Which burrito will heat up faster .03oz or .05 oz
Answer:
.03
Explination
I am god
Which medium does Wi-Fi use to send data between networks and devices?
What are signs of someone having social anxiety?
(in yo own wurds)
Answer:
There are many signs of having social anxiety. You might have some signs/symptoms but not the diagnosis.
Explanation:
Signs that you might have social anxiety:
Fear of situations in which you may be judged
Worrying about embarrassing or humiliating yourself
Intense fear of interacting or talking with strangers
Fear that others will notice that you look anxious
Fear of physical symptoms that may cause you embarrassment, such as blushing, sweating, trembling or having a shaky voice
Avoiding doing things or speaking to people out of fear of embarrassment
Avoiding situations where you might be the center of attention
Having anxiety in anticipation of a feared activity or event
Enduring a social situation with intense fear or anxiety
Spending time after a social situation analyzing your performance and identifying flaws in your interactions
Expecting the worst possible consequences from a negative experience during a social situation
Physical Signs:
Blushing
Fast heartbeat
Trembling
Sweating
Upset stomach or nausea
Trouble catching your breath
Dizziness or lightheadedness
Feeling that your mind has gone blank
Muscle tension
Things that could help:
Interacting with unfamiliar people or strangers
Attending parties or social gatherings
Going to work or school
Starting conversations
Making eye contact
Dating
Entering a room in which people are already seated
Returning items to a store
Eating in front of others
Using a public restroom
The change that occurs from age to age
what was The archetypal downfall of man
what was The role of Jupiter as the archetypal father/caretaker
what was The ultimate punishment
what was The use of personification in developing characters
All of the following except ____________ are possible side effects of stigmas associated with mental disorders.
All of the following except
A. discrimination
B. labels
C. prejudice
D. negative stereotypes
Please select the best answer from the choices provided
All of the following except labels are possible side effects of stigmas associated with mental disorders. Thus, option B is correct.
What are stigmas?Social stigma refer to the discrimination or the disapproval against the individual or the group that should be based on the social characteristics where it should be make a difference from the other society members.
Its side effects include the discrimination, prejudice. negative stereotypes, etc.The possible side effects of stigmas associated with mental disorders should not include the labels.
In social science and anthropology, as well as in everyday English discourse, the term "ethnocentrism" refers to the practise of using one's own culture or ethnicity as a frame of reference to evaluate the Other cultures.
Learn more about stigma on:
https://brainly.com/question/7893979
#SPJ7
FRQ- in relation to the land size describe why might a country choose either federal or unitary form of government.
Answer:
unitary
Explanation:
took the quiz and got it right
cite at least two events from your life that you experienced social inequality
Answer:
as a korean, living in america and going to schools with many white kids was tough. during the virus, i have experienced many moments where i have been stared down with scared faces, or been cussed out, telling me to go back to where i came from. even in school, the kids would do the normal things, and stretch out their eyes to mimic mine, which actually are pretty big. teachers ignored me more or asked insensitive questions, and all my life, i have felt a barrier, and social inequality. now that the korean things are trending though, many know who i am, but it is annoying for them to connect me to korean beauty, korean plastic surgery, kpop, and other things that managed to become popular in america.
Explanation:
I’m so lost, pls help
For a particle with some position function y(t), we're given its velocity function v(t) = 1 - tan⁻¹(eᵗ ) and we're told that it starts with a position of y = -1 at the start.
(a) Acceleration is the rate of change of velocity, so to get the acceleration function a(t), you have to differentiate v(t) :
a(t) = d/dt v(t)
a(t) = d/dt [1 - tan⁻¹(eᵗ )]
a(t) = - d/dt [tan⁻¹(eᵗ )]
Apply the chain rule: take f(u) = tan⁻¹(u) and u(t) = eᵗ, so that
df/dt = df/du × du/dt
→ a(t) = - 1/(1 + u ²) × eᵗ = - eᵗ / (1 + e²ᵗ )
Then when t = 2, the acceleration is
a (2) = - e² / (1 + e⁴) ≈ -0.1329
(b) The acceleration of the particle at t = 2 is negative, so the particle's speed at this moment is decreasing. (Recall the first derivative test.)
(c) Note that at t = 0, the particle's velocity is v (0) = 1 - tan⁻¹(e⁰) = 1 - π/4 ≈ 0.2416 > 0. This means that the particle is moving upward at the start.
From part (a), we see that the acceleration is always negative, so the particle would be slowing down until it reaches zero velocity, after which point its velocity will become negative (meaning its speed would increase again as it starts to accelerate in the negative direction).
This means the particle's highest position on the y-axis occurs at the same time v(t) becomes 0, so you solve:
1 - tan⁻¹(eᵗ ) = 0
1 = tan⁻¹(eᵗ )
tan(1) = tan(tan⁻¹(eᵗ ))
tan(1) = eᵗ
ln(tan(1)) = ln(eᵗ )
ln(tan(1)) = t ≈ 0.443
(d) Use the fundamental theorem of calculus to find an expression for y(t) :
y(t) = y (0) + ∫₀ᵗ v(s) ds
(where s is just a dummy variable)
Then the particle's position at t = 2 is
y (2) = y (0) + ∫₀² v(s) ds
v(t) unfortunately does not have a nice antiderivative, so you'll have to use a calculator. (I hope this question is given in the calculator portion!) You would find
∫₀² v(s) ds ≈ -0.3607
so that
y (2) ≈ -1 + (-0.3607) ≈ -1.3607
The sign of the particle's velocity at this time tells you in which way the particle is moving. We have
v (2) = 1 - tan⁻¹(e²) ≈ -0.4363
which is negative, so the particle is moving away from the origin. This is consistent with the answer found in part (c):
• before t ≈ 0.443, the particle is moving upward toward the origin;
• at t ≈ 0.443, the particle reaches its highest point at y (2) ≈ -1.3607, then turns around and accelerates back downward and away from the origin