A patient is supposed to have 800 mL every 24 hours. You kmow that the patiemt has three fourths of the fluid between breakfast 8am and dinmer 6pm. How much should be injested between 8am and 6pm?

Answer:

B

Step-by-step explanation:

Since x= 3/4

To take the fraction on left hand side, inverse 4/3

Take π as denominator

Then cube root the entire equation on the left hand side.

Answer:

Step-by-step explanation:

Answer and Step-by-step explanation:

The random point on the line is between A and B, and to find the probability of the A, let's find the probability that is distance A and more than times the distance B. Let's have the probability that A and distance to A are more than the distance to B. The distance C is the interval of A to B. If she is closer and landed in the interval, the equation can be (A, A+B/2). This is the interval length, and the probability is 0.5. If the distance to A is more than the distance B, then the interval is as follows in the given equation (A + 3B/2, B ). The probability of the given interval is 0.25.

Answer:

f(g(x)) = 9x^2 + 15x - 6

Step-by-step explanation:

We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.

Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side.  We obtain:

f(g(x)) = (3x - 1)^2 + 7(3x - 1).

If we multiply this out, we get:

f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or

f(g(x)) = 9x^2 + 15x - 6

Answer:

1 length ityoughkdds hshlkb

Let it be x

[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{3}{6}[/tex]

[tex]\\ \sf\longmapsto 6x=10(3)[/tex]

[tex]\\ \sf\longmapsto 6x=30[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{30}{6}[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Answer:

m<1 = 55°

m<2 = 125°

m<3 = 55°

m<5 = 55°

m<6 = 125°

m<7 = 55°

m<8 = 125°

Step-by-step explanation:

m<4 = 125° (given)

✔️m<8 = m<4 (alternate exterior angles are congruent)

m<8 = 125° (substitution)

✔️m<1 = 180° - m<8 (supplementary angles/linear pair)

m<1 = 180° - 125° (substitution)

m<1 = 55°

✔️m<2 = m<8 (vertical angles are congruent)

m<2 = 125° (substitution)

✔️m<7 = m<1 (vertical angles are congruent)

m<7 = 55° (Substitution)

✔️m<3 = m<7 (alternate interior angles are congruent)

m<3 = 55° (substitution)

✔️m<5 = m<3 (vertical angles are congruent)

m<5 = 55°

✔️m<6 = m<4 (vertical angles)

m<6 = 125°

Answer:

multiply the numerator together and denominator together

Answer:

Step-by-step explanation:

We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so

3L + 5s = 88

12L + 2s = 235 according to the other information given.

Solve the first equation for either L or s. I'll solve for L, just because:

3L = 88 - 5s and

L = [tex]\frac{88}{3}-\frac{5}{3}s[/tex] and sub that into the second equation for L:

[tex]12(\frac{88}{3}-\frac{5}{3}s)+2s=235[/tex] and if you distribute the 12 into the parenthesis you'll simplify it down a bit to

352 - 20s + 2s = 235 and combine like terms:

-18s= -117 so

s = 6.5 kg and plug that in to solve for L:

L = [tex]\frac{88}{3}-\frac{5}{3}(6.5)[/tex] and

L = 18.5 kg

1 dozen = 12

144 / 12 = 12 dozen

12 dozen/ 3 = 4

They need 4 times the amount of flour:

3 1/4 x 4 = 13

They need 13 cups of flour

Answer:

I think the answer is 3

hope it will help you

Answer:

D Replace on equation with sum /difference of both equations

The systems are still the same

Step-by-step explanation:

5x + y = 3

4x - 7y = 8

Subtract the second equation from the first

5x + y = 3

-(4x - 7y = 8)

-----------------

x    +8y = -5

The second equation in system B is the first equation in system a minus the second equation in system A

We added the same thing to each side of the equation so the the system is still the same

Answer:

arcsin0.616

Step-by-step explanation:

arcsino.616

Answer:

Not a function

Domain: {3,4}

Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

Answer:

shifting to the right is just an east/west movement

not a north/south

an east west movement is on the "X" ais, a north/south is on the "Y"

axis...

so just ADD 10 units to all the "X" values

a" = (9,-3)

b"=  (6,-1)

c"=  (4,-4)

Step-by-step explanation:

9514 1404 393

Answer:

  ₱6400

Step-by-step explanation:

Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...

  14%(13900-b)(2) +11%(b)(2) = 3508

  1946 -0.03b = 1754 . . . . . . divide by 2, simplify

  -0.03b = -192 . . . . . . . . . subtract 1946

  b = 6400 . . . . . . . . . . . divide by -0.03

The amount invested in scheme B was ₱6400.

Answer:

El cuadrado de la suma de dos números es igual a (a + b) ² = a² + 2ab + b²Un producto notable: es una expresión matemática que conocemos ya el resultado, a pesar de la operación ser sencilla tenemos

Answer:

So, remember that:

cos(x) > 0   for  -pi/2 < x < pi/2

cos(x) < 0 for  pi/2 < x < (3/2)*pi

and

sin(x) > 0 for 0 < x < pi

sin(x) < 0 for -pi < x <0  or  pi < x < 2pi

Also, we have the periodicty of the sine and cocine equations, such that:

sin(x) = sin(x + 2pi)

cos(x) = cos(x + 2pi)

Now let's solve the problem:

[tex]sin(\frac{13*\pi}{36} )[/tex]

here we have:

x = (13/36)π

This is larger than zero and smaller than π:

0 < (13/36)π < π

then:

[tex]sin(\frac{13*\pi}{36} )[/tex]

Is positive.

The next one is:

[tex]cos(\frac{7*\pi}{12} )[/tex]

Here we have x = (7/12)*pi

notice that:

7/12 > 1/2

Then:

(7/12)*π > (1/2)*π

Then:

[tex]cos(\frac{7*\pi}{12} )[/tex]

is negative.

next one:

[tex]sin(\frac{47*\pi}{36} )[/tex]

here:

x = (47/36)*π

here we have (47/36) > 1

then:

(47/36)*π > π

then:

[tex]sin(\frac{47*\pi}{36} )[/tex]

is negative.

the next one is:

[tex]cos(\frac{17*\pi}{10} )[/tex]

Here we have x = (17/10)*π

if we subtract 2*π (because of the periodicity) we get:

(17/10)*π - 2*π

(17/10)*π - (20/10)*π

(-3/10)*π

this is in the range where the cosine function is positive, thus:

[tex]cos(\frac{17*\pi}{10} )[/tex]

is positive.

the next one is:

[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]

here we have:

x = (41/36)*π

Notice that both functions, sine and cosine are negatives for that value, then we have the quotient of two negative values, so:

[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]

is positive.

The final one is:

[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]

Here:

x = (5/9)*π

The sin function is positive with this x value, while the cosine function is negative, thus:

[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]

Is negative.

9514 1404 393

Answer:

  (e) f′(x)=2xg(x)+x²g′(x)

Step-by-step explanation:

The product rule applies.

  (uv)' = u'v +uv'

__

Here, we have u=x² and v=g(x). Then u'=2x and v'=g'(x).

  f(x) = x²·g(x)

  f'(x) = 2x·g(x) +x²·g'(x)

Answer:

answers in the explanation cz I'm too lazy to type :(

not entirely sure tho

Step-by-step explanation:

w²+2w-42=0

*quadratic formula*

w= -1+ square root 43 m

or w= -1- square root 43 m

then since the length is 2m more than w

add 2 to both answers

l= 1+ square root 43 m

l=1- square root 43 m

9514 1404 393

Answer:

Step-by-step explanation:

Given:

  a rectangular patio of width w meters, length w+2 meters, and area 42 m²

Find:

  width and length

Solution:

The area is ...

  A = LW

  42 = w(w +2)

  43 = w² +2w +1 . . . . . . add 1 to complete the square

  √43 = w+1

  w = √43 -1 ≈ 5.557 . . . meters

  l = w+2 = √43 +1 ≈ 7.557 . . . meters

The width and length of the patio are 5.557 m and 7.557 m, respectively.

Answer:

Hello,

polynomial is x²-x+1

Step-by-step explanation:

if a=b*c+r then a=c*b+r

Using a long division, see the picture.

Answer:

32.64°

Step-by-step explanation:

From triangle Given :

The sides of the missing angle given are the Adjacent and hypotenus.

Since the triangle is right angled, we can apply trigonometry :

cosθ = adjacent / hypotenus

Cosθ = 16 / 19

θ = Cos^-1(16/19)

θ = 32.6368

θ = 32.64°

Answer:

Length = 2x+y cm and since it's a rectangle,

2x+y=3x-y ---------------- (i)

width = 2x-3 cm

It's perimeter,

2(2x+y+2x-3)=120 ---------------- (ii)

Solving both equations,

x = 14 cm

y = 7 cm

so length is, 2×14+7 = 35 cm

and width is, 2×14-3 = 25 cm

so area will be, 35×25 = 875 cm²

Answered by GAUTHMATH

Answer:

len = 35

width = 25

Step-by-step explanation:

3x-y = 2x+y

1) x-2y = 0

9x -6= 120

x = 14

y = 7

Answer:

1250000cm

Step-by-step explanation:

1:500000

1x2.5 : 500000x2.5

2.5:1250000

Step-by-step explanation:

Ru Tu yulyryosuyyyhlsgjpcbmb kvjvlcykxnlvdlbvhck

chgkbhlxyovk m.

chchhlzixhvkh

Answer:

The maximum number of minutes to keep the cost at $50 or less is 110 minutes

Step-by-step explanation:

Given

[tex]C(x) = 30[/tex] ---- [tex]x < 60[/tex]

[tex]C(x) = 30 + 0.40(x - 60)[/tex] --- [tex]x \ge 60[/tex]

Required

[tex]C(x) = 50[/tex] ---- find x

We have:

[tex]C(x) = 30 + 0.40(x - 60)[/tex]

Substitute 50 for C(x)

[tex]50 = 30 + 0.40(x - 60)[/tex]

Subtract 30 from both sides

[tex]20 = 0.40(x - 60)[/tex]

Divide both sides by 0.40

[tex]50 = x - 60[/tex]

Add 60 to both sides

[tex]110 = x[/tex]

[tex]x =110[/tex]

Answer:

a = 3√6 in

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 60°

Adjacent = 3√2 in

Opposite = a =?

The value of 'a' can be obtained by using the tan ratio as illustrated below:

Tan θ = Opposite / Adjacent

Tan 60 = a / 3√2

√3 = a / 3√2

Cross multiply

a = √3 × 3√2

Recall:

c√d × n√m = (c×n) √(d×m)

Thus,

√3 × 3√2 = (1×3)√(3×2)

√3 × 3√2 = 3√6

a = 3√6 in

Answer:

There are 32 nickels and 23 dimes.

Step-by-step explanation:

Lets say x is nickels and y is dimes

The first equation would be 55 = x + y

The second equation would be .05x + .10y = 3.90

The Solving Part:

Move y to the other side: x = 55 - y

Substitute x in the second equation: .05(55-y) + .10y = 3.90

Distribute, rearrange, and combine like terms: .05y = 1.15

Solve for y: Y = 23

Plug in 23 for y and solve: 55 - y = x ; 55 - 23 = x ; 55 - 23 = 32

x = 32

y = 23

32 nickels and 23 dimes

Answer:

There are 32 nickels and 23 dimes.

Step-by-step explanation:

Yay :) we solved the problem together :)))))