A π meson of rest energy 139.6 MeV moving at a speed of 0.921c collides with and sticks to a proton of rest energy 938.3 MeV that is at rest. (a) Find the total relativistic energy of the resulting composite particle. (b) Find the total linear momentum of the composite particle. (c) Using the results of (a) and (b), find the rest energy of the composite particle.

Answers

Answer 1

Answer:

A) 1268 MeV

B)  299MeV/c

C) 1268 MeV

Explanation:

Given :

π meson rest energy = 139.6 MeV

Speed = 0.921c

proton at rest energy = 938.3 MeV

a) Find the total relativistic energy of resulting composite particle

E = E(meson) + E(proton)

  = [tex]\frac{(mc^2)_{meson} }{\sqrt{1-\frac{v^2}{c^2} } } + (mc^2)_{proton}[/tex]

  = [tex]\frac{139.6MeV}{\sqrt{1-\frac{(0.906c)^2}{c^2} } } + 938.3[/tex]

E = 1268 MeV

B) determine the total linear momentum of the composite particle

= 299MeV/c

attached below is the detailed solution

C) Determine the rest energy of the composite particle

E = 1268 MeV

A Meson Of Rest Energy 139.6 MeV Moving At A Speed Of 0.921c Collides With And Sticks To A Proton Of

Related Questions

Jojo and Roro begin side-by-side at one end of the playground. At the same moment, they begin to move toward the other end of the playground, Jojo at a constant velocity of 3.0 m/s, Roro at a constant velocity of 2.0 m/s. Sometime during her trip, Roro stops to rest for 2.0 s, but then starts again at her original constant speed. When Jojo reaches the end of the playground, she is 10 m ahead of Roro.
(a) For how much time did Roro move?
(b) How far did Roro move? (Set it up, good notation, equations in symbols first, etc.)

Answers

Answer:

Roro's total travel time = 6 seconds out of which he rested for 2 seconds

Distance covered by Roro = 8 meters

Explanation:

Given that :

Jojo:

Constant velocity, v = 3m/s

Travel time = h

Roro:

Constant velocity, v = 2m/s

Roro rest for 2 seconds

Travel time = h - 2

Recall:

Distance = speed * time

Distance covered by Jojo:

3 * h = 3h

At this distance ;

Roro's distance = 3h - 10

Using formula :

Roro's distance = 2 * (h - 2)

Hence,

2(h - 2) = 3h - 10

2h - 4 = 3h - 10

2h - 3h = - 10 + 4

-h = - 6

h = 6

Hence, Roro moved for :

h - 2 = 6 - 2 = 4seconds

Distance moved by Roro:

2(h - 2) = 2(6 - 2) = 2(4) = 8 meters

A 0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 44.0 pC charge on its surface. What is the potential near its surface

Answers

Answer:

Explanation:

Radius of sphere R = .250 x 10⁻² m

Potential on the surface V = k Q / R , where Q is charge on the surface ,  R is radius of the surface and k = 9 x 10⁹

Q = 44  x 10⁻¹² C

V = 9 x 10⁹ x 44  x 10⁻¹² /  ( .25 x 10⁻²)

= 1584 x 10⁻¹ Volt .

= 158.4 Volt

Identify and sketch all the external forces acting on the chair. Because the chair can be represented as a point particle of mass m, draw the forces with their tails centered on the black dot in the middle of the chair. Be certain to draw your forces so that they have the correct orientation. Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.

Answers

Answer:

y axis normal (N) and the weight (W)

x axis  pplied force (F) and friction force (fr)

Explanation:

If we have a chair on a horizontal surface, the normal (N) and the weight (W) of the body act on the vertical axis.

On the x axis, the applied force (F) acts in the direction of movement and the friction force (fr) in the opposite direction of movement.

In this exercise we assume that the body tends to move to the right, all the forces can be seen in the adjoint

What is the symbol for carbonate ?

Answers

It is HCO3 the symbol of carbonate

What inspired Ronald McNair to do science

Answers

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

to what temperature it will a 30 KG of glass raise if it absorbs 4275 joules of heat in its specific heat is 0.5 J/KG degree celsius. The initial temperature of the glass is 35°C

Answers

Answer:

230° C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1∘C

How much force does it take to give a 70 kg object an acceleration of 20 mls2

Answers

Answer:

heyy

Explanation:how r uuu

Which subatomic particle is NOT found in the nucleus of an atom? *

protons
neutrons
electrons

Answers

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

electrons, only protons and neutrons are found within the nucleus.

A spacecraft is flying away from the moon toward earth.

What will be true of the moon’s gravitational pull on the spacecraft?

It will decrease.

It will increase.
It will repel the spacecraft.
It will remain the same.

Answers

Answer:

it will  decrease

Explanation:

According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.

Answer:

A. It will increase

Explanation:

I took the quiz on K12 and this was the correct option.

Hope I helped

Thomas knows that many machines transform electrical energy into other forms of energy

Answers

Question:-
So? Gd for him though

Answer:

Only the car transforms electrical energy into more than one form of energy.

Explanation:

The motion of the car is mechanical energy but it can also transform into another energy witch is electrical energy


A lunar eclipse occurs when the Moon passes through Earth's

Answers

False, when the moon passes between the earth and sun it’s a solar eclipse and lunar eclipse happens when earth passes between the moon and sun

Astronomers study the electromagnetic radiation emitted by distant stars and planets to determine things like: how far away they are, their temperatures and speed, etc. Based on what you learned in this class, explain why the NASA Hubble Space Telescope is better for observing the electromagnetic radiation emitted from stars and planets at 560 km above sea level compared to the Keck telescope in Hawaii, which is 4 km above sea level

Answers

Answer:

This same Hawaii telescope, which would be 4 km across water level, can't provide an appropriate version of distanced planetary bodies. A further overview is provided below.

Explanation:

The surface area of that same earth's orbit seems to be approximately 480 km heavy. The atmosphere isn't translucent to the only certain wavelength range of the radioactivity. Not because all-stars, as well as gliders, emit specific wavelengths, but several of them generate ultraviolet as well as infrared. Those same radiations have either been mediated primarily as well as passes through the atmosphere. Due to the Blockage, they can't even be interpreted with such a similar quality unless the telescope would be positioned throughout the portion of the atmosphere.

What are used to measure temperature.

Answers

Answer:

A thermometer is an instrument that measures temperature.

Explanation:

a thermometer everyone knows this

Which of these is an effect of gravity?
А
A cup placed on a table won't float away.
B
You can throw a ball or a rock up.
С
The brakes on a bike can make it stop.
D
Liquid water can become a gas.

Answers

Answer:

(A)

A cup placed on a table won't float away

A 6.00 nC is 2.00 m from a 3.00 nC charge. Find the magnitude of the electric field at a point midway between
the two charges? Which way does the electric field point, towards the positive or the negative charge?

Answers

Answer:

E_total = 26.97 N/C

Electric field points towards the positive charge

Explanation:

We are given;

Charge 1; q1 = 6 nC = 6 × 10^(-9) C

Charge 2; q2 = 3 nC = 3 × 10^(-9) C

Distance between both charges; R_o = 2 m

Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m

Using coulumbs law;

E = kq/r²

Where k is a constant with a value of 8.99 × 10^(9) N.m/C²

Thus;

E1 = kq1/r²

E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²

E1 = 53.94 N/C

Similarly;

E2 = kq2/r²

E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²

E2 = 26.97 N/C

Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.

This implies they will have opposite directions.

Thus, total electric field at the midway point is;

E_total = E1 - E2

E_total = 53.94 - 26.97

E_total = 26.97 N/C

If a skaters mass increases how does that effect kinetic energy

Answers

Answer:

By paying close attention to the formula for average kinetic energy, we can see that by increasing the mass by a proportional amount will lead to an increase in the total average kinetic energy. There is a direct relationship being observed between the values.

Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m. Do not use unit of measure, just a whole number. Give the result in standard notation, not in scientific notation. Use for the Coulomb constant the value k

Answers

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

During a storm, a car traveling on a level horizontal road comes upon a bridge that has washed out. The driver must get to the other side, so he decides to try leaping the river with his car. The side of the road the car is on is18.0 m above the river, while the opposite side is only1.8 m above the river. The river itself is a raging torrent69.0 m wide.Part AHow fast should the car be traveling at the time it leaves the road in order just to clear the river and land safely on the opposite side?Part BWhat is the speed of the car just before it lands on the other side?

Answers

Answer:

Part A: The speed the car should be travelling when leaping the river is approximately 37.948 m/s

Part B: The speed of the car just before it lands is approximately 41.92345 m/s

Explanation:

The parameters of the car attempting leaping the river are;

The height of the car over the river = 18 m

The height of the opposite side of the bridge above the river = 1.8 m

The width of the river, x = 69.0 m

Part A

The time, 't' it would take the car to fall from 18 m above the river to 1.8 m above the river is given as follows;

t = √(2·h/g)

Where;

h = The height of the fall = 18 m - 1.8 m = 16.2 m

g = The acceleration due to gravity = 9.8 m/s²

∴ t = √(2×16.2 m/(9.8 m/s²)) = (9/7)·√2 s

The horizontal speed, 'vₓ', with which the car should be travelling at the time it leaves the road in order just to clear the river and land safely on the opposite side is given as follows;

vₓ = x/t = 69.0 m/((9/7)·√2 s) = (161/6)·√2 m/s ≈ 37.948 m/s

The horizontal speed the car should be travelling when leaping the river, vₓ ≈ 37.948 m/s

Part B;

The vertical velocity of the car is given as follows;

[tex]v_y[/tex]² = [tex]u_y[/tex]² + 2·g·h

∴ [tex]v_y[/tex]² =2·g·h = 2 × 9.8 m/s² × 16.200 m = 317.52m²/s²

[tex]v_y[/tex] = √(317.52 m²/s²) = (63/5)·√2 ≈ 17.819 m/s

The magnitude of the speed of the car, 'v', just before it lands is given using Pythagoras' theorem for resultant vectors as follows;

v = √([tex]v_y[/tex]² + vₓ²) = √(317.52 m²/s² +((161/6)·√2 m/s)²) ≈ 41.92345 m/s

The speed of the car just before it lands, v ≈ 41.92345 m/s.

A car accelerates from zero to a speed of 110
km/hr in 15 seconds. What is the car's rate of
acceleration?

Answers

The car's rate of  acceleration : a = 2.04 m/s²

Further explanation

Given

speed = 110 km/hr

time = 15 s

Required

The acceleration

Solution

110 km/hr⇒30.56 m/s

Acceleration is the change in velocity over time

a = Δv : Δt

Input the value :

a = 30.56 m/s : 15 s

a = 2.04 m/s²

A baseball player hits a baseball. The mass of the ball is 0.15 kg. The ball accelerates at a rate of 60 m/s 2 . What is the net force on the ball to the nearest newton?

Answers

Answer:

Please find attached pdf

Explanation:

Pls help!!
1 example of a conductor and 1 example of a insulator in your EVERYDAY world.

Answers

Answer:

here

Explanation:

Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

Examples of conductors include metals, aqueous solutions of salts

Conductor= Metals are good conductors of heat, therefore cooking utensils, kettles, irons, boilers, are always made up of iron, copper, Aluminum, or their alloys.


Insulators= oppose electrical current and make poor conductors. Some common conductors are copper, aluminum, gold, and silver. Some common insulators are glass, air, plastic, rubber, and wood.

Hope it helps! :3

A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did it take the car to reach this final velocity?

Answers

Answer:

t = 5 s

Explanation:

Data:

Initial Velocity (Vo) = 7 m/sAcceleration (a) = 3 m/s²Final Velocity (Vf) = 22 m/sTime (t) = ?

Use formula:

[tex]\boxed{t=\frac{Vf - Vo}{a}}[/tex]

Replace:

[tex]\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]

Solve the subtraction of the numerator:

[tex]\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}[/tex]

It divides:

[tex]\boxed{t=5\ s}[/tex]

How much time did it take the car to reach this final velocity?

It took a time of 5 seconds.

Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. What will its angular velocity be after 3t?

Answers

Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t²        ........................1

here ω  = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t²             ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t²                            .........................3

now here we take in 3t

θ = ω × 3t + 0.5 × α × (3t)²

for ω  = 0

θ = 0 + 0.5 × α × 9t²

now put value in eq 2

so

θ = (0.5) ×  (50 ÷ t²) ×  (3t)²

θ = 25 × 9

θ = 225 rad


The kinetic theory states that the higher the temperature, the faster the

Answers

Answer: the higher the kinetic energy

Explanation:

Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.40 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.700 m/s2 to the right. Find the magnitudes of the two forces P and Q .

Answers

Answer:

Explanation:

Q is larger than P . When two forces act in the same direction , Resultant force  

can be calculated by adding them up . When two forces act in the opposite  direction , Resultant force  can be calculated by subtracting  them .

Force = mass x acceleration .

In the first case

Resultant force = mass x acceleration

P + Q = 7 x 1.4 = 9.8 N

In the second case

Q - P = 7 x 0.7 = 4.9

Adding up these two equations

2 Q = 14.7

Q = 7.35 N

P = 9.8 - 7.35 = 2.45 N .

What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?

Answers

Answer:

Momentum, [tex]p=7.8\times 10^{-5}\ N-m[/tex]

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

[tex]p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m[/tex]

So, the momentum of the mosquito is [tex]7.8\times 10^{-5}\ N-m[/tex].

In the 1986 Olympic Games, Abdon Pamich of Italy won the 50 km walk, in
4h, 11 min and 11.2 s. Find his average speed in m/s.

Answers

Answer: 4

Explanation: because my pet monkey said it was

noooooooooooooooooooooooo

Answers

Answer:

yes

Explanation:

Answer:yeeeeeeeeeeeeeeeeeeeeeees

Explanation:

A basketball with a mass of 20 kg is accelerated with a force of 10 N. If resisting forces are ignored, what is the acceleration of the basketball?

Answers

I’m pretty sure it would be 10/20= 0.5m/s2

How do projectors project the color black?

Answers

Answer:

Projectors do not project the color black. This makes sense since black is really the absence of light, and you can't project something that does not exist. When a projector sends a beam of light on to a wall or a projector screen so that an image is formed on the wall or screen, the parts of the image that look black are really a very dim white color (which we sometimes call gray).  - wtamu

Answer is:

Projectors do not project the color black.

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