark

Answer:

Zero

Explanation:

Answer:

m = 79.1 grams

Explanation:

Given that,

Density, d = 2.26 g/mL

Volume occupies, V = 35 mL

We need to find the mass of the substance. We know that the density of an object is equal to the mass per unit volume. So,

d = m/V

[tex]m=d\times V\\\\m=2.26\ g/mL\times 35\ mL\\\\m=79.1\ g[/tex]

So, the mass of the substance is 79.1 grams.

Answer:

The correct answer is "430 kJ/kg". A further explanation is given below.

Explanation:

The given values are:

T₁ = 400 k

T₂ = 800 k

The average temperature will be:

= [tex]\frac{T_1+T_2}{2}[/tex]

= [tex]\frac{400+800}{2}[/tex]

= [tex]600 \ k[/tex]

From table,

At 600 k the [tex]C p[/tex] will be = 1.075

Now,

⇒ The specific enthalpy = [tex]Cp(T_2-T_1)[/tex]

⇒                                [tex]\Delta h=1.075 (800-700)[/tex]

⇒                                      [tex]=430 \ kJ/kg[/tex]

Answer:

jayfeather friend me

Explanation:

Hence it is quite important to understand and learn the processes of the water cycle.

Step 1: Evaporation. The water cycle starts with evaporation. ...

Step 2: Condensation. ...

Step 3: Sublimation. ...

Step 4: Precipitation. ...

Step 5: Transpiration. ...

Step 6: Runoff. ...

Step 7: Infiltration.

Answer: We start by doing a 1/10 serial dilution, using 100 µL of 1M solution into 900 µL of water, until we get a 1.0x10^-5M (0.00001M) solution. Then use 1 mL of this 1.0x10^-5M solution into 9 mL of water.

Explanation:

To answer this question, we must use the law of conservation of mass, which states: In every chemical reaction mass is conserved, this means the total mass of the reactants is equal to the total mass of the products. The law implies that mass can neither be created nor destroyed, but it can be transformed. For example, in chemical reactions, the mass of the chemical components before the reaction is equal to the mass of the components after the reaction. Therefore, during any chemical reaction and low-energy thermodynamic processes in an isolated system, the total mass of the reactants or starting materials must be equal to the mass of the products. This law is quite accurate for low-energy processes, such as chemical reactions.

So, if the solution to be used is 1M , and a 10 mL of a 1.0x10^-6M solution is needed, we use the following equation:

Initial concentration x initial volume = final concentration x final volume.

The initial concentration is 1M, the final concentration is 1.0x10^-6M and the final volume required is 10 mL.

1M x initial volume = 1.0x10^-6M x 10 mL

initial volume=  1.0x10^-5 mL= 0.01 µL of 1M solution.

Since the final volume is 10 mL, we have to add the difference in volume with water, which is 10 mL - 1.0x10^-5 mL= 9.99999 mL.

However, since 0.01 mL is a very small volume that is difficult to take, the best option in this case is to make serial dilutions.

Usually, we start from a concentrated solution and prepare a series of dilutions to the tenth (1:10) or half (1:2). In this way a series of solutions is obtained, related for example by a dilution factor of 10, i.e. 1/10; 1/100; 1/1000 and so on.

Here we can prepare a series of dilutions to the tenth, from 1M to 1.0x10^-6.

We start by doing a 1/10 dilution, using 100 µL of 1M solution into 900 µL of water. This is a 0.1M solution. Then we take 100 µL of it into 900 µL of water to get a 0.01M solution. We continue doing that until we get a 1.0x10^-6M (0.000001M) solution. This final solution is the desired concentration, however we need 10 mL of it, and actually we have 1 mL. So we can just take 1 mL of the 1.0x10^-5M solution into 9 mL of water:

1.0x10^-5M x 1 mL = 1.0x10^-6M x 10 mL.