A 70 kg Throckmorton was riding his skateboard when a small, but juicy 0.001 kg beetle hits the front of his helmet, splattering, obstructing his view. Who experienced the greatest change in momentum?

Answer:

the Potential Energy is 2.304 × 10⁻¹⁶ J

Explanation:  

Given the data in the data in the question;

The expression for the electric potential energy between the charges can be expressed as follows;

PE = qV ------equ 1

where q is the charge and V is the electric potential

Also the formula for electric potential due to point a point in a field is;

V = kq /  r -------equ 2

where k is the electrostatic constant and r is the distance form the charged particle

input equation 2 into 1

PE = q × kq /  r

PE = kq²/r ------- equ 3

so we substitute into equation 3; 1.00×10⁻¹² for r, 9.00×10⁹ for k( constant ) and 1.60×10⁻¹⁹ for q( charge )

PE = ((9.00×10⁹) (1.60×10⁻¹⁹)²) / 1.00×10⁻¹²

PE = 2.304 × 10⁻²⁸ / 1.00×10⁻¹²

PE = 2.304 × 10⁻¹⁶ J

Therefore, the Potential Energy is 2.304 × 10⁻¹⁶ J

Answer:

Explanation:

60 mph = 60 x 1760 x 3 / (60 x 60) ft /s

speed of car , v = 88 ft /s

kinetic energy of car = 1/2 m v²

= .5 x 3000 x 88²

= 11616 x 10³ poundal - foot

Potential energy = mgh

= 3000 x 32 x 100

=  9600 x 10³ poundal - foot

Total energy = potential energy + kinetic energy

= ( 11616 + 9600 )x 10³

= 21216 x 10³ poundal - foot .

This energy is dissipated as heat when brakes are applied on the car to stop the car .

Answer:

NE DIYON INGILIZ MISIN SEN

Answer:2000 cm³

Here, pressure remains constant.

So, b the gas law

V/V' = T/ T'

1000 / V' = 300 / 600

V' = 2000 cm³

Explanation:also pls mark brainliest

Answer:

A. oceanic crust

Explanation:

I remember that the ocean is said to cover 71% of the Earth's surface. If you look at a globe, notice that most all the surface is blue like the ocean.

One other note: the surface is the Earth's outermost layer. Think of it this way: surface implies the top of something, something exposed to the outside.

Therefore, the answer is A. Hope this helps you understand the question more! Have a great day, 'kay?

Answer:

this is about momentum p=mv

A, the elephant has more mass

Answer:

3.2N

Explanation:

Given parameters:

Coefficient of kinetic friction  = 0.43

Weight of box  = 7.4N

Unknown:

Force of kinetic friction  = ?

Solution:

The force of kinetic friction is given as:

        Force of kinetic friction  = UN

U is the coefficient of friction

N is the weight

  Force of kinetic friction  = 0.43 x 7.4  = 3.2N

Answer:

Large; small.

Explanation:

A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies. The first telescope was invented by Sir Isaac Newton.

To have the highest magnification in a telescope, the focal length of the objective lens should be large and the focal length of the eyepiece lens should be small.

This ultimately implies that, the eyepiece lens has a small focal length while the objective lens has a large focal length.

Hello!

[tex]\large\boxed{4000 N}[/tex]

Use the following equation to solve for the net force (N):

∑F = m × a

Plug in the given mass (kg) and speed (m)

∑F = 2000 * 2

Simplify:

∑F = 4000 N

Answer:

Answer:

15.67 seconds

Explanation:

Using first equation of Motion

Final Velocity= Initial Velocity + (Acceleration * Time)  

v= u + at

v=3

u=50

a= - 4 (negative acceleration or deceleration)  

3= 50 +( -4 * t)

-47/-4 = t

Time = 15.67 seconds

We have that the speed  must be at the speed below if they want to just hit their target

From the Question we are told that

Distance [tex]d=50m[/tex]

Height [tex]h=70m[/tex]

Constant Velocity [tex]v= 7.0 m/s[/tex]

Generally the equation for the time  is mathematically given as

[tex]T=\frac{h}{v}\\\\T=\frac{70}{7}\\\\T=10s[/tex]

Therefore

The velocity required to make horizontal movement is

[tex]V=\frac{d}{T}\\\\V=\frac{50}{10}\\\\V=5m/s[/tex]

Given that

Velocity on the Vertical axis is

[tex]v_y=7m/s[/tex]

Velocity on the  horizontal axis is

[tex]v_x=5m/s[/tex]

Therefore resultant speed

[tex]v_r=\sqrt{v_x^2+V_y^2}\\\\v_r=\sqrt{(5)^2+(7)^2}[/tex]

[tex]v_r=8.6023m/s[/tex]

In conclusion

[tex]v_r=8.6023m/s[/tex] must be their total speed if they want to just hit their target

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Answer:45 m/s north

Explanation:

Answer:

Acceleration due to gravity, g = 2.68m/s²

Explanation:

Given the following data;

Period = 5.14s

Length = 0.25m

To find acceleration due to gravity, g;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 5.14 = 2*3.142 \sqrt {0.25g} [/tex]

[tex] 5.14 = 6.284 \sqrt {0.25g} [/tex]

[tex] \frac {5.14}{6.284} = \sqrt {0.25g} [/tex]

[tex] 0.8180 = \sqrt {0.25g} [/tex]

Taking the square of both sides

[tex] 0.8180^{2} = 0.25g [/tex]

[tex] 0.6691 = 0.25*g[/tex]

[tex] g = \frac {0.6691}{0.25} [/tex]

Acceleration due to gravity, g = 2.68m/s²

Answer:

Heat pump needs 1.965 megajoules each hour to run.

Explanation:

The Coefficient of Performance ([tex]COP[/tex]), no unit, of a Carnot's heat pump is:

[tex]COP = \frac{Q_{H}}{W}[/tex] (1)

Where:

[tex]Q_{H}[/tex] - Heat received by the building, measured in megajoules.

[tex]W[/tex] - Work needed to run the heat pump, measured in megajoules.

If heat pump is a Carnot engine working in reverse, then the amount of work needed to run the heat pump is the least possible work. If we know that [tex]Q_{H} = 7.27\,MJ[/tex] and [tex]COP = 3.70[/tex], then the amount needed by the heat pump each hour is:

[tex]W = \frac{Q_{H}}{COP}[/tex]

[tex]W = \frac{7.27\,MJ}{3.70}[/tex]

[tex]W = 1.965\,MJ[/tex]

Heat pump needs 1.965 megajoules each hour to run.

Answer:

6.29 μC/m³

Explanation:

Volume charge density is the quantity of charge per unit volume.

The direction of the electric field was not specified, therefore the volume charge density (ρ) is given by:

2πRLE = ρπR²L/ε₀

ρ = 2Eε₀ / R

Where E = electric field strength = 16 kN/C = 16 * 10³ N/C, R = radius of rod = 4.5 cm = 0.045 m, ε₀ = relative permittivity of free space = 8.85 * 10⁻¹² C² / Nm²

Therefore:

ρ = 2(16 * 10³ N/C)(8.85 * 10⁻¹² C²/Nm²) / 0.045 m = 6.29 * 10⁻⁶ C/m³

ρ = 6.29 μC/m³

Answer:

A. the average acceleration was the same

Explanation:

Acceleration is calculated by finding the difference of the initial velocity from the final velocity (on impact, usually 0) and then dividing by the amount of time that took place. If we assume that both balls were thrown at the same initial force, and ended up hitting the wall at the same time then we can say that the average acceleration was the same. If the initial velocity was not the same then we would need the initial velocity of each ball in order to calculate the acceleration of each object and determine which had a greater acceleration.

Answer:

L = 1.11 x [tex]10^{6}[/tex] m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.

Explanation:

Solution:

Data Given:

Heat Energy = 52000 J

Dielectric Constant of the plastic Bag = 3.7 = K

Thickness = 2.6 x [tex]10^{5}[/tex] m =d

V = 610 volts

A = width x Length

width = 20 cm = 20 x [tex]10^{-2}[/tex] m

Length = ?

So,

we know that,

U = 1/2 C Δ[tex]v^{2}[/tex]

U = 52000 J

C = ?

V = 610 volts'

So,

U = 1/2 C Δ[tex]v^{2}[/tex]  

52000 J = (0.5) x (C) x ([tex]610^{2}[/tex])

C = 0.28 F

And we also know that,

C = [tex]\frac{K*E*A}{d}[/tex]

E = 8.85 x [tex]10 ^{-12}[/tex]

K = 3.7

A = 0.20 x L

d = 2.6 x [tex]10^{5}[/tex] m

Plugging in the values into the formula, we get:

0.28 = [tex]\frac{3.7 * 8.85 .10^{-12} * (0.20 . L) }{2.6 . 10^{5} }[/tex]

Solving for L, we get:

L = 1.11 x [tex]10^{6}[/tex] m,

is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.  

Answer:

[tex]q=-2.26\times 10^{-5}\ C[/tex]

Explanation:

Given that,

The mass of a particle, m = 1.48 g = 0.00148 kg

The electric field, E = 640 N/C

We need to find the charge of the particle when placed in a downward-directed electric field.

The force of gravity is balanced by the electric force such that,

mg = qE

Where

q is the charge of the particle

[tex]q=\dfrac{mg}{E}\\\\q=\dfrac{0.00148\times 9.8}{640}\\\\q=2.26\times 10^{-5}\ C[/tex]

q must be negative, the force must be upward (opposite direction of the electric field).

Answer:

a=∆v/∆t

Explanation:

The definition of Acceleration is the change in velocity in a given time. So this means you first calculate ∆v (Change in velocity), and you calculate ∆t which is the time taken to apply that change in velocity. Then you find a= ∆v/∆t. This gives us the equation of Acceleration.

Answer:

Explanation:

Answer:

Explanation:

Pressure due to water column as deep as 10994 meters can be given by the following expression

Pressure = h d g , where h is depth of water , d is density of water and g is acceleration due to gravity .

Pressure = 10994 x 10³ x 9.8

= 10.77 x 10⁷ N / m²

Pressure will act on curved surface of the spherical shell , the effective surface area will be π R² where R is radius of the surface .

Effective surface = 3.14 x 0.1²

= .0314 m²

Total force = pressure due to water column x effective surface

= 10.77 x 10⁷  x .0314 N.

= 33.82 x 10⁵ N .

Complete question is;. A 73mH solenoid inductor is wound on a form that is 0.80m long and 0.10m in diameter a coil having a resistance of 7.7 ohms is tightly wound around the solenoid at its center the mutual inductance of the coil and solenoid is 19μH at a given instant the current in the solenoid is 820mA and is decreasing at the rate of 2.5A/s at the given instant what is the induced current in the coil

Answer:

6.169 μA

Explanation:

Formula for induced EMF is given by the equation;

EMF = M(di/dt). We are given;

di/dt = 2.5 A/s

M = 19μH = 19 × 10^(-6) H

Thus;

EMF = 19 × 10^(-6) × 2.5.

EMF = 47.5 × 10^(-6) V

Formula for current is;

i = EMF/R. R is resistance given as 7.7 ohms.

Thus; i = 47.5 × 10^(-6)/7.7

i = 6.169 μA

Answer:

D

Explanation:

A and C are balanced, B has a resultant force of 5N right, and D has a resultant force of 20N right.

Answer:

C Increase your potential energy

Explanation:

Because if you start falling your potential energy would convert to kinetic energy. So you would get potential energy climbing up a tree

Answer:

I think it's potential energy

Answer:

Charge at rest only produces electric field. Moving charge produces both electric field and magnetic field.

plz follow me

static friction force = The coefficient of static friction * normal force

static friction force = 0.46 * 51 = 23.46 N

kinetic friction force = The coefficient of kinetic friction * normal force

kinetic friction force = 0.23 * 51 = 11.73 N

the applied force acting on the object must be more than 23.5 N if the object was stationary to move it and must be more than 11.7 N during the movement to keep the object moving

The force formula can be rewritten  to solve the acceleration as:

acceleration = force/mass.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

From Newton's 2nd law of motion, we can write that:

Force = mass × acceleration

⇒ acceleration = force/mass.

Hence, the force formula can be rewritten  to solve the acceleration as:

acceleration = force/mass.

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Answer:

the work done by the field is positive and the potential energy of the electron field system decreases

Explanation:

This exercise asks to find the work and the potential energy of an electron in an electric field.

Work is defined by

         W = F .d = F d cos θ

the electric force is

          F_e = q E

         W = q E d cos θ

since the charge of the electron is negative the force is in the opposite direction to the electric field

          W = - e E d

we select the direction to the right is positive, point i is to the left of point f,

therefore the work moving from point i to point F has two possibilities

* The electric field lines go from i to f point , so that point i is on the side of the positive charges, so the electron approaches them, This movement is opposite to that indicated

* the field line reaches point i, this implies that the charges are negative, so the electrioc field is then negativeand the electron charge is negative too.  The electron moves away from this point, this is in accordance with the indicated movement

In the latter case the electric field lines go from f to i point, therefore the Work is positive

Now let's examine the potential energy

            ΔU = - q E .d

so we see that this definition is related to work,

            ΔU = -W

Therefore, as the work is positive, the power energy must decrease

When reviewing the different answers, the correct ones are:

the work done by the field is positive and the potential energy of the electron field system decreases

The work done by the electron while moving from point [tex]i[/tex] to point [tex]f[/tex] in the direction of uniform electric field is negative and the potential energy of the electron increases.

An electron moves from point i to point f, in the direction of a uniform electric field, then  the potential energy of the electron can be calculated s given below.

[tex]\Delta V=-qEd[/tex]

Where [tex]\Delta V[/tex] is the potential energy, [tex]E[/tex] is the electric field, [tex]q[/tex] is the charge and [tex]d[/tex] is the displacement of the electron.

The work done by the electron in the uniform electric field can be calculated as,

[tex]W = F\times d \times cos\theta[/tex]

Where [tex]W[/tex]is the work done by electron, [tex]F[/tex] is the electric force, [tex]d[/tex] is the displacement of the electron and  for uniform electric field, the value of [tex]\theta[/tex] is zero.

Hence  [tex]W=F\times d\times 1\\W=F \times d[/tex]

Electric force  [tex]F = q E[/tex]

By substituting the value of electric force on the above formula,

[tex]W = qEd[/tex]

Hence, the relation between the work done the electron in an uniform electric field and potential energy of the electron can be given below.

[tex]W = -\Delta V[/tex]

The work done by the electron is negative and the potential energy of the electron increases.

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Answer:

[tex]0.3\ \text{m}^3/\text{kg}[/tex]

[tex]36\ \text{kJ}[/tex]

[tex]18\ \text{kJ/kg}[/tex]

Explanation:

V = Volume of air = [tex]0.6\ \text{m}^3[/tex]

P = Power = 10 W

t = Time = 1 hour

m = Mass of air = 2 kg

Specific volume is given by

[tex]v=\dfrac{V}{m}\\\Rightarrow v=\dfrac{0.6}{2}\\\Rightarrow v=0.3\ \text{m}^3/\text{kg}[/tex]

The specific volume at the final state is [tex]0.3\ \text{m}^3/\text{kg}[/tex]

Work done is given by

[tex]W=Pt\\\Rightarrow W=10\times 60\times 60\\\Rightarrow W=36000\ \text{J}=36\ \text{kJ}[/tex]

The energy transfer by work, is [tex]36\ \text{kJ}[/tex]

Change in specific internal energy is given by

[tex]\Delta u=\dfrac{Q}{m}+\dfrac{W}{m}\\\Rightarrow \Delta u=0+\dfrac{36}{2}\\\Rightarrow \Delta u=18\ \text{kJ/kg}[/tex]

The change in specific internal energy of the air is [tex]18\ \text{kJ/kg}[/tex]

Answer:

Explanation:

concentration of substance X in chamber 1 = 100 mmol/L

total volume of chamber 1 = 10 L

total mass of substance X in chamber 1 = 100 x 10 mmol = 1000 mmol .

When the two chamber is joined , total volume of both the chamber

= 10 L + 5 L = 15 L .

In the volume of 15 litre , substance x is uniformly distributed because it is permeable .

concentration of substance X = mass of X / total volume = 1000 mmol / 15

= 66.67 mmol / L

Hence ,

"The concentration of Substance X in Chamber 2 will never exceed 66mmol/L."