20. Write an expression: Alexis has $10 less than twice the amount that David has. If David has
x dollars, write an expression to represent the amount that Alexis has.

Answer: i) [tex]\frac{1}{3}[/tex]

              ii) [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Total length of film = 45 mins

Fraction of time left after 15 mins = [tex]\frac{15}{45}[/tex]

                                                       = [tex]\frac{1}{3}[/tex]

Fraction of time left after 25 mins = [tex]\frac{25}{45}[/tex]

                                                        = [tex]\frac{5}{9}[/tex]

Answer:

64

Step-by-step explanation:

the different sum of money is 64

John can make 6 different sums of money. He can make $0.05 from $2, $0.15 from $1, $0.40 from $0.50, $0.90 from #0.25, $1.90 from $0.10, and $3.90 from $0.05 coins

To discover the different sums of money John can make, we are able to utilize a strategy called "coin alter" or "category" issue.

John has a $2, $1, $0.50, $0.25, $0.10, and $0.05 coin in his pocket

Step 1: Begin with a purge entirety (0).

Step 2: Include each coin group in its entirety, one at a time.

Step 3: Rehash Step 2 for all possible combinations of coins.

Let's go through the method:

With $0.05 coin: total sum = (+ $0.05) = $0.05

With $0.10 coin: total sum = ($0.05 + $0.10) = $0.15

With $0.25 coin: total sum = ($0.15 + $0.25) = $0.40

With $0.50 coin: total sum = ($0.40 + $0.50) = $0.90

With $1 coin: total sum = ($0.90 + $1) = $1.90

With $2 coin: total sum = ($1.90 + $2) = $3.90

Presently, John can make the following different sums of money from the coins:

$0.05

$0.15

$0.40

$0.90

$1.90

$3.90.

There are 6 diverse wholes of cash John can make.

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Multiplying block matrices works just like multiplication between regular matrices, provided that component matrices have the right sizes.

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf{IW}+\mathbf{0Y}&\mathbf{IX}+\mathbf{0Z}\\\mathbf{KW}+\mathbf{IY}&\mathbf{KX}+\mathbf{IZ}\end{bmatrix}[/tex]

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf W+\mathbf 0&\mathbf X+\mathbf 0\\\mathbf{KW}+\mathbf Y&\mathbf{KX}+\mathbf Z\end{bmatrix}[/tex]

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf W&\mathbf X\\\mathbf{KW}+\mathbf Y&\mathbf{KX}+\mathbf Z\end{bmatrix}[/tex]

(I assume I is the identity matrix and 0 is the zero matrix.)

Answer:

The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.

The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.

0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.

The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normally distributed variable:

For n instances of a normally distributed variable, the mean is:

[tex]M = n\mu[/tex]

The standard deviation is:

[tex]s = \sigma\sqrt{n}[/tex]

Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes.

This means that [tex]\mu = 2.3, \sigma = 2[/tex]

An operator in the call center is required to answer 76 calls each day.

This means that [tex]n = 76[/tex]

What is the expected total amount of time in minutes the operator will spend on the calls each day?

[tex]M = n\mu = 76*2.3 = 174.8[/tex]

The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.

What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day?

[tex]s = \sigma\sqrt{n} = 2\sqrt{76} = 17.4356[/tex]

The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.

What is the approximate probability that the total time spent on the calls will be less than 166 minutes?

This is the p-value of Z when X = 166.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

For this problem:

[tex]Z = \frac{X - M}{s}[/tex]

[tex]Z = \frac{166 - 174.8}{17.4356}[/tex]

[tex]Z = 0.5[/tex]

[tex]Z = 0.5[/tex] has a p-value of 0.6915.

1 - 0.6915 = 0.3085.

0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.

What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95?

This is X = c for which Z has a p-value of 0.95, so X = c when Z = 1.645. Then

[tex]Z = \frac{X - M}{s}[/tex]

[tex]1.645 = \frac{c - 174.8}{17.4356}[/tex]

[tex]c - 174.8 = 1.645*17.4356[/tex]

[tex]c = 203.4816[/tex]

The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]

Answer:

B.) 317

Step-by-step explanation:

100/2 = 50

124/2 = 62

180/2 = 90

634/2 = 317

Answer:

6

Step-by-step explanation:

đạo hàm cấp 2 của f(x) rồi thế 0 vào

Answer:

8.5

Step-by-step explanation:

Answer:

5/2

Step-by-step explanation:

Since MR=MR and XM=MY and angle XMR = angle RMY,

then triangle XMR is congruent to triangle RMY by SAS postulate

Therefore, XR has to be equal to RY.

Making 6x+2=17

subtracting both sides by 2 gives you 6x=15

then dividing both sides by 6 gives you x=15/6

simplifying this fraction gives you x=5/2

Hope this helps.

Answer:

The answer is (B) 1/2=12

Answer:

1320 m^2

Step-by-step explanation:

area of ground = π r ^2

= (22/7) × (137/2)^2

= 14,747.0714286 m^2

area of ground and path

=( 22/7)(143/2)^2

= 16,067.0714286 m^2

area of path

=16,067.0714286 -14,747.0714286

= 1320 m^2

note :

r = radius = diameter /2

area of a circle = π r^2

diameter of circle created with path and ground = 137 + 2 × width of path

= 137 + 2× 3 = 143 m

Answer:

7x sqrt(2) - 2 sqrt(2)

Step-by-step explanation:

5x sqrt(2) - 2 sqrt(2) + 2x sqrt(2)

Combine like terms

5x sqrt(2) + 2x sqrt(2)    - 2 sqrt(2)

7x sqrt(2) - 2 sqrt(2)

Answer:

f(g(-2)) = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Functions

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 4 - x²

g(x) = 2x + 5

Step 2: Find g(-2)

Step 3: Find f(g(-2))

Answer:

Answer:

Step-by-step explanation:

a + ab/100

Answer:

all answer are in given solution

Answer:

Pvalue

Step-by-step explanation:

The Pvalue measure which takes up a value in the range 0 - 1 is a statistical measure used on hypothesis testing to measure the likelihood of obtaining result atleast as extreme as the outcome of the statistical hypothesis test, The Pvalue is used in hypothesis testing to make a case for the alternative hypothesis, which involves being compared with the α - value.

Lower p values favors the adoption of alternative depending on how extreme th α-value is. The Pvalue is dependent on the value if the test statistic.

Answer:

Below.

Step-by-step explanation:

IQR is the same

Number of data points is the same.

Mode - can't tell

Range - different

First quartile - same

Median - different.

Given:

Consider the below figure attached with this question.

The value in the given figure are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Putting [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Hence, the correct option is C.

9514 1404 393

Answer:

  Rate

Step-by-step explanation:

Since there are no currency units involved, it is not a price or unit price.

Since the denominator (days) is not 1, it is not a unit rate.

The usual wording for a ratio is "to" rather than "in", so we probably would not say this is a ratio. Though, the usual reason for expressing the numbers this way is to indicate we might be interested in their ratio.

There is time involved, so it is reasonable to call this a "rate," which is usually the ratio of some quantity to the time associated with that quantity.

Answer:

cannot understand the language man

but please follow

Step-by-step explanation:

d(v)=1.1(45)+0.6(45)²

=1.1(45)+0.6(2025)

=49.5+1215

=1264.5

Answer:

b

Step-by-step explanation:

b intercepts the y axis

Answer:

The correct answer is:

Portfolio A = $107,000

Portfolio B = $36,000

Portfolio C = $32,000

Step-by-step explanation:

According to the question,

[tex]A+B+C=175000[/tex]...(1)

[tex]A+B = 143000[/tex]...(2)

[tex]A+C=139000[/tex]...(3)

Now,

From (1) and (2), we get

⇒ [tex]Portfolio \ C = (1)-(2)[/tex]

                        [tex]=175000-143000[/tex]

                        [tex]=32000[/tex]...(4)

From (1) and (3), we get

⇒ [tex]Portfolio \ B =(1)-(3)[/tex]

                        [tex]=175000-139000[/tex]

                        [tex]=36000[/tex]...(5)

From (1), (4) and (5), we get

⇒ [tex]Portfolio \ A = (1)-(4+5)[/tex]

                        [tex]=175000-(36000+32000)[/tex]

                        [tex]=175000-68000[/tex]

                        [tex]=107000[/tex]  

Thus the above is the correct answer.

Answer:

✔️6 × 5²

✔️6 × 5 × 5

✔️150

Step-by-step explanation:

6 times 5 squared is written as 6 × 5²

Thus:

6 × 25 = 150

Evaluate each of the expressions given to determine whether they are equivalent to 150 or not

✔️5 × 6² = 5 × 36 = 180 (NOT EQUIVALENT)

✔️6 × 5² = 6 × 25 = 150 (EQUIVALENT)

✔️192 ≠ 150 (NOT EQUIVALENT)

✔️6 × 5 × 5 = 6 × 25 = 150 (EQUIVALENT)

✔️6 × 5 × 2 = 6 × 10 = 60 (NOT EQUIVALENT)

✔️150 = 150 (EQUIVALENT)

✔️6 + 5 × 5 = 6 + 25 = 31 (NOT EQUIVALENT)

Answer:

0.6827

Step-by-step explanation:

Given that :

Mean, μ = 3

Standard deviation, σ = 0.1

To produce an acceptable cork. :

P(2.9 < X < 3.1)

Recall :

Z = (x - μ) / σ

P(2.9 < X < 3.1) = P[((2.9 - 3) / 0.1) < Z < ((3.1 - 3) / 0.1)]

P(2.9 < X < 3.1) = P(-1 < Z < 1)

Using a normal distribution calculator, we obtain the probability to the right of the distribution :

P(2.9 < X < 3.1) = P(1 < Z < - 1) = 0.8413 - 0.1587 = 0.6827

Hence, the probability that the first machine produces an acceptable cork is 0.6827

Answer:

Quadrant 4

Step-by-step explanation:

If the given angle was positive, then we go clockwise.

But it's negative so we go counterclockwise.

An alternative way of graphing

Quadrant 1 is 0-90°

Quadrant 2 is 90-180°

Quadrant 3 is 180-270°

Quadrant 4 is 270-360°

Subtract the given angle by 360 until no longer possible

750 - 360 = 390     390 - 360 = 30

Remember that this was originally a negative angle

Instead of going clockwise to quadrant 1, we go counterclockwise to quadrant 4, ending up at 330°

Answer:

I think

A display order of numbers are called​ sequences.

The figure has rotational symmetry from the given options is shown in Figure B.

When a figure is rotated (by a certain amount) about a set point on its surface (often the center), and retains its original appearance, it is said to have rotational symmetry.

According to the given question,

We have the given options in this question:

Assuming that the problem in this instance does not require full rotation (because after full rotation, any figure appears to itself when it returns to its original location as it did before), the first figure that possesses rotational symmetry can be chosen.

It is because you obtain the same figure whether you rotate the first figure by a quarter, half, or quarter and a half rotation. For any of the other stated figures, it won't occur (you can imagine those figures rotating, and then will notice that only option B has rotation symmetry for other angles in addition to full rotation).

Therefore, the figure from the listed figures which has rotational symmetry is Figure B.

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Answer:

5x^2-12x+7

Step-by-step explanation:

7x^2-5x+3-(2x^2 + 7X - 4)

Distribute the minus sign

7x^2-5x+3 - 2x^2 - 7X + 4

Combine like terms

5x^2-12x+7

Answer:

-12x + 17

Step-by-step explanation:

hope this helps!

Answer:

[tex]{ \sf{thats \: it}}[/tex]