A fan is set on a desk next to a stack of paper. The fan is turned on and then turned
on HIGH SPEED. Which of the following would best apply Newton's First Law to this
example.
The papers accelerated due to the force of the fan.
The papers are acted upon by an unbalanced force from the fan.
O The papers exerted an equal force on the air blown by the fan.
O The papers that were the heaviest were blown the closest.

Answers

Answer 1

Answer:

The second option - the papers are acted upon by an unbalanced force from the fan.

Explanation:


Related Questions

The nearest neighbor interaction force is of magnitude 481 nanoNewtons, e.g., the magnitude of the force of the leftmost electron on the proton, or the magnitude of the force of any of the three on its nearest neighbor electron. Calculate the size of the net force on the leftmost proton.

Answers

Answer:

 F = 120.25 10⁻⁹  N

Explanation:

In this exercise, the force between the closest neighbors is indicated by f = 481 10⁻⁹ N, in general between the one-dimensional solid the distances remain the same, if the distance between the first neighbor is d, the distance between the second neighbors is 2d.

For most solids the attractive forces are electrical, therefore force is proportional to the electrical charges and the inverse of the distance squared,

             F = [tex]k \frac{q_1 q_2}{r^2}[/tex]

if we call fo the force for the first neighbors

              F₀ = k \frac{q_1 q_2}{d^2}

the force for the second neighbors r= 2d  

              F = k \frac{q_1 q_2}{(2d)^2}

              F = F₀ / 4

let's calculate

              F = 481 10⁻⁹ / 4

              F = 120.25 10⁻⁹  N

a 90 kilogram dog runs across the dog park at a speed of 6.5 meters per second. what is the magnitude and direction of the average force required to stop the dog in .85 seconds?

Answers

Answer:

am not sure about the answer

Explanation:

you need to find out the amount of force it's going in for example 10n or 100n then you need to times it the distance then devide by the time

What does the word quantum mean?

Answers

Answer:

a required or allowed amount, especially an amount of money legally payable in damages.

OR

In physics it means a discrete quantity of energy proportional in magnitude to the frequency of the radiation it represents.

Explanation:

hmu if u brave shawtys

Answers

Answer:

BET, & done ✌

Answer:

boop

Explanation:

A helicopter is hovering at a constant height of 35 m. The upward lift force on the helicopter is 85500. What is the weight of the helicopter

Answers

2,442! I think..right ok

PLEASE HELP! THIS IS TO BE TURNED IN IN ABOUT 3 MINUTES!!!!!!!
How must the net force be acting on an object in order for the object to have a circular motion? What is this type of force called?​

Answers

The direction of the net force is in the same direction as the acceleration. So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement.

6th grade science I mark as brainliest !

Answers

1) Compound is the correct answer2) Molecule is the correct answerPlease let me know if I am wrong.
The first answer is compound and the second answer is molecule

Does fg increase or decrease when one mass increases

Answers

Answer:

It increases because fg means Force of gravity so When the mass of the two objects  increases with mass and increases the distance between an object

There you go!!!

3. A car has a mass of 1,000 kilograms. If a net force of 2,000 N is exerted on the car, what is its acceleration?

Answers

Answer:

2 m/s^2

Explanation:

Acceleration = Force/mass

= 2,000/1,000

= 2

A pendulum has a period of 6.98s. Calculate the length of the pendulum. Use
9.8m/s^2 for gravity. *

Answers

Answer:

Length, l = 0.126 meters.

Explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 6.98 = 2*3.142 \sqrt {l*9.8} [/tex]

[tex] 6.98 = 6.284 \sqrt {9.8l} [/tex]

[tex] \frac {6.98}{6.284} = \sqrt {9.8l} [/tex]

[tex] 1.1108 = \sqrt {9.8l} [/tex]

Taking the square of both sides

[tex] 1.1108^{2} = 9.8l [/tex]

[tex] 1.2339 = 9.8l [/tex]

[tex] l = \frac {1.2339}{9.8} [/tex]

Length, l = 0.126m.

A ball of mass 0.3 kg flies through the air at low speed, so that air resistance is negligible. (a) What is the net force acting on the ball while it is in motion

Answers

Answer:

X axis   F=0

Y axis    Fg = - 2.94 j ^

Explanation:

The motion of a ball in air where the air residence is indicated to be negligible can be analyzed using Newton's second law.

We set a reference system, where the x-axis is horizontal and the y-axis vertical.

X axis

There are no forces on this axis, therefore the ball goes at constant speed.

Force is zero

Y axis  

In this axis it is subjected to the acceleration of gravity that creates a force equal to the weight of the body, in a vertical direction.

           Fg = m g

           Fg = 0.3 9.8

           Fg = 2.94 N

           Fg = - 2.94 j ^

the boold are vectors; negative sign indicates that the force eta directed vertically downward

The study of heat is ____?

Answers

Explanation:

thermodynamics is the study of heat.

Answer The study of heat and its relationship to useful work is called thermodynamics and involves macroscopic quantities such as pressure, temperature, and volume without regard for the molecular basis of these quantitie

Explanation:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular,________ in electricity plays the equivalent role of mass in gravity, while_______ , plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have__________ , while in gravity mass is always positive, which means gravity is_______ , but electricity________ .

Answers

Answer:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.

Explanation:

The formulas of Electric and gravitational fields are as follow

Electric Field

F(electric)=kq1q2/r^2

Gravitationlal Fieeld

F(grav)=GMm/r^2

As you see both follow the inverse square law in the formula

Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.

The gravitational field can only attractive while the electric field can be attractive or repulsive.

Normally electric field is stronger than the gravitational field.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Electric and gravitational forces have many similar features because they follow identical mathematical formulas.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,

but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,

which means gravity is always attractive, but electricity could be attractive and repulsive.

Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

To learn more about the gravitational force refer to the link;

https://brainly.com/question/24783651

What inspired Ronald McNair to do science

Answers

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

Do You think History is the most important subject that deserves first place? Do you see a way that learning history could assist you in your future career?

Answers

yes

Explanation:

history is an important class and it helps to you understand what went on in the past so that we can learn from our mistakes and help us grow

A 0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 44.0 pC charge on its surface. What is the potential near its surface

Answers

Answer:

Explanation:

Radius of sphere R = .250 x 10⁻² m

Potential on the surface V = k Q / R , where Q is charge on the surface ,  R is radius of the surface and k = 9 x 10⁹

Q = 44  x 10⁻¹² C

V = 9 x 10⁹ x 44  x 10⁻¹² /  ( .25 x 10⁻²)

= 1584 x 10⁻¹ Volt .

= 158.4 Volt

A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, the wire stretches an amount 1.68 cm. A mole of titanium has a mass of 48 grams, and its density is 4.54 g/cm3. Based on these experimental measurements, what is Young's modulus for this alloy of titanium

Answers

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

2. A force of 10 N is applied to an object which accelerates at a rate of 2m/s2. What is the mass
of the object?
(10 Points)
10 kg
5 kg
2 kg
20 kg

Answers

5 kg because to find mass you’re going to divide force by acceleration 10/2 is 5

Please answer the question

Answers

Answer:

Option B. 300 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of student = 100 Kg

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

From Newton's 2nd law,

F = ma

Where

F => Force applied

m => mass of object

a => acceleration of object.

With the above formula, we can obtain the acceleration of the ball as follow:

Mass (m) of ball = 1.5 Kg

Force (F) applied on the ball = 450 N

Acceleration (a) of ball =?

F = ma

450 = 1.5 × a

Divide both side by 1.5

a = 450 / 1.5

a = 300 m/s²

Therefore, the acceleration of the ball is 300 m/s²

The number of complete wavelengths that pass a point in a given time is referred to as...
A. Wavelength
B. Frequency
C. Amplitude
D. Reflection​

Answers

The answer would be B. Frequency

A basketball with a mass of 20 kg is accelerated with a force of 10 N. If resisting forces are ignored, what is the acceleration of the basketball?

Answers

I’m pretty sure it would be 10/20= 0.5m/s2

Please answer the question

Answers

Answer:

D

Explanation:

He walked a shorter distance, she walked a longer distance but got that wing thingies

3. If the gravitational force between 2 objects is 50 N, what is the gravitational
force when the distance between the two is increased to four times the distance?

Answers

The gravitational  force : 3.125 N

Further explanation

Given

F₁ = 50 N

Required

F₂

Solution

Newton's Gravity Law:  

[tex]\rm F=G.\dfrac{m_1.m_2}{r^2}[/tex]

with F = gravitational force,  

G = gravitational constant,  

m1, m2 = mass of object,  

r = distance between two objects.  

The value of m and G are the same , so :

F₁ ≈ 1/r₁²

The distance between the two is increased to four times:

r₂ = 4r₁

F₂ = 1/(4r₁)²

F₂ = 1/16r₁²

F₂ = F₁ x 1/16

F₂ = 50 : 16

F₂ = 3.125 N

Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.40 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.700 m/s2 to the right. Find the magnitudes of the two forces P and Q .

Answers

Answer:

Explanation:

Q is larger than P . When two forces act in the same direction , Resultant force  

can be calculated by adding them up . When two forces act in the opposite  direction , Resultant force  can be calculated by subtracting  them .

Force = mass x acceleration .

In the first case

Resultant force = mass x acceleration

P + Q = 7 x 1.4 = 9.8 N

In the second case

Q - P = 7 x 0.7 = 4.9

Adding up these two equations

2 Q = 14.7

Q = 7.35 N

P = 9.8 - 7.35 = 2.45 N .

What are used to measure temperature.

Answers

Answer:

A thermometer is an instrument that measures temperature.

Explanation:

a thermometer everyone knows this

A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resulting oscillation has a period of 0.750 s and an amplitude of 15.0 cm. Determine the oscillation frequency, the spring constant, and the speed of the mass when it is halfway to the equilibrium position.

Answers

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

which is the product of cellular respiration? A. ATTP B. light C. oxygen D.sugar

Answers

the answer to the question is A

A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreciable air resistance. When it has reached a height of 575 m , its engines suddenly fail so that the only force acting on it is now gravity. Part A What is the maximum height this rocket will reach above the launch pad

Answers

Answer:

Explanation:

We shall first calculate the velocity at height h = 575 m .

acceleration a = 2.2 m /s²

v² = u² + 2 a s

u is initial velocity , v is final velocity , s is height achieved

v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

If it travels further by height H

from the relation

v² = u² - 2 g H

v = 0 , u = 50.3 m /s

H = ?

0 = 50.3² - 2 x 9.8 H

H = 129.08 m

Total height attained by rocket

= 575 + 129.08

= 704.08 m .

Meandering valleylike features on the Moon's surface are called

Answers

Answer:

Meandering valley like features on the Moon's surface are called rilles

Explanation:

NOUN

rilles (plural noun)

a fissure or narrow channel on the moon's surface.

Why can’t a real machine ever have 100% efficiency

Answers

Answer:

Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.

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