An object’s mechanical energy is

a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.

Answers

Answer 1

Explanation:

the sum of its potential (position) energy and kinetic (motion) energy.


Related Questions

Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved

Answers

The order of the location of each process in the carbon cycle are as follows;

Ingestion → Decomposition → Fossilization → Combustion

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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It requires a 70.4 N force (parallel to the inclined plane) to pull a 5.86 kg box up a 58.1° inclined plane with a rope at a constant speed. (a) What is the coefficient of kinetic friction between the inclined plane and the box?
(b) If the rope were to break, what acceleration would the box experience as it slid down the ramp?

Answers

Answer:

0.667; 4.965

Explanation:

Look at the picture I attached for the force analysis.

a) The coefficient=Friction/Normal Force. Because it's at constant speed, the force of friction + mgsin58.1° (because it's on an inclined plane and has split forces) is equal to the applied force (70.4N). Normal force is not equal to weight force though, because the box is on an inclined plane; it's equal to mgcos58.1°.

b) If it were to break, then the box no longer has an applied force, and the direction of friction has changed to up the inclined plane. F=m/a, so acceleration = mgsin58.1°- Friction/mass

How can you decrease the amount of input force of a wheel and axle?

Answers

Explanation:

hmm by the increasing the size of wheel and decreasing axle

Why does calcium chloride have a greater affect on colligative properties verses sodium
chloride?

Answers

Answer:

Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.

Explanation:

Hope this helps

how much brighter is Vega than the Sun? (astronomy)

Answers

Answer: 60 times brighter

In the fermentation of alcohol, sugars in the liquid are converted to alcohol and bubbles are formed on the surface of the liquids. Which gas forms the bubbles?

Answers

Answer:

I believe it is Carbon Dioxide because after yeast breaks down the glucose (sugar) molecule, it forms/creates CO2 and Ethanol. (though it might be Ethanol that creates the bubbles) I am not quite sure if this is correct, but I hope it helps! :,)

How charged objects can affect other objects without touching them. ?

Answers

By gravity as well as electrostatic and magnetic attraction and repulsion
Example forces being exerted by one object on another without them being in contact with each other

1 kg ball has eight joules of kinetic energy. what is its speed?

Answers

[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]

[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]

[tex]\\ \sf\Rrightarrow v^2=16[/tex]

[tex]\\ \sf\Rrightarrow v=√16[/tex]

[tex]\\ \sf\Rrightarrow v=4m/s[/tex]

Answer:

the answer is 4m/s


A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?

Answers

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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which term is defined by the interaction between two charged particles?

Answers

Answer: Electromagnetism

The term which is defined by the interaction between two charged particles is known as electromagnetism.

What is an electromagnet?

The study of charge and the fields and forces it generates is known as electromagnetism. Electromagnetism has two components: electricity and magnetism.

The special theory of relativity, developed by Albert Einstein in 1905, proved beyond a shadow of a doubt that both are components of the same reality. But in reality, magnetic and electric forces behave very differently and are modeled by various equations. Electric charges can produce forces whether they are stationary or moving. On the other hand, magnetic forces are only created by moving charges and only affect charges that are moving.

Thus, the term is known as electromagnetism.

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A car traveling in a northeasterly direction at a rate of 50 km/h represents which of the following?
A.
deceleration
B.
velocity
C.
speed
D.
acceleration

Answers

Answer:

c.

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Formula

s = \frac{d}{t}

s = speed

d = distance traveled

t = time elapsed

The function of the liver in the metabolism of amino acids is to

Answers

Answer:

Produce energy, or make carbohydrates or fats.

Explanation:

Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?

A. F2

B. 1/2F

C. 0.1F

D. 2F/5

E. 5F

J. 10F

Please help will mark brainliest

Answers

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?

The rabbits change of momentum is

A. 31 kg•m/s east

B. 31 kg•m/s west

C. 15.5 kg•m/s, west

D. 15.5 kg•m/s, east

This value can also be referred to as

E. Collisions

F. Potential energy

G. Kinetic energy

H. Impulse

Please help will mark brainliest

Answers

Hi there!

Recall that:

Change in momentum = mass × change in velocity

Or:

Δp = mΔv = m(vf - vi)

Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).

Thus:

Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.

The correct answer is B.

Change in momentum is EQUIVALENT to the quantity of IMPULSE.

The correct answer is H.

What two things related to sedimentary rocks do you see at the Grand Canyon ?

Answers

Answer:

sandstone and mudstone

Explanation:

Compare and contrast synthesis and decomposition reactions.

Answers

Answer:

Synthesis reactions are chemical reactions where two elements combine to make a product. Decomposition reactions are chemical reactions where a reactant produces another product, usually two, or even more. This is when the bonds in the compound are broken apart to make new compounds.

Explanation:

A car weighing 8000N is traveling at 45 m/s on a perfectly flat, frictionless road. If the driver slams on the brakes, how far will thw car slide before it comes to a stop?

Answers

Without friction, the car cannot stop...

Now you need to put handles on your cookware! You have five different options, including metals and nonmetals such as wood. Based on specific heat, which material would be the best choice? the material with the smallest specific heat the material with the greatest specific heat the material whose specific heat is farthest from the specific heat of the metal pan the material whose specific heat is closest to the specific heat of the metal pan.

Answers

Answer: B the material with the greatest specific heat

Explanation:

Just did the assignment

Answer:

B. The material with the greatest specific heat

Explanation:

Which particles within the atom are electricity charged?

a. Electrons only.
b. Neutrons only.
c. Protons only.
d. Electrons and protons.
e. Protons and neurons.

Answers

Answer:

I think b sorry if wrong

Explanation:

it b sorry if wrong

Answer:

Given that these particles make up atoms, they are often referred to as subatomic particles. There are three subatomic particles: protons, neutrons and electrons. Two of the subatomic particles have electrical charges: protons have a positive charge while electrons have a negative charge:


[tex] \huge \rm༆ question ༄[/tex]


Calculus proof of second equation of motion ~ ​

Answers

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

An object is dropped from a 42 m tall building. How long does it take to reach the ground?

Answers

Answer:

2.1 seconds

Explanation:

let D represent the height in meters

let g represent gravity in meters per second squared

let t represent time in seconds

D= -42 meters (negative because it falls down)

g= -9.8m/s^2

t= [tex]\frac{-42 meters}{9.8 m/s^2}[/tex]

this gives t= 4.2857 s^2

the meter units cancel out in the division

now we must simplify the units to singular seconds so...

[tex]\sqrt{4.3 s^{2} }[/tex] which simplifies to [tex]\sqrt{4.3}[/tex] x [tex]\sqrt{s^{2} }[/tex]

this equals 2.1 seconds

Physicists call any change in energy an impulse true or false?

Answers

False
.!.7:&//‘is sis sis did is

Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help
guide the content of your paragraph.
1. According to your data, was your hypothesis for each experiment correct? (Be sure to refer to your data and graphs
when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to gulde your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results.
Describe how you might change the procedure to avoid these problems.
4. Give at least one more example from real life where the principles demonstrated in this lab are evident.

Answers

Answer:

Sample answer: part 1:

What was your hypothesis?

This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:

"The viscosity of honey decreases as temperature increases".

According to your data, do you think your hypothesis was correct?

Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.

The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.

Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:

"one problem was that the temperature of the honey increased too fast"

And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.

part 2:

Viscosity depends strongly on temperature, but this relation depends also on the given material.

Generally, we would see that the viscosity decays exponentially as the temperature increases.

So for the first question:

What effect did the temperature have on the viscosity of the honey?

You should have seen that, as the temperature increased, the viscosity decreased.

Now, we need to give some practical examples where knowledge of viscosity is important.

The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.

Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.

So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.

Explanation:

An object is moving with a constant velocity of 311 m/s. How long will it take it to travel 9000 m?

Answers

[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]

What did Ernest Rutherford expect to happen when he aimed a beam of particles at a thin gold foil

Answers

Answer:

he expected a fire to happen I think

Answer:

When Ernest Rutherford aimed a beam of particles at a thin gold foil he expected that the particles would be deflected slightly after passing through the foil.

Explanation:

hope it helped

pls help it's due today​

Answers

Answer:

Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

5.D,A and B

6.A,C and D


19. A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. Its momentum is 3 kg'm/sec.
What is the mass of the beach ball? moss - 0.33
aroto from 10mle to speed of 14 m/s The mass of the bicycle

Answers

The mass of the beach ball is 0.33 kg

From the question,

We are to determine the mass of the beach ball.

Using the formula

ρ = mv

Where ρ is the momentum

m is the mass

and v is the velocity

From the given information,

ρ = 3 kg m/sec

v = 9 m/sec

Putting the parameters into the formula, we get

3 = m × 9

∴ m = 3 ÷ 9

m = 0.33 kg

Hence, the mass of the beach ball is 0.33 kg

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A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center, as shown above. The coin doesn’t slip and the time it takes for the coin to make a complete revolution is 1.5 s.
A)The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show instantaneous acceleration and linear velocity vectors for the pin when it is at the position shown below.
B)Determine the linear speed of the coin
C)The rate of rotation of the disk is gradually increased. The coefficient of stats if friction between the coin and the disk is 0.50. Determine the linear speed of the coin when it just begins to slip.
D)If the experiment in part c were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part c? Explain.

Answers

A) Figure attached below

B) The linear speed of the coin = 0.59 m/s

C) Linear speed as coin begins to slip = 0.83 m/s

D) The tangential speed will remain the same as seen in part C

Given data :

mass of coin = 0.0050 kg

Distance of coin from the center of disk = 0.14 m

Time to make a complete revolution = 1.5 s

A) Diagram showing the vectors on the figure is attached below

B) Determine the Linear speed of the coin

Linear speed of coin = 2 * π * ( 0.14 ) / 1.5

                                   = 0.59 m/s

C) Determine the linear speed of the coin when it just begins to slip

given that: friction between coin and disk = 0.50

Friction becomes maximum when coin begins to slip

Maximum frictional force (Fmax) =  uV

where V = mg

∴ Fmax = u*mg ---- ( 1 )centripetal force = [tex]\frac{mv^{2} }{r}[/tex] ---- ( 2 )

Equating equations ( 1 ) and ( 2 ) to determine the linear speed ( v )

v² = u*r*g

∴ v = √(u*r*g ) = √( 0.5 * 0.14 * 9.8 )

                        = 0.83 m/s

 

D) If the experiment is repeated with a second coin glued to the top of the first coin the tangential speed will remain the same

Hence we can conclude that The linear speed of the coin = 0.59 m/s Linear speed as coin begins to slip = 0.83 m/s , The tangential speed will remain the same as seen in part C

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The density of air is 1.3 kg/m'. Calculate the mass of air in the room.

Answers

Answer:

The density of air is 1.3 kg/m'. Calculate the mass of air in the room.

Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters

Answers

Other clusters with hundreds to thousands of galaxies are called rich clusters. The low mass of a poor cluster prevents the cluster from holding onto its members tightly. The poor cluster tends to be a bit more irregular in shape than a rich cluster. Each large spiral has several smaller galaxies orbiting them.

These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).

What clusters of galaxies likely to have irregular shapes?

In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.

Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.

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